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ZIMSEC A Level · N2002

Pure Mathematics Paper 1 November 2002

Questions
86
Total marks
108

Sit this paper online

Questions
86
Pass mark
52
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]quadratics and logarithmic graphs
For what set of values of kk does the equation kx2−3x=k−3kx^2 - 3x = k - 3 have (at least one) real root?
  1. AAll real values of kk
  2. Bk≥32k \geq \tfrac{3}{2}
  3. Ck=32k = \tfrac{3}{2} only
  4. DAll real kk except k=0k = 0

Question 102

[1 marks]quadratics and logarithmic graphs
Values of xx and yy satisfy y=Axby = Ax^b for constants AA and bb. Which pair of axes should be plotted, and what shape of graph confirms the relationship?
  1. APlot ln⁡y\ln y against ln⁡x\ln x: a straight line confirms the relationship
  2. BPlot yy against ln⁡x\ln x: a straight line confirms the relationship
  3. CPlot yy against xbx^b: a straight line confirms the relationship
  4. DPlot ln⁡y\ln y against xx: a straight line confirms the relationship

Question 103

[2 marks]quadratics and logarithmic graphs
Rearranging kx2−3x=k−3kx^2-3x=k-3 gives kx2−3x−k+3=0kx^2-3x-k+3=0. The discriminant of this quadratic simplifies to (2k−3)2(2k-3)^2. For what value of kk does this discriminant equal zero?

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Question 201

[1 marks]surds and rationalisation
Express 23−7−63\dfrac{2}{3-\sqrt7}-\sqrt{63} in the form a+bca+b\sqrt c, where aa, bb and cc are integers.
  1. A3+473+4\sqrt7
  2. B3−273-2\sqrt7
  3. C−3+27-3+2\sqrt7
  4. D3−473-4\sqrt7

Question 202

[1 marks]surds and rationalisation
For 23−7−63=a+bc\dfrac{2}{3-\sqrt7}-\sqrt{63}=a+b\sqrt c with a,b,ca,b,c integers, what is the value of a+b+ca+b+c?

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Question 203

[1 marks]surds and rationalisation
Simplify 63\sqrt{63} in the form k7k\sqrt7. What is the value of kk?

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Question 301

[1 marks]numerical integration
Use the trapezium rule with 5 equal intervals to estimate ∫01cos⁡(x2) dx\displaystyle\int_0^1\cos(x^2)\,dx, giving your answer correct to 3 significant figures.
  1. A0.6260.626
  2. B0.7700.770
  3. C0.8990.899
  4. D1.801.80

Question 302

[2 marks]numerical integration
Using the trapezium rule for ∫01cos⁡(x2) dx\int_0^1\cos(x^2)\,dx with 5 equal intervals (h=0.2h=0.2), find the last ordinate y5=cos⁡(12)y_5=\cos(1^2) correct to 3 significant figures.

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Question 401

[1 marks]exponential growth and logarithms
A population increases by 3% every year. Find, to 3 significant figures, the time in years for the population to double.
  1. A66.766.7 years
  2. B23.423.4 years
  3. C23.123.1 years
  4. D24.024.0 years

Question 402

[1 marks]exponential growth and logarithms
A population increases by 3% each year. Which equation must be solved to find the number of years nn for the population to double?
  1. A2n=1.032^n=1.03
  2. B1.03n=21.03^n=2
  3. C1.03n=21.03n=2
  4. Dn1.03=2n^{1.03}=2

Question 403

[2 marks]exponential growth and logarithms
Given 1.03n=21.03^n=2, taking logarithms gives n=ln⁡2ln⁡1.03n=\dfrac{\ln 2}{\ln 1.03}. Find ln⁡1.03\ln 1.03 correct to 4 decimal places.

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Question 501

[1 marks]volumes of revolution
The region between the curve y=ex+1y=e^x+1, the xx-axis, and the lines x=−1x=-1 and x=1x=1 is rotated through 44 right angles about the xx-axis. Find the volume of the solid formed, correct to 2 decimal places.
  1. A10.3310.33
  2. B11.3911.39
  3. C13.6713.67
  4. D32.4432.44

Question 502

[1 marks]volumes of revolution
Which integral correctly represents the volume generated when the region bounded by y=ex+1y=e^x+1, the xx-axis, x=−1x=-1 and x=1x=1 is rotated through 4 right angles about the xx-axis?
  1. Aπ∫−11(ex+1) dx\pi\displaystyle\int_{-1}^{1}(e^x+1)\,dx
  2. B2π∫−11(ex+1) dx2\pi\displaystyle\int_{-1}^{1}(e^x+1)\,dx
  3. Cπ∫−11(ex+1)2 dx\pi\displaystyle\int_{-1}^{1}(e^x+1)^2\,dx
  4. Dπ∫01(ex+1)2 dx\pi\displaystyle\int_{0}^{1}(e^x+1)^2\,dx

Question 503

[2 marks]volumes of revolution
In evaluating π[e2x2+2ex+x]−11\pi\left[\dfrac{e^{2x}}{2}+2e^x+x\right]_{-1}^{1}, find the value of e2−e−2e^2-e^{-2} correct to 3 significant figures.

