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ZIMSEC O Level · 4004/1 · J2023

Mathematics Paper 1 June 2023

Questions
64
Total marks
100
Time allowed
150 min
Syllabus code
4004/1

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Questions
64
Pass mark
39
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]Approximations & Estimations
Express 54,497 correct to the nearest tenth.

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Question 102

[1 marks]Ordinary & Standard Form
Express 0,000342 in standard form.

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Question 103

[1 marks]Approximations & Estimations
Express 478,367 correct to two significant figures.

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Question 201

[1 marks]Fractions, Decimals & Percentages
Simplify 27+13\dfrac{2}{7} + \dfrac{1}{3}, giving the answer as a common fraction in its lowest terms.

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Question 202

[1 marks]Fractions, Decimals & Percentages
Simplify 25÷10\dfrac{2}{5} \div 10, giving the answer as a common fraction in its lowest terms.

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Question 203

[1 marks]Fractions, Decimals & Percentages
Simplify 1835×1427\dfrac{18}{35} \times \dfrac{14}{27}, giving the answer as a common fraction in its lowest terms.

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Question 301

[1 marks]Fractions, Decimals & Percentages
Evaluate 0,024×0,30,024 \times 0,3, giving the answer as an exact decimal.

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Question 302

[1 marks]Fractions, Decimals & Percentages
Evaluate (0,4)3(0,4)^3, giving the answer as an exact decimal.

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Question 303

[1 marks]Fractions, Decimals & Percentages
Express 0,224 as a percentage.

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Question 401

[1 marks]Sets
The universal set is ξ={75;76;77;78;79;80}\xi = \{75; 76; 77; 78; 79; 80\} and M is the set of even numbers in ξ\xi. List the elements of set M.

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Question 402

[1 marks]Sets
The universal set is ξ={75;76;77;78;79;80}\xi = \{75; 76; 77; 78; 79; 80\} and R is the set of multiples of 4 in ξ\xi. List the elements of set R.

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Question 403

[1 marks]Sets
The universal set is ξ={75;76;77;78;79;80}\xi = \{75; 76; 77; 78; 79; 80\}, M={76;78;80}M = \{76; 78; 80\} and R={76;80}R = \{76; 80\}. Find n(M′∪R)n(M' \cup R).

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Question 501

[1 marks]Algebraic Expressions
Simplify 2(a−2)−4(a+3)2(a - 2) - 4(a + 3).

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Question 502

[2 marks]Algebraic Fractions
Express 3m−2−24m+3\dfrac{3}{m-2} - \dfrac{2}{4m+3} as a single fraction.

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Question 601

[1 marks]Polygons, Symmetry & Circles
State the special name of a quadrilateral with four lines of symmetry.

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Question 602

[2 marks]Polygons, Symmetry & Circles
A quadrilateral has interior angles of x°x°, 2x°2x°, (x+10)°(x + 10)° and (x+50)°(x + 50)°. Calculate the value of xx.

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Question 701

[2 marks]Variation
PP varies directly as the cube of rr. Given that P=2P = 2 when r=4r = 4, find the formula connecting PP and rr.

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Question 702

[1 marks]Variation
Given that P=r332P = \dfrac{r^3}{32}, find the value of PP when r=8r = 8.

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Question 801

[1 marks]Factorisation, H.C.F & L.C.M
Given that m+3n=5m + 3n = 5 and m2−9n2=−15m^2 - 9n^2 = -15, find the numerical value of m−3nm - 3n.

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Question 802

[2 marks]Simultaneous Equations
Given that m+3n=5m + 3n = 5 and m−3n=−3m - 3n = -3, find the numerical values of mm and nn.

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Question 901

[2 marks]Change of Subject of Formula
Given that p=qq+mp = \dfrac{q}{q+m}, make mm the subject of the formula.

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Question 902

[1 marks]Substitution
Given that m=q(1−p)pm = \dfrac{q(1-p)}{p}, find mm when q=3q = 3 and p=2p = 2.

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Question 1001

[1 marks]Circle Geometry
In the diagram, Q, S and R are on the circumference of a circle centre O and PQT is a tangent to the circle at Q. PQ^S=m°P\hat{Q}S = m°, OQ^S=n°O\hat{Q}S = n°, QO^R=p°Q\hat{O}R = p°, QS^R=70°Q\hat{S}R = 70° and OR^S=25°O\hat{R}S = 25°. Calculate the value of mm.

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Question 1002

[1 marks]Circle Geometry
In the diagram, Q, S and R are on the circumference of a circle centre O and PQT is a tangent to the circle at Q. PQ^S=m°P\hat{Q}S = m°, OQ^S=n°O\hat{Q}S = n°, QO^R=p°Q\hat{O}R = p°, QS^R=70°Q\hat{S}R = 70° and OR^S=25°O\hat{R}S = 25°. Calculate the value of nn.

