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ZIMSEC O Level · 4004/2 · N2024

Mathematics Paper 2 November 2024

Questions
58
Total marks
136
Time allowed
150 min
Syllabus code
4004/2

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Questions
58
Pass mark
35
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[3 marks]H.C.F and L.C.M
Find the Highest Common Factor (H.C.F) of 96 and 120.

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Question 102

[2 marks]H.C.F and L.C.M
On a certain day the temperature rose from −5 ∘-5\,^\circC to +27 ∘+27\,^\circC. Calculate the rise in temperature, in degrees Celsius.

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Question 103

[2 marks]H.C.F and L.C.M
Given that r=4,2×105r = 4,2 \times 10^5 and q=7×10−3q = 7 \times 10^{-3}, evaluate qrqr, leaving the answer in standard form.

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Question 104

[2 marks]H.C.F and L.C.M
Simplify 37+14×23\sqrt{7} + \sqrt{14} \times \sqrt{2}, leaving the answer in surd form.

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Question 201

[1 marks]Matrices
Write down the order of the matrix (28)\begin{pmatrix} 2 & 8 \end{pmatrix}.

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Question 202

[2 marks]Matrices
Matrix A=(50−89)A = \begin{pmatrix} 5 & 0 \\ -8 & 9 \end{pmatrix} and matrix B=(6−402)B = \begin{pmatrix} 6 & -4 \\ 0 & 2 \end{pmatrix}. Evaluate A−12BA - \frac{1}{2}B, giving the four entries in order.

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Question 203

[2 marks]Matrices
Matrix A=(50−89)A = \begin{pmatrix} 5 & 0 \\ -8 & 9 \end{pmatrix} and matrix B=(6−402)B = \begin{pmatrix} 6 & -4 \\ 0 & 2 \end{pmatrix}. Evaluate ABAB, giving the four entries in order.

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Question 204

[2 marks]Matrices
The matrix (x−162x+3)\begin{pmatrix} x - 1 & 6 \\ 2 & x + 3 \end{pmatrix} is singular. Write down its determinant in terms of xx, before expanding the brackets.

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Question 205

[3 marks]Matrices
Solve the equation x2+2x−15=0x^2 + 2x - 15 = 0.

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Question 301

[2 marks]Consumer Arithmetic
The selling price of a mobile phone is $2 760,00\$2\,760,00 including Value Added Tax of 15%. Calculate the price of the phone excluding Value Added Tax.

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Question 302

[2 marks]Consumer Arithmetic
A mobile phone sells for ZWL$2 760,00\$2\,760,00. On a certain day the exchange rate was ZWL$9,00\$9,00 to 1 Botswana Pula. Find the cost of the phone in Pula, correct to 2 decimal places.

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Question 303

[3 marks]Consumer Arithmetic
A sales person is paid 3,5% commission on each mobile phone sold at $2 760,00\$2\,760,00. Calculate the total commission earned when 23 such phones are sold.

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Question 304

[3 marks]Consumer Arithmetic
Electricity is charged at $2,25\$2,25 per unit for the first 50 units, $4,51\$4,51 per unit for units 51 to 100, $11,26\$11,26 per unit for units 101 to 300 and $12,94\$12,94 per unit for 301 units and above. Calculate the cost of 375 units.

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Question 401

[2 marks]Measures and Mensuration
An athletics field is a rectangle ABDE with a semicircle of radius 31,8 m on each end, and AB=100AB = 100 m. Taking π\pi to be 3,142, calculate the length of arc BCD, in metres.

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Question 402

[2 marks]Measures and Mensuration
An athletics field is a rectangle ABDE with a semicircular end of radius 31,8 m at each end, and AB=ED=100AB = ED = 100 m. Taking π\pi to be 3,142, calculate the perimeter of the field, in metres.