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Question 601

[1 marks]modulus inequalities and graphs
Solve the inequality 2x+2>∣3x−6∣2x+2>|3x-6|.
  1. A45<x<2\tfrac45<x<2
  2. Bx<8x<8
  3. C−8<x<45-8<x<\tfrac45
  4. D45<x<8\tfrac45<x<8

Question 602

[1 marks]modulus inequalities and graphs
What are the coordinates of the vertex of the graph y=∣3x−6∣y=|3x-6| (the point where its two straight-line branches meet)?
  1. A(2,0)(2,0)
  2. B(0,6)(0,6)
  3. C(0,−6)(0,-6)
  4. D(6,0)(6,0)

Question 603

[1 marks]modulus inequalities and graphs
Solving 2x+2>∣3x−6∣2x+2>|3x-6| for x≥2x\geq2 (where ∣3x−6∣=3x−6|3x-6|=3x-6) leads to which inequality?
  1. Ax<2x<2
  2. Bx>−8x>-8
  3. Cx>8x>8
  4. Dx<8x<8

Question 604

[2 marks]modulus inequalities and graphs
Solving 2x+2>∣3x−6∣2x+2>|3x-6| for x<2x<2 (where ∣3x−6∣=6−3x|3x-6|=6-3x) leads to 5x>45x>4. What is the resulting lower bound for xx, as a fraction?

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Question 701

[1 marks]factor theorem and polynomials
Given that f(x)≡2x4+ax3+bx2−5x+6f(x)\equiv2x^4+ax^3+bx^2-5x+6 has both (x+2)(x+2) and (x−3)(x-3) as factors, find the values of aa and bb.
  1. Aa=−1, b=14a=-1,\ b=14
  2. Ba=−1, b=−14a=-1,\ b=-14
  3. Ca=1, b=−14a=1,\ b=-14
  4. Da=−5, b=−2a=-5,\ b=-2

Question 702

[1 marks]factor theorem and polynomials
Given f(x)≡2x4+ax3+bx2−5x+6f(x)\equiv2x^4+ax^3+bx^2-5x+6 and that (x+2)(x+2) is a factor, applying the factor theorem (f(−2)=0f(-2)=0) leads to which simplified linear equation relating aa and bb?
  1. A−2a+b=−12-2a+b=-12
  2. B−2a+b=12-2a+b=12
  3. C2a+b=−122a+b=-12
  4. D−2a−b=−12-2a-b=-12

Question 703

[1 marks]factor theorem and polynomials
Given f(x)≡2x4+ax3+bx2−5x+6f(x)\equiv2x^4+ax^3+bx^2-5x+6 and that (x−3)(x-3) is a factor, applying the factor theorem (f(3)=0f(3)=0) leads to which simplified linear equation relating aa and bb?
  1. Aa+3b=−17a+3b=-17
  2. B27a+9b=15327a+9b=153
  3. C3a+b=173a+b=17
  4. D3a+b=−173a+b=-17

Question 704

[2 marks]factor theorem and polynomials
Using −2a+b=−12-2a+b=-12 and 3a+b=−173a+b=-17 together, find the value of aa only.

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Question 801

[1 marks]sequences and series
A sequence is defined by Ur=n−3rU_r=n-3r. What are its first three terms U1,U2,U3U_1,U_2,U_3?
  1. An−3, n−6, n−9n-3,\ n-6,\ n-9
  2. Bn−3, n−9, n−27n-3,\ n-9,\ n-27
  3. Cn−1, n−2, n−3n-1,\ n-2,\ n-3
  4. Dn, n−3, n−6n,\ n-3,\ n-6

Question 802

[1 marks]sequences and series
For the sequence Ur=n−3rU_r=n-3r, find ∑r=n2nUr\displaystyle\sum_{r=n}^{2n}U_r in terms of nn.
  1. A−7n(n−1)2-\dfrac{7n(n-1)}{2}
  2. B7n(n+1)2\dfrac{7n(n+1)}{2}
  3. C−9n(n+1)2-\dfrac{9n(n+1)}{2}
  4. D−7n(n+1)2-\dfrac{7n(n+1)}{2}

Question 803

[2 marks]sequences and series
Find ∑r=n2nn\displaystyle\sum_{r=n}^{2n}n (the constant nn added once per term over this range) in terms of nn, by first working out how many terms the sum has.

