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ZIMSEC A Level · 9164/2 · J2009

Pure Mathematics Paper 2 June 2009

Questions
52
Total marks
123
Syllabus code
9164/2

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Questions
52
Pass mark
32
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 1

[1 marks]Recurring decimals as fractions, geometric series
The recurring decimal 5,42˙7˙5,4\dot{2}\dot{7} can be written as 5,4+0,027+0,00027+0,0000027+…5,4+0,027+0,00027+0,0000027+\ldots. What is the common ratio of the geometric series that follows the 5,4?
  1. A0,001
  2. B0,01
  3. C0,027
  4. D0,1
[3 marks]Recurring decimals as fractions, geometric series
Given that 5,42˙7˙=5,4+0,027+0,00027+0,0000027+…5,4\dot{2}\dot{7}=5,4+0,027+0,00027+0,0000027+\ldots, express the number 5,42˙7˙5,4\dot{2}\dot{7} in the form ab\dfrac{a}{b}, where aa and bb are integers.

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Section a, Question 2

[3 marks]Parametric differentiation, eliminating a parameter
A curve has parametric equations x=asin⁡2θ+θx=a\sin^{2}\theta+\theta and y=acos⁡2θ−θy=a\cos^{2}\theta-\theta. Find dydx\dfrac{dy}{dx}.

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[2 marks]Parametric differentiation, eliminating a parameter
A curve has parametric equations x=asin⁡2θ+θx=a\sin^{2}\theta+\theta and y=acos⁡2θ−θy=a\cos^{2}\theta-\theta. By eliminating θ\theta, express the curve as a Cartesian equation.

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Section a, Question 3

[1 marks]Trigonometry: angles of a triangle and the sine rule
In a triangle ABC, BAC^=(π2+θ)\hat{BAC}=\left(\dfrac{\pi}{2}+\theta\right) radians and ACB^=(θ−π2)\hat{ACB}=\left(\theta-\dfrac{\pi}{2}\right) radians. Find ABC^\hat{ABC} in radians.

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[3 marks]Trigonometry: angles of a triangle and the sine rule
In a triangle ABC, BAC^=(π2+θ)\hat{BAC}=\left(\dfrac{\pi}{2}+\theta\right) radians and ABC^=(π−2θ)\hat{ABC}=(\pi-2\theta) radians. Use the sine rule to express BCAC\dfrac{BC}{AC} in terms of θ\theta as simply as possible.

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[2 marks]Trigonometry: angles of a triangle and the sine rule
In a triangle ABC it is known that BCAC=12sin⁡θ\dfrac{BC}{AC}=\dfrac{1}{2\sin\theta}. Find the value of θ\theta, in radians, for which BC=2ACBC=2AC.

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Section a, Question 4

[2 marks]Proof by induction applied to repeated differentiation
The result dn(xm)dxn=m!(m−n)!xm−n\dfrac{d^{n}(x^{m})}{dx^{n}}=\dfrac{m!}{(m-n)!}x^{m-n} is to be proved by induction. Write down the expression the formula gives when n=1n=1.

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[3 marks]Proof by induction applied to repeated differentiation
In proving dn(xm)dxn=m!(m−n)!xm−n\dfrac{d^{n}(x^{m})}{dx^{n}}=\dfrac{m!}{(m-n)!}x^{m-n} by induction, you assume it for n=kn=k and differentiate once more. Which step completes the argument?
  1. Am!(m−k)!(m−k)xm−k=m!(m−k−1)!xm−k\dfrac{m!}{(m-k)!}(m-k)x^{m-k}=\dfrac{m!}{(m-k-1)!}x^{m-k}
  2. Bm!(m−k)!(m−k)xm−k−1=m!(m−k−1)!xm−k−1\dfrac{m!}{(m-k)!}(m-k)x^{m-k-1}=\dfrac{m!}{(m-k-1)!}x^{m-k-1}
  3. Cm!(m−k)!xm−k×x=m!(m−k)!xm−k+1\dfrac{m!}{(m-k)!}x^{m-k}\times x=\dfrac{m!}{(m-k)!}x^{m-k+1}
  4. D(m−k)!m!(m−k)xm−k−1=m!(m−k+1)!xm−k−1\dfrac{(m-k)!}{m!}(m-k)x^{m-k-1}=\dfrac{m!}{(m-k+1)!}x^{m-k-1}
[3 marks]Proof by induction applied to repeated differentiation
Use the result dn(xm)dxn=m!(m−n)!xm−n\dfrac{d^{n}(x^{m})}{dx^{n}}=\dfrac{m!}{(m-n)!}x^{m-n} to find the third derivative of x7x^{7}.

