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ZIMSEC O Level · 4004/2 · N2021

Mathematics Paper 2 November 2021

Questions
57
Total marks
136
Time allowed
150 min
Syllabus code
4004/2

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Questions
57
Pass mark
35
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Circle Geometry
A, B, C, D and E lie on a circle with centre O, and EC is a straight line through O. Given that BC^E=53∘B\hat{C}E = 53^\circ, calculate BE^CB\hat{E}C, in degrees.

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Question 102

[1 marks]Circle Geometry
A, B, C, D and E lie in that order on a circle, and BC^E=53∘B\hat{C}E = 53^\circ. Calculate BA^EB\hat{A}E, in degrees.

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Question 103

[2 marks]Circle Geometry
A, B, C, D and E lie on a circle with centre O, and EC is a straight line through O. Given that EA^D=48∘E\hat{A}D = 48^\circ, calculate DO^CD\hat{O}C, in degrees.

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Question 104

[2 marks]Circle Geometry
In the diagram, A, B, C, D and E lie on a circle with centre O. Which angle is equal to AD^EA\hat{D}E?
  1. ABA^EB\hat{A}E, since it stands on the chord BE from the other side of that chord
  2. BAC^DA\hat{C}D, since it stands on the same chord AD as the angle given
  3. CDE^CD\hat{E}C, since it stands on the chord DC from the opposite segment of the circle
  4. DAB^EA\hat{B}E, since it stands on the same chord AE and in the same segment

Question 201

[2 marks]Matrices
Given the formula V=73πr2hV = \frac{7}{3}\pi r^2 h, calculate VV when r=3r = 3, π=227\pi = \frac{22}{7} and h=212h = 2\frac{1}{2}.

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Question 202

[2 marks]Matrices
Make rr the subject of the formula V=73πr2hV = \frac{7}{3}\pi r^2 h.
  1. Ar=13V7πhr = \dfrac{1}{3}\sqrt{\dfrac{V}{7\pi h}}
  2. Br=3V7πhr = \sqrt{\dfrac{3V}{7\pi h}}
  3. Cr=3V7πhr = \dfrac{3V}{7\pi h}
  4. Dr=7πh3Vr = \sqrt{\dfrac{7\pi h}{3V}}

Question 203

[2 marks]Matrices
Matrix A=(5−2−63)A = \begin{pmatrix} 5 & -2 \\ -6 & 3 \end{pmatrix} and matrix B=(34)B = \begin{pmatrix} 3 \\ 4 \end{pmatrix}. Find ABAB, giving the two entries in order.

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Question 204

[3 marks]Matrices
Find A−1A^{-1}, the inverse of A=(5−2−63)A = \begin{pmatrix} 5 & -2 \\ -6 & 3 \end{pmatrix}.
  1. A13(5263)\frac{1}{3}\begin{pmatrix} 5 & 2 \\ 6 & 3 \end{pmatrix}
  2. B127(3265)\frac{1}{27}\begin{pmatrix} 3 & 2 \\ 6 & 5 \end{pmatrix}
  3. C13(3265)\frac{1}{3}\begin{pmatrix} 3 & 2 \\ 6 & 5 \end{pmatrix}
  4. D13(3−2−65)\frac{1}{3}\begin{pmatrix} 3 & -2 \\ -6 & 5 \end{pmatrix}

Question 301

[3 marks]Constructions & Loci
Triangle ABC has AB = 8 cm, AC = 7 cm and BA^C=120∘B\hat{A}C = 120^\circ. Calculate the length of BC, in centimetres.

