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ZIMSEC A Level · 9164/2 · N2009

Pure Mathematics Paper 2 November 2009

Questions
48
Total marks
120
Syllabus code
9164/2

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Questions
48
Pass mark
29
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 1

[2 marks]Proof by mathematical induction
In a proof by induction that 52n−32n5^{2n}-3^{2n} is a multiple of 8 for every positive integer nn, the first step is to test n=1n=1. Evaluate 52n−32n5^{2n}-3^{2n} when n=1n=1.

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[3 marks]Proof by mathematical induction
In proving by induction that 52n−32n5^{2n}-3^{2n} is a multiple of 8, you assume that 52k−32k=8m5^{2k}-3^{2k}=8m for some integer mm. Which of these correctly rewrites 52(k+1)−32(k+1)5^{2(k+1)}-3^{2(k+1)} so that the assumption can be used?
  1. A2(52k−32k)+16⋅32k2\left(5^{2k}-3^{2k}\right)+16\cdot3^{2k}
  2. B25(52k−32k)−16⋅32k25\left(5^{2k}-3^{2k}\right)-16\cdot3^{2k}
  3. C25(52k−32k)+16⋅32k25\left(5^{2k}-3^{2k}\right)+16\cdot3^{2k}
  4. D25(52k−32k)+9⋅32k25\left(5^{2k}-3^{2k}\right)+9\cdot3^{2k}
[2 marks]Proof by mathematical induction
A student shows that if 52k−32k5^{2k}-3^{2k} is a multiple of 8 then 52(k+1)−32(k+1)5^{2(k+1)}-3^{2(k+1)} is also a multiple of 8, and stops there. Why is the proof by induction not yet complete?
  1. AThe implication must also be proved in the reverse direction.
  2. BThe result must be checked for at least three consecutive values of kk.
  3. CThe assumption is only valid once kk has been shown to be even.
  4. DNo case has been shown true, so nothing starts the chain.

Section a, Question 2

[2 marks]De Moivre's theorem and powers of sine
Given that z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta, express 1z\dfrac{1}{z} in terms of θ\theta.
  1. Asin⁡θ−icos⁡θ\sin\theta-i\cos\theta
  2. B−cos⁡θ−isin⁡θ-\cos\theta-i\sin\theta
  3. Ccos⁡θ−isin⁡θ\cos\theta-i\sin\theta
  4. Dcos⁡θ+isin⁡θ\cos\theta+i\sin\theta
[3 marks]De Moivre's theorem and powers of sine
Given that z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta, so that z−1z=2isin⁡θz-\dfrac{1}{z}=2i\sin\theta and zn+z−n=2cos⁡nθz^{n}+z^{-n}=2\cos n\theta, use De Moivre's theorem to express sin⁡4θ\sin^{4}\theta in terms of cos⁡4θ\cos4\theta and cos⁡2θ\cos2\theta.
  1. A18cos⁡4θ−12cos⁡2θ+38\dfrac{1}{8}\cos4\theta-\dfrac{1}{2}\cos2\theta+\dfrac{3}{8}
  2. B18cos⁡4θ+12cos⁡2θ+38\dfrac{1}{8}\cos4\theta+\dfrac{1}{2}\cos2\theta+\dfrac{3}{8}
  3. C116cos⁡4θ−14cos⁡2θ+316\dfrac{1}{16}\cos4\theta-\dfrac{1}{4}\cos2\theta+\dfrac{3}{16}
  4. D12cos⁡4θ−18cos⁡2θ+38\dfrac{1}{2}\cos4\theta-\dfrac{1}{8}\cos2\theta+\dfrac{3}{8}
[2 marks]De Moivre's theorem and powers of sine
Given that z=cos⁡θ+isin⁡θz=\cos\theta+i\sin\theta and nn is a positive integer, simplify zn+z−nz^{n}+z^{-n} as a single trigonometric term.

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Section a, Question 3

[3 marks]Binomial expansion
In the expansion of (1−xn)n\left(1-\dfrac{x}{n}\right)^{n} in ascending powers of xx, the term in x2x^{2} is kx2kx^{2}. Give kk in terms of nn, simplified as far as possible.