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Question 804

[2 marks]sequences and series
Find ∑r=n2nr\displaystyle\sum_{r=n}^{2n}r in terms of nn.

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Question 901

[1 marks]differentiation and integration by parts
Differentiate xsin⁡ ⁣(6x+π4)x\sin\!\left(6x+\dfrac{\pi}{4}\right) with respect to xx.
  1. Asin⁡ ⁣(6x+π4)+xcos⁡ ⁣(6x+π4)\sin\!\left(6x+\tfrac{\pi}{4}\right)+x\cos\!\left(6x+\tfrac{\pi}{4}\right)
  2. B6xcos⁡ ⁣(6x+π4)−sin⁡ ⁣(6x+π4)6x\cos\!\left(6x+\tfrac{\pi}{4}\right)-\sin\!\left(6x+\tfrac{\pi}{4}\right)
  3. C6cos⁡ ⁣(6x+π4)6\cos\!\left(6x+\tfrac{\pi}{4}\right)
  4. Dsin⁡ ⁣(6x+π4)+6xcos⁡ ⁣(6x+π4)\sin\!\left(6x+\tfrac{\pi}{4}\right)+6x\cos\!\left(6x+\tfrac{\pi}{4}\right)

Question 902

[1 marks]differentiation and integration by parts
Evaluate exactly ∫π/6π/4xsin⁡ ⁣(6x+π4)dx\displaystyle\int_{\pi/6}^{\pi/4}x\sin\!\left(6x+\dfrac{\pi}{4}\right)dx.
  1. A−52144π-\dfrac{5\sqrt2}{144}\pi
  2. B−2144π-\dfrac{\sqrt2}{144}\pi
  3. C52144π\dfrac{5\sqrt2}{144}\pi
  4. D−5272π-\dfrac{5\sqrt2}{72}\pi

Question 903

[1 marks]differentiation and integration by parts
In integrating ∫xsin⁡(6x+π/4) dx\int x\sin(6x+\pi/4)\,dx by parts, the coefficient of xcos⁡(6x+π/4)x\cos(6x+\pi/4) in the antiderivative is −1k-\dfrac{1}{k}. Find kk.

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Question 904

[2 marks]differentiation and integration by parts
Evaluate cos⁡ ⁣(6⋅π4+π4)\cos\!\left(6\cdot\dfrac{\pi}{4}+\dfrac{\pi}{4}\right) exactly, needed when evaluating the integral at x=π/4x=\pi/4.

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Question 905

[1 marks]differentiation and integration by parts
Evaluate sin⁡ ⁣(6⋅π6+π4)\sin\!\left(6\cdot\dfrac{\pi}{6}+\dfrac{\pi}{4}\right) exactly, needed when evaluating the integral at the lower limit x=π/6x=\pi/6.

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Question 1001

[1 marks]numerical methods and error analysis
Given x=8.7x=8.7 and y=0.3y=0.3, each correct to 1 decimal place, find the value of xyxy and estimate the relative error in this quantity.
  1. Axy=2.61xy=2.61, relative error ≈0.00575\approx0.00575
  2. Bxy=2.61xy=2.61, relative error ≈0.05\approx0.05
  3. Cxy=2.61xy=2.61, relative error ≈0.172\approx0.172
  4. Dxy=2.61xy=2.61, relative error ≈0.0862\approx0.0862

Question 1002

[1 marks]numerical methods and error analysis
Given x=8.7x=8.7 and y=0.3y=0.3, each correct to 1 decimal place, find y−1xy-\dfrac1x with an appropriate error bound, quoted to 1 significant figure.
  1. A0.19±0.100.19\pm0.10
  2. B−0.19±0.05-0.19\pm0.05
  3. C0.19±0.0010.19\pm0.001
  4. D0.19±0.050.19\pm0.05

Question 1003

[1 marks]numerical methods and error analysis
Which formula estimates the relative error in the product xyxy, given errors δx\delta x in xx and δy\delta y in yy?
  1. Aδ(xy)xy≈δxx⋅δyy\dfrac{\delta(xy)}{xy}\approx\dfrac{\delta x}{x}\cdot\dfrac{\delta y}{y}
  2. Bδ(xy)xy≈δxx−δyy\dfrac{\delta(xy)}{xy}\approx\dfrac{\delta x}{x}-\dfrac{\delta y}{y}
  3. Cδ(xy)xy≈δxx+δyy\dfrac{\delta(xy)}{xy}\approx\dfrac{\delta x}{x}+\dfrac{\delta y}{y}
  4. Dδ(xy)xy≈δxy+δyx\dfrac{\delta(xy)}{xy}\approx\dfrac{\delta x}{y}+\dfrac{\delta y}{x}

Question 1004

[2 marks]numerical methods and error analysis
Given x=8.7x=8.7 and y=0.3y=0.3 each correct to 1 decimal place (so δx=δy=0.05\delta x=\delta y=0.05), find the relative error δyy\dfrac{\delta y}{y} correct to 3 significant figures.