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Question 302

[2 marks]Constructions & Loci
What is the locus of the points that are 3 cm from the line AB?
  1. AA pair of lines parallel to AB, one 3 cm on each side of it
  2. BThe perpendicular bisector of AB, with a point marked 3 cm from A
  3. CA single line parallel to AB and 3 cm from it on the side of C
  4. DA circle of radius 3 cm drawn with its centre at the midpoint of AB

Question 303

[2 marks]Constructions & Loci
Using ruler and compasses only, how is an angle of 120∘120^\circ set up at A?
  1. AConstruct a perpendicular at A, then bisect the right angle and add it
  2. BConstruct 60∘60^\circ at A, then bisect the angle left on the other side
  3. CConstruct 60∘60^\circ at A, then a further 60∘60^\circ from the new arm
  4. DConstruct 60∘60^\circ at A, then bisect it and add the half to it

Question 304

[2 marks]Constructions & Loci
In triangle ABC, AB = 8 cm, AC = 7 cm and BA^C=120∘B\hat{A}C = 120^\circ. The perpendicular from A meets BC at D. Calculate AD, in centimetres, to 3 significant figures.

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Question 401

[2 marks]Sets
Calculate the simple interest obtained by investing $800 for 10 months at a rate of 36% per annum, in dollars.

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Question 402

[2 marks]Sets
If f(x)=x2+5x−6f(x) = x^2 + 5x - 6, find f(2)f(2).

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Question 403

[3 marks]Sets
If f(x)=x2+5x−6f(x) = x^2 + 5x - 6, find the values of xx for which f(x)=0f(x) = 0.

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Question 404

[2 marks]Sets
For ξ={x:1≤x≤12,  x∈Z}\xi = \{x : 1 \le x \le 12, \; x \in \mathbb{Z}\}, with P the perfect squares in ξ\xi and Q the even numbers in ξ\xi, list all the elements of P′∩QP' \cap Q.

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Question 405

[3 marks]Sets
For ξ={x:1≤x≤12,  x∈Z}\xi = \{x : 1 \le x \le 12, \; x \in \mathbb{Z}\}, P is the set of perfect squares in ξ\xi and Q is the set of even numbers in ξ\xi. What is P∩QP \cap Q?
  1. A{4}\{4\}, since 4 is the one number in ξ\xi that is a perfect square and even
  2. B{1,4,9}\{1, 4, 9\}, since every perfect square in ξ\xi is also an even number
  3. C{  }\{\;\}, since no number in ξ\xi is both a perfect square and an even number
  4. D{2,4,6,8,10,12}\{2, 4, 6, 8, 10, 12\}, since every even number in ξ\xi is a perfect square too

Question 501

[2 marks]Factorisation
Evaluate 312−614×253\frac{1}{2} - 6\frac{1}{4} \times \frac{2}{5}.

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Question 502

[2 marks]Factorisation
A lorry travels a distance of 123 km in 1121\frac{1}{2} hours. Find the average speed of the lorry, in km/h.

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Question 503

[3 marks]Factorisation
Solve the equation a−25=112\frac{a - 2}{5} = 1\frac{1}{2}.

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Question 504

[3 marks]Factorisation
Factorise completely 63−7p263 - 7p^2.

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Question 601

[3 marks]Statistics & Probability
The marks of 20 learners in a test were: mark 10 scored by 0 learners, mark 11 by 6, mark 12 by 5, mark 13 by 4, mark 14 by 3 and mark 15 by 2. Calculate the mean mark.

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Question 602

[2 marks]Statistics & Probability
Of 20 learners, 6 scored 11 marks. The distribution is to be shown on a pie chart. Calculate the angle, in degrees, that represents the learners who scored 11 marks.

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Question 603

[2 marks]Statistics & Probability
In a group of 20 learners, the marks scored were 11 by 6 learners, 12 by 5, 13 by 4, 14 by 3 and 15 by 2. Two learners are chosen at random from the group. Calculate the probability that their marks are both less than 14.

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Question 604

[3 marks]Statistics & Probability
Solve 3x2−5x−7=03x^2 - 5x - 7 = 0, giving the answers to 2 decimal places.
  1. Ax=−2,57x = -2,57 or x=0,91x = 0,91
  2. Bx=2,57x = 2,57 or x=−0,91x = -0,91
  3. Cx=2,91x = 2,91 or x=−0,57x = -0,57
  4. Dx=1,57x = 1,57 or x=−1,91x = -1,91

Question 605

[2 marks]Statistics & Probability
Find the value of the discriminant b2−4acb^2 - 4ac for the equation 3x2−5x−7=03x^2 - 5x - 7 = 0.

