Danho
ZIMSEC A Level · N2018

Chemistry Paper 2 November 2018

Questions
45
Total marks
70
Time allowed
75 min

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Questions
45
Pass mark
27
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]atomic structure and ionization energy
The species 79Br^{79}Br and 81Br^{81}Br are
  1. Aisomers
  2. Bisotopes
  3. Callotropes
  4. Disoelectronic ions

Question 102

[1 marks]atomic structure and ionization energy
A sample of bromine contains 50.52 % 79Br^{79}Br and the remainder 81Br^{81}Br. Its relative atomic mass is
  1. A79.0
  2. B79.5
  3. C80.0
  4. D81.0

Question 103

[1 marks]atomic structure and ionization energy
The equation which represents the second ionisation energy of oxygen is
  1. AO−(g)→O(g)+e−O^-(g) \rightarrow O(g) + e^-
  2. BO+(g)→O2+(g)+e−O^+(g) \rightarrow O^{2+}(g) + e^-
  3. CO(g)+e−→O−(g)O(g) + e^- \rightarrow O^-(g)
  4. DO(g)→O2+(g)+2e−O(g) \rightarrow O^{2+}(g) + 2e^-

Question 104

[2 marks]atomic structure and ionization energy
Relative atomic mass is defined as
  1. Athe mass of one atom of an element compared with the mass of one atom of hydrogen-1, ignoring how abundant each isotope actually is
  2. Bthe total combined mass of every isotope of an element simply added together, without any weighting by natural abundance
  3. Cthe mass number of only the single most abundant isotope of the element, ignoring all of its other isotopes entirely
  4. Dthe weighted average mass of the isotopes of an element, relative to 1/12 the mass of a carbon-12 atom

Question 105

[2 marks]atomic structure and ionization energy
An increase in nuclear charge, with atomic radius and shielding unchanged, tends to affect the first ionisation energy of an element by
  1. Araising it, because the extra positive charge attracts the outer electron more strongly
  2. Bleaving it completely unchanged, because nuclear charge is assumed to only ever affect the innermost core electrons in every case
  3. Clowering it, because an increase in nuclear charge automatically increases the amount of electron shielding present as well
  4. Dlowering it, because the extra protons in the nucleus repel the outer electrons away from each other repeatedly

Question 106

[2 marks]atomic structure and ionization energy
An increase in atomic radius, with nuclear charge and shielding unchanged, tends to affect the first ionisation energy of an element by
  1. Araising it, because the nucleus attracts the outer electron over a much longer range than before
  2. Bleaving it completely unchanged, because atomic radius does not affect the attraction between the nucleus and the outer electron at all
  3. Clowering it, because the outer electron is farther from the nucleus and less strongly attracted
  4. Draising it, because a larger atom automatically has more shielding electrons surrounding its nucleus at all times

Question 107

[1 marks]atomic structure and ionization energy
Increased shielding by inner-shell electrons lowers the effective nuclear charge felt by the outer electron, so the first ionisation energy

Answer this when you sit the paper.

Question 201

[1 marks]energetics and lattice enthalpy
The bond energy of a covalent bond is
  1. Athe energy needed to melt one mole of the compound
  2. Bthe energy needed to remove one mole of electrons from the bond
  3. Cthe energy released when one mole of the bond is formed in solution
  4. Dthe energy needed to break one mole of the bond in the gaseous state

Question 202

[1 marks]energetics and lattice enthalpy
For CH4+Cl2→CH3Cl+HClCH_4 + Cl_2 \rightarrow CH_3Cl + HCl, given C−HC-H = 413, Cl−ClCl-Cl = 243, C−ClC-Cl = 346 and H−ClH-Cl = 432 kJ mol−1432\ kJ\,mol^{-1}, the enthalpy change is
  1. A−122-122
  2. B−56-56
  3. C+56+56
  4. D+122+122

Question 203

[1 marks]energetics and lattice enthalpy
The lattice enthalpy of an ionic compound becomes more exothermic when
  1. Athe ionic charges decrease and the ionic radii decrease
  2. Bthe ionic charges increase and the ionic radii decrease
  3. Cthe ionic charges decrease and the ionic radii increase
  4. Dthe ionic charges increase and the ionic radii increase