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Question 1003

[1 marks]Circle Geometry
In the diagram, Q, S and R are on the circumference of a circle centre O and PQT is a tangent to the circle at Q. PQ^S=m°P\hat{Q}S = m°, OQ^S=n°O\hat{Q}S = n°, QO^R=p°Q\hat{O}R = p°, QS^R=70°Q\hat{S}R = 70° and OR^S=25°O\hat{R}S = 25°. Calculate the value of pp.

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Question 1101

[1 marks]Number Bases
Evaluate 7669+1439766_9 + 143_9, giving the answer in base 9.

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Question 1102

[2 marks]Number Bases
Convert 35635_6 to a number in base 2.

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Question 1103

[1 marks]Functional Notation
Given that f(x)=(4−x)(x−0,5)f(x) = (4 - x)(x - 0,5), find f(0)f(0).

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Question 1201

[1 marks]Inequalities & Linear Programming
In the diagram, the unshaded region R is bounded on the left by the solid vertical line through x=1x = 1. Write down the inequality whose boundary is that line.

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Question 1202

[1 marks]Inequalities & Linear Programming
In the diagram, the unshaded region R is bounded below by the solid horizontal line through y=2y = 2. Write down the inequality whose boundary is that line.

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Question 1203

[2 marks]Inequalities & Linear Programming
In the diagram, the unshaded region R is bounded above by the solid line through (0;6)(0; 6) and (6;0)(6; 0). Write down the inequality whose boundary is that line.

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Question 1301

[1 marks]Similarity & Congruency
Two similar cylinders have heights of 16 cm and 48 cm. Write down, in its simplest form, the ratio of their heights.

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Question 1302

[1 marks]Similarity & Congruency
Two similar cylinders have heights of 16 cm and 48 cm. Write down, in its simplest form, the ratio of their volumes.

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Question 1303

[2 marks]Similarity & Congruency
Two similar cylinders have heights of 16 cm and 48 cm. The curved surface area of the larger cylinder is 500 cm2500\ \text{cm}^2. Calculate the curved surface area, in square centimetres, of the smaller cylinder.

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Question 1401

[2 marks]Ratios, Rates & Proportions
A sum of money is shared in the ratio 2 : 3 : 4. The smallest share is $160,00. Calculate the total amount of money shared.

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Question 1402

[2 marks]Consumer Arithmetic
Find the time, in years, taken for $4 000,00 to earn a simple interest of $400,00 at a rate of 5% per annum.

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Question 1501

[2 marks]Linear Equations
Solve the equation 3(x−2)=5x+33(x - 2) = 5x + 3.

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Question 1502

[2 marks]Quadratic Equations
Solve the equation (q−29)2=4981\left(q - \dfrac{2}{9}\right)^2 = \dfrac{49}{81}.

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Question 1601

[3 marks]Approximations & Estimations
Evaluate 0,0469×2,132,28+3,83×2,06\dfrac{0,0469 \times 2,13}{2,28 + 3,83 \times 2,06} by first estimating each number to one significant figure.

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Question 1602

[2 marks]Laws of Indices
Solve the equation 27=32d+127 = 3^{2d+1}.

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Question 1701

[1 marks]Vector Geometry
Points EE, FF and GG have coordinates (4;8)(4; 8), (−4;0)(-4; 0) and (−6;4)(-6; 4) respectively. Express EF⃗\vec{EF} as a column vector.

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Question 1702

[1 marks]Vector Geometry
Points FF and GG have coordinates (−4;0)(-4; 0) and (−6;4)(-6; 4) respectively. Express −12GF⃗-\dfrac{1}{2}\vec{GF} as a column vector.

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Question 1703

[1 marks]Vector Geometry
Points EE, FF and GG have coordinates (4;8)(4; 8), (−4;0)(-4; 0) and (−6;4)(-6; 4) respectively. Express EF⃗+FG⃗\vec{EF} + \vec{FG} as a column vector.

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Question 1704

[2 marks]Vector Geometry
The point EE has coordinates (4;8)(4; 8) and O is the origin. Find ∣OE⃗∣\left|\vec{OE}\right|, leaving the answer in surd form.

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Question 1801

[2 marks]Change of Units
Convert 2 g/cm32\ \text{g/cm}^3 to kg/m3\text{kg/m}^3.

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Question 1802

[1 marks]Scales & Simple Map Problems
A map of a town is drawn to a scale of 1 cm to 9,5 km. Calculate the actual length, in kilometres, of a road that is 3 cm long on the map.

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Question 1803

[2 marks]Scales & Simple Map Problems
A map of a town is drawn to a scale of 1 cm to 9,5 km. Calculate the area, in square centimetres, on the map of a town that has an actual area of 361 km2361\ \text{km}^2.

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Question 1901

[1 marks]Trigonometry, Bearing & Distances
Village A is on a bearing of 092° from village B. Calculate the three figure bearing of village B from village A.