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Question 701

[2 marks]Functional Graphs
For the function y=1−2x−x2y = 1 - 2x - x^2, a table of values gives y=py = p when x=−1x = -1 and y=qy = q when x=2x = 2. Calculate the values of pp and qq.

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Question 702

[3 marks]Functional Graphs
What is the turning point of the curve y=1−2x−x2y = 1 - 2x - x^2, and what kind of turning point is it?
  1. A(1;−2)(1; -2), which is the maximum point of the curve
  2. B(−1;2)(-1; 2), which is the minimum point of the curve
  3. C(−1;2)(-1; 2), which is the maximum point of the curve
  4. D(−2;1)(-2; 1), which is the maximum point of the curve

Question 703

[2 marks]Functional Graphs
Find the gradient of the curve y=1−2x−x2y = 1 - 2x - x^2 at the point where x=1x = 1.

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Question 704

[3 marks]Functional Graphs
Estimate the roots of the equation 1−2x−x2=01 - 2x - x^2 = 0, to 1 decimal place.

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Question 705

[2 marks]Functional Graphs
The curve y=1−2x−x2y = 1 - 2x - x^2 rises above the xx axis between its two roots. Roughly what area does it enclose with that axis?
  1. AAbout 3,8 square units
  2. BAbout 1,9 square units
  3. CAbout 5,7 square units
  4. DAbout 2,4 square units

Question 801

[1 marks]Trigonometry, Bearing & Distances
In the diagram BED is a straight line and AB is parallel to DC. Which triangle is similar to triangle CDE?
  1. ATriangle ACD
  2. BTriangle ABE
  3. CTriangle ABC
  4. DTriangle BCD

Question 802

[2 marks]Trigonometry, Bearing & Distances
In the diagram BED is a straight line, AB is parallel to DC, CB^D=40∘C\hat{B}D = 40^\circ, AC^B=90∘A\hat{C}B = 90^\circ and EC^D=35∘E\hat{C}D = 35^\circ. Calculate AB^EA\hat{B}E, in degrees.

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Question 803

[2 marks]Trigonometry, Bearing & Distances
In the diagram AC^B=90∘A\hat{C}B = 90^\circ, CB^D=40∘C\hat{B}D = 40^\circ and BC = 8 cm, with E on AC. Calculate EC, in centimetres.

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Question 804

[3 marks]Trigonometry, Bearing & Distances
In the diagram BC^D=125∘B\hat{C}D = 125^\circ, CB^D=40∘C\hat{B}D = 40^\circ and CD = 10 cm. Calculate BD, in centimetres.

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Question 805

[2 marks]Trigonometry, Bearing & Distances
In the diagram BC = 8 cm, CD = 10 cm and BC^D=125∘B\hat{C}D = 125^\circ. Calculate the area of triangle BCD, in square centimetres.

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Question 806

[2 marks]Trigonometry, Bearing & Distances
In the diagram CD = 10 cm and the angle between CD and CA is 35∘35^\circ. Calculate the shortest distance from D to AC, in centimetres.

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Question 901

[2 marks]Statistics & Probability
The heights of 50 plants were grouped as 10<h≤1510 < h \le 15 (frequency 10), 15<h≤2015 < h \le 20 (15), 20<h≤3020 < h \le 30 (m), 30<h≤3530 < h \le 35 (2) and 35<h≤5035 < h \le 50 (9). The class 20<h≤3020 < h \le 30 has frequency density 1,4. Find the value of mm.

