Danho
ZIMSEC A Level · 9164/2 · N2017

Pure Mathematics Paper 2 November 2017

Questions
51
Total marks
120
Syllabus code
9164/2

Sit this paper online

Questions
51
Pass mark
31
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 1

[1 marks]Mathematical induction
For the statement ∑r=1n(r+1)2r=n2n+1\displaystyle\sum_{r=1}^{n}(r+1)2^{r}=n2^{n+1}, evaluate the left hand side when n=1n=1.

Answer this when you sit the paper.

[2 marks]Mathematical induction
In a proof by induction of ∑r=1n(r+1)2r=n2n+1\displaystyle\sum_{r=1}^{n}(r+1)2^{r}=n2^{n+1}, the inductive step adds the (k+1)(k+1)th term to the sum of the first kk terms. Which expression is that (k+1)(k+1)th term?
  1. A(k+1)2k+1(k+1)2^{k+1}
  2. B(k+1)2k+2(k+1)2^{k+2}
  3. C(k+2)2k+2(k+2)2^{k+2}
  4. D(k+2)2k+1(k+2)2^{k+1}
[3 marks]Mathematical induction
Assume that ∑r=1k(r+1)2r=k2k+1\displaystyle\sum_{r=1}^{k}(r+1)2^{r}=k2^{k+1}. Write ∑r=1k+1(r+1)2r\displaystyle\sum_{r=1}^{k+1}(r+1)2^{r} as a single fully factorised expression.

Answer this when you sit the paper.

Section a, Question 2

[2 marks]Coordinate geometry, circles
The circle defined by the equation x2−6x+y2−4y=0x^{2}-6x+y^{2}-4y=0 passes through the origin. Find the coordinates of its centre.

Answer this when you sit the paper.

[2 marks]Coordinate geometry, circles
The circle defined by the equation x2−6x+y2−4y=0x^{2}-6x+y^{2}-4y=0 passes through the origin. Find its radius, giving an exact answer.

Answer this when you sit the paper.

[2 marks]Coordinate geometry, circles
The circle x2−6x+y2−4y=0x^{2}-6x+y^{2}-4y=0 passes through the origin and crosses the yy-axis again at a point P\mathbf{P}. Find the coordinates of P\mathbf{P}.

Answer this when you sit the paper.

[3 marks]Coordinate geometry, circles
The circle x2−6x+y2−4y=0x^{2}-6x+y^{2}-4y=0 has centre (3;2)(3;2) and crosses the yy-axis at P(0;4)\mathbf{P}(0;4). Find the equation of the tangent to the circle at P\mathbf{P}.

Answer this when you sit the paper.

Section a, Question 3

[1 marks]Complex numbers, De Moivre's theorem
Find the modulus of the complex number 2+23i2+2\sqrt{3}i.

Answer this when you sit the paper.

[1 marks]Complex numbers, De Moivre's theorem
Find the argument of the complex number 2+23i2+2\sqrt{3}i, in radians.

Answer this when you sit the paper.

[2 marks]Complex numbers, De Moivre's theorem
Using De Moivre's Theorem, find the value of (2+23i)6\left(2+2\sqrt{3}i\right)^{6}.

Answer this when you sit the paper.

[3 marks]Complex numbers, De Moivre's theorem
Express sin⁡6θ4sin⁡θ\dfrac{\sin6\theta}{4\sin\theta} in terms of cos⁡θ\cos\theta.

Answer this when you sit the paper.

[2 marks]Complex numbers, De Moivre's theorem
Why can sin⁡6θ4sin⁡θ\dfrac{\sin6\theta}{4\sin\theta} be written entirely in terms of cos⁡θ\cos\theta, with no sin⁡θ\sin\theta left in it?
  1. ABecause the imaginary part of any power of a complex number is always a polynomial in its real part alone, whatever the angle involved.
  2. BIts expansion carries only odd powers of sin⁡θ\sin\theta, so dividing by sin⁡θ\sin\theta leaves even powers, each replaceable by 1−cos⁡2θ1-\cos^{2}\theta.
  3. CBecause sin⁡6θ\sin6\theta and 4sin⁡θ4\sin\theta cancel exactly, leaving a constant multiple of cos⁡θ\cos\theta behind.
  4. DBecause sin⁡θ\sin\theta and cos⁡θ\cos\theta are equal for every angle to which De Moivre's Theorem may be applied.

