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ZIMSEC O Level · 4008/1, 4028/1 · N2007

Mathematics Paper 1 November 2007

Questions
68
Total marks
100
Time allowed
150 min
Syllabus code
4008/1, 4028/1

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Questions
68
Pass mark
41
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]Approximations & Estimations
Express 1548 correct to one significant figure.

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Question 102

[1 marks]Approximations & Estimations
Express 1548 correct to the nearest ten.

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Question 103

[1 marks]Approximations & Estimations
Express 0,00349 correct to 3 decimal places.

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Question 201

[1 marks]Fractions, Decimals & Percentages
Write down 1340\frac{13}{40} as decimal fraction.

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Question 202

[1 marks]Ordinary & Standard Form
Write down 4 850×10−14\ 850 \times 10^{-1} in standard form.

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Question 203

[1 marks]Consumer Arithmetic
John works 461246\frac{1}{2} hours per week and is paid $5 000\$5\ 000 per hour. Find John's weekly wage, in dollars.

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Question 301

[3 marks]Simultaneous Equations
Solve the simultaneous equations x=12yx = \frac{1}{2}y and 3x−y=73x - y = 7. Give both values, as xx then yy.

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Question 401

[1 marks]Ratios, Rates & Proportions
Peter, John and Sekai share some money in the ratio 2 : 3 : 5 respectively. Express Peter's share as a fraction of John's share.

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Question 402

[2 marks]Ratios, Rates & Proportions
Peter, John and Sekai share some money in the ratio 2 : 3 : 5 respectively. Sekai received $24 000\$24\ 000. Calculate the total amount shared, in dollars.

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Question 501

[2 marks]Geometrical Transformation
In the diagram ABCD is a kite in which AB=5AB = 5 cm, BC=12BC = 12 cm and AB^C=90∘A\hat{B}C = 90^\circ. Triangle ABC is the image of triangle ADC under a single transformation. Describe fully the single transformation.

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Question 502

[1 marks]Measures & Mensuration
In the diagram ABCD is a kite in which AB=5AB = 5 cm, BC=12BC = 12 cm and AB^C=90∘A\hat{B}C = 90^\circ, and triangle ABC is the image of triangle ADC under a reflection. Calculate the area of the kite, in cm2\text{cm}^2.

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Question 601

[1 marks]Fractions, Decimals & Percentages
Giving your answer as a common fraction in its lowest terms, find the value of 316×3,2\frac{3}{16} \times 3,2.

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Question 602

[2 marks]Algebraic Fractions
Find the value of xx given that 1x=512+34\frac{1}{x} = \frac{5}{12} + \frac{3}{4}.

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Question 701

[3 marks]Fractions, Decimals & Percentages
Simplify 134+2×710÷2−2\dfrac{1\frac{3}{4} + 2 \times 7}{10 \div 2 - 2}.

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Question 801

[1 marks]Laws of Indices
Evaluate 25−1×52×1251325^{-1} \times 5^{2} \times 125^{\frac{1}{3}}.

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Question 802

[2 marks]Laws of Indices
Solve the equation 6x−3=486x^{-3} = 48.

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Question 901

[1 marks]Points, Lines & Angles
In the diagram, BCD is a straight line, AB^C=65∘A\hat{B}C = 65^\circ and BA^C=75∘B\hat{A}C = 75^\circ. Calculate AC^DA\hat{C}D.

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Question 902

[1 marks]Points, Lines & Angles
In the diagram, BCD is a straight line, AB^C=65∘A\hat{B}C = 65^\circ and BA^C=75∘B\hat{A}C = 75^\circ. Calculate AC^BA\hat{C}B.

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Question 903

[1 marks]Points, Lines & Angles
In the diagram, BCD is a straight line, AB^C=65∘A\hat{B}C = 65^\circ and BA^C=75∘B\hat{A}C = 75^\circ. Calculate reflex BA^CB\hat{A}C.

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Question 1001

[1 marks]Measures & Mensuration
In the diagram EC is parallel to AB and AE is parallel to BD. The perpendicular distance between AB and EC is 6 cm and the area of parallelogram ABDE is 45 cm245\ \text{cm}^2. Find the length of ED, in cm.

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Question 1002

[2 marks]Measures & Mensuration
In the diagram EC is parallel to AB and AE is parallel to BD. The perpendicular distance between AB and EC is 6 cm and the area of parallelogram ABDE is 45 cm245\ \text{cm}^2. Find the area of triangle ABC, in cm2\text{cm}^2.

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Question 1101

[1 marks]Fractions, Decimals & Percentages
Express 1712%17\frac{1}{2}\% as a common fraction in its lowest terms.

