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ZIMSEC O Level · 4030/2 · J2016

Mathematics Paper 2 June 2016

Questions
63
Total marks
136
Time allowed
150 min
Syllabus code
4030/2

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Questions
63
Pass mark
38
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Fractions, Decimals and Percentages
Simplify 712+12×8−27\frac{1}{2} + \frac{1}{2} \times 8 - 2.

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Question 102

[3 marks]Fractions, Decimals and Percentages
Find the Lowest Common Multiple (L.C.M) of 60 and 84.

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Question 103

[2 marks]Fractions, Decimals and Percentages
Mary, Peter and John share a total amount of $500 in the ratio 3:2:5. Calculate Mary's share.

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Question 104

[2 marks]Fractions, Decimals and Percentages
Mary's share of an amount is $150. She uses part of it to buy a pair of shoes costing $30. Calculate the percentage of Mary's share that is left.

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Question 201

[1 marks]Variation
Factorise completely 4c2+12cn4c^2 + 12cn.

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Question 202

[2 marks]Variation
Factorise completely k2+kh−kp−hpk^2 + kh - kp - hp.

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Question 203

[2 marks]Variation
Solve the equation 12−y3=5−2y\frac{12 - y}{3} = 5 - 2y.

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Question 204

[2 marks]Variation
The mass, mm grams, of a solid is inversely proportional to its volume, vv cm3^3. Given that m=3,5m = 3,5 g when v=4v = 4 cm3^3, find the formula connecting mm and vv.

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Question 205

[1 marks]Variation
The mass mm grams and volume vv cm3^3 of a solid are connected by m=14vm = \frac{14}{v}. Find mm when v=6v = 6 cm3^3.

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Question 206

[2 marks]Variation
Make xx the subject of the formula wx2=nwx^2 = n.
  1. Ax=nwx = \sqrt{\frac{n}{w}}, with the negative root dropped as though xx had to be positive
  2. Bx=±nwx = \pm\sqrt{\frac{n}{w}}, keeping both roots because squaring hides the sign of xx
  3. Cx=±nwx = \pm\sqrt{nw}, multiplying by ww instead of dividing when clearing it
  4. Dx=nwx = \frac{n}{w}, dividing by ww but leaving the square on xx undone

Question 301

[2 marks]Quadratic Equations
In triangle LMN the angle at M is 90∘90^\circ, MN =x= x cm, ML =(x+3)= (x + 3) cm and LN =7= 7 cm. Which equation does Pythagoras' theorem give for this triangle?
  1. A(x+3)2+72=x2(x + 3)^2 + 7^2 = x^2, treating MN as the side facing the right angle
  2. Bx2+(x+3)2=49x^2 + (x + 3)^2 = 49, since LN is the side facing the right angle at M
  3. Cx2+(x+3)2=7x^2 + (x + 3)^2 = 7, using the length of LN itself in place of its square
  4. Dx2+72=(x+3)2x^2 + 7^2 = (x + 3)^2, treating ML as the side facing the right angle

Question 302

[3 marks]Quadratic Equations
Solve the equation x2+3x−20=0x^2 + 3x - 20 = 0, giving the positive answer correct to 2 significant figures.

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Question 303

[2 marks]Quadratic Equations
In a right-angled triangle LMN, MN =x= x cm, ML =(x+3)= (x + 3) cm and LN =7= 7 cm, where x=3,2x = 3,2 correct to 2 significant figures. Calculate the perimeter of triangle LMN.

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Question 304

[1 marks]Quadratic Equations
In a class of 40 pupils, 6 like Mathematics only, 25 like both Mathematics and Physics, and 5 like Physics only. Taking M as the set who like Mathematics and P as the set who like Physics, find n(M∪P)n(M \cup P).

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Question 305

[2 marks]Quadratic Equations
In a class of 40 pupils, 6 like Mathematics only, 25 like both Mathematics and Physics, and 5 like Physics only. Find the number of pupils who do not like either subject.

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Question 306

[1 marks]Quadratic Equations
In a class of 40 pupils, 6 like Mathematics only, 25 like both Mathematics and Physics, and 5 like Physics only. Taking M as the set who like Mathematics and P as the set who like Physics, find n(M′∩P)n(M' \cap P).

