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ZIMSEC O Level · 4004/2 · J2023

Mathematics Paper 2 June 2023

Questions
59
Total marks
136
Time allowed
150 min
Syllabus code
4004/2

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Questions
59
Pass mark
36
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Standard Form, Percentages and Ratios
Simplify 0,92−0,33+0,240,92 - 0,33 + 0,24 and give the answer in standard form.

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Question 102

[2 marks]Standard Form, Percentages and Ratios
Amos sold a radio for $66,00\$66,00 and made a profit of 10%. Find the cost price of the radio.
  1. A$72,60\$72,60, by adding a further 10% onto the selling price
  2. B$60,00\$60,00, since $66,00\$66,00 is 110% of the cost price
  3. C$56,00\$56,00, by subtracting a flat $10,00\$10,00 from the selling price
  4. D$59,40\$59,40, by taking 10% off the selling price of $66,00\$66,00

Question 103

[3 marks]Standard Form, Percentages and Ratios
Share $286,00\$286,00 in the ratio 1:112:41 : 1\frac{1}{2} : 4. How much is the largest share?

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Question 104

[2 marks]Standard Form, Percentages and Ratios
Remove brackets and simplify (d+3)(6d−1)(d + 3)(6d - 1).

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Question 201

[2 marks]Change of Subject, Simple Interest and Algebraic Fractions
Given that T=g+n3−mT = g + \sqrt{n^3 - m}, find TT when g=−4g = -4, n=3n = 3 and m=−9m = -9.

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Question 202

[3 marks]Change of Subject, Simple Interest and Algebraic Fractions
Make mm the subject of the formula T=g+n3−mT = g + \sqrt{n^3 - m}.
  1. Am=n3−(T−g)2m = n^3 - (T - g)^2
  2. Bm=n3−T2+g2m = n^3 - T^2 + g^2
  3. Cm=n3−(T+g)2m = n^3 - (T + g)^2
  4. Dm=(T−g)2−n3m = (T - g)^2 - n^3

Question 203

[2 marks]Change of Subject, Simple Interest and Algebraic Fractions
Find the rate of interest per year when $144,00\$144,00 earns $22,68\$22,68 simple interest in 3123\frac{1}{2} years.

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Question 204

[3 marks]Change of Subject, Simple Interest and Algebraic Fractions
Express 2−xx2−4−1+xx+2\frac{2 - x}{x^2 - 4} - \frac{1 + x}{x + 2} as a single fraction in its simplest form.

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Question 301

[2 marks]Linear Equations, Factorisation and Wages
Solve the equation 35(f−1)=15f\frac{3}{5}(f - 1) = \frac{1}{5}f.

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Question 302

[3 marks]Linear Equations, Factorisation and Wages
Solve the equation (223−p)2=179\left(2\frac{2}{3} - p\right)^2 = 1\frac{7}{9}.
  1. Ap=4p = 4 only, because the other root makes the bracket negative
  2. Bp=49p = \frac{4}{9} or p=449p = \frac{44}{9}, squaring each term inside the bracket
  3. Cp=113p = 1\frac{1}{3} or p=4p = 4, one root from each square root of 169\frac{16}{9}
  4. Dp=113p = 1\frac{1}{3} only, taking just the positive square root of 169\frac{16}{9}

Question 303

[2 marks]Linear Equations, Factorisation and Wages
Factorise completely 10m2−tr−2mt+5mr10m^2 - tr - 2mt + 5mr.

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Question 304

[2 marks]Linear Equations, Factorisation and Wages
Factorise completely p3−16pp^3 - 16p.

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Question 305

[2 marks]Linear Equations, Factorisation and Wages
A carpenter is paid at a rate of $3,65\$3,65 per hour. Calculate her wage for working a 38 hour week.

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Question 401

[2 marks]Constructions and Loci
In a quadrilateral ABCDABCD, a point moves so that it stays the same distance from the line ABAB as from the line BCBC. Which construction gives its path?
  1. AThe perpendicular bisector of the side ABAB of the quadrilateral
  2. BThe line drawn through BB parallel to the side ADAD
  3. CThe bisector of the angle AB^CA\hat{B}C, drawn from BB
  4. DA circle centred on BB and passing through AA and CC

Question 402

[2 marks]Constructions and Loci
A point moves so that it stays 3 cm from a straight line ABAB. Describe the whole of its path.
  1. AOne line parallel to ABAB and 3 cm above it, with nothing below
  2. BTwo arcs of radius 3 cm, one centred on AA and one on BB
  3. CA single circle of radius 3 cm centred on the midpoint of ABAB
  4. DA pair of lines parallel to ABAB, one 3 cm on each side of it