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Question 403

[3 marks]Measures and Mensuration
An athletics field is a rectangle ABDE with a semicircle of radius 31,8 m on each end, and AB=100AB = 100 m. Taking π\pi to be 3,142, calculate the total area of the field, correct to the nearest square metre.

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Question 404

[2 marks]Measures and Mensuration
An athletics field has a total area of 9 5379\,537 m2^2. Calculate the cost of covering the whole field with grass at $620\$620 per square metre.

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Question 405

[2 marks]Measures and Mensuration
On a map, the length AB=100AB = 100 m of an athletics field is drawn as a line 4 cm long. Find the scale used, in the form 1:n1 : n where nn is an integer.

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Question 501

[1 marks]Constructions and Loci
Triangle ABC is constructed with BC=10,5BC = 10,5 cm, AB^C=90∘A\hat{B}C = 90^\circ and BC^A=30∘B\hat{C}A = 30^\circ. Measure and write down the length of AB, in centimetres.

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Question 502

[2 marks]Constructions and Loci
In triangle ABC, AB^C=90∘A\hat{B}C = 90^\circ and BC^A=30∘B\hat{C}A = 30^\circ. Find BA^CB\hat{A}C, in degrees.

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Question 503

[2 marks]Constructions and Loci
In triangle ABC, which construction gives the locus of the points inside the triangle that are equidistant from the lines AB and AC?
  1. AThe bisector of angle BAC, drawn from A
  2. BThe perpendicular bisector of the side BC
  3. CThe line through A parallel to the side BC
  4. DThe perpendicular from A to the side BC

Question 504

[2 marks]Constructions and Loci
What is the locus of the points that are 3 cm from the line BC?
  1. AThe perpendicular bisector of BC, marked 3 cm from B
  2. BA pair of lines parallel to BC, one 3 cm on each side of it
  3. CA single line parallel to BC and 3 cm above it
  4. DA circle of radius 3 cm centred on the midpoint of BC

Question 601

[2 marks]Factorisation
Factorise completely a2+ay−ax−xya^2 + ay - ax - xy.

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Question 602

[2 marks]Factorisation
Factorise completely x2y2−9x^2y^2 - 9.

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Question 603

[3 marks]Factorisation
Each side of a regular hexagon is 3x−52\frac{3x - 5}{2} cm long and its perimeter is 15 cm. Find the value of xx.

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Question 604

[2 marks]Factorisation
Given that V=kr2hV = kr^2h, find VV when k=227k = \frac{22}{7}, r=3,5r = 3,5 and h=15h = 15.

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Question 605

[2 marks]Factorisation
Given that V=kr2hV = kr^2h, express rr in terms of kk, VV and hh.

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Question 701

[1 marks]Functional Graphs
A particle moves so that its velocity, vv m/s, after tt seconds is v=t2−5t+10v = t^2 - 5t + 10. Find the value of vv when t=5t = 5.

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Question 702

[1 marks]Functional Graphs
The velocity of a particle is v=t2−5t+10v = t^2 - 5t + 10 m/s after tt seconds. Find the minimum velocity reached, in metres per second.

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Question 703

[2 marks]Functional Graphs
The velocity of a particle is v=t2−5t+10v = t^2 - 5t + 10 m/s after tt seconds. Find its acceleration when t=1t = 1, in m/s2^2.

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Question 704

[2 marks]Functional Graphs
The velocity of a particle is v=t2−5t+10v = t^2 - 5t + 10 m/s after tt seconds, for 0≤t≤60 \le t \le 6. Find the range of values of tt for which the velocity is less than 7 m/s.

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Question 705

[2 marks]Functional Graphs
The velocity of a particle is v=t2−5t+10v = t^2 - 5t + 10 m/s after tt seconds. Estimate the distance travelled between t=2t = 2 and t=4t = 4, in metres.

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Question 801

[1 marks]Statistics and Probability
In a Mathematics test the marks of 100 learners fall in the classes 0≤x<100 \le x < 10 (7 learners), 10≤x<2010 \le x < 20 (13), 20≤x<3020 \le x < 30 (31), 30≤x<4030 \le x < 40 (37) and 40≤x<5040 \le x < 50 (12). State the modal class.

