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ZIMSEC O Level · 4028/2 · N2010

Mathematics Paper 2 November 2010

Questions
55
Total marks
136
Time allowed
150 min
Syllabus code
4028/2

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Questions
55
Pass mark
33
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[3 marks]Fractions, Decimals and Percentages
Find the value of 13+179÷223\frac{1}{3} + 1\frac{7}{9} \div 2\frac{2}{3}.

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Question 102

[3 marks]Fractions, Decimals and Percentages
During a sale, the price of a camera was reduced from 160to160 to 148,80. Calculate the percentage decrease in price.

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Question 103

[3 marks]Fractions, Decimals and Percentages
Given that f(x)=x2−4x+3f(x) = x^2 - 4x + 3, find all the values of xx for which f(x)=0f(x) = 0.
  1. Ax=1x = 1 or x=3x = 3, the two numbers whose product is 3 and sum is 4
  2. Bx=2x = 2 only, because the curve turns on the axis at that point
  3. Cx=0x = 0 or x=4x = 4, obtained by taking xx out as a common factor
  4. Dx=−1x = -1 or x=−3x = -3, the two numbers whose sum is −4-4

Question 201

[2 marks]Algebraic Fractions
Express 1x−1+2x+1\frac{1}{x - 1} + \frac{2}{x + 1} as a single fraction in its simplest form.
  1. A32x\frac{3}{2x}, obtained by adding numerators and adding denominators
  2. B3x−1(x−1)(x+1)\frac{3x - 1}{(x - 1)(x + 1)}, since (x+1)+2(x−1)=3x−1(x + 1) + 2(x - 1) = 3x - 1
  3. C2x+3(x−1)(x+1)\frac{2x + 3}{(x - 1)(x + 1)}, since (x+1)+2(x+1)=2x+3(x + 1) + 2(x + 1) = 2x + 3
  4. D3(x−1)(x+1)\frac{3}{(x - 1)(x + 1)}, adding the numerators over the common denominator

Question 202

[2 marks]Algebraic Fractions
Solve the equation 1x−1+2x+1=3x\frac{1}{x - 1} + \frac{2}{x + 1} = \frac{3}{x}.

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Question 203

[3 marks]Algebraic Fractions
Solve the inequality y−4<3y+2≤6−yy - 4 < 3y + 2 \le 6 - y.
  1. A1≤y<31 \le y < 3
  2. B−3<y≤1-3 < y \le 1
  3. C−3≤y<1-3 \le y < 1
  4. Dy<−3y < -3 or y≥1y \ge 1

Question 204

[2 marks]Algebraic Fractions
List the integral values of yy that satisfy −3<y≤1-3 < y \le 1.
  1. A−3-3, −2-2, −1-1, 00, 11, taking both end values as included
  2. B−2-2, −1-1, 00, taking neither of the two end values as included
  3. C−3-3, −2-2, −1-1, 00, taking the left end value as included instead
  4. D−2-2, −1-1, 00, 11, since −3-3 is excluded but 11 is included

Question 205

[3 marks]Algebraic Fractions
In an Olympiad test there were 26 questions. Eight points were given for each correct answer and five points were deducted for each wrong answer. Tamara answered all questions and scored zero. Find the number of questions she had got correct.

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Question 301

[2 marks]Change of Subject of Formula
It is given that s=ut−12gt2s = ut - \frac{1}{2}gt^2. Find the value of ss when g=9,8g = 9,8, u=20u = 20 and t=2t = 2.

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Question 302

[2 marks]Change of Subject of Formula
Make gg the subject of the formula s=ut−12gt2s = ut - \frac{1}{2}gt^2.
  1. Ag=2t2(ut−s)g = 2t^2(ut - s)
  2. Bg=ut−s2t2g = \frac{ut - s}{2t^2}
  3. Cg=s−ut2t2g = \frac{s - ut}{2t^2}
  4. Dg=2(ut−s)t2g = \frac{2(ut - s)}{t^2}

Question 303

[2 marks]Change of Subject of Formula
In the diagram ADE is a triangle, B lies on AD with AB=2AB = 2 cm and BD=8BD = 8 cm, and C lies on AE with AC=4AC = 4 cm and CE=1CE = 1 cm. Name the triangle that is similar to triangle ABC.
  1. ATriangle AED
  2. BTriangle ADE
  3. CTriangle BCD
  4. DTriangle CDE

Question 304

[3 marks]Change of Subject of Formula
In the diagram ADE is a triangle with AB=2AB = 2 cm, BD=8BD = 8 cm, AC=4AC = 4 cm, CE=1CE = 1 cm and DE=8DE = 8 cm. Calculate the length of BC, in cm.

