Danho
ZIMSEC A Level · N2022

Chemistry Paper 2 November 2022

Questions
43
Total marks
60
Time allowed
75 min

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Questions
43
Pass mark
26
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]atomic structure and mass spectrometry
A gaseous atom of an element X loses electrons to form a cation. The chemical change which occurs is called
  1. Aatomisation
  2. Bhydration
  3. Creduction
  4. Dionisation

Question 102

[1 marks]atomic structure and mass spectrometry
The electronic configuration of the O2−O^{2-} ion is
  1. A1s22s22p41s^22s^22p^4
  2. B1s22s22p61s^22s^22p^6
  3. C1s22s22p63s21s^22s^22p^63s^2
  4. D1s22s22p63s23p61s^22s^22p^63s^23p^6

Question 103

[1 marks]atomic structure and mass spectrometry
The mass spectrum of element Q shows two peaks of equal abundance at m/em/e = 79 and 81. The relative atomic mass of Q is
  1. A79.0
  2. B79.9
  3. C80.0
  4. D81.0

Question 104

[3 marks]atomic structure and mass spectrometry
In an electric field, 11H−^1_1H^- deflects towards the positive plate while 12H+^2_1H^+ and 24He2+^4_2He^{2+} both deflect towards the negative plate. Compared with 12H+^2_1H^+, the ion 24He2+^4_2He^{2+} deflects
  1. Atowards the positive plate instead, because helium is a noble gas and does not respond to the field.
  2. Bless, because its larger mass gives it a smaller charge-to-mass ratio despite its greater charge.
  3. Cmore, because its charge is twice as great, and charge dominates completely over mass in electric deflection.
  4. Dby exactly the same amount, since both ions carry an overall positive charge and are accelerated identically.

Question 105

[2 marks]atomic structure and mass spectrometry
The general equation representing ionisation of a gaseous atom X, forming a cation of charge n+, is

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Question 106

[1 marks]atomic structure and mass spectrometry
A graph of successive log⁡10\log_{10}(ionisation energy) against number of electrons removed from O2−O^{2-} shows a large jump in value
  1. Aat every single electron removed, rising by a constant amount each time.
  2. Bonly after all ten electrons have been removed, as a single final jump.
  3. Cbetween removal of the electrons in the outer (n=2) shell and those in the inner (n=1) shell.
  4. Dimmediately after the very first electron is removed from the ion, before any other large jumps occur at all.

Question 107

[1 marks]atomic structure and mass spectrometry
AgI(s)AgI_{(s)} does not dissolve in aqueous ammonia because
  1. Asilver(I) does not form complexes with nitrogen-donor ligands such as ammonia.
  2. Bits lattice enthalpy is so large, and I−I^- such a poor ligand, that complex formation with NH3NH_3 cannot release enough energy to overcome it.
  3. Ciodide ions react directly with the ammonia molecules in solution to form a completely separate, insoluble compound that simply coats over the AgI crystals.
  4. Dammonia is too weak a base to dissolve any silver halide under any conditions at all.

Question 201

[1 marks]reaction kinetics
The order of reaction with respect to a reactant is
  1. Athe number of moles of it shown in the equation
  2. Bthe power to which its concentration is raised in the rate equation
  3. Cthe number of particles which collide in one step
  4. Dthe time taken for its concentration to halve

Question 202

[1 marks]reaction kinetics
The reaction H2O2+2I−+2H+→2H2O+I2H_2O_2 + 2I^- + 2H^+ \rightarrow 2H_2O + I_2 is first order with respect to H2O2H_2O_2 and to I−I^-, and zero order with respect to H+H^+. The rate equation is
  1. Arate =k[H2O2][I−][H+]= k[H_2O_2][I^-][H^+]
  2. Brate =k[H2O2][I−]= k[H_2O_2][I^-]
  3. Crate =k[H2O2]2[I−]= k[H_2O_2]^2[I^-]
  4. Drate =k[H2O2][I−]2[H+]2= k[H_2O_2][I^-]^2[H^+]^2

Question 203

[1 marks]reaction kinetics
In the kinetics experiment the total volume of each mixture was kept constant so that
  1. Athe concentration of each reactant depended only on the volume of that reactant added
  2. Bthe temperature would not change
  3. Cthe reaction would go to completion
  4. Dthe same apparatus could be used each time

Question 204

[1 marks]reaction kinetics
The rate of a chemical reaction is defined as the change in concentration of a reactant or product per unit

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Question 205

[3 marks]reaction kinetics
Comparing two experiments in which only [I−][I^-] is halved (with [H2O2][H_2O_2] and [H+][H^+] unchanged), the initial rate is found to halve. This shows the reaction is
  1. Afirst order with respect to I−I^-, since rate is directly proportional to [I−][I^-].
  2. Bsecond order with respect to I−I^-, since halving a concentration always halves the rate regardless of order.
  3. Czero order with respect to I−I^-, since the rate change exactly matches the concentration change.
  4. Dfirst order overall, regardless of which reactant's concentration was changed in the experiment.

