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ZIMSEC O Level · 4004/2 · J2025

Mathematics Paper 2 June 2025

Questions
54
Total marks
136
Time allowed
150 min
Syllabus code
4004/2

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Questions
54
Pass mark
33
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Approximations and Estimations
Estimate the value of 1,98+8,75×6,056,89\frac{1,98 + 8,75 \times 6,05}{6,89} by first rounding each of the given numbers off to the nearest whole number.
  1. A7
  2. B8
  3. C9
  4. D11

Question 102

[3 marks]Approximations and Estimations
The side of a cube is 8,7 cm given correct to the nearest millimetre. Find the least possible volume of the cube, correct to 2 decimal places.

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Question 103

[3 marks]Approximations and Estimations
Simplify 212÷334+1152\frac{1}{2} \div 3\frac{3}{4} + 1\frac{1}{5}, giving the answer as a fraction in its lowest terms.

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Question 201

[3 marks]Sets
In a group of 160 form one learners, every learner plays at least one of volleyball, netball or tennis. 40 play netball only, 25 play tennis only and 28 play volleyball only. 50 play netball and tennis, 35 play netball and volleyball, 30 play tennis and volleyball, and xx play all three games. Find the value of xx.

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Question 202

[2 marks]Sets
In the Venn diagram the region for netball and volleyball but not tennis is marked 35−x35-x, where xx is the number who play all three games. Given that 30 learners play tennis and volleyball, which expression belongs in the region for tennis and volleyball but not netball?
  1. Ax−30x - 30
  2. B30−2x30 - 2x
  3. C30+x30 + x
  4. D30−x30 - x

Question 203

[2 marks]Sets
The universal set is ξ={x:1≤x<10,x∈Z}\xi = \{x : 1 \le x < 10, x \in \mathbb{Z}\} and A is the set of odd numbers in ξ\xi. List all the elements of set A.

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Question 204

[2 marks]Sets
The universal set is ξ={x:1≤x<10,x∈Z}\xi = \{x : 1 \le x < 10, x \in \mathbb{Z}\}, A is the set of odd numbers and B is the set of factors of 10. Find n(A′∩B)n(A' \cap B).

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Question 301

[2 marks]Measures and Mensuration
A circular reservoir has a radius of 1,4 m. Taking π\pi to be 227\frac{22}{7}, calculate the area covered by the reservoir in square metres.

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Question 302

[3 marks]Measures and Mensuration
A rectangular vegetable garden is 50,7 m long and 30,5 m wide. A circular reservoir inside it covers 6,16 square metres and the rest of the garden grows vegetables. It costs \$38 507 to spray the space for growing vegetables. Find the cost per square metre, to the nearest dollar.

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Question 303

[3 marks]Measures and Mensuration
An arc AB of a circle centre O subtends an angle of 60°60° at the centre and is 11 cm long. Taking π\pi to be 227\frac{22}{7}, calculate the radius of the circle in centimetres.

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Question 304

[2 marks]Measures and Mensuration
The sector AOB has an angle of 60°60° at the centre O, a radius of 10,5 cm and an arc AB of length 11 cm. Taking π\pi to be 227\frac{22}{7}, calculate the area of the sector.
  1. A346,5 cm2^2
  2. B57,75 cm2^2
  3. C28,875 cm2^2
  4. D115,5 cm2^2

Question 401

[1 marks]Variation
The cost, C, of a party is partly constant and partly varies with the number, n, of people attending. Using constants hh and kk, which expression gives C in terms of nn?
  1. AC=hknC = hkn
  2. BC=hn+knC = hn + kn
  3. CC=hn+kC = \frac{h}{n} + k
  4. DC=h+knC = h + kn

Question 402

[3 marks]Variation
The cost of a party is C=h+knC = h + kn dollars for nn people. The cost is \$700 for 5 people and \$1 340 for 13 people. Find the value of kk.

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Question 403

[3 marks]Variation
The cost of a party is C=h+knC = h + kn dollars for nn people. The cost is \$700 for 5 people and \$1 340 for 13 people. Calculate the cost if 25 people attend.

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Question 404

[2 marks]Variation
PP varies directly as QQ, and P=12P = 12 when Q=5Q = 5. Find the formula connecting PP and QQ.
  1. AP=60QP = \frac{60}{Q}
  2. BP=2,4QP = 2,4Q
  3. CP=Q+7P = Q + 7
  4. DP=512QP = \frac{5}{12}Q

Question 405

[2 marks]Variation
PP varies directly as QQ, and P=12P = 12 when Q=5Q = 5. Calculate the value of QQ when P=42P = 42.

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Question 501

[2 marks]Constructions and Loci
In triangle ABC, AB=10AB = 10 cm, AB^C=45°A\hat{B}C = 45° and BA^C=60°B\hat{A}C = 60°. Find AC^BA\hat{C}B in degrees.