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Question 902

[2 marks]Statistics & Probability
For 50 plants grouped as 10<h≤1510 < h \le 15 (10 plants), 15<h≤2015 < h \le 20 (15), 20<h≤3020 < h \le 30 (14), 30<h≤3530 < h \le 35 (2) and 35<h≤5035 < h \le 50 (9), what is the modal class?
  1. A35<h≤5035 < h \le 50, because it covers the widest spread of heights in the table
  2. B10<h≤1510 < h \le 15, because it is the class in which the measurements begin
  3. C20<h≤3020 < h \le 30, because 14 plants fall in it, more than in any other class here
  4. D15<h≤2015 < h \le 20, because its bar is the tallest, its frequency density being 3

Question 903

[3 marks]Statistics & Probability
Fifty plants have heights grouped as 10<h≤1510 < h \le 15 (10 plants), 15<h≤2015 < h \le 20 (15), 20<h≤3020 < h \le 30 (14), 30<h≤3530 < h \le 35 (2) and 35<h≤5035 < h \le 50 (9). Calculate an estimate of the mean height, in centimetres.

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Question 904

[2 marks]Statistics & Probability
Of 50 plants, 2 have heights in 30<h≤3530 < h \le 35 and 9 in 35<h≤5035 < h \le 50. Two plants are chosen at random. Calculate the probability that the heights of both are greater than 30 cm.

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Question 905

[3 marks]Statistics & Probability
Grouped heights have classes of different widths. Why is frequency density, rather than frequency, plotted up the vertical axis of a histogram?
  1. ABecause dividing by the class width brings every bar down to the same height on the page
  2. BBecause the area of each bar then shows the frequency, so wide and narrow classes compare fairly
  3. CBecause frequency density gives the average height in each class, which is what a bar shows
  4. DBecause the height of each bar then shows the frequency, whatever width the class happens to have

Question 1001

[2 marks]Geometrical Transformation
Triangle ABC has A(−1;3)A(-1; 3), B(−2;2)B(-2; 2) and C(−0,5;1,5)C(-0,5; 1,5). It is mapped by a reflection onto triangle A1B1C1A_1B_1C_1 with A1(−1;−1)A_1(-1; -1), B1(−2;0)B_1(-2; 0) and C1(−0,5;0,5)C_1(-0,5; 0,5). Find the equation of the axis of reflection.

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Question 1002

[2 marks]Geometrical Transformation
In the diagram triangle ABC, with A(−1;3)A(-1; 3), B(−2;2)B(-2; 2) and C(−0,5;1,5)C(-0,5; 1,5), is mapped onto triangle A2B2C2A_2B_2C_2, with A2(2;4)A_2(2; 4), B2(1;3)B_2(1; 3) and C2(2,5;2,5)C_2(2,5; 2,5). Describe fully the single transformation.
  1. AA translation by the vector (13)\begin{pmatrix} 1 \\ 3 \end{pmatrix}
  2. BA translation by the vector (−3−1)\begin{pmatrix} -3 \\ -1 \end{pmatrix}
  3. CAn enlargement of scale factor 3 about the point (1;1)(1; 1)
  4. DA translation by the vector (31)\begin{pmatrix} 3 \\ 1 \end{pmatrix}

Question 1003

[2 marks]Geometrical Transformation
Triangle ABC, with A(−1;3)A(-1; 3), B(−2;2)B(-2; 2) and C(−0,5;1,5)C(-0,5; 1,5), is mapped by an enlargement onto triangle A3B3C3A_3B_3C_3, with A3(1;−3)A_3(1; -3), B3(2;−2)B_3(2; -2) and C3(0,5;−1,5)C_3(0,5; -1,5). Find the scale factor of the enlargement.

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Question 1004

[3 marks]Geometrical Transformation
In the diagram triangle ABC, with A(−1;3)A(-1; 3), B(−2;2)B(-2; 2) and C(−0,5;1,5)C(-0,5; 1,5), is mapped onto triangle A4B4C4A_4B_4C_4, with A4(2;3)A_4(2; 3), B4(0;2)B_4(0; 2) and C4(1;1,5)C_4(1; 1,5). Describe fully the single transformation.
  1. AA one way stretch parallel to the xx axis with factor 1
  2. BA rotation of 90∘90^\circ about the origin, then a translation
  3. CA shear with the xx axis invariant and shear factor 1
  4. DA shear with the yy axis invariant and shear factor 1

Question 1005

[3 marks]Geometrical Transformation
The transformation with matrix (−2003)\begin{pmatrix} -2 & 0 \\ 0 & 3 \end{pmatrix} maps A(−1;3)A(-1; 3) onto A5A_5. Calculate the coordinates of A5A_5.