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Question 401

[3 marks]Circle Geometry
J, K, M and L lie on the circumference of a circle. The chords JM and KL cross at H, with JH^K=97∘J\hat{H}K = 97^\circ and JK^H=48∘J\hat{K}H = 48^\circ. Find HL^MH\hat{L}M.
  1. A48∘48^\circ, copying the angle at K because both stand on a chord of the circle
  2. B83∘83^\circ, taking the supplement of the angle at H rather than working in the triangle
  3. C97∘97^\circ, copying the angle at H because it is vertically opposite the required angle
  4. D35∘35^\circ, since the angle at J found from triangle JKH stands on the same arc as it

Question 402

[1 marks]Circle Geometry
J, K, M and L lie on the circumference of a circle, and the chords JM and KL cross at H. Name, in the correct order, the triangle which is similar to triangle JKH.

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Question 403

[3 marks]Circle Geometry
In triangle JKH, JH =25= 25 cm, KH =20= 20 cm and the angle between them, JH^KJ\hat{H}K, is 97∘97^\circ. Calculate the length of JK, correct to 3 significant figures.

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Question 404

[2 marks]Circle Geometry
In triangle JKH, JH =25= 25 cm, KH =20= 20 cm and the angle between them, JH^KJ\hat{H}K, is 97∘97^\circ. Calculate the area of triangle JKH, correct to 3 significant figures.

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Question 405

[3 marks]Circle Geometry
Triangle HLM is similar to triangle HJK, with HM =6= 6 cm corresponding to HK =20= 20 cm. Given that the area of triangle JKH is 248 cm2^2, calculate the area of triangle HLM, correct to 3 significant figures.

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Question 501

[2 marks]Matrices
Matrix A=(25−3y)A = \begin{pmatrix} 2 & 5 \\ -3 & y \end{pmatrix}. Find the value of yy for which AA has no inverse.

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Question 502

[2 marks]Matrices
Matrices A=(25−3−7,5)A = \begin{pmatrix} 2 & 5 \\ -3 & -7,5 \end{pmatrix} and C=(5−42−9)C = \begin{pmatrix} 5 & -4 \\ 2 & -9 \end{pmatrix}. Evaluate A+CA + C.

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Question 503

[2 marks]Matrices
Matrix C=(5−42−9)C = \begin{pmatrix} 5 & -4 \\ 2 & -9 \end{pmatrix}. Evaluate C−1C^{-1}.
  1. A1−37(−94−25)\frac{1}{-37}\begin{pmatrix} -9 & 4 \\ -2 & 5 \end{pmatrix}, swapping the leading diagonal and negating the other
  2. B1−37(5−42−9)\frac{1}{-37}\begin{pmatrix} 5 & -4 \\ 2 & -9 \end{pmatrix}, dividing by the determinant but leaving the entries untouched
  3. C1−37(−9−425)\frac{1}{-37}\begin{pmatrix} -9 & -4 \\ 2 & 5 \end{pmatrix}, swapping the diagonal but negating the wrong pair
  4. D1−53(−94−25)\frac{1}{-53}\begin{pmatrix} -9 & 4 \\ -2 & 5 \end{pmatrix}, adding the two products instead of subtracting them

Question 504

[2 marks]Matrices
Matrices B=(−43)B = \begin{pmatrix} -4 & 3 \end{pmatrix} and C=(5−42−9)C = \begin{pmatrix} 5 & -4 \\ 2 & -9 \end{pmatrix}. Evaluate BCBC.

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Question 505

[2 marks]Matrices
If log⁡x27=1,5\log_x 27 = 1,5, find xx.

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Question 601

[2 marks]Constructions and Loci
In triangle ABC, AB == BC =8= 8 cm and AB^C=60∘A\hat{B}C = 60^\circ. Calculate the length of AC.

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Question 602

[1 marks]Constructions and Loci
Triangle ABC has AB == BC =8= 8 cm and AB^C=60∘A\hat{B}C = 60^\circ. N is marked on the bisector of AB^CA\hat{B}C so that BN =12= 12 cm, and ABCN is completed. State the special name given to the quadrilateral ABCN.
  1. AA trapezium, because the bisector runs parallel to one of the two equal sides
  2. BA rhombus, because two of its sides are equal and its diagonals cross at right angles
  3. CA kite, because BN is a line of symmetry, so AB == CB and AN == CN
  4. DA parallelogram, because opposite sides are equal in pairs across the bisector

Question 603

[2 marks]Constructions and Loci
In triangle ABC the angle AB^CA\hat{B}C is bisected, and N lies on the bisector. Describe fully the locus represented by the bisector BN.
  1. AThe locus of points equidistant from the two lines BA and BC, inside angle ABC
  2. BThe locus of points equidistant from the two vertices A and C of the triangle
  3. CThe locus of points at a fixed distance of 12 cm from the vertex B of the triangle
  4. DThe locus of points equidistant from the vertex B and from the opposite side AC

Question 604

[3 marks]Constructions and Loci
In a quadrilateral ABCN, BC =8= 8 cm, BN =12= 12 cm and CB^N=30∘C\hat{B}N = 30^\circ. Calculate the length of CN, correct to 3 significant figures.

