Danho
ZIMSEC A Level · N2020

Chemistry Paper 2 November 2020

Questions
40
Total marks
70
Time allowed
75 min

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Questions
40
Pass mark
24
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]chemical bonding and basicity of amines
The equation which shows ammonia acting as a base in water is
  1. ANH3+H2O⇌NH4++OH−NH_3 + H_2O \rightleftharpoons NH_4^+ + OH^-
  2. BNH3+H2O→NH2−+H3O+NH_3 + H_2O \rightarrow NH_2^- + H_3O^+
  3. CNH3→12N2+32H2NH_3 \rightarrow \frac{1}{2}N_2 + \frac{3}{2}H_2
  4. D2NH3+H2O→N2H4+H2O22NH_3 + H_2O \rightarrow N_2H_4 + H_2O_2

Question 102

[1 marks]chemical bonding and basicity of amines
Methylamine is a stronger base than ammonia because the methyl group
  1. Areleases electrons towards the nitrogen atom
  2. Bwithdraws electrons from the nitrogen atom
  3. Cforms hydrogen bonds with water
  4. Dincreases the relative molecular mass

Question 103

[1 marks]chemical bonding and basicity of amines
The shape of the sulphur dioxide molecule is
  1. Atrigonal planar, because there are three bonding pairs
  2. Bbent, because sulphur also carries a lone pair
  3. Ctetrahedral, because sulphur has four electron pairs
  4. Dlinear, because there are two bonding regions

Question 104

[2 marks]chemical bonding and basicity of amines
Phenylamine is a weaker base than ammonia because
  1. Aphenylamine has a much larger molecular mass, which spreads out and weakens its lone pair.
  2. Bthe nitrogen lone pair is delocalised into the benzene ring, reducing its availability to accept a proton.
  3. Cphenylamine is far less soluble in water than ammonia, limiting how well it can donate protons in aqueous solution.
  4. Dthe benzene ring withdraws electron density only through the sigma-bond framework, not the lone pair.

Question 105

[2 marks]chemical bonding and basicity of amines
In SO2, sulfur is surrounded by two bonding regions and one lone pair. Compared with the ideal 120° trigonal-planar bond angle, the O-S-O angle is
  1. Aclose to 90°, because the molecule adopts a tetrahedral arrangement of its electron pairs around sulfur.
  2. Bgreater than 120°, because the lone pair on sulfur pushes the two S-O bonding pairs further apart than another bonding pair would.
  3. Cexactly 120°, because a lone pair and a bonding pair repel each other exactly as strongly as two bonding pairs.
  4. Dslightly less than 120° (about 119°), because lone pair-bond pair repulsion is greater than bond pair-bond pair repulsion.

Question 201

[1 marks]electrolysis and electrode potentials
The electrodes used in the electrolytic extraction of aluminium from its ore are made of
  1. Apure aluminium
  2. Bsteel
  3. Cplatinum
  4. Dgraphite

Question 202

[1 marks]electrolysis and electrode potentials
During the purification of nickel by electrolysis, the anode
  1. Aincreases in mass as impurities collect on it
  2. Bdecreases in mass as nickel dissolves
  3. Cincreases in mass as nickel is deposited
  4. Dremains unchanged in mass

Question 203

[1 marks]electrolysis and electrode potentials
Given Eθ(Cr2O72−/Cr3+)=+1.33 VE^\theta(Cr_2O_7^{2-}/Cr^{3+}) = +1.33\ V and Eθ(Br2/Br−)=+1.07 VE^\theta(Br_2/Br^-) = +1.07\ V, the overall EθE^\theta for the reaction between dichromate(VI) ions and bromide ions is
  1. A+0.26 V+0.26\ V
  2. B+1.07 V+1.07\ V
  3. C+1.33 V+1.33\ V
  4. D+2.40 V+2.40\ V

Question 204

[2 marks]electrolysis and electrode potentials
One safety risk associated with the electrolytic extraction of aluminium is that the process
  1. Agenerates harmful ionising radiation from the graphite electrodes as they slowly wear away during operation.
  2. Bcauses the molten aluminium oxide itself to ignite spontaneously in air.
  3. Creleases toxic, corrosive fumes containing fluorine compounds from the molten cryolite-alumina mixture.
  4. Dproduces large volumes of explosive hydrogen gas that collect dangerously at the cathode during electrolysis.

Question 205

[2 marks]electrolysis and electrode potentials
In the reaction Cr2O72−→Cr3+Cr_2O_7^{2-} \rightarrow Cr^{3+}, the oxidation state of chromium changes from +6 to

Answer this when you sit the paper.