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Question 401

[2 marks]Variation
P varies directly as T and inversely as V. Write down an equation connecting P, V, T and a constant k.
  1. AP=kTVP = kTV, multiplying both quantities by the constant
  2. BP=kVTP = \frac{kV}{T}, putting the directly varying quantity below
  3. CP=k+TVP = k + \frac{T}{V}, adding the constant to the ratio of the two
  4. DP=kTVP = \frac{kT}{V}, with T on top and V underneath

Question 402

[3 marks]Variation
It is given that P=kTVP = \frac{kT}{V}. Calculate the value of kk when P=2×105P = 2 \times 10^5, V=1×10−3V = 1 \times 10^{-3} and T=300T = 300.

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Question 403

[2 marks]Variation
It is given that P=kTVP = \frac{kT}{V} with k=23k = \frac{2}{3}. Calculate P when V=0,0025V = 0,0025 and T=300T = 300.

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Question 404

[2 marks]Variation
Given that M=(3−2−14)\mathbf{M} = \begin{pmatrix} 3 & -2 \\ -1 & 4 \end{pmatrix}, find M−1\mathbf{M}^{-1}.
  1. A110(3214)\frac{1}{10}\begin{pmatrix} 3 & 2 \\ 1 & 4 \end{pmatrix}
  2. B114(4213)\frac{1}{14}\begin{pmatrix} 4 & 2 \\ 1 & 3 \end{pmatrix}
  3. C110(4213)\frac{1}{10}\begin{pmatrix} 4 & 2 \\ 1 & 3 \end{pmatrix}
  4. D110(4−2−13)\frac{1}{10}\begin{pmatrix} 4 & -2 \\ -1 & 3 \end{pmatrix}

Question 405

[2 marks]Variation
Given that R=(3−1)\mathbf{R} = \begin{pmatrix} 3 & -1 \end{pmatrix} and N=(57)\mathbf{N} = \begin{pmatrix} 5 \\ 7 \end{pmatrix}, evaluate RN\mathbf{RN}.

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Question 501

[2 marks]Circle Geometry
In the diagram A, B, C, D and E lie on a circle centre O, with BD passing through O, CA^E=68∘C\hat{A}E = 68^\circ and CA^B=36∘C\hat{A}B = 36^\circ. Find the size of CB^OC\hat{B}O, in degrees.

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Question 502

[2 marks]Circle Geometry
In the diagram AEF is a straight line, BD is parallel to AE, CA^B=36∘C\hat{A}B = 36^\circ and CA^E=68∘C\hat{A}E = 68^\circ. Find the size of DE^FD\hat{E}F.
  1. A76∘76^\circ, the supplement of 104∘104^\circ along the straight line AEF
  2. B36∘36^\circ, equal to the angle marked between BA and CA
  3. C104∘104^\circ, the sum of the two angles marked at A
  4. D68∘68^\circ, equal to the angle marked between CA and AE

Question 503

[2 marks]Circle Geometry
In the diagram BD is a diameter parallel to AE, and BA^E=104∘B\hat{A}E = 104^\circ. Find the size of AC^BA\hat{C}B, in degrees.

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Question 504

[2 marks]Circle Geometry
In a recipe for an apple pie, 500 g of apples and 200 g of flour make a pie for 4 people. Calculate the quantity of apples, in grams, needed to make a pie for 6 people.

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Question 505

[2 marks]Circle Geometry
In a recipe for an apple pie, 500 g of apples and 200 g of flour make a pie for 4 people. Calculate the quantity of flour, in grams, needed to make a pie for 3 people.

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Question 601

[2 marks]Constructions and Loci
A plot ABCD has AB=110AB = 110 m and is to be constructed using a scale of 1 cm to 10 m. Find the length, in cm, that AB must be drawn.

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Question 602

[2 marks]Constructions and Loci
On the same scale drawing of the plot, describe the locus of points that are 30 m from the side AB.
  1. AA circle of radius 3 cm centred on the midpoint of AB, drawn inside the plot
  2. BThe perpendicular bisector of AB, since its points sit 3 cm from each end of AB
  3. COne straight line parallel to AB drawn 3 cm inside the plot, because points beyond the boundary lie off the farmer's land
  4. DA pair of straight lines parallel to AB, one on each side of AB and each 3 cm from it

Question 603

[2 marks]Constructions and Loci
Describe the locus of points that are equidistant from the two corners A and B of the plot.
  1. AThe bisector of the angle at B, drawn with compasses from the corner B
  2. BA line drawn parallel to AB and exactly midway between the two lines that lie 3 cm from AB
  3. CThe perpendicular bisector of AB, constructed with equal arcs from A and from B
  4. DAn arc centred on the midpoint of AB whose radius is half the length of AB

Question 604

[2 marks]Constructions and Loci
On a scale drawing of the plot using 1 cm to 10 m, an arc is drawn to show the points inside the plot that are 60 m from the corner B. Find the radius, in cm, of that arc.