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Question 1005

[1 marks]numerical methods and error analysis
Given x=8.7x=8.7 correct to 1 decimal place, find 1x\dfrac1x correct to 4 decimal places.

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Question 1006

[1 marks]numerical methods and error analysis
Which formula gives the error bound in y−1xy-\dfrac1x, given errors δx\delta x in xx and δy\delta y in yy?
  1. Aδy−δxx2\delta y-\dfrac{\delta x}{x^2}
  2. Bδy+δxx\delta y+\dfrac{\delta x}{x}
  3. Cδy⋅δxx2\delta y\cdot\dfrac{\delta x}{x^2}
  4. Dδy+δxx2\delta y+\dfrac{\delta x}{x^2}

Question 1101

[1 marks]Maclaurin series and differentiation
Given f(x)=ln⁡(2−3x)f(x)=\ln(2-3x) with f′′(x)=−9(2−3x)2f''(x)=\dfrac{-9}{(2-3x)^2}, find f′′′(x)f'''(x).
  1. A18(2−3x)3\dfrac{18}{(2-3x)^3}
  2. B−54(2−3x)3\dfrac{-54}{(2-3x)^3}
  3. C54(2−3x)3\dfrac{54}{(2-3x)^3}
  4. D−54(2−3x)2\dfrac{-54}{(2-3x)^2}

Question 1102

[1 marks]Maclaurin series and differentiation
Given f(x)=ln⁡(2−3x)f(x)=\ln(2-3x), with f(0)=ln⁡2f(0)=\ln2, f′(0)=−32f'(0)=-\tfrac32, f′′(0)=−94f''(0)=-\tfrac94 and f′′′(0)=−274f'''(0)=-\tfrac{27}{4}, write down the Maclaurin expansion of ln⁡(2−3x)\ln(2-3x) up to and including the term in x3x^3.
  1. A2−32x−98x2−98x32-\tfrac32x-\tfrac98x^2-\tfrac98x^3
  2. Bln⁡2−32x−94x2−274x3\ln2-\tfrac32x-\tfrac94x^2-\tfrac{27}{4}x^3
  3. Cln⁡2+32x−98x2+98x3\ln2+\tfrac32x-\tfrac98x^2+\tfrac98x^3
  4. Dln⁡2−32x−98x2−98x3\ln2-\tfrac32x-\tfrac98x^2-\tfrac98x^3

Question 1103

[2 marks]Maclaurin series and differentiation
Given f(x)=ln⁡(2−3x)f(x)=\ln(2-3x), differentiate to find f′(x)f'(x), then use it to find the exact value of f′(0)f'(0).

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Question 1104

[1 marks]Maclaurin series and differentiation
Given f′′(x)=−9(2−3x)2f''(x)=\dfrac{-9}{(2-3x)^2}, find the exact value of f′′(0)f''(0).

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Question 1105

[1 marks]Maclaurin series and differentiation
Given f′′′(x)=−54(2−3x)3f'''(x)=\dfrac{-54}{(2-3x)^3}, find the exact value of f′′′(0)f'''(0).

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Question 1106

[1 marks]Maclaurin series and differentiation
In a Maclaurin series expansion, what circumstance justifies neglecting terms in x4x^4 and higher powers?
  1. AWhen the function is a polynomial of degree 3
  2. BWhen the series is evaluated at x=0x=0 only
  3. CWhen xx is a whole number greater than 1
  4. DWhen ∣x∣|x| is small, so higher powers become negligible compared to earlier terms

Question 1201

[1 marks]trigonometric functions and substitution
Given f(x)=3cos⁡2x−2sin⁡xf(x)=3\cos2x-2\sin x, using u=sin⁡xu=\sin x this can be written as f(x)=3−2u−6u2f(x)=3-2u-6u^2. Find the exact maximum value of f(x)f(x).
  1. A−196-\dfrac{19}{6}
  2. B176\dfrac{17}{6}
  3. C196\dfrac{19}{6}
  4. D33