Question 403

[2 marks]Constructions and Loci
Inside a quadrilateral ABCDABCD two loci are drawn: the bisector of AB^CA\hat{B}C, and the line parallel to ABAB and 3 cm from it on the same side as DCDC. What does their point of intersection represent?
  1. AThe midpoint of the side ABAB lifted 3 cm above the line ABAB
  2. BThe centre of the circle that passes through AA, BB and CC
  3. CThe point equidistant from ABAB and BCBC that is also 3 cm from ABAB
  4. DThe point that is 3 cm from both ABAB and BCBC, measured perpendicularly

Question 404

[2 marks]Constructions and Loci
In a quadrilateral ABCDABCD, AB=4,8AB = 4,8 cm, AD=8,9AD = 8,9 cm, BC=6,6BC = 6,6 cm, BA^D=60∘B\hat{A}D = 60^\circ and AB^C=135∘A\hat{B}C = 135^\circ. PP is the point that is equidistant from ABAB and BCBC and 3 cm from ABAB, on the same side of ABAB as DCDC. Find the length of PCPC in cm.

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Question 501

[2 marks]Number, Time and Functional Notation
Simplify 25,8−13+15,2525,8 - 13 + 15,25.

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Question 502

[2 marks]Number, Time and Functional Notation
Add 3 days 15 hours 40 minutes to 2 days 8 hours 40 minutes.
  1. A6 days 1 hour 20 minutes
  2. B6 days 0 hours 20 minutes
  3. C5 days 23 hours 80 minutes
  4. D5 days 24 hours 20 minutes

Question 503

[2 marks]Number, Time and Functional Notation
Tafadzwa borrows $600\$600 from Tendai at the start of the year. He agrees that at the end of the year he will repay Tendai and also give him 25\frac{2}{5} of any profit he makes. The $600\$600 grows to $1250\$1250. How much does Tafadzwa hand over to Tendai at the end of the year?

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Question 504

[2 marks]Number, Time and Functional Notation
Express 676 as a product of its prime factors in index notation.

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Question 505

[1 marks]Number, Time and Functional Notation
Find the square root of 676.

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Question 506

[2 marks]Number, Time and Functional Notation
Given that f(x)=3x+5f(x) = 3x + 5, find f(3)f(3) and the value of xx for which f(x)=83f(x) = 83.
  1. Af(3)=9f(3) = 9 and x=26x = 26
  2. Bf(3)=14f(3) = 14 and x=26x = 26
  3. Cf(3)=14f(3) = 14 and x=2913x = 29\frac{1}{3}
  4. Df(3)=8f(3) = 8 and x=78x = 78, adding 5 to 3 and to 78

Question 601

[2 marks]Variation, Mensuration and Quadratic Equations
The cost CC of printing a newspaper is partly constant and partly varies as nn, the number of newspapers printed. Which relation expresses CC in terms of nn and the constants kk and hh?
  1. AC=k+hnC = k + hn, a fixed part plus a part proportional to nn
  2. BC=khnC = khn, the two constants multiplied together with nn
  3. CC=kn+hn2C = kn + hn^2, two parts that both change as nn changes
  4. DC=k+hnC = k + \frac{h}{n}, a fixed part plus a part inversely proportional to nn

Question 602

[3 marks]Variation, Mensuration and Quadratic Equations
The cost CC of printing nn newspapers is C=k+hnC = k + hn. Printing 500 newspapers costs $320\$320 and printing 1 000 newspapers costs $540\$540. Find the cost of printing 750 newspapers.

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Question 603

[2 marks]Variation, Mensuration and Quadratic Equations
KLMNKLMN is a trapezium in which KLKL is parallel to NMNM and KL^M=90∘K\hat{L}M = 90^\circ, with KL=(3x−1)KL = (3x - 1) cm, NM=(x+3)NM = (x + 3) cm and LM=(x−3)LM = (x - 3) cm. Write an expression in xx for the area of the trapezium, in factorised form.

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Question 604

[2 marks]Variation, Mensuration and Quadratic Equations
Solve the equation 2x2−5x−18=02x^2 - 5x - 18 = 0.

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Question 605

[3 marks]Variation, Mensuration and Quadratic Equations
A trapezium has parallel sides of (3x−1)(3x - 1) cm and (x+3)(x + 3) cm, and the perpendicular side joining them is (x−3)(x - 3) cm. Its area is 15 cm2^2. Find the length of that perpendicular side, in cm.

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Question 701

[1 marks]Household Bills and Variation
A household water meter read 762 Kl at the start of a month and 776 Kl at the end. Find the consumption for the month, in Kl.

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Question 702

[2 marks]Household Bills and Variation
A family is allowed 11 Kl of water a month at a permitted rate, and that permitted consumption is charged $17,05\$17,05 in total. Find the rate charged per Kl for the permitted consumption.

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Question 703

[2 marks]Household Bills and Variation
A family used 14 Kl of water in a month. The first 11 Kl are the permitted consumption; anything above that is charged at $2,50\$2,50 per Kl. Find the amount paid for the excess water.