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Section a, Question 5

[3 marks]Binomial and Maclaurin series expansions
Expand 1+ax1−bx\dfrac{1+ax}{1-bx} as a series in ascending powers of xx, up to and including the term in x3x^{3}.
  1. A1+(a+b)x+(a+b)2x2+(a+b)3x31+(a+b)x+(a+b)^{2}x^{2}+(a+b)^{3}x^{3}
  2. B1+ax+abx2+ab2x31+ax+abx^{2}+ab^{2}x^{3}
  3. C1+(a+b)x+b(a+b)x2+b2(a+b)x31+(a+b)x+b(a+b)x^{2}+b^{2}(a+b)x^{3}
  4. D1+(a−b)x+b(a−b)x2+b2(a−b)x31+(a-b)x+b(a-b)x^{2}+b^{2}(a-b)x^{3}
[2 marks]Binomial and Maclaurin series expansions
Write down the Maclaurin's theorem expansion of exe^{x} up to and including the term in x3x^{3}.

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[2 marks]Binomial and Maclaurin series expansions
Given that 1+ax1−bx=1+(a+b)x+b(a+b)x2+b2(a+b)x3+…\dfrac{1+ax}{1-bx}=1+(a+b)x+b(a+b)x^{2}+b^{2}(a+b)x^{3}+\ldots and ex=1+x+x22+x36+…e^{x}=1+x+\dfrac{x^{2}}{2}+\dfrac{x^{3}}{6}+\ldots, determine the values of aa and bb for which 1+ax1−bx−ex=cx3\dfrac{1+ax}{1-bx}-e^{x}=cx^{3}.

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[2 marks]Binomial and Maclaurin series expansions
With a=b=12a=b=\dfrac12, the expansion of 1+ax1−bx\dfrac{1+ax}{1-bx} differs from that of exe^{x} only in the term in x3x^{3}, so that 1+ax1−bx−ex=cx3\dfrac{1+ax}{1-bx}-e^{x}=cx^{3}. State the value of cc.

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Section a, Question 6

[2 marks]Inverse of a 3 by 3 matrix, simultaneous equations
Given A=(−13125031−2)\mathbf{A}=\begin{pmatrix}-1&3&1\\2&5&0\\3&1&-2\end{pmatrix}, find det⁡A\det\mathbf{A}.

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[2 marks]Inverse of a 3 by 3 matrix, simultaneous equations
For the matrix A=(−13125031−2)\mathbf{A}=\begin{pmatrix}-1&3&1\\2&5&0\\3&1&-2\end{pmatrix}, find the cofactor of the top-left element −1-1.

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[3 marks]Inverse of a 3 by 3 matrix, simultaneous equations
Given A=(−13125031−2)\mathbf{A}=\begin{pmatrix}-1&3&1\\2&5&0\\3&1&-2\end{pmatrix} with det⁡A=9\det\mathbf{A}=9, which matrix is A−1\mathbf{A}^{-1}?
  1. A19(−107−54−12−1310−11)\dfrac19\begin{pmatrix}-10&7&-5\\4&-1&2\\-13&10&-11\end{pmatrix}
  2. B19(10−75−41−213−1011)\dfrac19\begin{pmatrix}10&-7&5\\-4&1&-2\\13&-10&11\end{pmatrix}
  3. C19(−13125031−2)\dfrac19\begin{pmatrix}-1&3&1\\2&5&0\\3&1&-2\end{pmatrix}
  4. D19(−104−137−110−52−11)\dfrac19\begin{pmatrix}-10&4&-13\\7&-1&10\\-5&2&-11\end{pmatrix}
[3 marks]Inverse of a 3 by 3 matrix, simultaneous equations
Using A−1=19(−107−54−12−1310−11)\mathbf{A}^{-1}=\dfrac19\begin{pmatrix}-10&7&-5\\4&-1&2\\-13&10&-11\end{pmatrix}, solve the equations −x+3y+z=1-x+3y+z=1, 2x+5y=32x+5y=3, 3x+y−2z=33x+y-2z=3.

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Section a, Question 7

[2 marks]Complex numbers: roots of a quartic, exponential form, loci
Express the complex number ei5π6e^{i\frac{5\pi}{6}} in the form a+iba+ib, where aa and bb are real.