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[2 marks]Binomial expansion
In the expansion of (1−xn)n\left(1-\dfrac{x}{n}\right)^{n} in ascending powers of xx, what is the term in x3x^{3}?
  1. A−(n−1)(n−2)3n2x3-\dfrac{(n-1)(n-2)}{3n^{2}}x^{3}
  2. B−(n−1)(n−2)6n2x3-\dfrac{(n-1)(n-2)}{6n^{2}}x^{3}
  3. C(n−1)(n−2)6n2x3\dfrac{(n-1)(n-2)}{6n^{2}}x^{3}
  4. D−(n−1)(n−2)6n3x3-\dfrac{(n-1)(n-2)}{6n^{3}}x^{3}
[3 marks]Binomial expansion
In the expansion of (1−xn)n\left(1-\dfrac{x}{n}\right)^{n}, the term in x3x^{3} takes the value 78\dfrac{7}{8} when x=−2x=-2. Given that nn is a positive integer, find nn.

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Section a, Question 4

[2 marks]Differential equations and exponential growth
A population has a birth rate of 55 persons per 1 000 per year and a death rate of 14 persons per 1 000 per year, with no other changes. Write down the net rate of increase per person per year, as a fraction with denominator 1 000.

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[3 marks]Differential equations and exponential growth
A population of PP persons at time tt years satisfies dPdt=411000P\dfrac{\mathrm{d}P}{\mathrm{d}t}=\dfrac{41}{1000}P, and P=10 000P=10\,000 when t=0t=0. Which is the solution of this equation?
  1. AP=10 000e0.41tP=10\,000e^{0.41t}
  2. BP=10 000+0.041t2−3tP=10\,000+0.041t^{2}-3t
  3. CP=10 000t0.041P=10\,000t^{0.041}
  4. DP=10 000e0.041tP=10\,000e^{0.041t}
[3 marks]Differential equations and exponential growth
A community of 10 000 people in 2005 grows so that its population tt years after 2005 is P=10 000e0.041tP=10\,000e^{0.041t}. Find the predicted population in the year 2020, to the nearest whole person.

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Section a, Question 5

[3 marks]Matrix multiplication and linear systems
Given A=(102210311)A=\begin{pmatrix}1&0&2\\2&1&0\\3&1&1\end{pmatrix} and B=(1−11021130)B=\begin{pmatrix}1&-1&1\\0&2&1\\1&3&0\end{pmatrix}, find ABAB.
  1. A(324502134)\begin{pmatrix}3&2&4\\5&0&2\\1&3&4\end{pmatrix}
  2. B(351203424)\begin{pmatrix}3&5&1\\2&0&3\\4&2&4\end{pmatrix}
  3. C(351203423)\begin{pmatrix}3&5&1\\2&0&3\\4&2&3\end{pmatrix}
  4. D(102020330)\begin{pmatrix}1&0&2\\0&2&0\\3&3&0\end{pmatrix}
[2 marks]Matrix multiplication and linear systems
Let M=(351203424)M=\begin{pmatrix}3&5&1\\2&0&3\\4&2&4\end{pmatrix} and C=(−6−181548−7414−10)C=\begin{pmatrix}-6&-18&15\\4&8&-7\\4&14&-10\end{pmatrix}. Given that MC=(a000a000a)MC=\begin{pmatrix}a&0&0\\0&a&0\\0&0&a\end{pmatrix}, find the value of aa.

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[2 marks]Matrix multiplication and linear systems
A 3×33\times3 matrix MM satisfies MC=6IMC=6I, where CC is a known 3×33\times3 matrix and II is the identity. What is M−1M^{-1}?
  1. A16C\tfrac{1}{6}C
  2. B6C6C
  3. CCC
  4. D16C2\tfrac{1}{6}C^{2}
[2 marks]Matrix multiplication and linear systems
Let M=(351203424)M=\begin{pmatrix}3&5&1\\2&0&3\\4&2&4\end{pmatrix}. Given that M(xyz)=(312)M\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}3\\1\\2\end{pmatrix}, find the value of xx.