Question 206

[3 marks]electrolysis and electrode potentials
Given Eθ(Ag+/Ag)=+0.80 VE^{\theta}(Ag^+/Ag) = +0.80\ V and Eθ(H+/H2)=0.00 VE^{\theta}(H^+/H_2) = 0.00\ V, silver does not react with dilute acids because
  1. AAg+/AgAg^+/Ag has a more positive electrode potential than H+/H2H^+/H_2, so H+H^+ ions cannot oxidise silver metal.
  2. Bsilver has a full outer electron shell, making it completely unreactive towards any acid.
  3. Csilver forms a thin, protective oxide layer on its surface that prevents any acid from ever reaching the metal underneath.
  4. Dthe reaction between silver and dilute acids is far too slow to be observed under normal conditions.

Question 301

[1 marks]ammonia preparation and enthalpy of combustion
The equation for the laboratory preparation of ammonia from ammonium chloride and calcium hydroxide is
  1. A2NH4Cl+Ca(OH)2→CaCl2+2NH3+2H2O2NH_4Cl + Ca(OH)_2 \rightarrow CaCl_2 + 2NH_3 + 2H_2O
  2. BNH4Cl+CaO→CaCl2+NH3+H2NH_4Cl + CaO \rightarrow CaCl_2 + NH_3 + H_2
  3. C2NH4Cl+CaCO3→CaCl2+2NH3+CO2+H2O2NH_4Cl + CaCO_3 \rightarrow CaCl_2 + 2NH_3 + CO_2 + H_2O
  4. DNH4Cl+Ca(OH)2→CaCl2+NH3+H2ONH_4Cl + Ca(OH)_2 \rightarrow CaCl_2 + NH_3 + H_2O

Question 302

[1 marks]ammonia preparation and enthalpy of combustion
Concentrated sulphuric acid cannot be used in place of calcium oxide to dry ammonia because it
  1. Aoxidises ammonia to nitrogen
  2. Bis acidic and reacts with the ammonia
  3. Cis not a drying agent
  4. Ddissolves in the ammonia

Question 303

[1 marks]ammonia preparation and enthalpy of combustion
Burning 1.04 g of methanol (MrM_r = 32) raised the temperature of 200 cm3200\ cm^3 of water by 27.0 °C. Taking c=4.18 J g−1K−1c = 4.18\ J\,g^{-1}K^{-1}, the enthalpy change of combustion, in kJ mol−1kJ\,mol^{-1}, is
  1. A−715-715
  2. B−694-694
  3. C−347-347
  4. D−22.6-22.6

Question 304

[1 marks]ammonia preparation and enthalpy of combustion
In this preparation of ammonia, the function of the calcium oxide lumps is to act as a

Answer this when you sit the paper.

Question 305

[3 marks]ammonia preparation and enthalpy of combustion
Eutrophication is best described as
  1. Athe direct chemical poisoning of fish and other aquatic animals, caused when nitrate ions are absorbed through their gills and skin over a long period of exposure.
  2. Bthe gradual thinning of the Earth's protective ozone layer, a separate environmental problem caused mainly by certain industrial and refrigerant gases, not nitrates.
  3. Cthe physical warming of a water body's temperature, caused by dissolved nitrate fertilisers absorbing sunlight more strongly than the surrounding pure water does.
  4. Denrichment of water bodies with nutrients like nitrates, triggering algal blooms whose decay depletes dissolved oxygen and kills aquatic life.

Question 306

[3 marks]ammonia preparation and enthalpy of combustion
Farmers can limit the amount of nitrate fertiliser entering water bodies by
  1. Aapplying as much fertiliser as possible in a single large dose, to reduce the total number of separate applications needed each season.
  2. Bspreading fertiliser deliberately during periods of heavy rainfall, so that it washes evenly into the soil across the whole field.
  3. Capplying fertiliser in recommended amounts, avoiding it just before heavy rain, and leaving buffer strips near water.
  4. Dswitching entirely to fertilisers containing phosphates instead of nitrates, since phosphate compounds never dissolve in water at all.

Question 307

[3 marks]ammonia preparation and enthalpy of combustion
The experimental enthalpy of combustion of methanol found in this experiment (−694 kJ mol−1-694\ kJ\,mol^{-1}) is less exothermic than the theoretical value (−715 kJ mol−1-715\ kJ\,mol^{-1}) mainly because
  1. Athe specific heat capacity value used for water in this calculation was significantly too high for the experiment's conditions.
  2. Bfar too much oxygen reached the flame during combustion, making the temperature rise unusually and unrealistically large.
  3. Cheat was lost to the surroundings, and some methanol evaporated or burned incompletely before releasing its energy.
  4. Dthe theoretical Data Booklet value itself was calculated using an incorrect molecular formula for methanol in the first place.

