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ZIMSEC A Level · 6042/1 · J2024

Pure Mathematics Paper 1 June 2024

Questions
52
Total marks
120
Syllabus code
6042/1

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Questions
52
Pass mark
32
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[2 marks]Sequences
A sequence is defined by Un+1=3Un+1U_{n+1}=3U_n+1, with U1=0U_1=0. Write down the first four terms of the sequence.

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Question 102

[1 marks]Sequences
A sequence is defined by Un+1=3Un+1U_{n+1}=3U_n+1, with U1=0U_1=0, so its terms are 00, 11, 44, 1313, 4040, and so on. Which statement best describes the behaviour of the sequence?
  1. AIt converges to the limit −12-\tfrac12
  2. BIt oscillates between two fixed values
  3. CIt is increasing and diverges, the terms growing without bound
  4. DIt is decreasing and converges to zero

Question 103

[2 marks]Sequences
A sequence is defined by Un+1=3Un+1U_{n+1}=3U_n+1. Express U3U_3 in terms of U1U_1.

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Question 201

[1 marks]Exponentials and logarithms
The variables xx and yy are connected by y=aebxy=ae^{bx}, where aa and bb are constants. When ln⁡y\ln y is plotted against xx a straight line is obtained. What is the gradient of that line?
  1. Abb
  2. Baa
  3. Cln⁡a\ln a
  4. Dabab

Question 202

[2 marks]Exponentials and logarithms
The variables xx and yy are connected by y=aebxy=ae^{bx}. When ln⁡y\ln y is plotted against xx, a straight line is obtained passing through (0;ln⁡2)(0;\ln 2) and (3;ln⁡5)(3;\ln 5). Find the exact value of aa.

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Question 203

[3 marks]Exponentials and logarithms
The variables xx and yy are connected by y=aebxy=ae^{bx}. When ln⁡y\ln y is plotted against xx, a straight line is obtained passing through (0;ln⁡2)(0;\ln 2) and (3;ln⁡5)(3;\ln 5). Find the exact value of bb.

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Question 301

[2 marks]Partial fractions
The expression 2x−3x2(x2−4)\dfrac{2x-3}{x^2\left(x^2-4\right)} is written as Ax+Bx2+Cx−2+Dx+2\dfrac{A}{x}+\dfrac{B}{x^2}+\dfrac{C}{x-2}+\dfrac{D}{x+2}. Find the value of BB.

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Question 302

[2 marks]Partial fractions
The expression 2x−3x2(x2−4)\dfrac{2x-3}{x^2\left(x^2-4\right)} is written as Ax+Bx2+Cx−2+Dx+2\dfrac{A}{x}+\dfrac{B}{x^2}+\dfrac{C}{x-2}+\dfrac{D}{x+2}. Find the value of CC.

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Question 303

[3 marks]Partial fractions
Express 2x−3x2(x2−4)\dfrac{2x-3}{x^2\left(x^2-4\right)} in partial fractions.

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Question 401

[2 marks]Exponential equations
The substitution u=e2xu=e^{2x} turns the equation e2x+e−2x5=1\dfrac{e^{2x}+e^{-2x}}{5}=1 into a quadratic in uu. Write down that quadratic equation.

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Question 402

[2 marks]Exponential equations
Solve the equation u2−5u+1=0u^2-5u+1=0, giving both roots in exact surd form.

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Question 403

[3 marks]Exponential equations
Solve the equation e2x+e−2x5=1\dfrac{e^{2x}+e^{-2x}}{5}=1, giving the answer in exact form.

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Question 501

[2 marks]Quadratic inequalities
Expand and simplify the inequality (x−3)2>2x+1(x-3)^2>2x+1 into the form x2+px+q>0x^2+px+q>0.

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Question 502

[2 marks]Quadratic inequalities
Find, in exact surd form, the roots of the equation x2−8x+8=0x^2-8x+8=0.

