Danho
ZIMSEC O Level · 4028/2 · N2014

Mathematics Paper 2 November 2014

Questions
50
Total marks
136
Time allowed
150 min
Syllabus code
4028/2

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Questions
50
Pass mark
30
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Number, L.C.M, Number Bases and Time
Simplify 3,27×0,593,27 \times 0,59, giving the answer correct to three significant figures.

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Question 102

[3 marks]Number, L.C.M, Number Bases and Time
Find the Lowest Common Multiple (L.C.M) of 72 and 96.

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Question 103

[3 marks]Number, L.C.M, Number Bases and Time
Express 10111210111_2 as a number in base 5.
  1. A1035103_5
  2. B23523_5
  3. C34534_5
  4. D43543_5

Question 104

[2 marks]Number, L.C.M, Number Bases and Time
A train that is scheduled to arrive in Bulawayo at 0027 is delayed by 3 hours 47 minutes. Find the time, on the 24 hour clock, at which it arrives in Bulawayo.

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Question 201

[3 marks]Equations, Factorisation and Algebraic Fractions
Solve the equation 2x−14=35x\dfrac{2}{x} - \dfrac{1}{4} = \dfrac{3}{5x}.

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Question 202

[2 marks]Equations, Factorisation and Algebraic Fractions
Factorise completely 7x3−28x7x^3 - 28x.

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Question 203

[3 marks]Equations, Factorisation and Algebraic Fractions
Factorise completely 3y2−5y+23y^2 - 5y + 2.

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Question 204

[3 marks]Equations, Factorisation and Algebraic Fractions
Express x+22x−3−1x\dfrac{x+2}{2x-3} - \dfrac{1}{x} as a single fraction in its simplest form.
  1. Ax+1x2−3x\frac{x+1}{x^2-3x}
  2. Bx2+32x2−3x\frac{x^2+3}{2x^2-3x}
  3. Cx2−32x2−3x\frac{x^2-3}{2x^2-3x}
  4. Dx2+4x−32x2−3x\frac{x^2+4x-3}{2x^2-3x}

Question 301

[3 marks]Approximations and Sets
A rectangle measures 8 cm by 6 cm to the nearest centimetre. Calculate the least possible value of the area of the rectangle, in square centimetres.

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Question 302

[2 marks]Approximations and Sets
The universal set is ξ={x:8<x≤16, x is an integer}\xi = \{x : 8 < x \le 16,\ x \text{ is an integer}\} and A={x:x is a square number}A = \{x : x \text{ is a square number}\}. List all the elements of AA.
  1. A{9;12;16}\{9; 12; 16\}
  2. B{9;16}\{9; 16\}
  3. C{10;12;14;16}\{10; 12; 14; 16\}
  4. D{4;9;16}\{4; 9; 16\}

Question 303

[2 marks]Approximations and Sets
The universal set is ξ={x:8<x≤16, x is an integer}\xi = \{x : 8 < x \le 16,\ x \text{ is an integer}\} and B={x:x is an even number}B = \{x : x \text{ is an even number}\}. Find n(B)n(B).

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Question 304

[3 marks]Approximations and Sets
The universal set is ξ={x:8<x≤16, x is an integer}\xi = \{x : 8 < x \le 16,\ x \text{ is an integer}\}, A={x:x is a square number}A = \{x : x \text{ is a square number}\} and B={x:x is an even number}B = \{x : x \text{ is an even number}\}. Find the number of elements of ξ\xi that belong to neither AA nor BB.

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Question 401

[2 marks]Similarity and Variation
In the diagram, △LMN\triangle LMN is right-angled at L and LP is an altitude drawn to NM. Which pair of triangles is similar to △LMN\triangle LMN?
  1. A△LPM\triangle LPM and △PMN\triangle PMN
  2. B△NPL\triangle NPL and △NLM\triangle NLM
  3. C△NPL\triangle NPL and △LPM\triangle LPM
  4. D△NPL\triangle NPL and △NPM\triangle NPM

Question 402

[3 marks]Similarity and Variation
In the diagram, △LMN\triangle LMN is right-angled at L and LP is an altitude. PN = 9 cm and LM = 6 cm. Find PM, in centimetres.

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Question 403

[2 marks]Similarity and Variation
The annual premium, PP dollars, for a funeral insurance scheme varies jointly as the square root of the age, YY years, and the number of dependants, DD, of the applicant. A 25 year old applicant with 6 dependants pays $150,00 a year. Find the constant of variation.