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Question 605

[2 marks]Constructions and Loci
In triangle BCN, BC =8= 8 cm, BN =12= 12 cm and CN =6,46= 6,46 cm. Calculate the size of BC^NB\hat{C}N, giving the answer in degrees correct to 1 decimal place.

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Question 701

[1 marks]Vector Geometry
O, F and H are points with OF→=3p\overrightarrow{OF} = 3p and OH→=2q\overrightarrow{OH} = 2q. Express FH→\overrightarrow{FH} in terms of pp and qq.

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Question 702

[2 marks]Vector Geometry
O, F, G and H are points with OF→=3p\overrightarrow{OF} = 3p, OH→=2q\overrightarrow{OH} = 2q and FG→=hOH→\overrightarrow{FG} = h\overrightarrow{OH}. Express OG→\overrightarrow{OG} in terms of pp, qq and hh.

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Question 703

[2 marks]Vector Geometry
O, F and H are points with OF→=3p\overrightarrow{OF} = 3p and OH→=2q\overrightarrow{OH} = 2q, and W lies on FH with FW→=kFH→\overrightarrow{FW} = k\overrightarrow{FH}. Express OW→\overrightarrow{OW} in terms of pp, qq and kk.

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Question 704

[2 marks]Vector Geometry
Points O and G satisfy OG→=3p+2hq\overrightarrow{OG} = 3p + 2hq, and W lies on OG with OW:OG =2:3= 2:3. Express OW→\overrightarrow{OW} in terms of pp, qq and hh.

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Question 705

[3 marks]Vector Geometry
The vector OW→\overrightarrow{OW} can be written both as 3(1−k)p+2kq3(1 - k)p + 2kq and as 2p+4h3q2p + \frac{4h}{3}q, where pp and qq are not parallel. Find the numerical value of kk.

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Question 706

[2 marks]Vector Geometry
W lies on FH with FW→=13FH→\overrightarrow{FW} = \frac{1}{3}\overrightarrow{FH}. Find the numerical value of FWWH\frac{FW}{WH}.

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Question 801

[1 marks]Statistics and Probability
In a grouped frequency distribution the class 400≤S<450400 \le S < 450 has frequency density 1,2. Find the frequency xx of that class.

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Question 802

[2 marks]Statistics and Probability
In a grouped frequency distribution the class 200≤S<300200 \le S < 300 has frequency 380. Find the frequency density yy of that class.

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Question 803

[1 marks]Statistics and Probability
The weekly sales of 1 000 traders fall into the classes 50≤S<10050 \le S < 100 (frequency density 1,6), 100≤S<200100 \le S < 200 (3,6), 200≤S<300200 \le S < 300 (3,8), 300≤S<400300 \le S < 400 (1,2) and 400≤S<450400 \le S < 450 (1,2). State the modal class.
  1. A100≤S<200100 \le S < 200, because it has a wide interval and a high frequency density
  2. B400≤S<450400 \le S < 450, because it is a narrow class and so packs its traders tightly
  3. C200≤S<300200 \le S < 300, because it has the highest frequency density of the five classes
  4. D50≤S<10050 \le S < 100, because the mode of a grouped distribution sits in the first class

Question 804

[2 marks]Statistics and Probability
A pie chart is drawn using frequency densities of 1,6, 3,6, 3,8, 1,2 and 1,2 for five classes of weekly sales. Calculate the angle at the centre, correct to the nearest degree, that would represent the class of density 1,6.

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Question 805

[3 marks]Statistics and Probability
The weekly sales of 1 000 traders are grouped as 50≤S<10050 \le S < 100 (80 traders), 100≤S<200100 \le S < 200 (360), 200≤S<300200 \le S < 300 (380), 300≤S<400300 \le S < 400 (120) and 400≤S<450400 \le S < 450 (60). Calculate an estimate of the mean sales, in dollars.

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Question 806

[3 marks]Statistics and Probability
Of 1 000 traders, 120 had weekly sales in the class 300≤S<400300 \le S < 400 and 60 in the class 400≤S<450400 \le S < 450. Two traders are chosen at random. Find the probability that both had earnings greater than or equal to $300, correct to 3 significant figures.

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Question 901

[2 marks]Geometrical Transformation
Point D has coordinates (1;3)(1;3). Find the coordinates of D1D_1, the image of D under the transformation with matrix (0−110)\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}.