Question 204

[2 marks]energetics and lattice enthalpy
A large lattice enthalpy tends to make an ionic compound
  1. Aless soluble, because more energy is needed to separate the ions before they can be hydrated
  2. Bmore soluble, because the ions separate from the lattice more easily than usual in this case
  3. Cunaffected in solubility, since lattice enthalpy and solubility are considered to be completely unrelated properties
  4. Dmore soluble, because a larger lattice enthalpy always favours the hydration of the separated ions

Question 205

[2 marks]energetics and lattice enthalpy
A higher ionic charge increases the magnitude of lattice enthalpy because
  1. Amore energy is released when the gaseous ions are formed
  2. Bthe lattice adopts a different, more stable crystal structure
  3. Cthe electrostatic attraction between the ions is stronger
  4. Dthe ions become larger, increasing surface contact

Question 206

[2 marks]energetics and lattice enthalpy
A smaller ionic radius increases the magnitude of lattice enthalpy because
  1. Athe ions somehow carry a higher electrical charge as a direct result of being smaller
  2. Bthe ions are closer together, increasing the electrostatic attraction between them
  3. Cthe ions pack less efficiently into the lattice, leaving larger empty gaps throughout the structure
  4. Dthe lattice becomes covalent rather than ionic once the ions fall below a certain critical size

Question 207

[1 marks]energetics and lattice enthalpy
If the hydration enthalpy of the ions exceeds the lattice enthalpy of the compound, the compound will

Answer this when you sit the paper.

Question 301

[1 marks]group II and group VII chemistry
The equation for the thermal decomposition of magnesium carbonate is
  1. A2MgCO3→Mg2O+2CO22MgCO_3 \rightarrow Mg_2O + 2CO_2
  2. BMgCO3→Mg(OH)2+CO2MgCO_3 \rightarrow Mg(OH)_2 + CO_2
  3. CMgCO3→MgO+CO2MgCO_3 \rightarrow MgO + CO_2
  4. DMgCO3→Mg+CO2+12O2MgCO_3 \rightarrow Mg + CO_2 + \frac{1}{2}O_2

Question 302

[1 marks]group II and group VII chemistry
Down Group II the thermal stability of the carbonates
  1. Aincreases, because the cation polarises the carbonate ion less
  2. Bincreases, because the carbonates become more covalent
  3. Cremains constant, because the charge on the cation is unchanged
  4. Ddecreases, because the cations become larger

Question 303

[1 marks]group II and group VII chemistry
Concentrated sulphuric acid is added to solid potassium bromide. The observations are
  1. Amisty white fumes only
  2. Ba green gas and a white precipitate
  3. Creddish-brown fumes together with a pungent gas
  4. Da violet vapour and a yellow solid

Question 304

[1 marks]group II and group VII chemistry
Give one use of magnesium oxide, one of the products of the thermal decomposition of magnesium carbonate.

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Question 305

[2 marks]group II and group VII chemistry
Write an equation for the reaction between solid sodium chloride and concentrated sulfuric acid.

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Question 306

[2 marks]group II and group VII chemistry
Concentrated sulfuric acid is added to solid sodium chloride. The observation is
  1. Aa green gas is evolved, accompanied by a strong smell of bleach throughout the flask
  2. Ba violet vapour forms together with a yellow solid deposit around the neck of the flask
  3. Csteamy, misty white fumes of hydrogen chloride are evolved
  4. Da brown precipitate forms slowly, with no gas evolved at any point during the reaction

Question 307

[2 marks]group II and group VII chemistry
Unlike potassium bromide, sodium chloride does not produce coloured fumes with concentrated sulfuric acid because
  1. Achlorine gas produced in this reaction is colourless under all laboratory conditions and temperatures
  2. Bchloride ions are not strong enough reducing agents to be oxidised by concentrated sulfuric acid
  3. Csodium ions themselves are simply too large in radius ever to be oxidised by any common oxidising agent
  4. Dhydrogen chloride gas is coloured only while it remains hot, becoming colourless again once it cools down

Question 401

[1 marks]amines
The first step in preparing propylamine from chloroethane is to heat the chloroethane under reflux with
  1. Apotassium cyanide in ethanol
  2. Bacidified potassium dichromate(VI)
  3. Caqueous sodium hydroxide
  4. Dammonia in ethanol