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Question 704

[3 marks]Household Bills and Variation
In one month a family used 14 Kl of water. The first 11 Kl are charged at $1,55\$1,55 per Kl, water above 11 Kl is charged at $2,50\$2,50 per Kl, and a fixed charge of $7,30\$7,30 is added. Find the total amount due.

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Question 705

[1 marks]Household Bills and Variation
NN varies inversely as the square root of MM. Which formula connects NN, MM and a constant kk?
  1. AN=MkN = \frac{\sqrt{M}}{k}
  2. BN=kMN = k\sqrt{M}
  3. CN=kM2N = \frac{k}{M^2}
  4. DN=kMN = \frac{k}{\sqrt{M}}

Question 706

[3 marks]Household Bills and Variation
NN varies inversely as the square root of MM. Given that N=17N = 17 when M=20,25M = 20,25, find the value of MM when N=34N = 34.

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Question 801

[3 marks]Geometrical Transformation
Triangle A has vertices (−6;2)(-6; 2), (−2;2)(-2; 2) and (−5;6)(-5; 6). Triangle B is the image of triangle A under a clockwise rotation of 90∘90^\circ about the point (2;2)(2; 2). Write down the coordinates of the image of the vertex (−5;6)(-5; 6).

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Question 802

[3 marks]Geometrical Transformation
Triangle A has vertices (−6;2)(-6; 2), (−2;2)(-2; 2) and (−5;6)(-5; 6). Its image has vertices (−6;14)(-6; 14), (−2;6)(-2; 6) and (−5;16)(-5; 16). Describe fully the single transformation that maps A onto that image.
  1. AA shear with the yy axis invariant and shear factor −2-2
  2. BA shear with the xx axis invariant and shear factor −2-2
  3. CA translation of 12 units upwards followed by an enlargement of factor 2
  4. DA one way stretch parallel to the yy axis of factor 2, with the xx axis invariant

Question 803

[3 marks]Geometrical Transformation
Triangle A has vertices (−6;2)(-6; 2), (−2;2)(-2; 2) and (−5;6)(-5; 6). Its image has vertices (−2;2)(-2; 2), (−2;−2)(-2; -2) and (2;−1)(2; -1). Describe fully the single transformation that maps A onto that image.
  1. AA rotation of 180∘180^\circ about the point midway between the two triangles
  2. BA reflection in the line y=x+4y = x + 4
  3. CA rotation of 90∘90^\circ clockwise about the point (−2;2)(-2; 2)
  4. DA reflection in the line y=−x−4y = -x - 4, which passes through (−4;0)(-4; 0)

Question 804

[3 marks]Geometrical Transformation
Triangle A has vertices (−6;2)(-6; 2), (−2;2)(-2; 2) and (−5;6)(-5; 6). A shear with the yy axis invariant and shear factor −2-2 is applied to it. Write down the image of the vertex (−2;2)(-2; 2).

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Question 901

[2 marks]Measures and Mensuration
A solid prism has an isosceles triangular cross section PQUPQU in which QP=QUQP = QU, PU=24PU = 24 cm, and the perpendicular from QQ to PUPU is 5 cm. Find the length of QUQU, in cm.

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Question 902

[2 marks]Measures and Mensuration
A triangle PQUPQU has PU=24PU = 24 cm, and the perpendicular from QQ to PUPU is 5 cm. Find its area.
  1. A120 cm2^2, taking 24 times 5 without halving it
  2. B65 cm2^2, adding the base to the height after doubling
  3. C156 cm2^2, using the slant side of 13 cm as the height
  4. D60 cm2^2, half of 24 multiplied by 5

Question 903

[2 marks]Measures and Mensuration
A prism has a triangular cross section of area 60 cm2^2 and a volume of 1 728 cm3^3. Find the length of the prism, in cm.

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Question 904

[3 marks]Measures and Mensuration
A prism has a volume of 1 728 cm3^3. The material it is made of has a density of 4 g/cm3^3 and costs $1,93\$1,93 per kg. Find the cost of the material used to make the prism.

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Question 905

[3 marks]Measures and Mensuration
A prism of volume 1 728 cm3^3 is 28,8 cm long. A similar prism has a volume of 512 cm3^3. Find its length, in cm.

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Question 1001

[3 marks]Probability and Functional Graphs
A class has 16 boys and 10 girls. Two learners are chosen one after the other, without replacement, to represent the school. Find the probability that both are of the same sex. Give the answer as a fraction in its lowest terms.

