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ZIMSEC A Level · 6042/1 · N2024

Pure Mathematics Paper 1 November 2024

Questions
48
Total marks
120
Syllabus code
6042/1

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Questions
48
Pass mark
29
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Indices
Simplify (x2)13×(x−12)3\left(x^2\right)^{\frac13}\times\left(x^{-\frac12}\right)^3, giving your answer as a single power of xx.

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Question 102

[2 marks]Indices
Simplify (x2)13×(x−12)3x−16×x−23\dfrac{\left(x^2\right)^{\frac13}\times\left(x^{-\frac12}\right)^3}{x^{-\frac16}\times x^{-\frac23}}.

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Question 201

[3 marks]Geometric progressions
A geometric progression has first term aa, where a≠0a\ne0, and common ratio rr, where 0<r<10<r<1. Its sum to infinity is double the sum of its first eight terms. Find the value of r4r^4.

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Question 202

[2 marks]Geometric progressions
A geometric progression has first term aa and common ratio rr, where 0<r<10<r<1, and r8=12r^8=\dfrac12. Given that the 9th term is 20, find the exact value of aa.

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Question 301

[3 marks]Variation
YY varies jointly as the square root of xx and inversely as the cube of zz. Given that Y=16Y=16 when x=9x=9 and z=12z=\dfrac12, express YY in terms of xx and zz.

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Question 302

[2 marks]Variation
Given that Y=2x3z3Y=\dfrac{2\sqrt{x}}{3z^3}, find the value of zz when Y=2.5Y=2.5 and x=900x=900.

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Question 401

[2 marks]Partial fractions
The expression 3−x+6x2(1−x)(2+x)(1+2x)\dfrac{3-x+6x^2}{(1-x)(2+x)(1+2x)} is written as A1−x+B2+x+C1+2x\dfrac{A}{1-x}+\dfrac{B}{2+x}+\dfrac{C}{1+2x}. Find the value of AA.

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Question 402

[3 marks]Partial fractions
Express 3−x+6x2(1−x)(2+x)(1+2x)\dfrac{3-x+6x^2}{(1-x)(2+x)(1+2x)} in partial fractions.

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Question 501

[3 marks]Polynomials
The polynomial h(x)=x4+3x3+ax+3h(x)=x^4+3x^3+ax+3 is divisible by x2−x+1x^2-x+1. Find the value of aa.

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Question 502

[2 marks]Polynomials
The polynomial h(x)=x4+3x3+x+3h(x)=x^4+3x^3+x+3 is divisible by x2−x+1x^2-x+1. Factorise h(x)h(x) completely.

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Question 601

[3 marks]Modulus inequalities
Squaring both sides of the inequality 3∣x−2∣>∣2x−1∣3\left|x-2\right|>\left|2x-1\right| gives a quadratic inequality. Write it in the form ax2+bx+c>0ax^2+bx+c>0.

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Question 602

[3 marks]Modulus inequalities
Solve the inequality 3∣x−2∣>∣2x−1∣3\left|x-2\right|>\left|2x-1\right|.

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Question 701

[3 marks]Vectors
The position vectors OM→=2i+3j−4k\overrightarrow{OM}=2\mathbf{i}+3\mathbf{j}-4\mathbf{k} and ON→=−i−2j+6k\overrightarrow{ON}=-\mathbf{i}-2\mathbf{j}+6\mathbf{k} are given. Find cos⁡MO^N\cos M\hat{O}N, correct to 2 significant figures.

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Question 702

[3 marks]Vectors
The position vectors OM→=2i+3j−4k\overrightarrow{OM}=2\mathbf{i}+3\mathbf{j}-4\mathbf{k} and ON→=−i−2j+6k\overrightarrow{ON}=-\mathbf{i}-2\mathbf{j}+6\mathbf{k} are given. Find the unit vector in the direction of MN→\overrightarrow{MN}.

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Question 801

[3 marks]Differential equations
The gradient of a curve at the point (x,y)(x,y) is given by dydx=4xy2\dfrac{dy}{dx}=4xy^2. Find the general solution of this differential equation.

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Question 802

[3 marks]Differential equations
The gradient of a curve at the point (x,y)(x,y) is given by dydx=4xy2\dfrac{dy}{dx}=4xy^2, and the curve passes through the point where x=2x=2 and y=4y=4. Find the particular solution.

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Question 901

[2 marks]Proof by induction
A proof by induction is to show that 11n−4n11^n-4^n is a multiple of 7 for all n∈Z+n\in\mathbb{Z}^+. Find the value of 11n−4n11^n-4^n when n=1n=1, which establishes the base case.