Question 308

[2 marks]ammonia preparation and enthalpy of combustion
In this experiment, the mass of methanol burnt was 13.06 g - 12.02 g = 1.04 g. Given Mr(CH3OH)=32M_r(CH_3OH) = 32, the number of moles of methanol burnt is

Answer this when you sit the paper.

Question 309

[2 marks]ammonia preparation and enthalpy of combustion
In this experiment, 200 cm³ of water rose in temperature from 24.0°C to 51.0°C. Taking the specific heat capacity of water as 4.18 J g⁻¹K⁻¹, the heat released, in kJ, is

Answer this when you sit the paper.

Question 401

[1 marks]amines, polymers and carbonyl reactions
The base dissociation constants are (CH3)2NH(CH_3)_2NH 5.9×10−45.9 \times 10^{-4}, NH3NH_3 1.8×10−51.8 \times 10^{-5} and C6H5NH2C_6H_5NH_2 4.2×10−10 mol dm−34.2 \times 10^{-10}\ mol\,dm^{-3}. This order arises because
  1. Aphenylamine is insoluble in water
  2. Bonly ammonia can form hydrogen bonds
  3. Cthe relative molecular masses increase in the same order
  4. Dalkyl groups release electrons to nitrogen while the benzene ring delocalises the lone pair

Question 402

[1 marks]amines, polymers and carbonyl reactions
The polyester S is flexible because its chains
  1. Aare held together by strong ionic bonds
  2. Bare extensively cross-linked
  3. Care held only by weak van der Waals forces and can slide over one another
  4. Dcontain many carbon-carbon double bonds

Question 403

[1 marks]amines, polymers and carbonyl reactions
Carbonyl compounds do not react with HCN in the presence of an acid because the acid
  1. Aprotonates the carbonyl oxygen
  2. Bhydrolyses the carbonyl group
  3. Coxidises the hydrogen cyanide
  4. Dremoves the CN−CN^- nucleophile by forming HCN

Question 404

[2 marks]amines, polymers and carbonyl reactions
Propylamine, CH3CH2CH2NH2CH_3CH_2CH_2NH_2, is basic because
  1. Athe propyl chain forms strong, direct hydrogen bonds with any hydrogen ions that happen to be nearby in solution.
  2. Bnitrogen in propylamine carries a permanent partial positive charge that strongly attracts nearby hydrogen ions.
  3. Cnitrogen's lone pair can accept a proton, and the electron-donating propyl group increases its availability.
  4. Dit readily loses a proton from one of its own N-H bonds, releasing hydroxide ions directly into the surrounding solution.

Question 405

[2 marks]amines, polymers and carbonyl reactions
Polymer S, formed from a diol and a dicarboxylic acid monomer, is produced by what type of polymerisation?

Answer this when you sit the paper.

Question 406

[1 marks]amines, polymers and carbonyl reactions
Besides a diol, the other monomer used to produce polymer S (a polyester) is a

Answer this when you sit the paper.

Question 501

[1 marks]aromatic and organic reactions
2-hydroxybenzaldehyde is converted in one step into the ester A. The reagent used is
  1. Aethanol with a trace of acid
  2. Bethanoic anhydride
  3. Cacidified potassium dichromate(VI)
  4. Daqueous sodium hydroxide

Question 502

[1 marks]aromatic and organic reactions
Sodium tetrahydridoborate reacts with 2-hydroxybenzaldehyde to give compound B. B is
  1. A2-methylphenol
  2. B2-hydroxybenzoic acid
  3. Cbenzene-1,2-diol
  4. D2-(hydroxymethyl)phenol

Question 503

[1 marks]aromatic and organic reactions
Benzene undergoes electrophilic substitution more readily than nitrobenzene because the nitro group
  1. Areleases electrons into the ring
  2. Bmakes the molecule polar
  3. Cincreases the size of the molecule
  4. Dwithdraws electrons, reducing the electron density of the ring

Question 504

[1 marks]aromatic and organic reactions
The type of reaction that converts 2-hydroxybenzaldehyde into the dibromo compound C is

Answer this when you sit the paper.