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Question 802

[3 marks]Statistics and Probability
The marks of 100 learners fall in the classes 0≤x<100 \le x < 10 (7 learners), 10≤x<2010 \le x < 20 (13), 20≤x<3020 \le x < 30 (31), 30≤x<4030 \le x < 40 (37) and 40≤x<5040 \le x < 50 (12). Calculate an estimate of the mean mark.

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Question 803

[1 marks]Statistics and Probability
The marks of 100 learners fall in the classes 0≤x<100 \le x < 10 (7 learners), 10≤x<2010 \le x < 20 (13), 20≤x<3020 \le x < 30 (31), 30≤x<4030 \le x < 40 (37) and 40≤x<5040 \le x < 50 (12). State the class interval in which the median mark lies.

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Question 804

[2 marks]Statistics and Probability
In a class of 100 learners, 7 scored 0≤x<100 \le x < 10, 13 scored 10≤x<2010 \le x < 20, 31 scored 20≤x<3020 \le x < 30, 37 scored 30≤x<4030 \le x < 40 and 12 scored 40≤x<5040 \le x < 50. One learner is picked at random. Find the probability that the mark is at least 10 but less than 40.

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Question 901

[2 marks]Inequalities and Linear Programming
A dressmaker has 18 m of cloth. Each pair of trousers needs 0,75 m and each skirt needs 0,5 m. Taking xx as the number of trousers and yy as the number of skirts, write down the cloth inequality before it is simplified.

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Question 902

[2 marks]Inequalities and Linear Programming
A dressmaker should make at least 6 pairs of trousers and at least 10 skirts, where xx is the number of trousers and yy the number of skirts. Write down the two inequalities that state these conditions.

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Question 903

[1 marks]Inequalities and Linear Programming
A dressmaker makes xx pairs of trousers and yy skirts, and the number of skirts should be more than the number of trousers. Form an inequality for this condition.

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Question 904

[2 marks]Inequalities and Linear Programming
A dressmaker makes xx pairs of trousers and yy skirts subject to 3x+2y≤723x + 2y \le 72, x≥6x \ge 6, y≥10y \ge 10 and y>xy > x. Each pair of trousers profits $300\$300 and each skirt $120\$120. Calculate the maximum possible profit.

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Question 1001

[2 marks]Geometrical Transformation
Triangle ABC has vertices A(4;2), B(4;4) and C(7;4). It is translated by the vector (2−5)\begin{pmatrix} 2 \\ -5 \end{pmatrix}. Write down the coordinates of the image vertices A1A_1, B1B_1 and C1C_1.

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Question 1002

[2 marks]Geometrical Transformation
Triangle ABC has vertices A(4;2), B(4;4) and C(7;4). It is reflected in the line y=x+2y = x + 2. Write down the coordinates of the image vertices A2A_2, B2B_2 and C2C_2.

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Question 1003

[3 marks]Geometrical Transformation
Triangle ABC has vertices A(4;2), B(4;4) and C(7;4). The matrix (1−21201)\begin{pmatrix} 1 & -2\frac{1}{2} \\ 0 & 1 \end{pmatrix} maps it onto triangle A3B3C3A_3B_3C_3. Write down the coordinates of A3A_3, B3B_3 and C3C_3.

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Question 1004

[3 marks]Geometrical Transformation
Describe fully the single transformation represented by the matrix (1−21201)\begin{pmatrix} 1 & -2\frac{1}{2} \\ 0 & 1 \end{pmatrix}.
  1. AA one way stretch parallel to the xx-axis with factor −212-2\frac{1}{2}
  2. BA reflection in the xx-axis followed by a translation
  3. CA shear with the xx-axis invariant and shear factor −212-2\frac{1}{2}
  4. DA shear with the yy-axis invariant and shear factor −212-2\frac{1}{2}

Question 1101

[1 marks]Vector Geometry
PQRS is a parallelogram with PQ⃗=a\vec{PQ} = \mathbf{a} and PS⃗=b\vec{PS} = \mathbf{b}. Express RQ⃗\vec{RQ} in terms of a\mathbf{a} and/or b\mathbf{b}.