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Section a, Question 6

[2 marks]Vectors: lines and planes in three dimensions
The line ll passes through the points Q(3,1,−2)Q(3,1,-2) and R(2,7,−4)R(2,7,-4). Which vector is a direction vector of ll?
  1. A(1,6,2)(1,6,2)
  2. B(6,−1,−2)(6,-1,-2)
  3. C(−1,6,−2)(-1,6,-2)
  4. D(5,8,−6)(5,8,-6)
[3 marks]Vectors: lines and planes in three dimensions
The line ll passes through Q(3,1,−2)Q(3,1,-2) and R(2,7,−4)R(2,7,-4). What is the cartesian equation of ll?
  1. Ax−32=y−17=z+2−4\dfrac{x-3}{2}=\dfrac{y-1}{7}=\dfrac{z+2}{-4}
  2. Bx−3−1=y−16=z+2−2\dfrac{x-3}{-1}=\dfrac{y-1}{6}=\dfrac{z+2}{-2}
  3. Cx−3−1=y−16=z−2−2\dfrac{x-3}{-1}=\dfrac{y-1}{6}=\dfrac{z-2}{-2}
  4. Dx+3−1=y+16=z−2−2\dfrac{x+3}{-1}=\dfrac{y+1}{6}=\dfrac{z-2}{-2}
[2 marks]Vectors: lines and planes in three dimensions
The line ll passes through Q(3,1,−2)Q(3,1,-2) and R(2,7,−4)R(2,7,-4). It meets the plane x=yx=y at one point. Find the value of xx at that point, as a fraction.

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[2 marks]Vectors: lines and planes in three dimensions
The plane P1P_{1} has equation 2x−3y−z−5=02x-3y-z-5=0 and the plane P2P_{2} has equation −6x+9y+3z+2=0-6x+9y+3z+2=0. Which fact shows that P1P_{1} and P2P_{2} are parallel and distinct?
  1. A(−6,9,3)=−3(2,−3,−1)(-6,9,3)=-3(2,-3,-1) but −3(−5)=15≠2-3(-5)=15\ne2.
  2. B(−6,9,3)⋅(2,−3,−1)=0(-6,9,3)\cdot(2,-3,-1)=0 and the constants differ.
  3. CBoth equations have three variables and no common solution point.
  4. DThe sum of the coefficients of P2P_{2} is −3-3 times that of P1P_{1}.
[3 marks]Vectors: lines and planes in three dimensions
The plane P3P_{3} has equation 3x+2y−6z+10=03x+2y-6z+10=0. The plane P4P_{4} passes through the point P(5,−2,4)P(5,-2,4) and is parallel to P3P_{3}. Find the equation of P4P_{4}.

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[3 marks]Vectors: lines and planes in three dimensions
Find the perpendicular distance of the point P(5,−2,4)P(5,-2,4) from the plane 2x−3y−z−5=02x-3y-z-5=0, correct to 3 significant figures.

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Section a, Question 7

[2 marks]Complex numbers, roots of polynomials and De Moivre's theorem
Express 4(3−i)4\left(\sqrt{3}-i\right) in the form reiθre^{i\theta} with r>0r>0. Find the value of rr.

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[2 marks]Complex numbers, roots of polynomials and De Moivre's theorem
Express 4(3−i)4\left(\sqrt{3}-i\right) in the form reiθre^{i\theta} where r>0r>0 and −π<θ≤π-\pi<\theta\le\pi. Find θ\theta as a multiple of π\pi.

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[2 marks]Complex numbers, roots of polynomials and De Moivre's theorem
The equation x4−4x3−6x2+20x−75=0x^{4}-4x^{3}-6x^{2}+20x-75=0 has 1+2i1+2i as a root. Why must 1−2i1-2i also be a root?
  1. AThe constant term is negative, which forces conjugate roots.
  2. BThe sum of the roots is 4, which is real, so the roots pair up.
  3. CAll the coefficients are real, so complex roots occur in conjugate pairs.
  4. DA quartic equation must have exactly two complex roots and two real roots.
[3 marks]Complex numbers, roots of polynomials and De Moivre's theorem
Express sin⁡5θ\sin5\theta in terms of powers of sin⁡θ\sin\theta using De Moivre's theorem.
  1. A16sin⁡5θ−20sin⁡3θ−5sin⁡θ16\sin^{5}\theta-20\sin^{3}\theta-5\sin\theta
  2. B16sin⁡5θ−20sin⁡3θ+5sin⁡θ16\sin^{5}\theta-20\sin^{3}\theta+5\sin\theta
  3. C16sin⁡5θ+20sin⁡3θ−5sin⁡θ16\sin^{5}\theta+20\sin^{3}\theta-5\sin\theta
  4. D5sin⁡5θ−20sin⁡3θ+16sin⁡θ5\sin^{5}\theta-20\sin^{3}\theta+16\sin\theta
[3 marks]Complex numbers, roots of polynomials and De Moivre's theorem
Given that x1=1+2ix_{1}=1+2i is a root of x4−4x3−6x2+20x−75=0x^{4}-4x^{3}-6x^{2}+20x-75=0, find the two real roots of the equation.