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Question 902

[3 marks]Proof by induction
In a proof by induction that 11n−4n11^n-4^n is a multiple of 7, it is assumed that 11k−4k=7m11^k-4^k=7m for some integer mm. Show that 11k+1−4k+111^{k+1}-4^{k+1} is a multiple of 7 by writing it in the form 7×(an integer)7\times(\text{an integer}).

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Question 903

[1 marks]Proof by induction
A proof by induction has shown that a statement is true for n=1n=1, and that whenever it is true for n=kn=k it is also true for n=k+1n=k+1. What conclusion follows?
  1. ANo conclusion can be drawn without checking n=2n=2 separately
  2. BThe statement is true for all positive integers nn
  3. CThe statement is true only for n=1n=1 and n=2n=2
  4. DThe statement is true for all real numbers nn

Question 1001

[3 marks]Implicit differentiation
Given the equation x2+y2−3x2y+5y+2x=0x^2+y^2-3x^2y+5y+2x=0, find dydx\dfrac{dy}{dx} in terms of xx and yy.

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Question 1002

[2 marks]Implicit differentiation
For the equation x2+y2−3x2y+5y+2x=0x^2+y^2-3x^2y+5y+2x=0 the gradient is dydx=6xy−2x−22y−3x2+5\dfrac{dy}{dx}=\dfrac{6xy-2x-2}{2y-3x^2+5}. Evaluate this gradient at the point (1;3)(1;3).

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Question 1003

[2 marks]Implicit differentiation
A curve has gradient 74\dfrac{7}{4} at the point (1;3)(1;3). Find the equation of the normal to the curve at that point, in the form ax+by+c=0ax+by+c=0.

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Question 1101

[3 marks]Inverse functions
The function f(x)=x2−6x+8f(x)=x^2-6x+8 is defined for 0≤x≤30\le x\le3. Find f−1(x)f^{-1}(x).

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Question 1102

[2 marks]Inverse functions
The function f(x)=x2−6x+8f(x)=x^2-6x+8 is defined for 0≤x≤30\le x\le3. Find the range of ff.

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Question 1103

[1 marks]Inverse functions
The function f(x)=x2−6x+8f(x)=x^2-6x+8 is defined for 0≤x≤30\le x\le3, and its range is −1≤f(x)≤8-1\le f(x)\le8. State the domain of f−1(x)f^{-1}(x).

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Question 1104

[2 marks]Inverse functions
The graphs of a function ff and its inverse f−1f^{-1} are sketched on the same axes. What is the geometrical relationship between the two graphs?
  1. AThey are reflections of each other in the line y=xy=x
  2. BThey are reflections of each other in the xx axis
  3. CThey are reflections of each other in the yy axis
  4. DThey are translations of each other parallel to the yy axis

Question 1201

[3 marks]Binomial expansion
Expand (1−x3)−23\left(1-\dfrac{x}{3}\right)^{-\frac23} in ascending powers of xx up to and including the term in x3x^3, simplifying the coefficients.

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Question 1202

[3 marks]Binomial expansion
Expand 2x+3(1−x3)23\dfrac{2x+3}{\sqrt[3]{\left(1-\frac{x}{3}\right)^2}} in ascending powers of xx up to and including the term in x3x^3, simplifying the coefficients.

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Question 1203

[2 marks]Binomial expansion
State the set of values of xx for which the binomial expansion of (1−x3)−23\left(1-\dfrac{x}{3}\right)^{-\frac23} is valid.

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Question 1301

[2 marks]Newton-Raphson method
Let f(x)=x+x+1+x+2−5f(x)=\sqrt{x}+\sqrt{x+1}+\sqrt{x+2}-5. Find the values of f(1)f(1) and f(2)f(2), each correct to 4 decimal places.

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Question 1302

[2 marks]Newton-Raphson method
For f(x)=x+x+1+x+2−5f(x)=\sqrt{x}+\sqrt{x+1}+\sqrt{x+2}-5, the values f(1)=−0.8537f(1)=-0.8537 and f(2)=0.1463f(2)=0.1463 have been found. What does this show about the equation f(x)=0f(x)=0?
  1. Aff is continuous and changes sign, so a root lies between 1 and 2
  2. Bff has a minimum between 1 and 2
  3. CThere is no root of f(x)=0f(x)=0 between 1 and 2
  4. DThere are exactly two roots of f(x)=0f(x)=0 between 1 and 2

Question 1303

[2 marks]Newton-Raphson method
For f(x)=x+x+1+x+2−5f(x)=\sqrt{x}+\sqrt{x+1}+\sqrt{x+2}-5, write down an expression for f′(x)f'(x).