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Question 1101

[2 marks]Inequalities & Linear Programming
A publisher prints xx pocket size copies and yy medium size copies. At most 100 pocket size copies and at least 30 medium size copies are wanted. Which pair of inequalities states this?
  1. Ax≤100x \le 100 and y≥30y \ge 30
  2. Bx≤30x \le 30 and y≥100y \ge 100
  3. Cx≥100x \ge 100 and y≤30y \le 30
  4. Dx<100x < 100 and y>30y > 30

Question 1102

[2 marks]Inequalities & Linear Programming
A publisher prints xx pocket size copies and yy medium size copies. The medium size copies must number at most 35\frac{3}{5} of the pocket size copies. Which inequality states this?
  1. Ay≥35xy \ge \frac{3}{5}x, that is 5y≥3x5y \ge 3x
  2. By≤35xy \le \frac{3}{5}x, that is 5y≤3x5y \le 3x
  3. Cx≤35yx \le \frac{3}{5}y, that is 5x≤3y5x \le 3y
  4. Dy≤53xy \le \frac{5}{3}x, that is 3y≤5x3y \le 5x

Question 1103

[2 marks]Inequalities & Linear Programming
A pocket size copy costs $8,00 to produce and a medium size copy costs $10,00. Calculate the cost, in dollars, of producing 40 pocket size copies and 20 medium size copies.

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Question 1104

[3 marks]Inequalities & Linear Programming
A publisher prints xx pocket size copies and yy medium size copies, subject to x≤100x \le 100, y≥30y \ge 30, 5y≤3x5y \le 3x and 4x+5y≤5004x + 5y \le 500. Find the greatest total number of books, pocket size plus medium size, that can be printed.

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Question 1105

[3 marks]Inequalities & Linear Programming
A publisher works under x≤100x \le 100, y≥30y \ge 30, 5y≤3x5y \le 3x and 4x+5y≤5004x + 5y \le 500. Which of the four conditions plays no part in bounding the region of possible values?
  1. Ax≤100x \le 100, since the cost condition holds xx to 87 at most
  2. By≥30y \ge 30, since the ratio condition already forces yy above 30 anyway
  3. C5y≤3x5y \le 3x, since the cost condition already holds yy below that line
  4. D4x+5y≤5004x + 5y \le 500, since x≤100x \le 100 already limits what can be spent

Question 1201

[2 marks]Measures & Mensuration
A tumbler is a frustum of a cone whose base circle has diameter 4 cm. Taking π\pi to be 227\frac{22}{7}, calculate the circumference of the base circle, in centimetres.

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Question 1202

[2 marks]Measures & Mensuration
A frustum of a cone has base radius 2 cm and top radius 3 cm, with the two circles 12 cm apart. Extending it downwards to the vertex E gives a small cone of height hh cm below the base. Calculate hh, in centimetres.

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Question 1203

[3 marks]Measures & Mensuration
A frustum has base radius 2 cm and top radius 3 cm, cut from a cone of height 36 cm by removing a cone of height 24 cm. Taking π\pi to be 227\frac{22}{7}, calculate the volume of the frustum, in cubic centimetres, to 3 significant figures.

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Question 1204

[2 marks]Measures & Mensuration
A tumbler holds 238,857238,857 cm3^3. Express this volume in litres, to 3 significant figures.

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Question 1205

[3 marks]Measures & Mensuration
The cone of height 36 cm and the small cone of height 24 cm cut from its point are similar. What is the ratio of the volume of the larger to the volume of the smaller?
  1. A3:23 : 2, the ratio of their radii themselves
  2. B9:49 : 4, the square of the ratio of their radii
  3. C36:2436 : 24, the ratio of their vertical heights
  4. D27:827 : 8, the cube of the ratio of their radii

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