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[3 marks]Complex numbers, roots of polynomials and De Moivre's theorem
Using the identity sin⁡5θ−5sin⁡θ=16sin⁡5θ−20sin⁡3θ\sin5\theta-5\sin\theta=16\sin^{5}\theta-20\sin^{3}\theta, find the exact value of ∫π/6π/2(16sin⁡5θ−20sin⁡3θ)dθ\displaystyle\int_{\pi/6}^{\pi/2}\left(16\sin^{5}\theta-20\sin^{3}\theta\right)\mathrm{d}\theta.

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Section b

Section b, Question 8

[3 marks]Motion on a rough inclined plane
A block is released from rest on a plane inclined at angle α\alpha to the horizontal, where tan⁡α=34\tan\alpha=\dfrac{3}{4}, and slides down. The coefficient of friction between the block and the plane is 14\dfrac{1}{4}. Taking g=9.81g=9.81 ms−2^{-2}, calculate the acceleration of the block down the plane, in ms−2^{-2}.

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[2 marks]Motion on a rough inclined plane
A block slides down a rough plane inclined at α\alpha to the horizontal, with coefficient of friction μ\mu. Why does the acceleration down the plane not depend on the mass of the block?
  1. AFriction on an inclined plane does not depend on the normal reaction.
  2. BThe normal reaction is equal to the weight, whatever the angle of the plane.
  3. CMass affects the speed reached but never the rate at which speed changes.
  4. DWeight component and friction are both proportional to mass, so it cancels.
[2 marks]Motion on a rough inclined plane
A block of mass 3.5 kg rests on a plane inclined at angle α\alpha to the horizontal, where tan⁡α=34\tan\alpha=\dfrac{3}{4}, and slides down it. The coefficient of friction is 14\dfrac{1}{4}. Taking g=9.81g=9.81 ms−2^{-2}, calculate the friction force on the block, in newtons, to 3 significant figures.

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Section b, Question 9

[2 marks]Friction and Newton's second law
A ring of mass mm kg slides along a rough horizontal wire. A force of 6 N acts on it at 60∘60^{\circ} above the wire, in the same vertical plane as the wire. Write down the normal reaction between the ring and the wire, in terms of mm and gg, in exact form.

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[2 marks]Friction and Newton's second law
A ring of mass mm kg slides along a rough horizontal wire under a force of 6 N acting at 60∘60^{\circ} above the wire. The coefficient of friction between the ring and the wire is 14\dfrac{1}{4} and the normal reaction is mg−33mg-3\sqrt3 N. Write down the friction force in exact form.

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[3 marks]Friction and Newton's second law
A ring of mass mm kg accelerates at 1 ms−2^{-2} along a rough horizontal wire under a force of 6 N acting at 60∘60^{\circ} above the wire, in the same vertical plane as the wire. The coefficient of friction is 14\dfrac{1}{4}. Taking g=9.81g=9.81 ms−2^{-2}, find mm to 3 decimal places.

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Section b, Question 10

[3 marks]Projectile motion
A particle is projected from a point O on the ground with speed VV ms−1^{-1} at 60∘60^{\circ} to the horizontal. Taking O as the origin, it passes through the point AA with coordinates (3, 2)\left(\sqrt3,\,2\right) metres. Express V2V^{2} in terms of gg.

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[2 marks]Projectile motion
A particle is projected from a point O on the ground at 60∘60^{\circ} to the horizontal with speed VV ms−1^{-1}, where V2=6gV^{2}=6g. Find the greatest height, in metres, that the particle reaches above O.