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Question 1002

[2 marks]Probability and Functional Graphs
For the function y=2x2−x−6y = 2x^2 - x - 6, one value of yy is missing at x=−2x = -2 and another at x=3x = 3. Find both values.
  1. A44 at x=−2x = -2 and 99 at x=3x = 3
  2. B00 at x=−2x = -2 and 1515 at x=3x = 3
  3. C−4-4 at x=−2x = -2 and 99 at x=3x = 3, treating 2x22x^2 as (2x)2(2x)^2
  4. D88 at x=−2x = -2 and 2121 at x=3x = 3, dropping the −x-x term

Question 1003

[2 marks]Probability and Functional Graphs
Find the values of xx at which the curve y=2x2−x−6y = 2x^2 - x - 6 meets the xx axis.
  1. Ax=−1,5x = -1,5 and x=2x = 2
  2. Bx=−6x = -6 and x=1x = 1, taking them from the constant term
  3. Cx=0,25x = 0,25 alone, which is where the curve turns
  4. Dx=1,5x = 1,5 and x=2x = 2, reading the signs the wrong way round

Question 1004

[2 marks]Probability and Functional Graphs
Find the minimum value of y=2x2−x−6y = 2x^2 - x - 6.

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Question 1005

[3 marks]Probability and Functional Graphs
Find the gradient of the curve y=2x2−x−6y = 2x^2 - x - 6 at the point where x=−3x = -3.

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Question 1101

[2 marks]Pie Charts and Vector Geometry
In a pie chart of 192 learners' favourite subjects, the sector for Shona has an angle of 120∘120^\circ. Find the number of learners who preferred Shona.

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Question 1102

[2 marks]Pie Charts and Vector Geometry
In a pie chart of 192 learners' favourite subjects, the sector for Accounts is marked with a right angle. Find the number of learners who preferred Accounts.

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Question 1103

[2 marks]Pie Charts and Vector Geometry
In a pie chart of 192 learners' favourite subjects, 40 learners preferred Commerce and the Commerce sector has an angle of p∘p^\circ. Find the value of pp.

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Question 1104

[2 marks]Pie Charts and Vector Geometry
In a pie chart of 192 learners' favourite subjects the sectors are Shona 120∘120^\circ, Accounts 90∘90^\circ, Commerce 75∘75^\circ, History (chosen by 32 learners) and Others. Find the angle of the sector for Others.

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Question 1105

[2 marks]Pie Charts and Vector Geometry
ABCDABCD is a trapezium with ABAB parallel to DCDC, AB→=6a\overrightarrow{AB} = 6a, DC→=2a\overrightarrow{DC} = 2a and DA→=3b\overrightarrow{DA} = 3b. Express BC→\overrightarrow{BC} in terms of aa and bb.
  1. A−4a+3b-4a + 3b
  2. B4a+3b4a + 3b
  3. C−8a−3b-8a - 3b
  4. D−4a−3b-4a - 3b

Question 1106

[2 marks]Pie Charts and Vector Geometry
ABCDABCD is a trapezium with ABAB parallel to DCDC, AB→=6a\overrightarrow{AB} = 6a, DC→=2a\overrightarrow{DC} = 2a and DA→=3b\overrightarrow{DA} = 3b. ACAC and BDBD meet at PP, where AP:PC=3:1AP:PC = 3:1. Express DP→\overrightarrow{DP} in terms of aa and bb.

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Question 1201

[2 marks]Matrices, Quadratic Equations, Polygons and Inequalities
Given that A=(−2314)A = \begin{pmatrix} -2 & 3 \\ 1 & 4 \end{pmatrix} and B=(−14)B = \begin{pmatrix} -1 \\ 4 \end{pmatrix}, evaluate ABAB.

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Question 1202

[2 marks]Matrices, Quadratic Equations, Polygons and Inequalities
A matrix AA has order 2×22 \times 2 and a matrix BB has order 2×12 \times 1. State the order of the product ABAB.
  1. AThe product cannot be formed, since the two orders differ
  2. B2×12 \times 1
  3. C1×21 \times 2
  4. D2×22 \times 2

Question 1203

[3 marks]Matrices, Quadratic Equations, Polygons and Inequalities
The function ff is given by f(x)=3x2−5x−1f(x) = 3x^2 - 5x - 1. Solve the equation f(x)=−3f(x) = -3.

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Question 1204

[3 marks]Matrices, Quadratic Equations, Polygons and Inequalities
The interior angles of a hexagon are 82∘82^\circ, 94∘94^\circ, 109∘109^\circ, x∘x^\circ, 2x∘2x^\circ and 3x∘3x^\circ. Find the value of xx.

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Question 1205

[2 marks]Matrices, Quadratic Equations, Polygons and Inequalities
Solve the inequality 5−x>3x+25 - x > 3x + 2.
  1. Ax>0,75x > 0,75
  2. Bx>72x > \frac{7}{2}, from collecting the constants on the wrong side
  3. Cx<0,75x < 0,75
  4. Dx<−0,75x < -0,75

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