Question 1202

[1 marks]trigonometric functions and substitution
Given f(x)=3cos⁡2x−2sin⁡x=3−2u−6u2f(x)=3\cos2x-2\sin x=3-2u-6u^2 where u=sin⁡xu=\sin x, find all values of xx for 0∘≤x<360∘0^\circ\leq x<360^\circ for which f(x)=3f(x)=3.
  1. Ax=0∘, 180∘, 199.5∘, 340.5∘x=0^\circ,\ 180^\circ,\ 199.5^\circ,\ 340.5^\circ
  2. Bx=0∘, 180∘x=0^\circ,\ 180^\circ only
  3. Cx=19.5∘, 160.5∘, 199.5∘, 340.5∘x=19.5^\circ,\ 160.5^\circ,\ 199.5^\circ,\ 340.5^\circ
  4. Dx=0∘, 180∘, 109.5∘, 250.5∘x=0^\circ,\ 180^\circ,\ 109.5^\circ,\ 250.5^\circ

Question 1203

[1 marks]trigonometric functions and substitution
Which double angle identity for cos⁡2x\cos2x, expressed in terms of sin⁡x\sin x, is used to rewrite f(x)=3cos⁡2x−2sin⁡xf(x)=3\cos2x-2\sin x as a quadratic in u=sin⁡xu=\sin x?
  1. Acos⁡2x=2cos⁡2x−1\cos2x=2\cos^2x-1
  2. Bcos⁡2x=cos⁡2x−sin⁡2x\cos2x=\cos^2x-\sin^2x
  3. Ccos⁡2x=1−2sin⁡2x\cos2x=1-2\sin^2x
  4. Dcos⁡2x=1−sin⁡2x\cos2x=1-\sin^2x

Question 1204

[2 marks]trigonometric functions and substitution
Writing f(x)=3−2u−6u2f(x)=3-2u-6u^2 in completed-square form gives a maximum at a certain value of uu. Find that value of uu.

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Question 1205

[2 marks]trigonometric functions and substitution
Solving 3−2u−6u2=33-2u-6u^2=3 gives u(2+6u)=0u(2+6u)=0. State both values of uu that satisfy this equation.

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Question 1206

[1 marks]trigonometric functions and substitution
Given sin⁡x=−13\sin x=-\dfrac13, find the reference angle (acute angle) correct to 2 decimal places, in degrees.

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Question 1301

[1 marks]numerical methods and Newton-Raphson
For g(x)=e3x−2x−10g(x)=e^{3x}-2x-10, what is g(−4)g(-4) to 3 significant figures, and what does it show together with g(−5)=e−15>0g(-5)=e^{-15}>0?
  1. Ag(−4)≈−10.0g(-4)\approx-10.0; the sign change shows a root lies between x=−5x=-5 and x=−4x=-4
  2. Bg(−4)≈−18.0g(-4)\approx-18.0; the sign change shows a root lies between x=−5x=-5 and x=−4x=-4
  3. Cg(−4)≈2.00g(-4)\approx2.00; the sign change shows a root lies between x=−5x=-5 and x=−4x=-4
  4. Dg(−4)≈−2.00g(-4)\approx-2.00; the sign change shows a root lies between x=−5x=-5 and x=−4x=-4

Question 1302

[1 marks]numerical methods and Newton-Raphson
For g(x)=e3x−2x−10g(x)=e^{3x}-2x-10, besides the root between x=−5x=-5 and x=−4x=-4, state the pair of consecutive integers between which another root lies.

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Question 1303

[1 marks]numerical methods and Newton-Raphson
For g(x)=e3x−2x−10g(x)=e^{3x}-2x-10, taking x1=−4x_1=-4 and applying one step of the Newton-Raphson formula x2=x1−g(x1)g′(x1)x_2=x_1-\dfrac{g(x_1)}{g'(x_1)} (with g′(x)=3e3x−2g'(x)=3e^{3x}-2), find x2x_2 correct to 5 decimal places.
  1. A−5.00061-5.00061
  2. B−5.00001-5.00001
  3. C−4.99994-4.99994
  4. D−3.00001-3.00001

Question 1304

[2 marks]numerical methods and Newton-Raphson
For g(x)=e3x−2x−10g(x)=e^{3x}-2x-10, find g′(x)g'(x).

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Question 1305

[2 marks]numerical methods and Newton-Raphson
For g(x)=e3x−2x−10g(x)=e^{3x}-2x-10, find g(1)g(1) correct to 3 significant figures, confirming a root lies between x=0x=0 and x=1x=1.