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Question 1102

[2 marks]Algebraic Fractions
Express x2−x−12\frac{x}{2} - \frac{x-1}{2} as a single fraction.

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Question 1201

[1 marks]Trigonometry, Bearing & Distances
A, B, C and P are four points on level ground. The bearing of C from B is 160∘160^\circ. P is due north of A and AB^C=90∘A\hat{B}C = 90^\circ. Calculate PA^BP\hat{A}B.

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Question 1202

[2 marks]Trigonometry, Bearing & Distances
A, B, C and P are four points on level ground. The bearing of C from B is 160∘160^\circ. P is due north of A and AB^C=90∘A\hat{B}C = 90^\circ. Find the three-figure bearing of B from C.

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Question 1301

[1 marks]Inequalities & Linear Programming
The diagram shows the unshaded region R, bounded by the broken line y=3xy = 3x, the line x+y=4x + y = 4 and the xx-axis. The three lines meet at O(0;0)O(0; 0), (1;3)(1; 3) and (4;0)(4; 0). Write down the one of the 3 inequalities defining R which involves yy and 3x3x.

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Question 1302

[1 marks]Inequalities & Linear Programming
The diagram shows the unshaded region R, bounded by the broken line y=3xy = 3x, the line x+y=4x + y = 4 and the xx-axis. The three lines meet at O(0;0)O(0; 0), (1;3)(1; 3) and (4;0)(4; 0). Write down the one of the 3 inequalities defining R which involves x+yx + y.

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Question 1303

[1 marks]Inequalities & Linear Programming
The diagram shows the unshaded region R, bounded by the broken line y=3xy = 3x, the line x+y=4x + y = 4 and the xx-axis. The three lines meet at O(0;0)O(0; 0), (1;3)(1; 3) and (4;0)(4; 0). Write down the one of the 3 inequalities defining R which involves yy alone.

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Question 1401

[1 marks]Measures & Mensuration
The diagram shows a right-angled triangle with perpendicular sides xx and yy and hypotenuse zz. Use the diagram to write down Pythagoras Theorem in terms of xx, yy and zz.

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Question 1402

[2 marks]Rational, Irrational Numbers & Surds
An equilateral triangle is of side 18 cm. Calculate the length of its altitude leaving your answer in surd form, in cm.

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Question 1501

[1 marks]Statistics & Probability
The pie chart shows professionals in town A. The Teachers sector is 150∘150^\circ, the Doctors sector is x∘x^\circ and the Lawyers sector is 2x∘2x^\circ. Calculate the value of xx.

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Question 1502

[2 marks]Statistics & Probability
The pie chart shows professionals in town A. The Teachers sector is 150∘150^\circ, the Doctors sector is x∘x^\circ and the Lawyers sector is 2x∘2x^\circ. Given that there are 900 teachers in the town, find the number of doctors.

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Question 1601

[1 marks]Prime Numbers, Sequences & Types of Numbers
The table shows a difference pattern. The top row reads 4, 7, 12, 20, pp; the second row reads 3, 5, 8, nn; the third row reads 2, 3, mm, qq; and the bottom row reads 1, 1, 1. Each row is the row of differences of the row above it. Write the value of mm.

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Question 1602

[1 marks]Prime Numbers, Sequences & Types of Numbers
The table shows a difference pattern. The top row reads 4, 7, 12, 20, pp; the second row reads 3, 5, 8, nn; the third row reads 2, 3, mm, qq; and the bottom row reads 1, 1, 1. Each row is the row of differences of the row above it. Write the value of nn.

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Question 1603

[1 marks]Prime Numbers, Sequences & Types of Numbers
The table shows a difference pattern. The top row reads 4, 7, 12, 20, pp; the second row reads 3, 5, 8, nn; the third row reads 2, 3, mm, qq; and the bottom row reads 1, 1, 1. Each row is the row of differences of the row above it. Write the value of pp.

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Question 1604

[1 marks]Prime Numbers, Sequences & Types of Numbers
The table shows a difference pattern. The top row reads 4, 7, 12, 20, pp; the second row reads 3, 5, 8, nn; the third row reads 2, 3, mm, qq; and the bottom row reads 1, 1, 1. Each row is the row of differences of the row above it. Write the value of qq.

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Question 1701

[2 marks]Algebraic Expressions
Factorise completely 4t2−36b24t^{2} - 36b^{2}.

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Question 1702

[2 marks]Linear Equations
Solve the equation p+2=5−4(p+2)p + 2 = 5 - 4(p + 2).