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[2 marks]Projectile motion
A particle is projected from a point O on the ground at 60∘60^{\circ} to the horizontal with speed VV ms−1^{-1}, where V2=6gV^{2}=6g. Find the horizontal distance from O, in metres, at which the particle reaches its greatest height, correct to 3 significant figures.

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[3 marks]Projectile motion
A particle projected from O passes through A(3, 2)A\left(\sqrt3,\,2\right) on its way up and reaches its greatest height at B(332, 94)B\left(\dfrac{3\sqrt3}{2},\,\dfrac{9}{4}\right), distances in metres. Find the angle, in degrees, that AB makes with the horizontal, correct to 1 decimal place.

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Section c

Section c, Question 11

[2 marks]Binomial probability
In the long run 40% of the people who inquire about a room at a motel actually book one. The owners want to be 99% sure of getting at least one booking from nn inquiries. Which inequality expresses that requirement?
  1. A0.4n≥0.990.4^{n}\ge0.99
  2. B1−0.4n≥0.991-0.4^{n}\ge0.99
  3. C0.6n≥0.990.6^{n}\ge0.99
  4. D1−0.6n≥0.991-0.6^{n}\ge0.99
[3 marks]Binomial probability
In the long run 40% of the people who inquire about a room at a motel actually book one, independently of each other. How many inquiries must the owners answer to be 99% sure of at least one booking?

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Section c, Question 12

[2 marks]Data presentation and the normal distribution
Give one advantage of using a stem and leaf diagram rather than a grouped frequency table to analyse a set of data.
  1. AEvery original data value is kept and shown in rank order.
  2. BIt can display data that has no numerical order at all.
  3. CIt removes outliers from the data automatically.
  4. DIt shows the mean and the standard deviation without any calculation.
[1 marks]Data presentation and the normal distribution
In which of these situations is the mode the most appropriate measure of central tendency?
  1. AA shop deciding which shoe size to stock the most of.
  2. BA teacher reporting the average score of a class in a test.
  3. CAn economist reporting the typical household income in a country.
  4. DA farmer working out the average mass of a batch of harvested maize.
[3 marks]Data presentation and the normal distribution
The masses of a group of adult males are normally distributed with mean 65 kg and standard deviation 10 kg. A male is considered overweight if he is in the top 5% of the group by mass. Find the least mass, in kg, to be considered overweight, correct to 1 decimal place.

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Section c, Question 13

[3 marks]Probability with selections without replacement
Fifteen girls and ten boys each want one of three tickets. The three people to receive a ticket are chosen at random from the 25. Find the probability that exactly 2 boys receive a ticket, correct to 3 significant figures.

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[3 marks]Probability with selections without replacement
Fifteen girls and ten boys each want one of three tickets. The three people to receive a ticket are chosen at random from the 25. Find the probability that at least 2 girls receive a ticket, correct to 3 significant figures.

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Section c, Question 14

[2 marks]Continuous random variables and conditional probability
The duration XX minutes of a telephone call has probability density function f(x)=x−2f(x)=x^{-2} for x≥1x\ge1 and f(x)=0f(x)=0 otherwise. Find P(X>5)P(X>5).

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[2 marks]Continuous random variables and conditional probability
The duration XX minutes of a telephone call has probability density function f(x)=x−2f(x)=x^{-2} for x≥1x\ge1. A call has already lasted 5 minutes. Which expression gives the probability that its total duration is less than 7 minutes?
  1. AP(X>5)P(5<X<7)\dfrac{P(X>5)}{P(5<X<7)}
  2. BP(5<X<7)P(X>5)\dfrac{P(5<X<7)}{P(X>5)}
  3. CP(X<7)P(X>5)\dfrac{P(X<7)}{P(X>5)}
  4. DP(5<X<7)×P(X>5)P(5<X<7)\times P(X>5)
[3 marks]Continuous random variables and conditional probability
The duration XX minutes of a telephone call has probability density function f(x)=x−2f(x)=x^{-2} for x≥1x\ge1 and f(x)=0f(x)=0 otherwise. Given that a call has already lasted 5 minutes, find the probability that its total duration will be less than 7 minutes.

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