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Question 1306

[1 marks]numerical methods and Newton-Raphson
Which formula is used for one step of the Newton-Raphson method, starting from x1x_1?
  1. Ax2=x1−g(x1)g′(x1)x_2=x_1-\dfrac{g(x_1)}{g'(x_1)}
  2. Bx2=x1+g(x1)g′(x1)x_2=x_1+\dfrac{g(x_1)}{g'(x_1)}
  3. Cx2=x1−g(x1)g′(x1)x_2=x_1-g(x_1)g'(x_1)
  4. Dx2=g(x1)g′(x1)x_2=\dfrac{g(x_1)}{g'(x_1)}

Question 1401

[1 marks]differential equations
Fans arrive at a stadium gate at a rate modelled by dxdt=−500t\dfrac{dx}{dt}=-\dfrac{500}{t}, where xx is the number of fans present and tt is the number of minutes remaining before the gate opens. Given x=100x=100 when t=10t=10, find the general solution for xx in terms of tt.
  1. Ax=500ln⁡10tx=500\ln\dfrac{10}{t}
  2. Bx=100+500ln⁡tx=100+500\ln t
  3. Cx=100+500ln⁡10tx=100+500\ln\dfrac{10}{t}
  4. Dx=100−500ln⁡10tx=100-500\ln\dfrac{10}{t}

Question 1402

[1 marks]differential equations
Using x=100+500ln⁡10tx=100+500\ln\dfrac{10}{t} (fans present tt minutes before a gate opens, with x=100x=100 when t=10t=10), find the number of fans present 1 minute before the gate opens, to the nearest whole number.
  1. A11511151
  2. B12511251
  3. C14591459
  4. D24032403

Question 1403

[1 marks]differential equations
Fans arrive at a stadium gate at a rate dxdt=−500t\dfrac{dx}{dt}=-\dfrac{500}{t}, where xx is the number of fans present and tt is the time remaining before the gate opens. Which further assumption is needed for this continuous model to be valid?
  1. AThe gate opens exactly at t=0t=0 minutes, with no delay
  2. BFans arrive continuously and none leave the queue once they have joined it
  3. CThe rate of arrival stays constant at 50 fans per minute throughout
  4. DAll fans arrive in equally sized groups, once every minute

Question 1404

[2 marks]differential equations
The arrival rate satisfies dxdt=−kt\dfrac{dx}{dt}=-\dfrac{k}{t}. Given that at t=10t=10 the rate has size 50 per minute, find the value of kk.

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Question 1405

[2 marks]differential equations
Solving dxdt=−500t\dfrac{dx}{dt}=-\dfrac{500}{t} gives x=−500ln⁡t+Cx=-500\ln t+C. Given x=100x=100 when t=10t=10, find the exact value of CC.

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Question 1406

[2 marks]differential equations
Using dxdt=−500t\dfrac{dx}{dt}=-\dfrac{500}{t}, find the size of the arrival rate (in fans per minute) when t=1t=1 minute before the gate opens.

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Question 1501

[1 marks]vectors in 3D
Points A, B, C, D have coordinates (5,7,3)(5,7,3), (7,8,0)(7,8,0), (8,10,3)(8,10,3), (6,9,6)(6,9,6) respectively. Find AB→\overrightarrow{AB} and CD→\overrightarrow{CD}, and state what this tells you about lines AB and CD.
  1. AAB→=(2,1,−3)\overrightarrow{AB}=(2,1,-3), CD→=(2,1,−3)\overrightarrow{CD}=(2,1,-3); since the vectors are identical, AB and CD are the same line
  2. BAB→=(−2,−1,3)\overrightarrow{AB}=(-2,-1,3), CD→=(−2,−1,3)\overrightarrow{CD}=(-2,-1,3); since the vectors are equal, ABCD is a parallelogram
  3. CAB→=(2,1,−3)\overrightarrow{AB}=(2,1,-3), CD→=(−2,−1,3)\overrightarrow{CD}=(-2,-1,3); since CD→=−AB→\overrightarrow{CD}=-\overrightarrow{AB}, AB and CD are parallel and equal in length
  4. DAB→=(2,1,−3)\overrightarrow{AB}=(2,1,-3), CD→=(−2,−1,3)\overrightarrow{CD}=(-2,-1,3); since CD→=−AB→\overrightarrow{CD}=-\overrightarrow{AB}, AB and CD are perpendicular

Question 1502

[1 marks]vectors in 3D
Points B and C have coordinates (7,8,0)(7,8,0) and (8,10,3)(8,10,3) respectively. Find the length of BC.
  1. A18\sqrt{18}
  2. B14\sqrt{14}
  3. C1414
  4. D5\sqrt5