Section a, Question 4

[2 marks]Matrices and simultaneous equations
Find the determinant of the matrix M=(234−3224−43)\mathbf{M}=\begin{pmatrix}2&3&4\\-3&2&2\\4&-4&3\end{pmatrix}.

Answer this when you sit the paper.

[2 marks]Matrices and simultaneous equations
The matrix M=(234−3224−43)\mathbf{M}=\begin{pmatrix}2&3&4\\-3&2&2\\4&-4&3\end{pmatrix} has determinant 9595 and adjoint (14−25−217−10−1642013)\begin{pmatrix}14&-25&-2\\17&-10&-16\\4&20&13\end{pmatrix}. Which matrix is M−1\mathbf{M}^{-1}?
  1. A195(14−25−217−10−1642013)\dfrac{1}{95}\begin{pmatrix}14&-25&-2\\17&-10&-16\\4&20&13\end{pmatrix}
  2. B95(14−25−217−10−1642013)95\begin{pmatrix}14&-25&-2\\17&-10&-16\\4&20&13\end{pmatrix}
  3. C195(14174−25−1020−2−1613)\dfrac{1}{95}\begin{pmatrix}14&17&4\\-25&-10&20\\-2&-16&13\end{pmatrix}
  4. D195(234−3224−43)\dfrac{1}{95}\begin{pmatrix}2&3&4\\-3&2&2\\4&-4&3\end{pmatrix}
[3 marks]Matrices and simultaneous equations
Given that M−1=195(14−25−217−10−1642013)\mathbf{M}^{-1}=\dfrac{1}{95}\begin{pmatrix}14&-25&-2\\17&-10&-16\\4&20&13\end{pmatrix} where M=(234−3224−43)\mathbf{M}=\begin{pmatrix}2&3&4\\-3&2&2\\4&-4&3\end{pmatrix}, solve the simultaneous equations 2x+3y+4z=12x+3y+4z=1, −3x+2y+2z=14-3x+2y+2z=14 and 4x−4y+3z=224x-4y+3z=22.

Answer this when you sit the paper.

[2 marks]Matrices and simultaneous equations
The system 2x+3y+4z=12x+3y+4z=1, −3x+2y+2z=14-3x+2y+2z=14, 4x−4y+3z=224x-4y+3z=22 has coefficient matrix M\mathbf{M} with det⁡M=95\det\mathbf{M}=95. What does that determinant tell you about the solution?
  1. AThe determinant is not zero, so M−1\mathbf{M}^{-1} exists and the system has exactly one solution.
  2. BThe determinant is not zero, so the system has infinitely many solutions.
  3. CThe determinant is not zero, so the three planes are parallel and there is no solution.
  4. DThe determinant tells you nothing about the number of solutions; only the constants on the right can do that.

Section a, Question 5

[3 marks]Differentiation and integration
Given that ln⁡y=(1+8e3x)12\ln y=\left(1+8e^{3x}\right)^{\frac{1}{2}}, find dydx\dfrac{dy}{dx} in terms of xx and yy.

Answer this when you sit the paper.

[2 marks]Differentiation and integration
Which is the correct form of the partial fractions for 3x2(3−x)\dfrac{3}{x^{2}(3-x)}?
  1. AAx+Bx2+C3−x\dfrac{A}{x}+\dfrac{B}{x^{2}}+\dfrac{C}{3-x}
  2. BAx2+B3−x\dfrac{A}{x^{2}}+\dfrac{B}{3-x}
  3. CAx+Bx2+Cx+D3−x\dfrac{Ax+B}{x^{2}}+\dfrac{Cx+D}{3-x}
  4. DAx+Bx2+C3−x+D(3−x)2\dfrac{A}{x}+\dfrac{B}{x^{2}}+\dfrac{C}{3-x}+\dfrac{D}{(3-x)^{2}}
[3 marks]Differentiation and integration
Express 3x2(3−x)\dfrac{3}{x^{2}(3-x)} in the form Ax+Bx2+C3−x\dfrac{A}{x}+\dfrac{B}{x^{2}}+\dfrac{C}{3-x}, stating the values of AA, BB and CC.

Answer this when you sit the paper.

[3 marks]Differentiation and integration
Find the exact value of ∫123x2(3−x) dx\displaystyle\int_{1}^{2}\frac{3}{x^{2}(3-x)}\,dx.

Answer this when you sit the paper.