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Question 404

[3 marks]Similarity and Variation
The annual premium, PP dollars, for a funeral insurance scheme varies jointly as the square root of the age, YY years, and the number of dependants, DD, of the applicant. A 25 year old applicant with 6 dependants pays $150,00 a year. Calculate the monthly premium, in dollars, for a 49 year old applicant with 4 dependants.

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Question 501

[3 marks]Consumer Arithmetic
Mrs Shoko erects a durawall around her rectangular stand measuring 20 m by 11 m. Three metres are to be left for a gate. Find the perimeter of the durawall, in metres.

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Question 502

[2 marks]Consumer Arithmetic
A durawall 59 m long is to be built. A contractor charges $12 per metre on a fix-and-supply basis. Calculate the total cost, in dollars, of engaging the contractor.

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Question 503

[3 marks]Consumer Arithmetic
To build a durawall Mrs Shoko buys 5 000 bricks at $80,00 for every 1 000, ten 50 kg bags of cement at $10 per bag, 5 bundles of brick force at $5 per bundle and 2 loads of pit sand at $30 per load. She also engages a builder who charges $100 for the job. Calculate her total cost, in dollars.

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Question 504

[2 marks]Consumer Arithmetic
Mrs Shoko can erect her durawall either by engaging a contractor, at a total cost of $708,00, or by buying materials and paying a builder, at a total cost of $685,00. She uses the cheaper of the two. Calculate the amount, in dollars, that she saves.

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Question 601

[2 marks]Constructions and Loci
A triangular field PQR has PQ = 30 m, PQ^R=60∘P\hat{Q}R = 60^\circ and RP^Q=45∘R\hat{P}Q = 45^\circ. Calculate the size, in degrees, of QR^PQ\hat{R}P.

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Question 602

[3 marks]Constructions and Loci
A triangular field PQR has PQ = 30 m, PQ^R=60∘P\hat{Q}R = 60^\circ and RP^Q=45∘R\hat{P}Q = 45^\circ. Calculate the length of QR, in metres, correct to three significant figures.

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Question 603

[3 marks]Constructions and Loci
A triangular field PQR has PQ = 30 m, PQ^R=60∘P\hat{Q}R = 60^\circ and RP^Q=45∘R\hat{P}Q = 45^\circ. Calculate the length of PR, in metres, correct to three significant figures.

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Question 604

[2 marks]Constructions and Loci
A triangular field PQR is to be drawn to a scale of 1 cm to represent 3 m. The side PQ measures 30 m on the ground. Find the length, in centimetres, that PQ must be drawn.

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Question 701

[2 marks]Measures and Mensuration
A farmer has a square orchard of side 10 m. He extends it by increasing the length of one side by xx metres and the other by 2x2x metres, as in the diagram. Which expression gives the area, in square metres, of the extension alone?
  1. A2x2+30x2x^2 + 30x
  2. B2x2+30x+1002x^2 + 30x + 100
  3. C2x2+20x2x^2 + 20x
  4. D3x2+30x3x^2 + 30x

Question 702

[3 marks]Measures and Mensuration
Solve the equation 2x2+30x−87,5=02x^2 + 30x - 87,5 = 0.
  1. Ax=2,5x = 2,5 or x=17,5x = 17,5
  2. Bx=−2,5x = -2,5 or x=17,5x = 17,5
  3. Cx=3,5x = 3,5 or x=−12,5x = -12,5
  4. Dx=2,5x = 2,5 or x=−17,5x = -17,5

Question 703

[2 marks]Measures and Mensuration
A square orchard of side 10 m is extended by increasing one side by xx metres and the other by 2x2x metres. Given that x=2,5x = 2,5, write down the actual length, in metres, of the longer side of the extended orchard.

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Question 704

[3 marks]Measures and Mensuration
A square orchard of side 10 m is extended by increasing one side by xx metres and the other by 2x2x metres, where x=2,5x = 2,5. Calculate the total area, in square metres, of the extended orchard.

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Question 801

[3 marks]Geometrical Transformation
Describe fully the single transformation represented by the matrix (−100−1)\begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix}.
  1. AA rotation through 180∘180^\circ about the origin
  2. BA reflection in the xx-axis
  3. CA rotation through 90∘90^\circ anticlockwise about the origin
  4. DA reflection in the line y=xy = x

Question 802

[3 marks]Geometrical Transformation
Triangle PQR has vertices P(1; 1), Q(3; 4) and R(4; 0). It is mapped onto triangle P1Q1R1P_1Q_1R_1 by the transformation whose matrix is (−100−1)\begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix}. Find the coordinates of Q1Q_1.