Question 206

[1 marks]reaction kinetics
The species involved in the rate-determining step of this reaction's mechanism are

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Question 207

[2 marks]reaction kinetics
The relative rate of this reaction can be monitored by
  1. Atitrating the entire reaction mixture with sodium thiosulfate right at the very start, before any reaction occurs.
  2. Brecording the temperature rise of the mixture at fixed time intervals throughout the entire reaction.
  3. Ctiming how long it takes for a fixed, small amount of iodine to appear (using a starch indicator), then taking 1/time as the relative rate.
  4. Dmeasuring the total mass of the whole reaction flask continuously on an electronic balance for the entire duration of the reaction, from start to finish.

Question 301

[1 marks]Group II chemistry and bonding
The observations made when magnesium burns in oxygen are
  1. Aa yellow flame and a brown solid
  2. Ba green flame and a white smoke only
  3. Ca brilliant white flame and a white ash
  4. Da blue flame and a black residue

Question 302

[1 marks]Group II chemistry and bonding
The equation for the reaction between magnesium and steam is
  1. AMg(s)+H2O(g)→MgH2(s)+12O2(g)Mg(s) + H_2O(g) \rightarrow MgH_2(s) + \frac{1}{2}O_2(g)
  2. BMg(s)+2H2O(g)→Mg(OH)2(s)+H2(g)Mg(s) + 2H_2O(g) \rightarrow Mg(OH)_2(s) + H_2(g)
  3. CMg(s)+H2O(g)→MgO(s)+H2(g)Mg(s) + H_2O(g) \rightarrow MgO(s) + H_2(g)
  4. D2Mg(s)+H2O(g)→Mg2O(s)+H2(g)2Mg(s) + H_2O(g) \rightarrow Mg_2O(s) + H_2(g)

Question 303

[1 marks]Group II chemistry and bonding
A suspension of magnesium hydroxide is preferred to calcium hydroxide for treating acid indigestion because it is
  1. Aable to react with water in the stomach
  2. Ba stronger base
  3. Cmuch cheaper to produce
  4. Dfar less soluble, so the suspension is only weakly alkaline

Question 304

[1 marks]Group II chemistry and bonding
Down Group (II), the trend in solubility of the metal oxides/hydroxides is that solubility

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Question 305

[2 marks]Group II chemistry and bonding
CO2CO_2 has
  1. Aa giant covalent (macromolecular) structure, with every carbon and oxygen atom linked in a continuous 3D lattice.
  2. Ban ionic lattice structure, with C4+C^{4+} and O2−O^{2-} ions held together by strong electrostatic forces.
  3. Ca simple molecular (covalent) structure, held together between molecules only by weak van der Waals forces.
  4. Da metallic structure, with delocalised electrons free to move throughout the solid.

Question 306

[2 marks]Group II chemistry and bonding
Unlike CO2CO_2, SiO2SiO_2 has
  1. Aa giant covalent (macromolecular) structure, with each Si atom covalently bonded to 4 O atoms tetrahedrally.
  2. Ba layered structure like graphite, with only weak forces holding the layers together.
  3. Ca simple molecular structure, with only weak van der Waals forces acting between separate, discrete SiO2SiO_2 molecules in the solid.
  4. Dan ionic lattice, with Si4+Si^{4+} and O2−O^{2-} ions arranged in a giant ionic structure.

Question 307

[2 marks]Group II chemistry and bonding
One use of SiO2SiO_2 (silicon dioxide) is in making

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Question 401

[1 marks]organic chemistry - synthesis
Benzocaine is the ethyl ester of 4-aminobenzoic acid. Two functional groups present in it are
  1. Aester and amine
  2. Bcarboxylic acid and amide
  3. Cester and nitro
  4. Damide and ketone

Question 402

[1 marks]organic chemistry - synthesis
Benzocaine is prepared from compound B in two steps. Compound B is
  1. A4-aminobenzoic acid
  2. B4-nitrobenzoic acid
  3. Cethyl benzoate
  4. Dbenzoic acid

Question 403

[1 marks]organic chemistry - synthesis
In step 2 the nitro group of ethyl 4-nitrobenzoate is converted into an amine group. The reagents and conditions are
  1. ANaNO2NaNO_2 and HCl below 10 °C
  2. Bethanol and concentrated H2SO4H_2SO_4 under reflux
  3. CSn and concentrated HCl, followed by NaOH
  4. Dconcentrated HNO3HNO_3 and H2SO4H_2SO_4 at 55 °C

Question 404

[2 marks]organic chemistry - synthesis
Heating benzocaine in dilute hydrochloric acid hydrolyses the ester group and protonates the amine, giving ethanol and
  1. A4-aminobenzoic acid as its ammonium salt (the −NH2-NH_2 group protonated to −NH3+Cl−-NH_3^+Cl^-).
  2. Bethyl 4-aminobenzoate, since only the ester linkage's alkyl group is affected by hydrolysis.
  3. C4-nitrobenzoic acid, since the amine group is oxidised back to a nitro group under acidic conditions.
  4. Dbenzoic acid only, with the amine group completely removed from the aromatic ring.