Section a, Question 6

[1 marks]Trigonometric graphs and equations
State the yy-intercept of the graph of f(x)=cos⁡(x−60∘)f(x)=\cos(x-60^{\circ}).

Answer this when you sit the paper.

[2 marks]Trigonometric graphs and equations
State the values of xx at which the graph of f(x)=cos⁡(x−60∘)f(x)=\cos(x-60^{\circ}) crosses the xx-axis for 0∘≤x≤360∘0^{\circ}\le x\le360^{\circ}.

Answer this when you sit the paper.

[2 marks]Trigonometric graphs and equations
What is the geometrical relationship between the graph of f(x)=cos⁡(x−60∘)f(x)=\cos(x-60^{\circ}) and the graph of f(x)=cos⁡xf(x)=\cos x?
  1. AA reflection in the line x=60∘x=60^{\circ}.
  2. BA translation of 60∘60^{\circ} in the positive xx-direction.
  3. CA translation of 60∘60^{\circ} in the negative xx-direction.
  4. DA stretch parallel to the xx-axis with scale factor 6060.
[2 marks]Trigonometric graphs and equations
Show that the equation 2sin⁡2(x−60∘)=1+cos⁡(x−60∘)2\sin^{2}(x-60^{\circ})=1+\cos(x-60^{\circ}) may be written as a quadratic equation in cos⁡(x−60∘)\cos(x-60^{\circ}), and write down that quadratic equation with all terms on one side.

Answer this when you sit the paper.

[3 marks]Trigonometric graphs and equations
Solve the equation 2sin⁡2(x−60∘)=1+cos⁡(x−60∘)2\sin^{2}(x-60^{\circ})=1+\cos(x-60^{\circ}) for 0∘≤x≤360∘0^{\circ}\le x\le360^{\circ}.

Answer this when you sit the paper.

Section a, Question 7

[2 marks]Vectors, lines in three dimensions
The point P\mathbf{P} has position vector (531)\begin{pmatrix}5\\3\\1\end{pmatrix} and the line ll has equation r=(10−2)+λ(2−15)\mathbf{r}=\begin{pmatrix}1\\0\\-2\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\5\end{pmatrix}. Does P\mathbf{P} lie on ll?
  1. ANo: the three components give λ=2\lambda=2, −3-3 and 35\tfrac{3}{5}, which disagree.
  2. BYes, because the first component gives λ=2\lambda=2, and a parameter value satisfying one component satisfies them all.
  3. CYes, because (531)\begin{pmatrix}5\\3\\1\end{pmatrix} is a scalar multiple of the direction vector (2−15)\begin{pmatrix}2\\-1\\5\end{pmatrix}.
  4. DNo, because none of the components of the direction vector of the line ll is equal to zero.
[3 marks]Vectors, lines in three dimensions
Points P\mathbf{P} and Q\mathbf{Q} have position vectors (531)\begin{pmatrix}5\\3\\1\end{pmatrix} and (4c2)\begin{pmatrix}4\\c\\2\end{pmatrix}. Given that line PQ\mathbf{PQ} intersects the line ll with equation r=(10−2)+λ(2−15)\mathbf{r}=\begin{pmatrix}1\\0\\-2\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\5\end{pmatrix}, find the value of cc.

Answer this when you sit the paper.

[3 marks]Vectors, lines in three dimensions
The line ll has direction (2−15)\begin{pmatrix}2\\-1\\5\end{pmatrix} and the line PQ\mathbf{PQ} has direction (−1−21)\begin{pmatrix}-1\\-2\\1\end{pmatrix}. Calculate the acute angle between the two lines, giving your answer in degrees.

Answer this when you sit the paper.

[3 marks]Vectors, lines in three dimensions
The point P\mathbf{P} has position vector (531)\begin{pmatrix}5\\3\\1\end{pmatrix} and the line ll has equation r=(10−2)+λ(2−15)\mathbf{r}=\begin{pmatrix}1\\0\\-2\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\5\end{pmatrix}. Find the position vector of the point R\mathbf{R} on ll such that PR\mathbf{PR} is perpendicular to ll.

Answer this when you sit the paper.

Section b

Section b, Question 8

[2 marks]Statics, equilibrium of forces
A light inextensible string is attached to two points at the same horizontal level. A smooth ring RR of mass 22 kg slides freely along the string. A horizontal force of magnitude PP newtons holds the ring in equilibrium, with the two parts of the string inclined at 60∘60^{\circ} and 30∘30^{\circ} to the vertical. Taking g=9,81g=9,81 ms−2^{-2}, find the tension in the string.