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Question 803

[3 marks]Geometrical Transformation
Triangle PQR has vertices P(1; 1), Q(3; 4) and R(4; 0). It is mapped onto triangle P2Q2R2P_2Q_2R_2 by the translation (5−2)\begin{pmatrix} 5 \\ -2 \end{pmatrix} followed by the transformation whose matrix is (−100−1)\begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix}. Find the coordinates of P2P_2.

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Question 804

[2 marks]Geometrical Transformation
Triangle PQR has vertices P(1; 1), Q(3; 4) and R(4; 0). Calculate its area, in square units.

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Question 901

[2 marks]Statistics and Probability
In one week a University library lent out 30 Geography books, 45 Science books, 25 Maths books, 20 Shona books and 60 Theory of Education books. Find the total number of books borrowed in that week.

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Question 902

[2 marks]Statistics and Probability
In one week a University library lent out 30 Geography books, 45 Science books, 25 Maths books, 20 Shona books and 60 Theory of Education books. Express the number of Theory of Education books as a fraction, in its lowest terms, of all the books borrowed.

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Question 903

[3 marks]Statistics and Probability
In one week a University library lent out 30 Geography books, 45 Science books, 25 Maths books, 20 Shona books and 60 Theory of Education books. These five figures are to be shown as sectors of a circle. Calculate the angle, in degrees, of the sector representing Theory of Education.

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Question 904

[3 marks]Statistics and Probability
A University library lent out 180 books in one week: 30 Geography, 45 Science, 25 Maths, 20 Shona and 60 Theory of Education. Two students each borrowed one of these books, and the book taken by the first student was no longer available to the second. Calculate the probability that the first student borrowed a Science book and the second a Maths book. Give the answer as a fraction in its lowest terms.

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Question 1001

[2 marks]Travel Graphs
The velocity, vv m/s, of a moving body at time tt seconds is given by v=t2−3t+5v = t^2 - 3t + 5. In a list of values of vv, the entry at t=0t = 0 is mm and the entry at t=4t = 4 is nn. Find the value of mm and the value of nn.
  1. Am=3m = 3 and n=11n = 11
  2. Bm=5m = 5 and n=9n = 9
  3. Cm=0m = 0 and n=9n = 9
  4. Dm=5m = 5 and n=7n = 7

Question 1002

[3 marks]Travel Graphs
The velocity, vv m/s, of a moving body at time tt seconds is given by v=t2−3t+5v = t^2 - 3t + 5, for 0≤t≤70 \le t \le 7. Find the values of tt at which v=4v = 4, each correct to one decimal place.
  1. At=0,6t = 0,6 and t=2,4t = 2,4
  2. Bt=1,5t = 1,5 and t=3,5t = 3,5
  3. Ct=0,4t = 0,4 and t=2,6t = 2,6
  4. Dt=1,0t = 1,0 and t=2,0t = 2,0

Question 1003

[2 marks]Travel Graphs
The velocity, vv m/s, of a moving body at time tt seconds is given by v=t2−3t+5v = t^2 - 3t + 5. Find the acceleration, in m/s squared, when t=3t = 3.

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Question 1004

[3 marks]Travel Graphs
The velocity, vv m/s, of a moving body at time tt seconds is given by v=t2−3t+5v = t^2 - 3t + 5. Estimate the distance, in metres, travelled by the body from t=4t = 4 to t=6t = 6.

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Question 1101

[2 marks]Polygons, Bearings and Trigonometry
A regular polygon has an interior angle that is twice the exterior angle. Find the number of sides of the polygon.

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Question 1102

[2 marks]Polygons, Bearings and Trigonometry
A regular polygon has an interior angle that is twice the exterior angle. Find the sum, in degrees, of the interior angles of the polygon.

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Question 1103

[3 marks]Polygons, Bearings and Trigonometry
In the diagram, A, B, C and D lie on level ground and ABC is a straight road running west to east. AD = BD = 9 km and AB^D=40∘A\hat{B}D = 40^\circ. Calculate the bearing of A from D, in degrees.

