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ZIMSEC O Level · 4008/1 · J2014

Mathematics Paper 1 June 2014

Questions
61
Total marks
96
Time allowed
150 min
Syllabus code
4008/1

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Questions
61
Pass mark
37
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]Approximations & Estimations
Express 2046,489 correct to the nearest ten.

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Question 102

[1 marks]Approximations & Estimations
Express 2046,489 correct to 2 decimal places.

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Question 103

[1 marks]Approximations & Estimations
Express 2046,489 correct to 2 significant figures.

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Question 201

[1 marks]Fractions, Decimals & Percentages
Evaluate 35+17\frac{3}{5} + \frac{1}{7}, giving your answer as a common fraction in its lowest terms.

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Question 202

[1 marks]Fractions, Decimals & Percentages
Evaluate 58×3245\frac{5}{8} \times \frac{32}{45}, giving your answer as a common fraction in its lowest terms.

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Question 203

[1 marks]Fractions, Decimals & Percentages
Evaluate 524÷13\frac{5}{24} \div \frac{1}{3}, giving your answer as a common fraction in its lowest terms.

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Question 301

[1 marks]Fractions, Decimals & Percentages
Giving your answer as a decimal, find the exact value of 0,175−0,0490,175 - 0,049.

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Question 302

[1 marks]Fractions, Decimals & Percentages
Giving your answer as a decimal, find the exact value of 0,0144\sqrt{0,0144}.

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Question 303

[1 marks]Fractions, Decimals & Percentages
Giving your answer as a decimal, find the exact value of (0,06)2(0,06)^2.

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Question 401

[2 marks]Algebraic Expressions
Expand (2a−b)(1+c)(2a - b)(1 + c).

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Question 402

[1 marks]Algebraic Fractions
Simplify m2−mnn2−np÷m(n−p)\dfrac{m^2 - mn}{n^2 - np} \div \dfrac{m}{(n - p)}.

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Question 501

[1 marks]Sets
It is given that ξ={30;31;32;33;34;35;36;37;38;39}\xi = \{30; 31; 32; 33; 34; 35; 36; 37; 38; 39\}, A is the set of odd numbers and B is the set of prime numbers. List the elements of A.

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Question 502

[1 marks]Sets
It is given that ξ={30;31;32;33;34;35;36;37;38;39}\xi = \{30; 31; 32; 33; 34; 35; 36; 37; 38; 39\}, A is the set of odd numbers and B is the set of prime numbers. List the elements of B1B^1 (the complement of B).

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Question 503

[1 marks]Sets
It is given that ξ={30;31;32;33;34;35;36;37;38;39}\xi = \{30; 31; 32; 33; 34; 35; 36; 37; 38; 39\}, A is the set of odd numbers and B is the set of prime numbers. Find n(A∩B1)n(A \cap B^1).

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Question 601

[1 marks]Symmetry
State the special type of a triangle which has one line of symmetry.

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Question 602

[2 marks]Polygons, Symmetry & Circles
A polygon has nn sides. Two of its exterior angles are 55∘55^\circ and 45∘45^\circ. The remaining (n−2)(n - 2) exterior angles are each 20∘20^\circ. Calculate the value of nn.

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Question 701

[1 marks]Time
Express 9 minutes after midnight as time on the 24 hour clock.

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Question 702

[2 marks]Fractions, Decimals & Percentages
In 1998 the population of a village was 2,8×1022,8 \times 10^2. In 2004, the population was 3,5×1023,5 \times 10^2. Calculate the percentage increase of the population from 1998 to 2004.

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Question 801

[3 marks]Simultaneous Equations
Solve the simultaneous equations 13x=y\frac{1}{3}x = y and 2x+y=−72x + y = -7.

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Question 901

[1 marks]Functional Notation
Given that f(x)=(x−1)(x+6)f(x) = (x - 1)(x + 6) and that f(0)=pf(0) = p, find the value of pp.

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Question 902

[2 marks]Change of Subject of Formula
If yk=ax−bkyk = ax - bk, make kk the subject of the formula.

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Question 1001

[1 marks]Number Bases
Express 34+32+33^4 + 3^2 + 3 as a number in base 3.

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Question 1002

[1 marks]Number Bases
Evaluate 1438+578143_8 + 57_8, giving your answer in base 8.

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Question 1003

[1 marks]Number Bases
Evaluate 45−23+124_5 - 2_3 + 1_2, giving your answer in base 10.

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Question 1101

[1 marks]Circle Geometry
In the diagram, ABCD is a circle. Tangents at C and D meet at E and ED is produced to F such that AD^F=50∘A\hat{D}F = 50^\circ and AB^C=116∘A\hat{B}C = 116^\circ. Calculate AD^CA\hat{D}C.

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Question 1102

[1 marks]Circle Geometry
In the diagram, ABCD is a circle. Tangents at C and D meet at E and ED is produced to F such that AD^F=50∘A\hat{D}F = 50^\circ and AB^C=116∘A\hat{B}C = 116^\circ. Calculate CD^EC\hat{D}E.