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Question 1801

[1 marks]Matrices
It is given that P=(53−12)P = \begin{pmatrix} 5 & 3 \\ -1 & 2 \end{pmatrix}, Q=(−224−3)Q = \begin{pmatrix} -2 & 2 \\ 4 & -3 \end{pmatrix} and R=(2−1)R = \begin{pmatrix} 2 \\ -1 \end{pmatrix}. Write down the order of matrix RR.

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Question 1802

[1 marks]Matrices
It is given that P=(53−12)P = \begin{pmatrix} 5 & 3 \\ -1 & 2 \end{pmatrix}, Q=(−224−3)Q = \begin{pmatrix} -2 & 2 \\ 4 & -3 \end{pmatrix} and R=(2−1)R = \begin{pmatrix} 2 \\ -1 \end{pmatrix}. Find P+QP + Q.

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Question 1803

[2 marks]Matrices
It is given that P=(53−12)P = \begin{pmatrix} 5 & 3 \\ -1 & 2 \end{pmatrix}, Q=(−224−3)Q = \begin{pmatrix} -2 & 2 \\ 4 & -3 \end{pmatrix} and R=(2−1)R = \begin{pmatrix} 2 \\ -1 \end{pmatrix}. Find QRQR.

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Question 1901

[1 marks]Approximations & Estimations
Estimate the value of 4003251×410\frac{40032}{51 \times 410} correct to one significant figure.

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Question 1902

[1 marks]Approximations & Estimations
Given that 4≤a≤84 \le a \le 8, 3≤b≤53 \le b \le 5 and 7≤c≤97 \le c \le 9, find the maximum value of c−bc - b.

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Question 1903

[2 marks]Approximations & Estimations
Given that 4≤a≤84 \le a \le 8, 3≤b≤53 \le b \le 5 and 7≤c≤97 \le c \le 9, find the minimum value of c+ab\frac{c + a}{b}.

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Question 2001

[1 marks]Statistics & Probability
The numbers 4; 7; 8; kk; 10; 11; 14; 18 are in ascending order. Given that the mode is 8, find the value of kk.

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Question 2002

[1 marks]Statistics & Probability
The numbers 4; 7; 8; 8; 10; 11; 14; 18 are in ascending order. Find the median.

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Question 2003

[2 marks]Statistics & Probability
The numbers 4; 7; 8; 8; 10; 11; 14; 18 are in ascending order. Find the mean.

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Question 2101

[1 marks]Inequalities & Linear Programming
Solve the inequality 10−2y<410 - 2y < 4.

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Question 2102

[3 marks]Quadratic Equations
Solve the equation (2x−3)2=49(2x - 3)^{2} = 49. Give both values of xx.

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Question 2201

[1 marks]Measures & Mensuration
In the diagram, ABCD is a square of side 7 cm APCB and AQCD are quadrants of circles of centres B and D respectively. The shaded part is the region common to the two quadrants. Use π=317\pi = 3\frac{1}{7}. Calculate the perimeter of the shaded part, in cm.

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Question 2202

[3 marks]Measures & Mensuration
In the diagram, ABCD is a square of side 7 cm APCB and AQCD are quadrants of circles of centres B and D respectively. The shaded part is the region common to the two quadrants. Use π=317\pi = 3\frac{1}{7}. Calculate the area of the shaded part, in cm2\text{cm}^2.

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Question 2301

[1 marks]Polygons, Symmetry & Circles
A, B, C and D are points on the circumference of the circle centre O. AD is a diameter and CO is parallel to BA. It is given that CB^D=28∘C\hat{B}D = 28^\circ. Calculate CO^DC\hat{O}D.

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Question 2302

[1 marks]Polygons, Symmetry & Circles
A, B, C and D are points on the circumference of the circle centre O. AD is a diameter and CO is parallel to BA. It is given that CB^D=28∘C\hat{B}D = 28^\circ. Calculate BA^DB\hat{A}D.

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Question 2303

[1 marks]Polygons, Symmetry & Circles
A, B, C and D are points on the circumference of the circle centre O. AD is a diameter and CO is parallel to BA. It is given that CB^D=28∘C\hat{B}D = 28^\circ. Calculate BD^CB\hat{D}C.

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Question 2304

[2 marks]Polygons, Symmetry & Circles
A, B, C and D are points on the circumference of the circle centre O. AD is a diameter and CO is parallel to BA. It is given that CB^D=28∘C\hat{B}D = 28^\circ. Calculate BO^CB\hat{O}C.

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Question 2401

[1 marks]Travel Graphs
The diagram shows the velocity-time graph of a moving object. The velocity rises in a straight line from 5 m/s at t=0t = 0 to 15 m/s at t=4t = 4 s, stays at 15 m/s until t=10t = 10 s, then falls in a straight line to 0 at t=15t = 15 s. Write down the initial velocity of the object, in m/s.