Question 405

[2 marks]organic chemistry - synthesis
Compound X, formed in step 1 from 4-nitrobenzoic acid, is

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Question 406

[2 marks]organic chemistry - synthesis
The reagents and conditions for step 1 (esterification of 4-nitrobenzoic acid) are

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Question 407

[1 marks]organic chemistry - synthesis
The type of reaction occurring in step 1, forming compound X from 4-nitrobenzoic acid, is called

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Question 501

[1 marks]organic chemistry - reactions and isomerism
Excluding geometrical isomers, the isomers of C4H8C_4H_8 are
  1. Abutan-1-ol, butan-2-ol and methylpropan-2-ol
  2. Bbut-1-yne, but-2-yne and cyclobutene
  3. Cbut-1-ene, but-2-ene and butane
  4. Dbut-1-ene, 2-methylpropene, cyclobutane and methylcyclopropane

Question 502

[1 marks]organic chemistry - reactions and isomerism
Compound G contains an −OH-OH group. Its reaction with SOCl2SOCl_2 replaces the −OH-OH group by
  1. A=O=O
  2. B−Cl-Cl
  3. C−H-H
  4. D−OSO2Cl-OSO_2Cl

Question 503

[1 marks]organic chemistry - reactions and isomerism
Platinum is used in the catalytic converters of motor vehicles because it is
  1. Aa good conductor of heat
  2. Bunreactive and an efficient catalyst for the oxidation of exhaust gases
  3. Ccheap and easily replaced
  4. Dreadily oxidised by exhaust gases

Question 504

[3 marks]organic chemistry - reactions and isomerism
Hot acidified KMnO4KMnO_4 reacts with compound G (which contains a C=CC=C double bond, an −OH-OH group and a C=OC=O group) by
  1. Aoxidatively cleaving the C=CC=C double bond and oxidising the −OH-OH and carbonyl groups to carboxylic acids or CO2CO_2 as appropriate.
  2. Breducing the C=OC=O group to −OH-OH, while leaving the C=CC=C double bond and existing −OH-OH group unchanged.
  3. Csubstituting the −OH-OH group with a −Mn-Mn containing group, with no effect on the C=CC=C or C=OC=O groups.
  4. Dpolymerising the entire molecule through addition across its C=CC=C double bond only, leaving both the −OH-OH and C=OC=O groups completely unreacted throughout.

Question 505

[2 marks]organic chemistry - reactions and isomerism
2,4-DNPH in acidified methanol reacts with the carbonyl group of G to give an orange precipitate of a

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Question 506

[1 marks]organic chemistry - reactions and isomerism
The type of reaction that occurs between G and SOCl2SOCl_2 is

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Question 507

[1 marks]organic chemistry - reactions and isomerism
Besides the chloro compound, the gaseous by-products formed when G reacts with SOCl2SOCl_2 are

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Question 601

[1 marks]analytical techniques - genetic fingerprinting
Genetic fingerprinting is a technique which
  1. Aseparates proteins according to their solubility
  2. Bidentifies the elements present in a sample
  3. Cmeasures the mass of DNA in a cell
  4. Dproduces a pattern of DNA fragments unique to an individual

Question 602

[1 marks]analytical techniques - genetic fingerprinting
During electrophoresis, DNA fragments move towards the positive electrode and the smaller fragments
  1. Atravel further through the gel
  2. Btravel less far through the gel
  3. Cdo not move at all
  4. Dmove towards the negative electrode

Question 603

[1 marks]analytical techniques - genetic fingerprinting
An application of genetic fingerprinting other than criminal investigation is
  1. Ameasuring the pH of blood
  2. Bestimating the age of rocks
  3. Cdetecting metal ions in water
  4. Ddetermining paternity

Question 604

[1 marks]analytical techniques - genetic fingerprinting
In electrophoresis, DNA fragments migrate towards the positive electrode because DNA is

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Question 605

[1 marks]analytical techniques - genetic fingerprinting
In gel electrophoresis, DNA fragments are separated primarily on the basis of their

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Question 606

[2 marks]analytical techniques - genetic fingerprinting
In DNA profiling, a suspect is identified as a likely match to a crime-scene sample when
  1. Athe suspect's bands are a similar colour to the crime-scene sample's bands after staining.
  2. Bthe suspect's DNA sample migrates exactly the same total distance through the gel as the crime-scene sample, regardless of the actual band pattern observed.
  3. Cthe pattern (number and position) of bands in the suspect's DNA profile aligns exactly with the crime-scene sample's bands.
  4. Dthe suspect's DNA sample produces more bands in total than the crime-scene sample.

Question 607

[2 marks]analytical techniques - genetic fingerprinting
Besides criminal investigation and paternity testing, another application of genetic fingerprinting is

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Question 608

[1 marks]analytical techniques - genetic fingerprinting
In gel electrophoresis, the separated DNA bands are made visible using

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The answers, and why they are the answers

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