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ZIMSEC O Level · 4008/2 · N2000

Mathematics Paper 2 November 2000

Questions
53
Total marks
136
Time allowed
150 min
Syllabus code
4008/2

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Questions
53
Pass mark
32
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Algebra, factorising and rates
Simplify 4rt2(3r−t3)4rt^2(3r-t^3).

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Question 102

[2 marks]Algebra, factorising and rates
Solve the equation 4(3x+5)−7(6−x)=164(3x+5)-7(6-x)=16.

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Question 103

[2 marks]Algebra, factorising and rates
Factorise completely x3+7x2+12xx^3+7x^2+12x.

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Question 104

[2 marks]Algebra, factorising and rates
Factorise completely ab−ad−bc+cdab-ad-bc+cd.

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Question 105

[3 marks]Algebra, factorising and rates
Express as a single fraction in its simplest form y4y−1+35\frac{y}{4y-1}+\frac{3}{5}.

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Question 106

[3 marks]Algebra, factorising and rates
The time taken to cook w kg of meat is (48w+23)(48w+23) minutes. Calculate how long it takes to cook 3kg of meat, giving the answer in hours and minutes.

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Question 201

[2 marks]Pythagoras and rhombus geometry
In a diagram, BA^D=BC^D=90°B\hat{A}D=B\hat{C}D=90°, AB=ADAB=AD, BC=7cmBC=7cm and CD=1cmCD=1cm. Using Pythagoras in triangle BCD (right-angled at C), calculate BD2BD^2.

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Question 202

[2 marks]Pythagoras and rhombus geometry
In a diagram, BA^D=90°B\hat{A}D=90°, AB=ADAB=AD and BD2=50BD^2=50 (from triangle BCD). Using Pythagoras in triangle ABD, calculate the length of AB.

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Question 203

[3 marks]Pythagoras and rhombus geometry
A rhombus has sides of length 8cm and one of its angles is 70°. Calculate the length of the longer diagonal of the rhombus.

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Question 204

[3 marks]Pythagoras and rhombus geometry
A rhombus has sides of length 8cm and one of its angles is 70°. Calculate the area of the rhombus.

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Question 301

[2 marks]Matrices and sets
Given U=(4−102)U=\begin{pmatrix}4&-1\\0&2\end{pmatrix}, calculate the determinant of U.

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Question 302

[2 marks]Matrices and sets
Given U=(4−102)U=\begin{pmatrix}4&-1\\0&2\end{pmatrix} with det⁡U=8\det U=8, what is U−1U^{-1}?
  1. A(1/8) x [[4,1],[0,2]]
  2. B(1/8) x [[2,1],[0,4]]
  3. C(1/8) x [[2,-1],[0,4]]
  4. D[[2,1],[0,4]] (no scalar factor)

Question 303

[2 marks]Matrices and sets
Given U=(4−102)U=\begin{pmatrix}4&-1\\0&2\end{pmatrix}, V=(230t)V=\begin{pmatrix}2&3\\0&t\end{pmatrix}, and UV=VUUV=VU, calculate the value of t.

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Question 304

[2 marks]Matrices and sets
Let ξ={x:1≤x<10,x an integer}\xi=\{x: 1\le x<10, x \text{ an integer}\} and A={x:x is a perfect square}A=\{x: x \text{ is a perfect square}\}. List the elements of A.

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Question 305

[1 marks]Matrices and sets
Let ξ={x:1≤x<10,x an integer}\xi=\{x: 1\le x<10, x \text{ an integer}\}, A={1,4,9}A=\{1,4,9\} (perfect squares) and B={3,6,9}B=\{3,6,9\} (multiples of 3). Find n(A∩B)n(A\cap B).

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Question 306

[2 marks]Matrices and sets
Let ξ={x:1≤x<10,x an integer}={1,...,9}\xi=\{x: 1\le x<10, x \text{ an integer}\}=\{1,...,9\}, A={1,4,9}A=\{1,4,9\} and B={3,6,9}B=\{3,6,9\}. Write down (A∪B)′(A\cup B)' by listing its elements.

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Question 401

[2 marks]Circle geometry and congruent triangles
KL is a diameter of circle KLMN. NM is parallel to KL and MK^L=22°M\hat{K}L=22°. Calculate KN^MK\hat{N}M.

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Question 402

[2 marks]Circle geometry and congruent triangles
KL is a diameter of circle KLMN. NM is parallel to KL, MK^L=22°M\hat{K}L=22° and KN^M=112°K\hat{N}M=112°. Calculate MK^NM\hat{K}N.