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Question 701

[2 marks]Measures and Mensuration
A wine glass is a cone whose depth is equal to its diameter at the top. Write down an expression for the volume of the cone in terms of its radius rr and π\pi.
  1. A43πr3\frac{4}{3}\pi r^3, since the height is 4r4r
  2. B2πr32\pi r^3, since the height is 6r6r
  3. C23πr3\frac{2}{3}\pi r^3, since the height is 2r2r
  4. D13πr3\frac{1}{3}\pi r^3, since the height is rr

Question 702

[3 marks]Measures and Mensuration
A cone of volume 23πr3\frac{2}{3}\pi r^3 holds 20 ml when full. Taking π\pi as 227\frac{22}{7}, calculate the radius rr, in cm, correct to 3 significant figures.

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Question 703

[2 marks]Measures and Mensuration
Wine is bought in bottles of volume 750 ml and each wine glass holds 20 ml when full. Calculate the number of full wine glasses that can be filled from one bottle.

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Question 704

[2 marks]Measures and Mensuration
The base of a triangle is xx cm and its height is (x−7)(x - 7) cm. Write down an expression for the area of the triangle.
  1. A2x(x−7)2x(x - 7) cm2^2, twice the base multiplied by the height
  2. Bx+(x−7)x + (x - 7) cm2^2, the base added to the height
  3. C12x(x−7)\frac{1}{2}x(x - 7) cm2^2, half the base multiplied by the height
  4. Dx(x−7)x(x - 7) cm2^2, the base multiplied by the height

Question 705

[3 marks]Measures and Mensuration
Solve the equation x2−7x−12=0x^2 - 7x - 12 = 0, giving the positive root correct to 2 decimal places.

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Question 801

[2 marks]Functional Graphs
State the maximum value of the function y=7−5x−x2y = 7 - 5x - x^2.

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Question 802

[2 marks]Functional Graphs
Find the value of xx at which the function y=7−5x−x2y = 7 - 5x - x^2 takes its maximum value.

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Question 803

[3 marks]Functional Graphs
Solve the equation 7−5x−x2=07 - 5x - x^2 = 0, giving the answers correct to 2 decimal places.
  1. Ax=1,32x = 1,32 or x=−5,32x = -5,32
  2. Bx=7,00x = 7,00 or x=−1,00x = -1,00
  3. Cx=6,14x = 6,14 or x=−1,14x = -1,14
  4. Dx=1,14x = 1,14 or x=−6,14x = -6,14

Question 804

[2 marks]Functional Graphs
The curve y=7−5x−x2y = 7 - 5x - x^2 has been drawn. Write down the equation of the straight line that must be drawn across the curve in order to solve −5x−x2=2-5x - x^2 = 2.

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Question 805

[2 marks]Functional Graphs
Find the gradient of the curve y=7−5x−x2y = 7 - 5x - x^2 at the point where x=0x = 0.

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Question 901

[2 marks]Travel Graphs
Farai cycled from home to a station 5 km away, leaving at 08 20 and arriving at 09 10. Find his speed on the outward journey, in km/h.

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Question 902

[2 marks]Travel Graphs
Tanya walked from home to a station 5 km away, leaving at 08 00 and arriving at 10 00. Calculate her average speed for the whole journey, in km/h.

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Question 903

[2 marks]Travel Graphs
The distance-time graph shows Farai and Tanya travelling from home to a station 5 km away. State the distance, in km, that Tanya had covered when Farai overtook her on the way to the station.

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Question 904

[2 marks]Travel Graphs
The distance-time graph shows Farai returning home from the station while Tanya is still walking to it. State the distance, in km, that Tanya had left to cover when Farai met her the second time.

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Question 905

[3 marks]Travel Graphs
Two cards were picked at random from a pack of 52 playing cards with replacement. Find the probability that one was a Court card (J, K or Q) and the other was an Ace.

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Question 1001

[2 marks]Trigonometry, Bearing & Distances
B is 12 km from A on a bearing of 062∘062^\circ and C is 15 km from A on a bearing of 158∘158^\circ. Calculate the size of BA^CB\hat{A}C, in degrees.

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Question 1002

[3 marks]Trigonometry, Bearing & Distances
In triangle ABC, AB=12AB = 12 km, AC=15AC = 15 km and BA^C=96∘B\hat{A}C = 96^\circ. Calculate the distance BC, in km, correct to 3 significant figures.

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Question 1003

[3 marks]Trigonometry, Bearing & Distances
In triangle ABC, AB=12AB = 12 km, BC=20,2BC = 20,2 km and BA^C=96∘B\hat{A}C = 96^\circ. Calculate AC^BA\hat{C}B to the nearest degree.