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Question 1104

[3 marks]Polygons, Bearings and Trigonometry
In the diagram, A, B, C and D lie on level ground and ABC is a straight road. BD = 9 km, AB^D=40∘A\hat{B}D = 40^\circ and BC = 6 km. Calculate the distance CD, in kilometres, correct to three significant figures.

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Question 1105

[2 marks]Polygons, Bearings and Trigonometry
In the diagram, A, B, C and D lie on level ground and ABC is a straight road. BD = 9 km, AB^D=40∘A\hat{B}D = 40^\circ and BC = 6 km. Calculate the area of △\triangleBCD, in square kilometres, correct to three significant figures.

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Question 1201

[2 marks]Vector Geometry
In the diagram, ABC is a triangle with AB→=q\overrightarrow{AB} = \mathbf{q} and AC→=p\overrightarrow{AC} = \mathbf{p}, and M is the mid-point of AB. Express CM→\overrightarrow{CM} in terms of p\mathbf{p} and q\mathbf{q}.
  1. Ap−12q\mathbf{p} - \frac{1}{2}\mathbf{q}
  2. B12q+p\frac{1}{2}\mathbf{q} + \mathbf{p}
  3. C12q−p\frac{1}{2}\mathbf{q} - \mathbf{p}
  4. D12(p+q)\frac{1}{2}(\mathbf{p} + \mathbf{q})

Question 1202

[3 marks]Vector Geometry
In the diagram, ABC is a triangle with AB→=q\overrightarrow{AB} = \mathbf{q} and AC→=p\overrightarrow{AC} = \mathbf{p}, and X lies on BC with BX : XC = 4 : 1. Express AX→\overrightarrow{AX} in terms of p\mathbf{p} and q\mathbf{q}.
  1. A45p+15q\frac{4}{5}\mathbf{p} + \frac{1}{5}\mathbf{q}
  2. B45p−15q\frac{4}{5}\mathbf{p} - \frac{1}{5}\mathbf{q}
  3. C15p+15q\frac{1}{5}\mathbf{p} + \frac{1}{5}\mathbf{q}
  4. D15p+45q\frac{1}{5}\mathbf{p} + \frac{4}{5}\mathbf{q}

Question 1203

[3 marks]Vector Geometry
In the diagram, ABC is a triangle with AB→=q\overrightarrow{AB} = \mathbf{q} and AC→=p\overrightarrow{AC} = \mathbf{p}, M is the mid-point of AB and X lies on BC with BX : XC = 4 : 1. CM and AX cross at Y, where CY→=k CM→\overrightarrow{CY} = k\,\overrightarrow{CM} and AY→=h AX→\overrightarrow{AY} = h\,\overrightarrow{AX}. Find the value of hh, as a fraction.

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Question 1204

[2 marks]Vector Geometry
In the diagram, ABC is a triangle with AB→=q\overrightarrow{AB} = \mathbf{q} and AC→=p\overrightarrow{AC} = \mathbf{p}, M is the mid-point of AB and X lies on BC with BX : XC = 4 : 1. CM and AX cross at Y, where CY→=k CM→\overrightarrow{CY} = k\,\overrightarrow{CM} and AY→=h AX→\overrightarrow{AY} = h\,\overrightarrow{AX}. Given that h=56h = \frac{5}{6}, find the value of kk, as a fraction.

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Question 1205

[2 marks]Vector Geometry
In the diagram, ABC is a triangle with AB→=q\overrightarrow{AB} = \mathbf{q} and AC→=p\overrightarrow{AC} = \mathbf{p}, and X lies on BC with BX : XC = 4 : 1, so that AX→=45p+15q\overrightarrow{AX} = \frac{4}{5}\mathbf{p} + \frac{1}{5}\mathbf{q}. Given that AY→=56AX→\overrightarrow{AY} = \frac{5}{6}\overrightarrow{AX}, express AY→\overrightarrow{AY} in terms of p\mathbf{p} and q\mathbf{q}.
  1. A16p+23q\frac{1}{6}\mathbf{p} + \frac{2}{3}\mathbf{q}
  2. B45p+15q\frac{4}{5}\mathbf{p} + \frac{1}{5}\mathbf{q}
  3. C56p+16q\frac{5}{6}\mathbf{p} + \frac{1}{6}\mathbf{q}
  4. D23p+16q\frac{2}{3}\mathbf{p} + \frac{1}{6}\mathbf{q}

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