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Question 902

[3 marks]Geometrical Transformation
Point F has coordinates (2;5)(2;5). Find the coordinates of F2F_2, the image of F under an enlargement of factor 2 and centre (4;2)(4;2).

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Question 903

[3 marks]Geometrical Transformation
Point E has coordinates (1;5)(1;5). Find the coordinates of E3E_3, the image of E after a shear of factor −2-2 with the y-axis invariant.

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Question 904

[3 marks]Geometrical Transformation
Describe fully the transformation defined by the matrix (0−110)\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}.
  1. AA rotation through 180∘180^\circ about the origin, since the matrix carries a negative entry
  2. BA rotation through 90∘90^\circ clockwise about the origin, reading the columns the wrong way
  3. CA reflection in the line y=xy = x, since the two coordinates appear to trade places
  4. DA rotation through 90∘90^\circ anticlockwise about the origin, since it sends (1;0)(1;0) to (0;1)(0;1)

Question 1001

[2 marks]Inequalities and Linear Programming
On a school trip the number of pupils must be at least the number of teachers, and must not be greater than three times the number of teachers. Taking xx as the number of teachers and yy as the number of pupils, which pair of inequalities states these conditions?
  1. Ay≥xy \ge x and y≤3xy \le 3x, reading pupils as at least the teachers and at most three times them
  2. By≥xy \ge x and y≥3xy \ge 3x, treating three times the teachers as a lower limit on the pupils
  3. Cy≤xy \le x and y≥3xy \ge 3x, with both inequality signs turned the wrong way round
  4. Dx≥yx \ge y and x≤3yx \le 3y, with the roles of teachers and pupils interchanged

Question 1002

[1 marks]Inequalities and Linear Programming
A bus can take up to 60 passengers. If xx teachers and yy pupils travel on it, write down an inequality that satisfies this condition.

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Question 1003

[2 marks]Inequalities and Linear Programming
Transport costs $4,00 per teacher and $2,00 per pupil, and the money collected must cover the $120,00 hire of the bus. If xx teachers and yy pupils travel, write down an inequality that satisfies this condition.

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Question 1004

[3 marks]Inequalities and Linear Programming
The numbers of teachers xx and pupils yy on a trip satisfy y≥xy \ge x, y≤3xy \le 3x, x+y≤60x + y \le 60 and 4x+2y≥1204x + 2y \ge 120. Find the least number of teachers.

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Question 1005

[3 marks]Inequalities and Linear Programming
The numbers of teachers xx and pupils yy on a trip satisfy y≥xy \ge x, y≤3xy \le 3x, x+y≤60x + y \le 60 and 4x+2y≥1204x + 2y \ge 120. Find the greatest number of pupils that could go on the trip.

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Question 1101

[1 marks]Functional Graphs
For the function y=x(4−x)y = x(4 - x), calculate the value of yy when x=−1x = -1.

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Question 1102

[1 marks]Functional Graphs
For the function y=x(4−x)y = x(4 - x), calculate the value of yy when x=3x = 3.

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Question 1103

[2 marks]Functional Graphs
The curve y=x(4−x)y = x(4 - x) has a maximum point. Write down the coordinates of that maximum point.

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Question 1104

[2 marks]Functional Graphs
Find the gradient of the curve y=x(4−x)y = x(4 - x) when x=3x = 3.

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Question 1105

[3 marks]Functional Graphs
Solve the equation x(4−x)=xx(4 - x) = x.

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Question 1106

[3 marks]Functional Graphs
Estimate the area of the region bounded by the curve y=x(4−x)y = x(4 - x) and the line y=xy = x, in square units.

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Question 1201

[3 marks]Measures and Mensuration
The diagram shows the transverse cross-section of a steel bar. The measurements are in centimetres. Calculate the area of the cross-section.

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Question 1202

[2 marks]Measures and Mensuration
A steel bar 2 m long has a uniform cross-section of area 550 cm2^2. Calculate the volume of the bar, in cm3^3.

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Question 1203

[2 marks]Measures and Mensuration
A steel bar has a volume of 110 000 cm3^3 and a density of 7 800 kg/m3^3. Find the mass of the bar, in kilograms.

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Question 1204

[3 marks]Measures and Mensuration
The diagram shows the transverse cross-section of a steel bar which is 2 m long, with measurements in centimetres and a cross-sectional area of 550 cm2^2. Calculate the total surface area of the bar, in cm2^2.

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Question 1205

[2 marks]Measures and Mensuration
A steel bar has a total surface area of 27 100 cm2^2. It is to be coated with zinc at a cost of $10,00 per square metre. Calculate the cost of coating the bar.

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