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Question 503

[3 marks]Quadratic inequalities
Find the set of values of xx for which (x−3)2>2x+1(x-3)^2>2x+1, giving your answer in exact form.

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Question 601

[2 marks]Circular measure
A chord subtends an angle of 2θ2\theta radians at the centre of a circle of radius rr. Write down an expression, in terms of rr and θ\theta, for the area of the minor segment cut off by the chord.

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Question 602

[3 marks]Circular measure
A chord subtends an angle of 2θ2\theta radians at the centre of a circle of radius rr. The area of the minor segment is 16\dfrac16 of the area of the major segment. Find, in terms of π\pi, the exact value of 2θ−sin⁡2θ2\theta-\sin2\theta.

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Question 603

[2 marks]Circular measure
For a chord subtending 2θ2\theta radians at the centre of a circle, the condition that the minor segment is 16\dfrac16 of the major segment leads to 2θ−sin⁡2θ=2π72\theta-\sin2\theta=\dfrac{2\pi}{7}. Which of these is an equivalent form of that result?
  1. Asin⁡2θ=2π7−2θ\sin2\theta=\dfrac{2\pi}{7}-2\theta
  2. Bsin⁡2θ=27(7θ−π)\sin2\theta=\dfrac{2}{7}(7\theta-\pi)
  3. Csin⁡2θ=27(7θ+π)\sin2\theta=\dfrac{2}{7}(7\theta+\pi)
  4. Dsin⁡2θ=72(2θ−π)\sin2\theta=\dfrac{7}{2}(2\theta-\pi)

Question 701

[3 marks]Binomial expansion
Expand (1−2x)12(1-2x)^{\frac12} up to and including the term in x2x^2, simplifying the coefficients.

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Question 702

[1 marks]Binomial expansion
State the values of xx for which the binomial expansion of (1−2x)12(1-2x)^{\frac12} is valid.

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Question 703

[2 marks]Binomial expansion
Using the expansion (1−2x)12≈1−x−12x2(1-2x)^{\frac12}\approx1-x-\dfrac12x^2, find the value it gives when x=19x=\dfrac19, as a fraction in its lowest terms.

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Question 704

[2 marks]Binomial expansion
Putting x=19x=\dfrac19 in the expansion (1−2x)12≈1−x−12x2(1-2x)^{\frac12}\approx1-x-\dfrac12x^2 gives 73≈143162\dfrac{\sqrt7}{3}\approx\dfrac{143}{162}. Write down the resulting approximation for 7\sqrt7 as a fraction.

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Question 801

[1 marks]Coordinate geometry
The equation of line ll is y+3x−9=0y+3x-9=0. Write down the gradient of ll.

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Question 802

[3 marks]Coordinate geometry
The equation of line ll is y+3x−9=0y+3x-9=0. Find the equation of the line mm that is perpendicular to ll and passes through the point A(1;6), giving your answer in the form ax+by+c=0ax+by+c=0.

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Question 803

[2 marks]Coordinate geometry
The equation of line ll is y+3x−9=0y+3x-9=0. Find the equation of the line parallel to ll that passes through the point B(5;6), giving your answer in the form ax+by+c=0ax+by+c=0.

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Question 804

[3 marks]Coordinate geometry
Find the perpendicular distance of the point B(5;6) from the line x−3y+17=0x-3y+17=0, giving your answer in exact form.

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Question 901

[2 marks]Completing the square, range of a function
Express x2+6x+5x^2+6x+5 in the form (x+b)2+c(x+b)^2+c, where bb and cc are constants.

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Question 902

[1 marks]Completing the square, range of a function
Given that x2+6x+5=(x+3)2−4x^2+6x+5=(x+3)^2-4, state the turning point of the graph of y=x2+6x+5y=x^2+6x+5.