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Question 1304

[3 marks]Newton-Raphson method
Using x0=1.5x_0=1.5 as the initial estimate, apply the Newton-Raphson method three times to the equation x+x+1+x+2−5=0\sqrt{x}+\sqrt{x+1}+\sqrt{x+2}-5=0, and give the root correct to two decimal places.

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Question 1401

[3 marks]Complex numbers
Solve the equation z2+4z+7=0z^2+4z+7=0, giving both roots in the form a+bia+bi with bb in exact surd form.

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Question 1402

[2 marks]Complex numbers
Find the modulus of the complex number z2=−2−3 iz_2=-2-\sqrt3\,i, giving your answer in exact form.

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Question 1403

[2 marks]Complex numbers
Find the argument of the complex number z2=−2−3 iz_2=-2-\sqrt3\,i, giving your answer to the nearest degree.

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Question 1404

[2 marks]Complex numbers
Write the complex number z2=−2−3 iz_2=-2-\sqrt3\,i in polar form, using a modulus in exact form and an argument to the nearest degree.

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Question 1405

[2 marks]Complex numbers
The complex numbers z1=−2+3 iz_1=-2+\sqrt3\,i and z2=−2−3 iz_2=-2-\sqrt3\,i are given. Find z1z2z_1z_2.

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Question 1406

[1 marks]Complex numbers
On an Argand diagram, where is the product z1z2=7z_1z_2=7 of the conjugate pair z1=−2+3 iz_1=-2+\sqrt3\,i and z2=−2−3 iz_2=-2-\sqrt3\,i plotted?
  1. AAt the point (−7;0)(-7;0), on the real axis
  2. BAt the point (−2;7)(-2;7)
  3. CAt the point (7;0)(7;0), on the real axis
  4. DAt the point (0;7)(0;7), on the imaginary axis

Question 1501

[3 marks]Circle geometry
A circle has centre C(−4;5)(-4;5) and the point A(0;8)(0;8) lies on its circumference. Find the equation of the circle.

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Question 1502

[2 marks]Circle geometry
A circle has centre C(−4;5)(-4;5) and radius 5. Show that the point B(0;2)(0;2) lies on its circumference by finding the distance CB.

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Question 1503

[3 marks]Circle geometry
A circle has centre C(−4;5)(-4;5) and the point B(0;2)(0;2) lies on its circumference. Find the equation of the tangent to the circle at B, in the form ax+by+c=0ax+by+c=0.

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Question 1504

[2 marks]Circle geometry
The points B(0;2)(0;2) and D(−16;8)(-16;8) are given. Calculate the coordinates of the midpoint of BD.

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Question 1505

[3 marks]Circle geometry
The points B(0;2)(0;2) and D(−16;8)(-16;8) are given, and the midpoint of BD is (−8;5)(-8;5). Find the equation of the perpendicular bisector of BD, in the form ax+by+c=0ax+by+c=0.

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Question 1601

[2 marks]Linear law, logarithmic graphs
An experiment gives values of xx and yy believed to satisfy the law y=ab−xy=ab^{-x}. Which plot gives a straight line, allowing aa and bb to be found from its gradient and intercept?
  1. Ayy against lg⁡x\lg x
  2. Blg⁡y\lg y against lg⁡x\lg x
  3. Cyy against x2x^2
  4. Dlg⁡y\lg y against xx

Question 1602

[3 marks]Linear law, logarithmic graphs
The table shows values of xx and yy from an experiment satisfying the law y=ab−xy=ab^{-x}, where xx takes the values 1.0, 1.5, 2.0, 2.5 and 3.0 and yy takes the values 4.0, 5.7, 8.0, 11.3 and 16.0 in that order. Taking logarithms to base 10, find the gradient of the straight line obtained when lg⁡y\lg y is plotted against xx.

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Question 1603

[3 marks]Linear law, logarithmic graphs
An experiment satisfies the law y=ab−xy=ab^{-x}. Plotting lg⁡y\lg y against xx gives a straight line of gradient 0.301 and intercept 0.301 on the lg⁡y\lg y axis. Find the values of aa and bb.

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Question 1604

[2 marks]Linear law, logarithmic graphs
An experiment satisfies the law y=ab−xy=ab^{-x} with a=2a=2 and b=0.5b=0.5. Use the law to find the value of yy when x=4.0x=4.0.

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The answers, and why they are the answers

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