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Question 502

[1 marks]Constructions and Loci
A point B is marked on a sheet of paper. Which construction gives the locus of all points that are 4,5 cm from B?
  1. AAn arc of centre A with radius 4,5 cm
  2. BA circle of centre B and radius 4,5 cm
  3. CA straight line parallel to AB and 4,5 cm from it
  4. DThe perpendicular bisector of the side AB

Question 503

[2 marks]Constructions and Loci
In triangle ABC the side AB has been drawn. Which construction gives the locus of points that are 1,5 cm from AB on the same side of AB as C?
  1. AA straight line parallel to AB, drawn 1,5 cm from AB on the same side as C
  2. BAn arc of radius 1,5 cm drawn with centre B, on the same side of AB as C
  3. CA pair of straight lines parallel to AB, one drawn 1,5 cm on each side of it
  4. DA circle of radius 1,5 cm drawn with the midpoint of AB as its centre

Question 504

[2 marks]Constructions and Loci
In triangle ABC, AB=10AB = 10 cm, AB^C=45°A\hat{B}C = 45° and BA^C=60°B\hat{A}C = 60°. Calculate the length of AC in centimetres, correct to 1 decimal place.

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Question 601

[3 marks]Algebraic Fractions
Solve the equation 2a+34+a−53=1\frac{2a + 3}{4} + \frac{a - 5}{3} = 1.

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Question 602

[2 marks]Algebraic Fractions
It is given that M=NN+PM = \frac{N}{N + P}. Find the value of MM when N=60N = 60 and P=45P = 45, giving the answer as a fraction in its lowest terms.

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Question 603

[3 marks]Algebraic Fractions
It is given that M=NN+PM = \frac{N}{N + P}. Make N the subject of the formula.
  1. AN=MP1−MN = \frac{MP}{1 - M}
  2. BN=MPM−1N = \frac{MP}{M - 1}
  3. CN=P1−MN = \frac{P}{1 - M}
  4. DN=MP−MN = MP - M

Question 604

[3 marks]Algebraic Fractions
Solve the equation log⁡3(x−2)2=2\log_3 (x - 2)^2 = 2.

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Question 701

[3 marks]Statistics and Probability
The ages in years of 100 grandfathers are grouped as 50≤x<5550 \le x < 55 with frequency 6, 55≤x<6055 \le x < 60 with 10, 60≤x<6560 \le x < 65 with 22, 65≤x<7065 \le x < 70 with 32, 70≤x<7570 \le x < 75 with 20 and 75≤x<8075 \le x < 80 with 10. Calculate an estimate of the mean age.

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Question 702

[1 marks]Statistics and Probability
The ages of 100 grandfathers give the running totals x<50x<50: 0, x<55x<55: 6, x<60x<60: 16, x<65x<65: 38, x<70x<70: pp, x<75x<75: 90 and x<80x<80: 100. The class 65≤x<7065 \le x < 70 holds 32 grandfathers. Find the value of pp.

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Question 703

[2 marks]Statistics and Probability
A cumulative frequency curve is drawn for grandfathers' ages grouped as 50≤x<5550 \le x < 55, 55≤x<6055 \le x < 60, 60≤x<6560 \le x < 65 and so on. The class 60≤x<6560 \le x < 65 has frequency 22 and the running total up to the end of that class is 38. Which point is plotted for that class?
  1. A(65;38)(65; 38)
  2. B(62,5;22)(62,5; 22)
  3. C(65;22)(65; 22)
  4. D(60;22)(60; 22)

Question 704

[3 marks]Statistics and Probability
A cumulative frequency curve for the ages of 100 grandfathers passes through (60;16)(60; 16), (65;38)(65; 38), (70;70)(70; 70) and (75;90)(75; 90). Estimate the median age.
  1. A67 years
  2. B70 years
  3. C63 years
  4. D65 years

Question 705

[3 marks]Statistics and Probability
A cumulative frequency curve for the ages of 100 grandfathers passes through (60;16)(60; 16), (65;38)(65; 38), (70;70)(70; 70) and (75;90)(75; 90). Estimate the interquartile range, in years, correct to the nearest whole number.