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Question 403

[2 marks]Circle geometry and congruent triangles
In a diagram, BP=BQBP=BQ, PB^A=CB^QP\hat{B}A=C\hat{B}Q and BA^Q=BC^PB\hat{A}Q=B\hat{C}P. Triangle ABQ is congruent to which triangle, and by which case?
  1. ATriangle CBP, case AAS
  2. BTriangle PBC, case SSS
  3. CTriangle CBP, case SAS
  4. DTriangle BCP, case AAS

Question 404

[3 marks]Circle geometry and congruent triangles
In a diagram, BP=BQBP=BQ, PB^A=CB^QP\hat{B}A=C\hat{B}Q, BA^Q=BC^PB\hat{A}Q=B\hat{C}P, and triangle ABQ is congruent to triangle CBP. Write down the pairs of equal elements, not already given, in the congruent triangles.

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Question 501

[3 marks]Number, bills and percentage loss
Find the average of the three numbers 1341\frac{3}{4}, −212-2\frac{1}{2}, 3583\frac{5}{8}.

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Question 502

[3 marks]Number, bills and percentage loss
A householder used 960 units of electricity, charged at 35,2 cents per unit for the first 100 units, 30,5 cents per unit for the next 200 units, and 26 cents per unit for the remainder. Calculate the total cost.

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Question 503

[2 marks]Number, bills and percentage loss
A greengrocer bought 30kg of bananas at \$18,75 per kg. He sold 40% of them (12kg) at \$20,50 per kg, and 6623%66\frac{2}{3}\% of the remaining 18kg (12kg) at \$19,50 per kg; the last 6kg went unsold. Calculate the total revenue from the bananas he sold.

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Question 504

[3 marks]Number, bills and percentage loss
A greengrocer bought 30kg of bananas at \$18,75 per kg (cost price \$562,50 total) and sold them for a total revenue of \$480. Find the percentage loss he made, giving the answer correct to 2 significant figures.

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Question 601

[1 marks]Constructions & Loci
Triangle ABC has BC=10cmBC=10cm, CA=7cmCA=7cm, AB=8,5cmAB=8,5cm. Q lies on AC with AQ=4cmAQ=4cm. By accurate construction and measurement, find the length of BQ.

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Question 701

[2 marks]Equations and variation
Calculate the discriminant of 3x2−5x−4=03x^2-5x-4=0.

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Question 702

[3 marks]Equations and variation
Solve 3x2−5x−4=03x^2-5x-4=0, giving both answers correct to 2 decimal places.

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Question 703

[2 marks]Equations and variation
Given that 1g=1e+1f\frac{1}{g}=\frac{1}{e}+\frac{1}{f}, express 1e\frac{1}{e} in terms of f and g.

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Question 704

[2 marks]Equations and variation
Given that 1g=1e+1f\frac{1}{g}=\frac{1}{e}+\frac{1}{f} and 1e=f−gfg\frac{1}{e}=\frac{f-g}{fg}, express e in terms of f and g.

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Question 705

[3 marks]Equations and variation
y is inversely proportional to (x−3)(x-3), and y=4y=4 when x=2x=2. Express y in terms of x.

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Question 801

[2 marks]Graphs and quadratic curves
Using the graph of y=x2−6x+8y=x^2-6x+8 together with the line y=6y=6 (since x2−6x+2=0⇔x2−6x+8=6x^2-6x+2=0 \Leftrightarrow x^2-6x+8=6), estimate the solutions of x2−6x+2=0x^2-6x+2=0 correct to 1 decimal place.

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Question 802

[2 marks]Graphs and quadratic curves
In the diagram, line l intersects the curve y=x2−6x+8y=x^2-6x+8 at P and Q. Using the diagram, write down the coordinates of P and Q.

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Question 803

[1 marks]Graphs and quadratic curves
A line l passes through P(1,3) and Q(6,8). Find the gradient of l.

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Question 804

[2 marks]Graphs and quadratic curves
A line l passes through P(1,3) and Q(6,8) and has gradient 1. Write down the equation of l.

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Question 805

[3 marks]Graphs and quadratic curves
A line l intersects the curve y=x2−6x+8y=x^2-6x+8 at P(1,3) and Q(6,8). Write down the equation in x, in the form ax2+bx+c=0ax^2+bx+c=0 with a, b, c integers, whose solutions are the x-coordinates of P and Q.

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Question 806

[2 marks]Graphs and quadratic curves
Using the diagram, estimate the area of the shaded region, which is bounded above by the line ll, at the sides by x=2x=2 and x=5x=5, and below by the xx-axis and the curve y=x2−6x+8y=x^2-6x+8.

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Question 901

[2 marks]Statistics & Probability
The masses of Form 1 pupils fall into 5kg classes with frequencies 5, 30, 23, 25, 12, 5 (from 35kg up to 65kg). The cumulative frequency at 40kg is 5 and at 50kg is 58. Find the cumulative frequencies at 45kg, 55kg and 60kg, in that order.