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Question 903

[2 marks]Completing the square, range of a function
Setting y=1x2+6x+5y=\dfrac{1}{x^2+6x+5} and rearranging gives the quadratic yx2+6yx+(5y−1)=0yx^2+6yx+(5y-1)=0 in xx. Write down the discriminant condition for xx to be real, simplified to the form ay2+by≥0ay^2+by\ge0.

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Question 904

[3 marks]Completing the square, range of a function
Find the set of values taken by y=1x2+6x+5y=\dfrac{1}{x^2+6x+5} for real values of xx.

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Question 1001

[3 marks]Complex numbers, polynomials
Given that f(x)=x4+x3+23x2+25x−50f(x)=x^4+x^3+23x^2+25x-50, evaluate f(−5i)f(-5i), and hence state whether −5i-5i is a root of f(x)=0f(x)=0.

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Question 1002

[2 marks]Complex numbers, polynomials
The polynomial f(x)=x4+x3+23x2+25x−50f(x)=x^4+x^3+23x^2+25x-50 has real coefficients, and −5i-5i is a root of f(x)=0f(x)=0. Which of the following must therefore also be a root?
  1. A−5-5
  2. B55
  3. C−15i-\dfrac{1}{5}i
  4. D5i5i

Question 1003

[2 marks]Complex numbers, polynomials
The polynomial f(x)=x4+x3+23x2+25x−50f(x)=x^4+x^3+23x^2+25x-50 has x2+25x^2+25 as a factor. Find the other quadratic factor.

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Question 1004

[3 marks]Complex numbers, polynomials
Solve the equation x4+x3+23x2+25x−50=0x^4+x^3+23x^2+25x-50=0 completely, given that −5i-5i is one of its roots.

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Question 1101

[2 marks]Functions
The functions gg and hh are defined by g:x→4x+1g:x\to 4x+1 and h:x→1x−3h:x\to\dfrac{1}{x-3}, x≠3x\ne3. Find gh(x)gh(x), giving your answer as a single fraction.

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Question 1102

[1 marks]Functions
The functions gg and hh are defined by g:x→4x+1g:x\to 4x+1 and h:x→1x−3h:x\to\dfrac{1}{x-3}, x≠3x\ne3, and gh(x)=x+1x−3gh(x)=\dfrac{x+1}{x-3}. State the domain of ghgh.

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Question 1103

[3 marks]Functions
The function ff is defined by f:x→x2+2xf:x\to x^2+2x for x∈Rx\in\mathbb{R}, x≥−1x\ge-1. Find f−1(x)f^{-1}(x).

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Question 1104

[2 marks]Functions
The function gg is defined by g:x→4x+1g:x\to 4x+1 for −2≤x≤3-2\le x\le3. State the coordinates of the two end points of the graph of y=∣g(x)∣y=\left|g(x)\right|.

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Question 1105

[1 marks]Functions
The function gg is defined by g:x→4x+1g:x\to 4x+1 for −2≤x≤3-2\le x\le3. State the range of ∣g(x)∣\left|g(x)\right|.

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Question 1201

[2 marks]Trigonometric identities and equations
Write cos⁡θ1−cos⁡θ−cos⁡θ1+cos⁡θ\dfrac{\cos\theta}{1-\cos\theta}-\dfrac{\cos\theta}{1+\cos\theta} as a single fraction in terms of cos⁡θ\cos\theta and sin⁡θ\sin\theta.

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Question 1202

[2 marks]Trigonometric identities and equations
The expression 2cos⁡2θsin⁡2θ\dfrac{2\cos^2\theta}{\sin^2\theta} is identical to which of the following?
  1. Acot⁡22θ\cot^2 2\theta
  2. B2cosec⁡2θ2\operatorname{cosec}^2\theta
  3. C2cot⁡2θ2\cot^2\theta
  4. D2tan⁡2θ2\tan^2\theta

Question 1203

[2 marks]Trigonometric identities and equations
Given the identity cos⁡θ1−cos⁡θ−cos⁡θ1+cos⁡θ≡2cot⁡2θ\dfrac{\cos\theta}{1-\cos\theta}-\dfrac{\cos\theta}{1+\cos\theta}\equiv2\cot^2\theta, the equation cos⁡θ1−cos⁡θ−cos⁡θ1+cos⁡θ=1\dfrac{\cos\theta}{1-\cos\theta}-\dfrac{\cos\theta}{1+\cos\theta}=1 reduces to 2cot⁡2θ=12\cot^2\theta=1. Find the exact values of tan⁡θ\tan\theta.