Question 1503

[1 marks]vectors in 3D
Points A, B, C, D have coordinates (5,7,3)(5,7,3), (7,8,0)(7,8,0), (8,10,3)(8,10,3), (6,9,6)(6,9,6) respectively. Evaluate the scalar product AC→⋅BD→\overrightarrow{AC}\cdot\overrightarrow{BD}, and state what it shows about lines AC and BD.
  1. AAC→⋅BD→=14\overrightarrow{AC}\cdot\overrightarrow{BD}=14; AC and BD have equal length
  2. BAC→⋅BD→=0\overrightarrow{AC}\cdot\overrightarrow{BD}=0; AC and BD are perpendicular
  3. CAC→⋅BD→=6\overrightarrow{AC}\cdot\overrightarrow{BD}=6; AC and BD are neither parallel nor perpendicular
  4. DAC→⋅BD→=−6\overrightarrow{AC}\cdot\overrightarrow{BD}=-6; AC and BD are parallel

Question 1504

[2 marks]vectors in 3D
Points A(5,7,3)(5,7,3) and C(8,10,3)(8,10,3). Find the vector AC→\overrightarrow{AC}.

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Question 1505

[2 marks]vectors in 3D
Points B(7,8,0)(7,8,0) and D(6,9,6)(6,9,6). Find the vector BD→\overrightarrow{BD}.

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Question 1506

[2 marks]vectors in 3D
Points A(5,7,3)(5,7,3) and B(7,8,0)(7,8,0). Find the exact length of ABAB, in simplified surd form.

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Question 1601

[1 marks]logarithms, functions and inverses
Express ln⁡(2x+1)−2ln⁡x−1\ln(2x+1)-2\ln x-1 as a single logarithm.
  1. Aln⁡2x+1x2−1\ln\dfrac{2x+1}{x^2}-1
  2. Bln⁡2x+1ex2\ln\dfrac{2x+1}{ex^2}
  3. Cln⁡2x+1ex\ln\dfrac{2x+1}{ex}
  4. Dln⁡(e(2x+1)x2)\ln\big(e(2x+1)x^2\big)

Question 1602

[1 marks]logarithms, functions and inverses
For what values of xx is y=ln⁡(2x+1)y=\ln(2x+1) defined?
  1. Ax>−1x>-1
  2. Bx>0x>0
  3. Cx≥−12x\geq-\tfrac12
  4. Dx>−12x>-\tfrac12

Question 1603

[1 marks]logarithms, functions and inverses
The function ff is defined by f:x↦(2x−5)2−3f:x\mapsto(2x-5)^2-3, x∈Rx\in\mathbb R, x≥52x\geq\tfrac52. Find the range of ff.
  1. Af(x)≥−3f(x)\geq-3
  2. Bf(x)≥3f(x)\geq3
  3. Cf(x)≥0f(x)\geq0
  4. Df(x)≤−3f(x)\leq-3

Question 1604

[1 marks]logarithms, functions and inverses
The function ff is defined by f:x↦(2x−5)2−3f:x\mapsto(2x-5)^2-3, x∈Rx\in\mathbb R, x≥52x\geq\tfrac52. Find f−1(x)f^{-1}(x).
  1. Af−1(x)=5+x−32f^{-1}(x)=\dfrac{5+\sqrt{x-3}}{2}
  2. Bf−1(x)=x+3+54f^{-1}(x)=\dfrac{\sqrt{x+3}+5}{4}
  3. Cf−1(x)=5+x+32f^{-1}(x)=\dfrac{5+\sqrt{x+3}}{2}
  4. Df−1(x)=5−x+32f^{-1}(x)=\dfrac{5-\sqrt{x+3}}{2}

Question 1605

[1 marks]logarithms, functions and inverses
The point B(2,2)B(2,2) lies on the graph y=f(x)y=f(x). What is the corresponding point on the graph y=f ⁣(x2)y=f\!\left(\dfrac{x}{2}\right)?
  1. A(1,2)(1,2)
  2. B(4,2)(4,2)
  3. C(2,4)(2,4)
  4. D(4,4)(4,4)

Question 1606

[1 marks]logarithms, functions and inverses
The point B(2,2)B(2,2) lies on y=f(x)y=f(x). Why does BB also lie on the graph y=f−1(x)y=f^{-1}(x)?
  1. ABB's coordinates satisfy x=yx=y, so it lies on the line y=xy=x, and any point of ff on y=xy=x also lies on f−1f^{-1}
  2. BBB is the only point where ff is defined
  3. Cf−1f^{-1} is a straight line passing through every point of ff
  4. DBB lies exactly halfway between AA and CC on the curve

Question 1607

[2 marks]logarithms, functions and inverses
Under the transformation y=f ⁣(x2)y=f\!\left(\dfrac{x}{2}\right), the point A(−4,−5)(-4,-5) on y=f(x)y=f(x) maps to which point?

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Question 1608

[2 marks]logarithms, functions and inverses
Under the transformation y=f ⁣(x2)y=f\!\left(\dfrac{x}{2}\right), the point C(4,8)(4,8) on y=f(x)y=f(x) maps to which point?