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Question 1103

[1 marks]Circle Geometry
In the diagram, ABCD is a circle. Tangents at C and D meet at E and ED is produced to F such that AD^F=50∘A\hat{D}F = 50^\circ and AB^C=116∘A\hat{B}C = 116^\circ. Calculate CE^DC\hat{E}D.

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Question 1201

[1 marks]Inequalities
The cost of making a telephone call on Teneco is 25 cents per minute. Kuda has pp cents and is able to make a call. Xolani has qq cents which is insufficient to make a call. Write down an inequality in pp, other than p>0p > 0, that satisfies the given conditions.

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Question 1202

[1 marks]Inequalities
The cost of making a telephone call on Teneco is 25 cents per minute. Kuda has pp cents and is able to make a call. Xolani has qq cents which is insufficient to make a call. Write down an inequality in qq, other than q>0q > 0, that satisfies the given conditions.

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Question 1203

[1 marks]Inequalities
The cost of making a telephone call on Teneco is 25 cents per minute. Kuda has pp cents and is able to make a call. Xolani has qq cents which is insufficient to make a call. Write down an inequality relating pp and qq that satisfies the given conditions.

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Question 1301

[1 marks]Co-ordinate Geometry
AB is a line whose equation is 6y=7x+486y = 7x + 48. Find the gradient of line AB.

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Question 1302

[2 marks]Co-ordinate Geometry
AB is a line whose equation is 6y=7x+486y = 7x + 48. Find the equation of the line parallel to AB which passes through the point (3;1)(3; 1), giving your equation in the form ay+bx+c=0ay + bx + c = 0.

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Question 1401

[1 marks]Ratios, Rates & Proportions
Given that 4m=7n4m = 7n, find the ratio m:nm : n.

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Question 1402

[2 marks]Consumer Arithmetic
A holiday trip to South Africa cost R333. If the exchange rate was US$1 to R8, calculate the cost of the trip in US$, giving your answer to the nearest cent.

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Question 1501

[3 marks]Factorisation
Factorise completely 3x3y−12xy33x^3y - 12xy^3.

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Question 1601

[3 marks]Quadratic Equations
Solve the equation (y+14)2=916\left(y + \frac{1}{4}\right)^2 = \frac{9}{16}.

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Question 1701

[2 marks]Laws of Indices
Simplify (32x10)15\left(32x^{10}\right)^{\frac{1}{5}}.

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Question 1702

[2 marks]Laws of Indices
Given that 2−2×2c24=23\dfrac{2^{-2} \times 2^c}{2^4} = 2^3, find the value of cc.

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Question 1801

[2 marks]Matrices
It is given that P=(2111)\mathbf{P} = \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix} and Q=2P−I\mathbf{Q} = 2\mathbf{P} - \mathbf{I} where I\mathbf{I} is the identity matrix. Find P−1\mathbf{P}^{-1}.

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Question 1802

[2 marks]Matrices
It is given that P=(2111)\mathbf{P} = \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix} and Q=2P−I\mathbf{Q} = 2\mathbf{P} - \mathbf{I} where I\mathbf{I} is the identity matrix. Find Q\mathbf{Q}.

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Question 1901

[1 marks]Vectors
In the diagram, OABCDE is a hexagon drawn on a grid, with O at the origin, A at (−2;1)(-2; 1), B at (0;4)(0; 4), C at (2;5)(2; 5), D at (3;3)(3; 3) and E at (2;1)(2; 1). Express OE→\overrightarrow{OE} as a column vector.

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Question 1902

[1 marks]Vectors
In the diagram, OABCDE is a hexagon drawn on a grid, with O at the origin, A at (−2;1)(-2; 1), B at (0;4)(0; 4), C at (2;5)(2; 5), D at (3;3)(3; 3) and E at (2;1)(2; 1). Express OA→+AD→\overrightarrow{OA} + \overrightarrow{AD} as a column vector.

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Question 1903

[2 marks]Vectors
In the diagram, OABCDE is a hexagon drawn on a grid, with O at the origin, A at (−2;1)(-2; 1), B at (0;4)(0; 4), C at (2;5)(2; 5), D at (3;3)(3; 3) and E at (2;1)(2; 1). Describe fully the single transformation which maps side BC onto side OE.

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Question 2001

[1 marks]Scales & Simple Map Problems
All lengths on a map are 1500\frac{1}{500} of their actual lengths. Calculate the actual length of a line represented on the map by a line 7,3 cm.

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Question 2002

[3 marks]Scales & Simple Map Problems
All lengths on a map are 1500\frac{1}{500} of their actual lengths. Calculate the area on the map which represents an actual area of 525 m2\text{m}^2, giving your answer in cm2\text{cm}^2.