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Question 1902

[2 marks]Measures & Mensuration
OPQ is a sector with centre O and radius 9 cm, and PO^Q=84°P\hat{O}Q = 84°. Taking π\pi to be 227\frac{22}{7}, calculate the length, in centimetres, of arc PQ.

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Question 1903

[2 marks]Measures & Mensuration
OPQ is a sector with centre O and radius 9 cm, and PO^Q=84°P\hat{O}Q = 84°. Taking π\pi to be 227\frac{22}{7}, calculate the area, in square centimetres, of the sector OPQ.

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Question 2001

[1 marks]Statistics & Probability
A table shows the enrollment at a certain school: Form 1 has 128 learners, Form 2 has 127, Form 3 has 125 and Form 4 has 120. State the modal form.

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Question 2002

[2 marks]Statistics & Probability
A table shows the enrollment at a certain school: Form 1 has 128 learners, Form 2 has 127, Form 3 has 125 and Form 4 has 120. Calculate the mean number of learners per form.

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Question 2003

[2 marks]Statistics & Probability
A school has 500 learners, of whom 125 are in form 3. Two learners are chosen at random from the school. Calculate the probability that both learners are in form 3.

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Question 2101

[1 marks]Similarity & Congruency
In the diagram, XDF and YEG are two straight lines which intersect at O, and XY, ED and GF are parallel lines with OX=OD=7OX = OD = 7 cm and DF=3DF = 3 cm. Name, in correct order, the triangle which is similar but not congruent to triangle XOY.

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Question 2102

[1 marks]Similarity & Congruency
In the diagram, XDF and YEG are two straight lines which intersect at O, and XY, ED and GF are parallel lines with OX=OD=7OX = OD = 7 cm and DF=3DF = 3 cm. Name, in correct order, the triangle which is congruent to triangle XOY.

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Question 2103

[3 marks]Similarity & Congruency
In the diagram, XDF and YEG are two straight lines which intersect at O, and XY, ED and GF are parallel lines with OX=OD=7OX = OD = 7 cm, DF=3DF = 3 cm, ED=(x+2)ED = (x + 2) cm and GF=(2x−4)GF = (2x - 4) cm. Calculate the length of FG, in centimetres.

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Question 2201

[3 marks]Matrices
Matrix M=(5−3−22)M = \begin{pmatrix} 5 & -3 \\ -2 & 2 \end{pmatrix}. Find M−1M^{-1}, the inverse of matrix M.

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Question 2202

[3 marks]Matrices
Matrix N=(y2632)N = \begin{pmatrix} y^2 & 6 \\ 3 & 2 \end{pmatrix} is singular. Find the possible values of yy.

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Question 2301

[1 marks]Trigonometry, Bearing & Distances
In the diagram, PQRS is a trapezium with PS parallel to QR, PQ^R=PR^S=90°P\hat{Q}R = P\hat{R}S = 90°, PQ=24PQ = 24 cm, QR=32QR = 32 cm and PR=40PR = 40 cm. Express tan⁡RP^S\tan R\hat{P}S as a fraction in its lowest terms.

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Question 2302

[2 marks]Trigonometry, Bearing & Distances
In the diagram, PQRS is a trapezium with PS parallel to QR, PQ^R=PR^S=90°P\hat{Q}R = P\hat{R}S = 90°, PQ=24PQ = 24 cm, QR=32QR = 32 cm and PR=40PR = 40 cm. Calculate the length of RS, in centimetres.

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Question 2303

[2 marks]Measures & Mensuration
In the diagram, PQRS is a trapezium with PS parallel to QR, PQ^R=PR^S=90°P\hat{Q}R = P\hat{R}S = 90°, PQ=24PQ = 24 cm, QR=32QR = 32 cm, PR=40PR = 40 cm and RS=30RS = 30 cm. Calculate the area, in square centimetres, of trapezium PQRS.

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Question 2401

[3 marks]Geometrical Transformation
Triangle X has vertices (2;2)(2; 2), (4;2)(4; 2) and (4;3)(4; 3). Triangle A is the image of triangle X under a translation of (−23)\begin{pmatrix} -2 \\ 3 \end{pmatrix}. Write down the vertices of triangle A.

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Question 2402

[3 marks]Geometrical Transformation
Triangle X has vertices (2;2)(2; 2), (4;2)(4; 2) and (4;3)(4; 3). Triangle B is the image of triangle X under a rotation of 180° with centre Q(4;4)Q(4; 4). Write down the vertices of triangle B.

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Question 2403

[3 marks]Geometrical Transformation
Triangle X has vertices (2;2)(2; 2), (4;2)(4; 2) and (4;3)(4; 3), and triangle C has vertices (−4;2)(-4; 2), (−2;2)(-2; 2) and (−5;3)(-5; 3). Describe fully the single transformation which maps triangle X onto triangle C.

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