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Question 1004

[3 marks]Trigonometry, Bearing & Distances
In triangle ABC the bearing of B from A is 062∘062^\circ, BA^C=96∘B\hat{A}C = 96^\circ and AC^B=36∘A\hat{C}B = 36^\circ. Find the bearing of C from B.
  1. A146∘146^\circ
  2. B194∘194^\circ
  3. C242∘242^\circ
  4. D048∘048^\circ

Question 1101

[2 marks]Inequalities and Linear Programming
A builder builds xx houses and yy flats. There must be more than 6 houses and there must be more flats than houses. Write down two inequalities, other than x>0x > 0 and y>0y > 0, which satisfy these conditions.
  1. Ax>6x > 6 and y>xy > x
  2. Bx≥6x \ge 6 and y≥xy \ge x
  3. Cx>6x > 6 and x>yx > y
  4. Dy>6y > 6 and x>yx > y

Question 1102

[2 marks]Inequalities and Linear Programming
A builder allows 300 m2^2 for each of yy flats and 400 m2^2 for each of xx houses, on a plot of 6 000 m2^2. Write down the inequality this gives, before it is simplified.
  1. A400x+300y≤6 000400x + 300y \le 6\,000, since the land used cannot exceed the plot
  2. B300x+400y≤6 000300x + 400y \le 6\,000, with each house taking 300 m2^2
  3. C400x+300y≥6 000400x + 300y \ge 6\,000, since the plot must be filled completely
  4. D700(x+y)≤6 000700(x + y) \le 6\,000, since a house and a flat together take 700 m2^2

Question 1103

[2 marks]Inequalities and Linear Programming
The number of houses xx and the number of flats yy are whole numbers satisfying x>6x > 6, y>xy > x and 4x+3y≤604x + 3y \le 60. Find the maximum number of flats that can be built.

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Question 1104

[2 marks]Inequalities and Linear Programming
The number of houses xx and the number of flats yy are whole numbers satisfying x>6x > 6, y>xy > x and 4x+3y≤604x + 3y \le 60. Find the maximum number of houses that can be built.

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Question 1105

[3 marks]Inequalities and Linear Programming
The number of houses xx and the number of flats yy are whole numbers satisfying x>6x > 6, y>xy > x and 4x+3y≤604x + 3y \le 60. Find the values of xx and yy which give the maximum number of dwelling units.
  1. Ax=8x = 8 and y=8y = 8, giving 16 dwelling units in total
  2. Bx=7x = 7 and y=10y = 10, or x=8x = 8 and y=9y = 9, giving 17 dwelling units
  3. Cx=7x = 7 and y=8y = 8, giving 15 dwelling units in total
  4. Dx=6x = 6 and y=12y = 12, giving 18 dwelling units in total

Question 1201

[3 marks]Geometrical Transformation
Triangle PQR has vertices P(3; 1), Q(4; 1) and R(4; 3). It is mapped onto triangle P1_1Q1_1R1_1 where P1_1(-2; -3), Q1_1(-1; -3) and R1_1(-1; -1). Describe completely the single transformation involved.
  1. AA reflection in the line y=−xy = -x, which sends each point across that line
  2. BA translation with vector (−5−4)\begin{pmatrix} -5 \\ -4 \end{pmatrix}
  3. CA translation with vector (−4−5)\begin{pmatrix} -4 \\ -5 \end{pmatrix}
  4. DA rotation of 180∘180^\circ about the origin, which turns the triangle over

Question 1202

[3 marks]Geometrical Transformation
Triangle PQR has vertices P(3; 1), Q(4; 1) and R(4; 3). Find the coordinates of its image under a reflection in the line y=xy = x.
  1. AP2_2(-3; -1), Q2_2(-4; -1), R2_2(-4; -3)
  2. BP2_2(-3; 1), Q2_2(-4; 1), R2_2(-4; 3)
  3. CP2_2(1; 3), Q2_2(1; 4), R2_2(3; 4)
  4. DP2_2(1; -3), Q2_2(1; -4), R2_2(3; -4)

Question 1203

[2 marks]Geometrical Transformation
The point Q(4; 1) is enlarged with centre (0; 1) and scale factor −12-\frac{1}{2}. Find the coordinates of its image Q3_3.

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Question 1204

[2 marks]Geometrical Transformation
The point R(4; 3) is enlarged with centre (0; 1) and scale factor −12-\frac{1}{2}. Find the coordinates of its image R3_3.

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Question 1205

[2 marks]Geometrical Transformation
A stretch represented by the matrix (100−2)\begin{pmatrix} 1 & 0 \\ 0 & -2 \end{pmatrix} maps the point R(4; 3) onto R4_4. Find the coordinates of R4_4.

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