Question 402

[1 marks]amines
Propylamine is a stronger base than phenylamine because in propylamine
  1. Athe nitrogen atom carries a positive charge
  2. Bthe molecule is smaller and more volatile
  3. Cthe lone pair is delocalised over the carbon chain
  4. Dthe alkyl group releases electrons, making the lone pair on nitrogen more available

Question 403

[1 marks]amines
Propylamine dissolves in water according to CH3CH2CH2NH2+H2O⇌CH3CH2CH2NH3++OH−CH_3CH_2CH_2NH_2 + H_2O \rightleftharpoons CH_3CH_2CH_2NH_3^+ + OH^-. The solution formed is
  1. Aacidic
  2. Bneutral
  3. Calkaline
  4. Damphoteric

Question 404

[2 marks]amines
Propanenitrile, CH3CH2CNCH_3CH_2CN, is then converted into propylamine by reduction using
  1. Aaqueous sodium hydroxide solution, heated strongly under reflux for several hours
  2. Bconcentrated sulfuric acid, warmed gently in the presence of a small amount of water
  3. Clithium tetrahydridoaluminate (LiAlH4LiAlH_4) in dry ether, or hydrogen with a nickel catalyst
  4. Dacidified potassium dichromate(VI), heated gently under reflux for a considerable period of time

Question 405

[2 marks]amines
Write an equation to show propylamine acting as a base when it dissolves in water.

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Question 406

[2 marks]amines
The overall sequence chloroethane →\rightarrow propanenitrile →\rightarrow propylamine is best described as
  1. Aa reduction reaction only, occurring with absolutely no change whatsoever in the total number of carbon atoms present
  2. Bchain extension: a nucleophilic substitution that adds a carbon atom, followed by reduction of the nitrile to an amine
  3. Can elimination reaction immediately followed by an addition polymerisation of the resulting alkene product
  4. Da single-step hydrolysis reaction that converts the nitrile directly into a carboxylic acid product

Question 407

[1 marks]amines
Name the intermediate compound formed when chloroethane reacts with ethanolic potassium cyanide.

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Question 501

[1 marks]organic reactions of carbonyl and alkene
2,4-dinitrophenylhydrazine is added to a compound containing a ketone group. The observation is
  1. Athe solution turns green
  2. Ba silver mirror forms
  3. Can orange precipitate forms
  4. Da white precipitate forms

Question 502

[1 marks]organic reactions of carbonyl and alkene
Cold dilute potassium manganate(VII) reacts with a carbon-carbon double bond to give
  1. Aa ketone
  2. Ba diol
  3. Can epoxide
  4. Da carboxylic acid

Question 503

[1 marks]organic reactions of carbonyl and alkene
Lithium tetrahydridoaluminate reduces the ketone group of a molecule to
  1. Aa primary alcohol
  2. Ban aldehyde
  3. Can alkane
  4. Da secondary alcohol

Question 504

[1 marks]organic reactions of carbonyl and alkene
Jasmine contains a ketone group, a hydroxyl group and a carbon-carbon double bond. The functional group that reacts with 2,4-dinitrophenylhydrazine to give an orange precipitate is the
  1. Aketone (carbonyl) group
  2. Bhydroxyl group
  3. Ccarbon-carbon double bond
  4. Dester group

Question 505

[2 marks]organic reactions of carbonyl and alkene
Jasmine contains a ketone group and a carbon-carbon double bond. Reducing Jasmine with LiAlH4LiAlH_4 converts the ketone to a secondary alcohol but leaves the double bond unaffected because
  1. Athe double bond is somehow protected by the nearby hydroxyl group for the duration of the whole reaction
  2. BLiAlH4LiAlH_4 only ever reacts with functional groups located at the very end of a carbon chain
  3. Cthe double bond is simultaneously converted into a second alcohol group during the same reaction step
  4. DLiAlH4LiAlH_4 reduces carbonyl groups but does not react with isolated carbon-carbon double bonds