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Question 801

[3 marks]Inequalities and Linear Programming
Mr Ndou plants xx hectares of beans and yy hectares of peas in a 5-hectare field. Beans need 2 bags of fertilizer per hectare and peas need 4 bags, and he has 16 bags. He plants at least 1,5 hectares of beans and at least 1 hectare of peas. Which set of inequalities states these conditions?
  1. Ax+y≤5x + y \le 5, 2x+4y≤162x + 4y \le 16, x≥1,5x \ge 1,5, y≥1y \ge 1
  2. Bx+y≤16x + y \le 16, 2x+4y≤52x + 4y \le 5, x≥1,5x \ge 1,5, y≥1y \ge 1
  3. Cx+y≤5x + y \le 5, 4x+2y≤164x + 2y \le 16, x≥1x \ge 1, y≥1,5y \ge 1,5
  4. Dx+y≥5x + y \ge 5, 2x+4y≥162x + 4y \ge 16, x≤1,5x \le 1,5, y≤1y \le 1

Question 802

[2 marks]Inequalities and Linear Programming
Mr Ndou plants xx hectares of beans and yy hectares of peas, subject to x+y≤5x + y \le 5 and 2x+4y≤162x + 4y \le 16. Find the value of yy at the point where the two boundary lines x+y=5x + y = 5 and 2x+4y=162x + 4y = 16 cross.

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Question 803

[2 marks]Inequalities and Linear Programming
Beans earn a profit of \$30 000 per hectare and peas \$40 000 per hectare. Calculate the profit, in dollars, from planting 1,5 hectares of beans and 3,25 hectares of peas.

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Question 804

[3 marks]Inequalities and Linear Programming
Mr Ndou plants xx hectares of beans and yy hectares of peas subject to x+y≤5x + y \le 5, 2x+4y≤162x + 4y \le 16, x≥1,5x \ge 1,5 and y≥1y \ge 1. Beans earn \$30 000 per hectare and peas \$40 000 per hectare. Calculate the maximum possible profit, in dollars.

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Question 901

[2 marks]Geometrical Transformation
Quadrilateral ABCD has vertices A(3;2), B(4;2), C(4;3) and D(3;4). It is mapped onto A1B1C1D1A_1B_1C_1D_1 by the translation vector (3−5)\begin{pmatrix} 3 \\ -5 \end{pmatrix}. Write down the coordinates of A1A_1.

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Question 902

[3 marks]Geometrical Transformation
Quadrilateral ABCD has vertices A(3;2), B(4;2), C(4;3) and D(3;4). Its image A2B2C2D2A_2B_2C_2D_2 has vertices A2(112;1)A_2(1\frac{1}{2}; 1), B2(2;1)B_2(2; 1), C2(2;112)C_2(2; 1\frac{1}{2}) and D2(112;2)D_2(1\frac{1}{2}; 2). Describe fully the single transformation that maps ABCD onto A2B2C2D2A_2B_2C_2D_2.
  1. AAn enlargement of scale factor 2 with centre the origin (0;0)(0; 0)
  2. BAn enlargement of scale factor 12\frac{1}{2} with centre the origin (0;0)(0; 0)
  3. CAn enlargement of scale factor 12\frac{1}{2} with centre the point (1;1)(1; 1)
  4. DA stretch of factor 12\frac{1}{2} parallel to the xx-axis with the yy-axis invariant

Question 903

[3 marks]Geometrical Transformation
Quadrilateral ABCD has vertices A(3;2), B(4;2), C(4;3) and D(3;4). It is rotated through 90°90° clockwise about the centre (1;1)(1; 1) to give A3B3C3D3A_3B_3C_3D_3. Write down the coordinates of C3C_3.

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Question 904

[2 marks]Geometrical Transformation
Write down the matrix representing a stretch parallel to the xx-axis with a stretch factor of 3.
  1. A(3003)\begin{pmatrix} 3 & 0 \\ 0 & 3 \end{pmatrix}
  2. B(0310)\begin{pmatrix} 0 & 3 \\ 1 & 0 \end{pmatrix}
  3. C(3001)\begin{pmatrix} 3 & 0 \\ 0 & 1 \end{pmatrix}
  4. D(1003)\begin{pmatrix} 1 & 0 \\ 0 & 3 \end{pmatrix}

Question 1001

[3 marks]Matrices
Matrix A=(−34−21)A = \begin{pmatrix} -3 & 4 \\ -2 & 1 \end{pmatrix} and matrix B=(4−125)B = \begin{pmatrix} 4 & -1 \\ 2 & 5 \end{pmatrix}. Evaluate 3A−B3A - B.

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Question 1002

[2 marks]Matrices
Matrix B=(4−125)B = \begin{pmatrix} 4 & -1 \\ 2 & 5 \end{pmatrix} and matrix C=(−23)C = \begin{pmatrix} -2 \\ 3 \end{pmatrix}. Evaluate BCBC.

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Question 1003

[3 marks]Matrices
Find the inverse of the matrix A=(−34−21)A = \begin{pmatrix} -3 & 4 \\ -2 & 1 \end{pmatrix}.
  1. A15(14−2−3)\frac{1}{5}\begin{pmatrix} 1 & 4 \\ -2 & -3 \end{pmatrix}
  2. B15(−34−21)\frac{1}{5}\begin{pmatrix} -3 & 4 \\ -2 & 1 \end{pmatrix}
  3. C−111(1−42−3)-\frac{1}{11}\begin{pmatrix} 1 & -4 \\ 2 & -3 \end{pmatrix}
  4. D15(1−42−3)\frac{1}{5}\begin{pmatrix} 1 & -4 \\ 2 & -3 \end{pmatrix}

Question 1004

[3 marks]Matrices
Using the inverse of (−34−21)\begin{pmatrix} -3 & 4 \\ -2 & 1 \end{pmatrix}, or otherwise, solve the simultaneous equations −3x+4y=11-3x + 4y = 11 and −2x+y=4-2x + y = 4. Give the values of xx and yy.