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Question 1701

[1 marks]coordinate geometry and circles
The circle x2+y2−2x+4y−8=0x^2+y^2-2x+4y-8=0 has centre C. Find the coordinates of C and the radius of the circle.
  1. AC=(−1,2)C=(-1,2), radius 13\sqrt{13}
  2. BC=(1,−2)C=(1,-2), radius 1313
  3. CC=(1,−2)C=(1,-2), radius 13\sqrt{13}
  4. DC=(1,−2)C=(1,-2), radius 5\sqrt5

Question 1702

[1 marks]coordinate geometry and circles
The circle x2+y2−2x+4y−8=0x^2+y^2-2x+4y-8=0 cuts the xx-axis at two points. Find their xx-coordinates.
  1. Ax=4x=4 only (double root)
  2. Bx=−2x=-2 and x=4x=4
  3. Cx=2x=2 and x=−4x=-4
  4. Dx=−1x=-1 and x=8x=8

Question 1703

[1 marks]coordinate geometry and circles
The circle x2+y2−2x+4y−8=0x^2+y^2-2x+4y-8=0 has centre C(1,−2)(1,-2) and radius 13\sqrt{13}, and cuts the xx-axis at A(−2,0)(-2,0) and B(4,0)(4,0). What is the exact value of cos⁡(∠ACB)\cos(\angle ACB)?
  1. A−526-\dfrac{5}{26}
  2. B−513-\dfrac{5}{13}
  3. C513\dfrac{5}{13}
  4. D−1013-\dfrac{10}{13}

Question 1704

[1 marks]coordinate geometry and circles
The circle x2+y2−2x+4y−8=0x^2+y^2-2x+4y-8=0 has centre C(1,−2)(1,-2), radius 13\sqrt{13}, and cuts the xx-axis at A and B with ∠ACB≈1.97\angle ACB\approx1.97 radians (3 s.f.). Since C lies below the xx-axis, find the area of the part of the circle that lies above the xx-axis, to 2 significant figures.
  1. A6.06.0
  2. B6.86.8
  3. C12.812.8
  4. D34.034.0

Question 1705

[2 marks]coordinate geometry and circles
The circle has centre C(1,−2)(1,-2) and cuts the xx-axis at A(−2,0)(-2,0) and B(4,0)(4,0). Find the exact length of chord ABAB.

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Question 1706

[2 marks]coordinate geometry and circles
Using r2=13r^2=13 and ∠ACB≈1.97\angle ACB\approx1.97 radians, find the area of sector ACBACB correct to 1 decimal place.

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Question 1707

[2 marks]coordinate geometry and circles
Triangle ACBACB has base AB=6AB=6 and the perpendicular distance from C to line ABAB equal to 2 (since C is 2 units below the xx-axis). Find the area of triangle ACBACB.

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Question 1801

[1 marks]differentiation and curve sketching
Given y=x3−x2−5x+5y=x^3-x^2-5x+5, find dydx\dfrac{dy}{dx}.
  1. A3x2−x−53x^2-x-5
  2. Bx3−2x−5x^3-2x-5
  3. C3x2−2x−53x^2-2x-5
  4. D3x2−2x+53x^2-2x+5

Question 1802

[1 marks]differentiation and curve sketching
Find the equation of the tangent to the curve y=x3−x2−5x+5y=x^3-x^2-5x+5 at the point where x=2x=2.
  1. Ay=−x+1y=-x+1
  2. By=3x−13y=3x-13
  3. Cy=3x−7y=3x-7
  4. Dy=3x−1y=3x-1

Question 1803

[1 marks]differentiation and curve sketching
For y=x3−x2−5x+5y=x^3-x^2-5x+5, the turning points occur where 3x2−2x−5=03x^2-2x-5=0. Find the xx-coordinates of the turning points.
  1. Ax=53x=\tfrac53 and x=−1x=-1
  2. Bx=1x=1 and x=−53x=-\tfrac53
  3. Cx=53x=\tfrac53 and x=1x=1
  4. Dx=−53x=-\tfrac53 and x=−1x=-1

Question 1804

[1 marks]differentiation and curve sketching
For y=x3−x2−5x+5y=x^3-x^2-5x+5, use the second derivative d2ydx2=6x−2\dfrac{d^2y}{dx^2}=6x-2 to classify the turning point at x=−1x=-1.
  1. AMaximum, since y′′(−1)=−8<0y''(-1)=-8<0
  2. BMaximum, since y′′(−1)=8>0y''(-1)=8>0
  3. CMinimum, since y′′(−1)=8>0y''(-1)=8>0
  4. DMinimum, since y′′(−1)=−8<0y''(-1)=-8<0

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