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Question 902

[2 marks]Statistics & Probability
The cumulative frequency distribution of Form 1 pupils' masses passes through (45,35), (50,58) and (55,83), out of 100 pupils in total. Estimate the median mass.

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Question 903

[2 marks]Statistics & Probability
Out of 100 Form 1 pupils, 23 have mass in 45<m≤5045<m\le50 and 25 have mass in 50<m≤5550<m\le55. One pupil is picked at random. Find, as a fraction in its lowest terms, the probability that the pupil's mass is more than 45kg but at most 55kg.

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Question 904

[2 marks]Statistics & Probability
Out of 100 Form 1 pupils, the probability that a randomly picked pupil's mass is more than m kg is 110\frac{1}{10}. Given the cumulative frequency curve reaches 90 at m=57,5kg, find the value of m.

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Question 1001

[3 marks]Bearings and trigonometry
E, F, G, H are points on a sportsfield. E is due north of F, H is due east of F (so EF^H=90°E\hat{F}H=90°), FE^H=65°F\hat{E}H=65° and FH=15,2mFH=15,2m. Calculate the distance EF.

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Question 1002

[2 marks]Bearings and trigonometry
In triangle FGH, HG=12,5mHG=12,5m, FH=15,2mFH=15,2m and FG^H=75°20′F\hat{G}H=75°20'. Using the sine rule, calculate sin⁡(GF^H)\sin(G\hat{F}H).

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Question 1003

[2 marks]Bearings and trigonometry
In triangle FGH, sin⁡(GF^H)≈0,795\sin(G\hat{F}H)\approx0,795. Find angle GF^HG\hat{F}H correct to 1 decimal place.

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Question 1004

[2 marks]Bearings and trigonometry
H is due east of F (bearing 090° from F), and G lies a further 52,7°52,7° round from FH. Calculate the bearing of G from F.

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Question 1005

[3 marks]Bearings and trigonometry
A vertical pole of height 5,6m stands at H, and FH=15,2mFH=15,2m. Calculate the angle of elevation of the top of the pole from F.

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Question 1101

[3 marks]Geometrical Transformation
Triangle X has vertices (-4,4), (-2,2) and (0,4). A single transformation Z maps triangle X onto triangle Z(X) with vertices (6,-6), (3,-3) and (0,-6). Describe fully the transformation Z.

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Question 1102

[2 marks]Geometrical Transformation
Triangle X has a vertex at (-4,4). A translation T maps this vertex onto (8,2). Write down the translation vector T.

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Question 1103

[3 marks]Geometrical Transformation
Triangle X has a vertex at (-4,4). The transformation R is a clockwise rotation of 90° about (4,2). Find the coordinates of the image of (-4,4) under R.

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Question 1201

[3 marks]Inequalities and vectors
List the integer values of x that satisfy the inequality 14−x≤5x<2714-x \le 5x < 27.

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Question 1202

[3 marks]Inequalities and vectors
Ratidzo has \$200 pocket money to buy c crayons at \$12,50 each and b books at \$25 each. She wants at least 5 crayons and at most 4 books. Write down three inequalities, other than c≥0c\ge0 and b≥0b\ge0, that describe these conditions.

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Question 1203

[1 marks]Inequalities and vectors
In a diagram, OPA and OBR are straight lines, OA→=a\overrightarrow{OA}=\mathbf{a} and OB→=b\overrightarrow{OB}=\mathbf{b}. Express AB→\overrightarrow{AB} in terms of a and/or b.

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Question 1204

[2 marks]Inequalities and vectors
In a diagram, OPA and OBR are straight lines, OA→=a\overrightarrow{OA}=\mathbf{a}, OB→=b\overrightarrow{OB}=\mathbf{b}, OP→=4PA→\overrightarrow{OP}=4\overrightarrow{PA} (so OP→=45a\overrightarrow{OP}=\frac{4}{5}\mathbf{a}) and OR→=3OB→\overrightarrow{OR}=3\overrightarrow{OB}. Express PR→\overrightarrow{PR} in terms of a and/or b.

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Question 1205

[3 marks]Inequalities and vectors
In a diagram, OP→=45a\overrightarrow{OP}=\frac{4}{5}\mathbf{a}, PR→=−45a+3b\overrightarrow{PR}=-\frac{4}{5}\mathbf{a}+3\mathbf{b}, and Q is on PR with PQ→=hPR→\overrightarrow{PQ}=h\overrightarrow{PR}. Express PQ→\overrightarrow{PQ} in terms of h, a and b.

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