Answer this when you sit the paper.

[2 marks]Statics, equilibrium of forces
A light inextensible string is attached to two points at the same horizontal level. A smooth ring RR of mass 22 kg slides freely along the string, and the tension throughout the string is 14,3614,36 N. A horizontal force of magnitude PP newtons holds the ring in equilibrium, with the two parts of the string inclined at 60∘60^{\circ} and 30∘30^{\circ} to the vertical. Find the value of PP.

Answer this when you sit the paper.

Section b, Question 9

[2 marks]Kinematics, velocity-time graphs
A particle moves in a straight line with a constant velocity of 33 ms−1^{-1} for 33 seconds and then moves with a constant acceleration of −2-2 ms−2^{-2} for 88 seconds. Find its velocity at the end of the 1111 seconds.

Answer this when you sit the paper.

[3 marks]Kinematics, velocity-time graphs
A particle moves in a straight line with a constant velocity of 33 ms−1^{-1} for 33 seconds and then moves with a constant acceleration of −2-2 ms−2^{-2} for 88 seconds. Find the displacement of the particle after the 1111 seconds.

Answer this when you sit the paper.

Section b, Question 10

[2 marks]Connected particles, Newton's laws
A particle of mass 1212 kg rests on a smooth plane inclined at 45∘45^{\circ} to the horizontal. It is connected by a light inextensible string passing over a smooth pulley at the top of the plane to a particle of mass 55 kg hanging freely. Taking g=9,81g=9,81 ms−2^{-2}, find the acceleration of the system.

Answer this when you sit the paper.

[2 marks]Connected particles, Newton's laws
A particle of mass 1212 kg on a smooth plane inclined at 45∘45^{\circ} is connected by a light inextensible string over a smooth pulley at the top of the plane to a freely hanging particle of mass 55 kg. The system accelerates at 2,0112,011 ms−2^{-2}. Taking g=9,81g=9,81 ms−2^{-2}, find the tension in the string.

Answer this when you sit the paper.

[2 marks]Connected particles, Newton's laws
A light inextensible string passes over a smooth pulley fixed at the top of a plane inclined at 45∘45^{\circ} to the horizontal. One part of the string lies along the plane and the other hangs vertically, and the tension throughout is 59,10559,105 N. Find the magnitude of the force exerted by the string on the pulley.

Answer this when you sit the paper.

Section b, Question 11

[3 marks]Projectile motion
A particle is projected from a point OO on level ground with speed 2020 ms−1^{-1}. It passes through a point PP that is 1010 m from OO horizontally and 1010 m vertically above OO. Taking g=9,81g=9,81 ms−2^{-2}, find the two possible angles of projection, correct to the nearest degree.

Answer this when you sit the paper.

[2 marks]Projectile motion
A particle is projected from a point OO on level ground with speed 2020 ms−1^{-1} at 53,3∘53,3^{\circ} to the horizontal. Taking g=9,81g=9,81 ms−2^{-2}, find the time taken by the particle to hit the ground.

Answer this when you sit the paper.

[2 marks]Projectile motion
A particle is projected from a point OO on level ground with speed 2020 ms−1^{-1} at 81,6∘81,6^{\circ} to the horizontal. State the direction of motion of the particle when it hits the ground.

Answer this when you sit the paper.

Section c

Section c, Question 12

[2 marks]Continuous random variables
A continuous random variable XX has probability density function f(x)=2(a−x)a2f(x)=\dfrac{2(a-x)}{a^{2}} for 0≤x≤a0\le x\le a and f(x)=0f(x)=0 otherwise, where aa is a constant. Find E(X)\mathrm{E}(X) in terms of aa.

Answer this when you sit the paper.

[3 marks]Continuous random variables
A continuous random variable XX has probability density function f(x)=2(a−x)a2f(x)=\dfrac{2(a-x)}{a^{2}} for 0≤x≤a0\le x\le a and f(x)=0f(x)=0 otherwise. Which equation must the median mm satisfy?
  1. A2m2−4am−a2=02m^{2}-4am-a^{2}=0
  2. Bm2−4am+2a2=0m^{2}-4am+2a^{2}=0
  3. C2m2−4am+a2=02m^{2}-4am+a^{2}=0
  4. Dm2−2am+a2=0m^{2}-2am+a^{2}=0

Section c, Question 13

[2 marks]Normal distribution
The random variable XX is Normally distributed with mean μ\mu and standard deviation σ\sigma. Given that P(X>3,6)=0,5\mathrm{P}(X>3,6)=0,5, find the value of μ\mu.