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Question 1102

[1 marks]Vector Geometry
PQRS is a parallelogram with PQ⃗=a\vec{PQ} = \mathbf{a} and PS⃗=b\vec{PS} = \mathbf{b}. Express QS⃗\vec{QS} in terms of a\mathbf{a} and b\mathbf{b}.

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Question 1103

[1 marks]Vector Geometry
PQRS is a parallelogram with PQ⃗=a\vec{PQ} = \mathbf{a} and PS⃗=b\vec{PS} = \mathbf{b}, and M is the midpoint of SR. Express PM⃗\vec{PM} in terms of a\mathbf{a} and b\mathbf{b}.

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Question 1104

[1 marks]Vector Geometry
PQRS is a parallelogram with PQ⃗=a\vec{PQ} = \mathbf{a} and PS⃗=b\vec{PS} = \mathbf{b}. Express PR⃗\vec{PR} in terms of a\mathbf{a} and b\mathbf{b}.

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Question 1105

[1 marks]Vector Geometry
In parallelogram PQRS, M is the midpoint of SR and PM⃗=12a+b\vec{PM} = \frac{1}{2}\mathbf{a} + \mathbf{b}. Given that PN⃗=hPM⃗\vec{PN} = h\vec{PM}, express PN⃗\vec{PN} in terms of hh, a\mathbf{a} and b\mathbf{b}.

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Question 1106

[3 marks]Vector Geometry
In parallelogram PQRS, PN⃗=(1−k)a+kb\vec{PN} = (1-k)\mathbf{a} + k\mathbf{b} and also PN⃗=12ha+hb\vec{PN} = \frac{1}{2}h\mathbf{a} + h\mathbf{b}, where a\mathbf{a} and b\mathbf{b} are not parallel. Find the values of hh and kk.

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Question 1107

[1 marks]Vector Geometry
In parallelogram PQRS, PM and QS meet at N, and PN⃗=23PM⃗\vec{PN} = \frac{2}{3}\vec{PM}. Write down the numerical value of MNNP\frac{MN}{NP}.

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Question 1201

[2 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, PST is a straight line, QP^S=65∘Q\hat{P}S = 65^\circ, RS^T=100∘R\hat{S}T = 100^\circ and PQ^O=40∘P\hat{Q}O = 40^\circ. Find QR^SQ\hat{R}S, in degrees.

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Question 1202

[2 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, with QP^S=65∘Q\hat{P}S = 65^\circ. Find the reflex angle QO^SQ\hat{O}S, in degrees.

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Question 1203

[2 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, PST is a straight line, RS^T=100∘R\hat{S}T = 100^\circ and PQ^O=40∘P\hat{Q}O = 40^\circ. Find OQ^RO\hat{Q}R, in degrees.

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Question 1204

[2 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, with QP^S=65∘Q\hat{P}S = 65^\circ and PQ^O=40∘P\hat{Q}O = 40^\circ. Find PS^OP\hat{S}O, in degrees.

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Question 1205

[1 marks]Circle Geometry
State the name given to the region of a circle enclosed by a chord PQ and the minor arc PQ.

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Question 1206

[1 marks]Circle Geometry
The interior angles of a polygon are in the ratio 2:3:4:5:62 : 3 : 4 : 5 : 6. State the name of the polygon.

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Question 1207

[2 marks]Circle Geometry
The interior angles of a pentagon are in the ratio 2:3:4:5:62 : 3 : 4 : 5 : 6. Calculate the size of the largest interior angle, in degrees.

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