Question 505

[2 marks]aromatic and organic reactions
The equation for the formation of ester A when 2-hydroxybenzaldehyde reacts with ethanoic anhydride is
  1. A2-hydroxybenzaldehyde + ethanoic anhydride -> the ethanoate ester of 2-hydroxybenzaldehyde + ethanoic acid.
  2. B2-hydroxybenzaldehyde + ethanoic anhydride -> the ethanoate ester of 2-hydroxybenzaldehyde + carbon dioxide.
  3. C2-hydroxybenzaldehyde + ethanoic anhydride -> the ethanoate ester of 2-hydroxybenzaldehyde + water.
  4. D2-hydroxybenzaldehyde + ethanoic anhydride -> the ethanoate ester of 2-hydroxybenzaldehyde + hydrogen gas.

Question 506

[2 marks]aromatic and organic reactions
Formation of the ester A from 2-hydroxybenzaldehyde and ethanoic anhydride is observed by
  1. Avigorous effervescence, with gas bubbling out of the mixture.
  2. Ba distinct white precipitate forming and slowly settling at the bottom of the reaction flask.
  3. Cthe smell of ethanoic acid developing, with no other dramatic visible change.
  4. Da deep purple colour developing immediately in the reaction mixture.

Question 507

[2 marks]aromatic and organic reactions
Methylbenzene is miscible with carbon tetrachloride but immiscible with water because
  1. Amethylbenzene undergoes an actual chemical reaction with carbon tetrachloride, but simply does not react with water molecules at all.
  2. Bwater molecules are simply far too large in size to fit between methylbenzene's own molecules, unlike the smaller carbon tetrachloride molecules.
  3. Cmethylbenzene and carbon tetrachloride are both non-polar (like dissolves like), but methylbenzene cannot hydrogen-bond with polar water.
  4. Dcarbon tetrachloride is considerably denser than water, so methylbenzene naturally sinks into it rather than mixing with the water layer above.

Question 601

[1 marks]nanomaterials and indicators
For phenolphthalein, HIn⇌H++In−HIn \rightleftharpoons H^+ + In^- (colourless to red). In acidic solution the indicator is colourless because
  1. Athe indicator does not dissolve in acid
  2. Bthe high [H+][H^+] shifts the equilibrium to the left
  3. Cthe indicator is destroyed by the acid
  4. DIn−In^- is colourless in acid

Question 602

[1 marks]nanomaterials and indicators
The KaK_a of phenolphthalein is 7.0×10−10 mol dm−37.0 \times 10^{-10}\ mol\,dm^{-3}. At pH 9.0 the ratio [In−]/[HIn][In^-]/[HIn] is
  1. A0.070
  2. B0.70
  3. C1.43
  4. D7.00

Question 603

[1 marks]nanomaterials and indicators
Phenolphthalein is unsuitable for the titration of hydrochloric acid with aqueous ammonia because
  1. Ait is colourless in both solutions
  2. Bammonia destroys the indicator
  3. Cthe end point occurs in the acidic region, outside its pH range
  4. Dthe reaction is too slow to reach an end point

Question 604

[2 marks]nanomaterials and indicators
An application of nanomaterials in medicine is
  1. Aacting as a contrast-free alternative that skips medical imaging in diagnosis.
  2. Btargeted drug delivery, where nanoparticles carry medication directly to diseased cells.
  3. Cproviding a stand-alone cure for common viral infections through nanoparticle injection.
  4. Dusing nanoscale robots as a general replacement for surgical instruments in routine operations.

Question 605

[2 marks]nanomaterials and indicators
A potential risk associated with the use of nanomaterials is that they
  1. Amay be toxic or cause damage to cells if they accumulate within the body over time.
  2. Bare too large in size to ever enter human cells, causing blockages in small blood vessels.
  3. Ccannot currently be manufactured on any scale large enough for practical medical use.
  4. Ddissolve completely and harmlessly in body fluids, leaving no biological trace behind.

Question 606

[2 marks]nanomaterials and indicators
Besides targeted drug delivery, another application of nanomaterials in medicine is
  1. Amedical imaging and diagnostics, using nanoparticles as contrast agents or biosensors.
  2. Bediting a patient's own DNA directly at the nanoscale in order to cure inherited genetic diseases.
  3. Creplacing vaccination programmes with nanoparticle-based immune boosters.
  4. Dusing nanoparticles as a permanent substitute for donated blood in transfusions.

Question 607

[1 marks]nanomaterials and indicators
Besides toxicity, another potential risk of nanomaterials is that their
  1. Amanufacturing cost makes them entirely impractical for any medical application.
  2. Blong-term health and environmental effects are not yet fully understood.
  3. Cphysical size makes them too large to be inhaled or absorbed by the body.
  4. Dchemical structure makes them completely immune to any form of degradation.

The answers, and why they are the answers

Sit the paper here to see which ones you got right. Danho explains every question, keeps your score, and works without a connection.