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Question 2402

[1 marks]Travel Graphs
The diagram shows the velocity-time graph of a moving object. The velocity rises in a straight line from 5 m/s at t=0t = 0 to 15 m/s at t=4t = 4 s, stays at 15 m/s until t=10t = 10 s, then falls in a straight line to 0 at t=15t = 15 s. Find the duration when the acceleration of the object was zero, in seconds.

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Question 2403

[3 marks]Travel Graphs
The diagram shows the velocity-time graph of a moving object. The velocity rises in a straight line from 5 m/s at t=0t = 0 to 15 m/s at t=4t = 4 s, stays at 15 m/s until t=10t = 10 s, then falls in a straight line to 0 at t=15t = 15 s. Calculate the total distance travelled by the object, in m.

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Question 2501

[2 marks]Change of Units
Convert 2 500 cm22\ 500\ \text{cm}^2 to m2\text{m}^2.

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Question 2502

[1 marks]Similarity & Congruency
Two similar cylindrical mugs have their volumes in the ratio 8 : 27. Write down the ratio of their heights.

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Question 2503

[2 marks]Similarity & Congruency
Two similar cylindrical mugs have their volumes in the ratio 8 : 27, so their heights are in the ratio 2 : 3. The total surface area of the larger mug is 63 cm263\ \text{cm}^2. Calculate the total surface area of the smaller mug, in cm2\text{cm}^2.

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Question 2601

[1 marks]Trigonometry, Bearing & Distances
In the diagram, AB^C=θA\hat{B}C = \theta, BC=17BC = 17 cm, CD=15CD = 15 cm, BD^C=90∘B\hat{D}C = 90^\circ and ABD is a straight line, so θ\theta is obtuse. Calculate BD, in cm.

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Question 2602

[1 marks]Trigonometry, Bearing & Distances
In the diagram, AB^C=θA\hat{B}C = \theta, BC=17BC = 17 cm, CD=15CD = 15 cm, BD^C=90∘B\hat{D}C = 90^\circ and ABD is a straight line, so θ\theta is obtuse. Write down, as a common fraction, the value of sin⁡θ\sin\theta.

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Question 2603

[2 marks]Trigonometry, Bearing & Distances
In the diagram, AB^C=θA\hat{B}C = \theta, BC=17BC = 17 cm, CD=15CD = 15 cm, BD^C=90∘B\hat{D}C = 90^\circ and ABD is a straight line, so θ\theta is obtuse. Write down, as a common fraction, the value of cos⁡θ\cos\theta.

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Question 2604

[2 marks]Trigonometry, Bearing & Distances
In the diagram, AB^C=θA\hat{B}C = \theta, BC=17BC = 17 cm, CD=15CD = 15 cm, BD^C=90∘B\hat{D}C = 90^\circ and ABD is a straight line, so θ\theta is obtuse. Write down, as a common fraction, the value of tan⁡θ\tan\theta.

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Question 2701

[2 marks]Trigonometry, Bearing & Distances
In the diagram, ADC is a straight line, AD=8AD = 8 cm, BD=6BD = 6 cm, BC=9BC = 9 cm and BD^C=60∘B\hat{D}C = 60^\circ. Use sin⁡60∘=0,866\sin 60^\circ = 0,866, cos⁡60∘=0,5\cos 60^\circ = 0,5 and tan⁡60∘=1,73\tan 60^\circ = 1,73 as necessary. Calculate AB2AB^{2}.

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Question 2702

[2 marks]Trigonometry, Bearing & Distances
In the diagram, ADC is a straight line, AD=8AD = 8 cm, BD=6BD = 6 cm, BC=9BC = 9 cm and BD^C=60∘B\hat{D}C = 60^\circ. Use sin⁡60∘=0,866\sin 60^\circ = 0,866, cos⁡60∘=0,5\cos 60^\circ = 0,5 and tan⁡60∘=1,73\tan 60^\circ = 1,73 as necessary. Calculate sin⁡BC^D\sin B\hat{C}D, giving your answer correct 3 to decimal places.

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Question 2703

[2 marks]Trigonometry, Bearing & Distances
In the diagram, ADC is a straight line, AD=8AD = 8 cm, BD=6BD = 6 cm, BC=9BC = 9 cm and BD^C=60∘B\hat{D}C = 60^\circ. Use sin⁡60∘=0,866\sin 60^\circ = 0,866, cos⁡60∘=0,5\cos 60^\circ = 0,5 and tan⁡60∘=1,73\tan 60^\circ = 1,73 as necessary. Calculate the area of triangle ABD, in cm2\text{cm}^2.

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