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Question 1101

[1 marks]Vector Geometry
PQRS is a parallelogram in which PQ⃗=3p\vec{PQ} = 3p and PS⃗=3q\vec{PS} = 3q. Express RS⃗\vec{RS} in terms of pp and qq.
  1. A3q3q
  2. B−3q-3q
  3. C3p3p
  4. D−3p-3p

Question 1102

[2 marks]Vector Geometry
PQRS is a parallelogram in which PQ⃗=3p\vec{PQ} = 3p and PS⃗=3q\vec{PS} = 3q. Express SQ⃗\vec{SQ} in terms of pp and qq.

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Question 1103

[2 marks]Vector Geometry
PQRS is a parallelogram in which PQ⃗=3p\vec{PQ} = 3p and PS⃗=3q\vec{PS} = 3q. The point X lies on QS so that QS=3XSQS = 3XS. Express XQ⃗\vec{XQ} in terms of pp and qq.

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Question 1104

[2 marks]Vector Geometry
PQRS is a parallelogram in which PQ⃗=3p\vec{PQ} = 3p and PS⃗=3q\vec{PS} = 3q. The point X lies on QS so that QS=3XSQS = 3XS. Express XP⃗\vec{XP} in terms of pp and qq.

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Question 1105

[3 marks]Vector Geometry
In parallelogram PQRS, XP⃗=−p−2q\vec{XP} = -p - 2q. PX produced meets SR at N, where NP⃗=hXP⃗\vec{NP} = h\vec{XP} and also NP⃗=−3kp−3q\vec{NP} = -3kp - 3q with NS=kRSNS = kRS. Find the value of hh.

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Question 1106

[1 marks]Vector Geometry
In parallelogram PQRS, PX produced meets SR at N and it is found that NP⃗=32XP⃗\vec{NP} = \frac{3}{2}\vec{XP}, where NS=kRSNS = kRS and k=12k = \frac{1}{2}. Write down the ratio NSRS\frac{NS}{RS}.

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Question 1201

[1 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, and TPV is a tangent at P. QP^V=40°Q\hat{P}V = 40°, QS^R=34°Q\hat{S}R = 34° and RP^S=54°R\hat{P}S = 54°. Find QP^RQ\hat{P}R.
  1. A54°54°
  2. B20°20°
  3. C34°34°
  4. D40°40°

Question 1202

[1 marks]Circle Geometry
P, Q, R and S lie on a circle centre O, and TPV is a tangent at P with QP^V=40°Q\hat{P}V = 40°. Find PR^QP\hat{R}Q.
  1. A17°17°
  2. B34°34°
  3. C40°40°
  4. D54°54°

Question 1203

[2 marks]Circle Geometry
P, Q, R and S lie on a circle centre O and TPV is a tangent at P. Given QP^V=40°Q\hat{P}V = 40°, QP^R=34°Q\hat{P}R = 34° and RP^S=54°R\hat{P}S = 54°, find PQ^SP\hat{Q}S in degrees.

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Question 1204

[2 marks]Circle Geometry
In the circle PQRS the chords PR and QS meet at X. Given RP^S=54°R\hat{P}S = 54° and PS^Q=40°P\hat{S}Q = 40°, find PX^QP\hat{X}Q in degrees.

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Question 1205

[1 marks]Circle Geometry
In the circle PQRS the chords PR and QS meet at X, with XP^S=XQ^R=54°X\hat{P}S = X\hat{Q}R = 54° and XS^P=XR^Q=40°X\hat{S}P = X\hat{R}Q = 40°. Name correctly the triangle which is similar to triangle PXS.
  1. ATriangle XRQ
  2. BTriangle QRX
  3. CTriangle QXR
  4. DTriangle RXQ

Question 1206

[2 marks]Circle Geometry
In the circle PQRS the chords PR and QS meet at X, and triangle PXS is similar to triangle QXR with P matching Q and S matching R. Given PS=12PS = 12 cm, QR=8QR = 8 cm and SX=9SX = 9 cm, calculate the length of RX in centimetres.

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Question 1207

[2 marks]Circle Geometry
Triangle QRX is similar to triangle PSX, with QR=8QR = 8 cm corresponding to PS=12PS = 12 cm. Find the ratio of the area of triangle QRX to the area of triangle PSX.

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