Question 506

[3 marks]organic reactions of carbonyl and alkene
Hot, concentrated potassium manganate(VII) reacts with a carbon-carbon double bond by
  1. Apolymerising the molecule through the double bond in a manner similar to how alkenes undergo addition polymerisation
  2. Badding an −OH-OH group to each carbon atom of the double bond, forming a diol, exactly as the cold dilute reagent also does
  3. Csimply reducing the double bond to a single bond, with absolutely no other observable change to the molecule
  4. Dcleaving the double bond completely, oxidising each fragment to a carboxylic acid or a ketone depending on its substitution

Question 601

[1 marks]separation techniques and environmental chemistry
A mixture of 2-nitrophenol and 4-nitrophenol is separated using the apparatus shown. The technique is
  1. Afractional distillation
  2. Bsteam distillation
  3. Cpaper chromatography
  4. Dsolvent extraction

Question 602

[1 marks]separation techniques and environmental chemistry
The distillate contains 2-nitrophenol rather than 4-nitrophenol because 2-nitrophenol
  1. Aforms stronger intermolecular hydrogen bonds
  2. Bis much more soluble in water
  3. Chas a higher relative molecular mass
  4. Dforms intramolecular hydrogen bonds and so is more volatile

Question 603

[1 marks]separation techniques and environmental chemistry
Methane is produced in landfill sites by
  1. Athe anaerobic decomposition of organic matter by bacteria
  2. Bthe evaporation of petroleum residues
  3. Cthe reaction of rainwater with buried metals
  4. Dthe combustion of plastic waste

Question 604

[2 marks]separation techniques and environmental chemistry
Leachate forms in a landfill site when
  1. Arainwater percolates through decomposing waste, dissolving soluble and toxic substances
  2. Bplastic waste slowly combusts underground due to the heat generated by decomposition nearby
  3. Cburied metal objects react slowly with atmospheric oxygen that has seeped into the landfill
  4. Dbacteria break down the organic waste in the total absence of air deep within the landfill

Question 605

[1 marks]separation techniques and environmental chemistry
State one problem caused by leachate escaping into the environment.

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Question 606

[1 marks]separation techniques and environmental chemistry
After the steam distillation, the residue remaining in the distillation flask mainly contains

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Question 607

[2 marks]separation techniques and environmental chemistry
Steam distillation is a suitable technique for separating ortho- and para-nitrophenol because it allows
  1. Aa steam-volatile compound to distil over at a temperature below its normal boiling point, avoiding decomposition
  2. Bthe two isomers to react chemically together and then separate out as a single new compound entirely
  3. Cboth compounds to boil simultaneously at their own separate normal boiling points, without any interference whatsoever
  4. Dthe entire mixture to be distilled cleanly and completely without any water being present at any stage

Question 608

[1 marks]separation techniques and environmental chemistry
Methane released from landfill sites is of environmental concern mainly because it
  1. Ais highly corrosive to metal structures and pipework located near the landfill site itself
  2. Bdissolves readily in rainwater collecting nearby to form a dilute and highly localised acid rain
  3. Cis a greenhouse gas that traps heat in the atmosphere, contributing to global warming
  4. Ddepletes the ozone layer directly, allowing more harmful ultraviolet radiation to reach the ground

Question 701

[1 marks]polymerization
Superglue contains compound A, H2C=C(CN)COOCH3H_2C=C(CN)COOCH_3. The functional groups present in A are
  1. Aalkene, nitrile and carboxylic acid
  2. Balkene, nitrile and ester
  3. Calkene, amine and ester
  4. Dalkyne, nitrile and ketone

Question 702

[1 marks]polymerization
Compound A, H2C=C(CN)COOCH3H_2C=C(CN)COOCH_3, forms a polymer by
  1. Ahydrolysis
  2. Boxidation
  3. Ccondensation
  4. Daddition

Question 703

[1 marks]polymerization
The repeat unit of the polymer formed from H2C=C(CN)COOCH3H_2C=C(CN)COOCH_3 is
  1. A−[CH2−C(CN)(COOCH3)]−-[CH_2-C(CN)(COOCH_3)]-
  2. B−[CH=C(CN)(COOCH3)]−-[CH=C(CN)(COOCH_3)]-
  3. C−[OCH2−CO(CN)]−-[OCH_2-CO(CN)]-
  4. D−[CH2−CH(CN)]−-[CH_2-CH(CN)]-

The answers, and why they are the answers

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