Answer this when you sit the paper.

[3 marks]Normal distribution
The random variable XX is Normally distributed with mean 3,63,6 and standard deviation σ\sigma. Given that P(X>2,8)=0,6554\mathrm{P}(X>2,8)=0,6554, find the value of σ\sigma.

Answer this when you sit the paper.

Section c, Question 14

[2 marks]Conditional probability
A\mathbf{A} and B\mathbf{B} play a series of games, each of which is won by one of them. The probability that A\mathbf{A} wins the first game is 0,60,6. If A\mathbf{A} wins a game, the probability of winning the next is 0,70,7; if A\mathbf{A} loses a game, the probability of winning the next is 0,40,4. Find the probability that A\mathbf{A} loses the second game.

Answer this when you sit the paper.

[3 marks]Conditional probability
A\mathbf{A} and B\mathbf{B} play a series of games, each of which is won by one of them. The probability that A\mathbf{A} wins the first game is 0,60,6. If A\mathbf{A} wins a game, the probability of winning the next is 0,70,7; if A\mathbf{A} loses a game, the probability of winning the next is 0,40,4. Find the probability that A\mathbf{A} wins the first game, given that A\mathbf{A} loses the second game.

Answer this when you sit the paper.

Section c, Question 15

[1 marks]Stem and leaf diagrams, measures of spread
State one advantage of using a stem and leaf diagram to represent data.
  1. AIt removes outliers automatically before the data is summarised, so the spread is never distorted.
  2. BIt shows the exact mean of the data without any calculation being needed.
  3. CThe original data values are preserved and can still be read off.
  4. DIt works well however many thousands of readings there are, since the leaves simply extend further to the right.
[1 marks]Stem and leaf diagrams, measures of spread
State one disadvantage of using a stem and leaf diagram to represent data.
  1. AIt hides the individual readings, so the original values cannot be recovered.
  2. BIt gives no indication of the shape of the distribution.
  3. CIt cannot be drawn for data that includes negative values.
  4. DEvery value is written out, so it becomes cluttered and hard to read once the data set is large.
[2 marks]Stem and leaf diagrams, measures of spread

The heights, in centimetres, of 3030 students, measured correct to the nearest centimetre, are

167174156180162169177154165174160184169179151163173148171168158158167166149153171162182162\begin{array}{cccccc}167&174&156&180&162&169\\177&154&165&174&160&184\\169&179&151&163&173&148\\171&168&158&158&167&166\\149&153&171&162&182&162\end{array}

Find the median height.

Answer this when you sit the paper.

[1 marks]Stem and leaf diagrams, measures of spread

The heights, in centimetres, of 3030 students, measured correct to the nearest centimetre, are

167174156180162169177154165174160184169179151163173148171168158158167166149153171162182162\begin{array}{cccccc}167&174&156&180&162&169\\177&154&165&174&160&184\\169&179&151&163&173&148\\171&168&158&158&167&166\\149&153&171&162&182&162\end{array}

Find the lower quartile.

Answer this when you sit the paper.

[1 marks]Stem and leaf diagrams, measures of spread

The heights, in centimetres, of 3030 students, measured correct to the nearest centimetre, are

167174156180162169177154165174160184169179151163173148171168158158167166149153171162182162\begin{array}{cccccc}167&174&156&180&162&169\\177&154&165&174&160&184\\169&179&151&163&173&148\\171&168&158&158&167&166\\149&153&171&162&182&162\end{array}

Find the upper quartile.

Answer this when you sit the paper.

[2 marks]Stem and leaf diagrams, measures of spread

The heights, in centimetres, of 3030 students, measured correct to the nearest centimetre, are

167174156180162169177154165174160184169179151163173148171168158158167166149153171162182162\begin{array}{cccccc}167&174&156&180&162&169\\177&154&165&174&160&184\\169&179&151&163&173&148\\171&168&158&158&167&166\\149&153&171&162&182&162\end{array}

Find the interquartile range.

Answer this when you sit the paper.

More sittings of this paper

The answers, and why they are the answers

Sit the paper here to see which ones you got right. Danho explains every question, keeps your score, and works without a connection.