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Question 2101

[2 marks]Logarithms
Evaluate log⁡564log⁡54\dfrac{\log_5 64}{\log_5 4}.

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Question 2102

[2 marks]Logarithms
Evaluate 1+log⁡391 + \log_3 9.

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Question 2201

[1 marks]Constructions and Loci
AB is a line segment 7 cm long. P1P_1 and P2P_2 are the two points which are 3 cm from B and 2 cm from line AB, on the same side of AB. Find the distance P1P2P_1P_2, in centimetres.

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Question 2301

[2 marks]Trigonometry, Bearing & Distances
P and Q are points on level ground. The bearing of P from Q is 237∘237^\circ. Find the bearing of Q from P.

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Question 2302

[3 marks]Measures & Mensuration
The diagram shows two semi circles APM and AQB, where M is the midpoint of AB and AM = MB = 3,5 cm. The shaded region is the part of semi circle AQB that lies outside semi circle APM. Taking π\pi to be 227\frac{22}{7}, calculate the perimeter of the shaded region, in centimetres.

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Question 2401

[2 marks]Probability
The ages of pupils in a class of 30 are: age 11, 3 pupils; age 12, 10 pupils; age 13, 8 pupils; age 14, 6 pupils; age 15, 3 pupils. Two pupils are chosen at random from the class. Find the probability that one is aged 11 years and the other is aged 14.

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Question 2402

[3 marks]Statistics
The ages of pupils in a class of 30 are: age 11, 3 pupils; age 12, 10 pupils; age 13, 8 pupils; age 14, 6 pupils; age 15, 3 pupils. Calculate the mean age of the pupils.

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Question 2501

[1 marks]Similarity & Congruency
In the diagram, PQ is parallel to RS. PS and QR intersect at X. It is given that PX = 2 cm, SX = 3 cm, QX = (y+2)(y + 2) cm and RX = (2y−1)(2y - 1) cm. Name the triangle which is similar to triangle PQX.

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Question 2502

[3 marks]Similarity & Congruency
In the diagram, PQ is parallel to RS. PS and QR intersect at X. It is given that PX = 2 cm, SX = 3 cm, QX = (y+2)(y + 2) cm and RX = (2y−1)(2y - 1) cm. Find the value of yy.

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Question 2503

[1 marks]Similarity & Congruency
In the diagram, PQ is parallel to RS. PS and QR intersect at X. It is given that PX = 2 cm, SX = 3 cm, QX = (y+2)(y + 2) cm and RX = (2y−1)(2y - 1) cm. Given that y=8y = 8, write down the length of QR, in centimetres.

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Question 2601

[1 marks]Travel Graphs
The velocity-time graph shows an object which accelerated uniformly for 10 seconds. During this time the velocity, V m/s, at time t seconds from the start, was given by V=6+2tV = 6 + 2t. It then decelerated uniformly to rest in a further 12 seconds. Calculate the velocity of the object when t=0t = 0.

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Question 2602

[2 marks]Travel Graphs
The velocity-time graph shows an object which accelerated uniformly for 10 seconds. During this time the velocity, V m/s, at time t seconds from the start, was given by V=6+2tV = 6 + 2t. It then decelerated uniformly to rest in a further 12 seconds. Calculate the deceleration of the object.

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Question 2603

[2 marks]Travel Graphs
The velocity-time graph shows an object which accelerated uniformly for 10 seconds. During this time the velocity, V m/s, at time t seconds from the start, was given by V=6+2tV = 6 + 2t. It then decelerated uniformly to rest in a further 12 seconds. Calculate the distance covered by the object in the 22 seconds.

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Question 2604

[1 marks]Travel Graphs
The velocity-time graph shows an object which accelerated uniformly for 10 seconds. During this time the velocity, V m/s, at time t seconds from the start, was given by V=6+2tV = 6 + 2t. It then decelerated uniformly to rest in a further 12 seconds. Calculate the average speed of the object for the whole journey.

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Question 2701

[4 marks]Trigonometry, Bearing & Distances
In the diagram, ABC is a triangle in which AB = xx cm, AC = 2x2x cm, BC = 14 cm and BA^C=120∘B\hat{A}C = 120^\circ. [sin⁡60∘=0,87\sin 60^\circ = 0,87; cos⁡60∘=0,5\cos 60^\circ = 0,5; tan⁡60∘=1,73\tan 60^\circ = 1,73] Calculate the value of xx, leaving your answer in surd form.

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Question 2702

[2 marks]Trigonometry, Bearing & Distances
In the diagram, ABC is a triangle in which AB = xx cm, AC = 2x2x cm, BC = 14 cm and BA^C=120∘B\hat{A}C = 120^\circ. [sin⁡60∘=0,87\sin 60^\circ = 0,87; cos⁡60∘=0,5\cos 60^\circ = 0,5; tan⁡60∘=1,73\tan 60^\circ = 1,73] Calculate the area of triangle ABC, in cm2\text{cm}^2.

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