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Question 1204

[3 marks]Trigonometric identities and equations
Solve the equation cos⁡θ1−cos⁡θ−cos⁡θ1+cos⁡θ=1\dfrac{\cos\theta}{1-\cos\theta}-\dfrac{\cos\theta}{1+\cos\theta}=1 for 0∘≤θ≤360∘0^\circ\le\theta\le360^\circ, giving all answers to the nearest degree.

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Question 1301

[2 marks]Roots of equations, iteration
To show graphically that x3+x−4=0x^3+x-4=0 has exactly one real root, the equation is rearranged and two graphs are sketched on the same axes. Which pair of graphs makes the argument work most simply?
  1. Ay=x3y=x^3 and y=4−xy=4-x
  2. By=x3+xy=x^3+x and y=x−4y=x-4
  3. Cy=x2y=x^2 and y=4−xy=4-x
  4. Dy=x3−4y=x^3-4 and y=−x2y=-x^2

Question 1302

[2 marks]Roots of equations, iteration
Let f(x)=x3+x−4f(x)=x^3+x-4. Find the values of f(1)f(1) and f(1.5)f(1.5).

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Question 1303

[1 marks]Roots of equations, iteration
For f(x)=x3+x−4f(x)=x^3+x-4, the values f(1)=−2f(1)=-2 and f(1.5)=0.875f(1.5)=0.875 have been calculated. What does this pair of values show?
  1. Af(x)=0f(x)=0 has two roots between 1 and 1.5
  2. Bff changes sign, so a root of f(x)=0f(x)=0 lies between 1 and 1.5
  3. Cff has a maximum between 1 and 1.5
  4. DThere is no root of f(x)=0f(x)=0 between 1 and 1.5

Question 1304

[2 marks]Roots of equations, iteration
Using the iteration xn+1=4xn−1x_{n+1}=\sqrt{\dfrac{4}{x_n}-1} with x1=1.37x_1=1.37, find x2x_2 correct to 4 decimal places.

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Question 1305

[3 marks]Roots of equations, iteration
Using the iteration xn+1=4xn−1x_{n+1}=\sqrt{\dfrac{4}{x_n}-1} with x1=1.37x_1=1.37, approximate the root of x3+x−4=0x^3+x-4=0 correct to 2 decimal places.

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Question 1401

[3 marks]Implicit differentiation
The equation of a curve is y2−3xy+2x2=6y^2-3xy+2x^2=6. Use implicit differentiation to find dydx\dfrac{dy}{dx} in terms of xx and yy.

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Question 1402

[3 marks]Implicit differentiation
The equation of a curve is y2−3xy+2x2=6y^2-3xy+2x^2=6. Find the value of yy on the curve where x=1x=1 and y>0y>0.

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Question 1403

[2 marks]Implicit differentiation
For the curve y2−3xy+2x2=6y^2-3xy+2x^2=6 the gradient is given by dydx=3y−4x2y−3x\dfrac{dy}{dx}=\dfrac{3y-4x}{2y-3x}. Find the gradient of the curve at the point (1;4)(1;4).

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Question 1404

[3 marks]Implicit differentiation
The curve y2−3xy+2x2=6y^2-3xy+2x^2=6 has gradient 85\dfrac{8}{5} at the point (1;4)(1;4). Find the equation of the tangent to the curve at that point, in the form ax+by+c=0ax+by+c=0.

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