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[2 marks]Complex numbers: roots of a quartic, exponential form, loci
The polynomial f(z)=z4+3z3+2z2+3z+1f(z)=z^{4}+\sqrt3z^{3}+2z^{2}+\sqrt3z+1 has real coefficients and ei5π6e^{i\frac{5\pi}{6}} as a root. Why must e−i5π6e^{-i\frac{5\pi}{6}} also be a root?
  1. ABecause the roots of any polynomial with irrational coefficients are always symmetric about the imaginary axis.
  2. BBecause the non-real roots of a polynomial with real coefficients occur in conjugate pairs.
  3. CBecause the coefficients of f(z)f(z) include 3\sqrt3, which is irrational.
  4. DBecause every quartic must have four roots of equal modulus.
[3 marks]Complex numbers: roots of a quartic, exponential form, loci
Given that ei5π6e^{i\frac{5\pi}{6}} and its conjugate are roots of f(z)=z4+3z3+2z2+3z+1f(z)=z^{4}+\sqrt3z^{3}+2z^{2}+\sqrt3z+1, find the two quadratic factors of f(z)f(z).

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[3 marks]Complex numbers: roots of a quartic, exponential form, loci
Solve f(z)=z4+3z3+2z2+3z+1=0f(z)=z^{4}+\sqrt3z^{3}+2z^{2}+\sqrt3z+1=0 completely, given that f(z)=(z2+3z+1)(z2+1)f(z)=(z^{2}+\sqrt3z+1)(z^{2}+1). Give the roots in the form eiθe^{i\theta}.

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[2 marks]Complex numbers: roots of a quartic, exponential form, loci
Describe fully the locus of points in the Argand diagram for which ∣z−1+i∣=2|z-1+i|=2.

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[2 marks]Complex numbers: roots of a quartic, exponential form, loci
Which region of the Argand diagram is defined by −π3≤arg⁡(z)≤π3-\dfrac{\pi}{3}\le\arg(z)\le\dfrac{\pi}{3}?
  1. AThe infinite wedge with vertex at the origin between the half-lines at π3\dfrac{\pi}{3} above and π3\dfrac{\pi}{3} below the negative real axis, with both boundary half-lines included.
  2. BA disc of radius π3\dfrac{\pi}{3} centred at the origin.
  3. CThe half-plane to the right of the imaginary axis.
  4. DThe infinite wedge with vertex at the origin between the half-lines at π3\dfrac{\pi}{3} above and π3\dfrac{\pi}{3} below the positive real axis.

Section a, Question 8

[3 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
The lines ℓ1\ell_1 and ℓ2\ell_2 have equations r=(0,1,1)+μ(1,3,2)\mathbf{r}=(0,1,1)+\mu(1,3,2) and r=(1,2,3)+λ(1,1,2)\mathbf{r}=(1,2,3)+\lambda(1,1,2). Find the coordinates of the point A where they intersect.

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[3 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
The line ℓ1\ell_1 has equation r=(0,1,1)+μ(1,3,2)\mathbf{r}=(0,1,1)+\mu(1,3,2) and the plane π\pi has equation r⋅(1,2,−3)=2\mathbf{r}\cdot(1,2,-3)=2. Find the coordinates of the point B where ℓ1\ell_1 meets π\pi.

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[3 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
The line ℓ2\ell_2 has equation r=(1,2,3)+λ(1,1,2)\mathbf{r}=(1,2,3)+\lambda(1,1,2) and the plane π\pi has equation r⋅(1,2,−3)=2\mathbf{r}\cdot(1,2,-3)=2. Find the coordinates of the point C where ℓ2\ell_2 meets π\pi.

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[3 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
The lines ℓ1\ell_1 and ℓ2\ell_2 have direction vectors (1,3,2)(1,3,2) and (1,1,2)(1,1,2). Find cos⁡θ\cos\theta, where θ\theta is the acute angle between them.

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[2 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
The acute angle θ\theta between two lines satisfies cos⁡θ=421\cos\theta=\dfrac{4}{\sqrt{21}}. Find sin⁡θ\sin\theta in surd form.

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[2 marks]Vectors: intersecting lines, line and plane intersections, area of a triangle
Points A(0,1,1)A(0,1,1), B(3,10,7)B(3,10,7) and C(−1,0,−1)C(-1,0,-1) are such that AB lies along a line ℓ1\ell_1 and AC along a line ℓ2\ell_2, and the acute angle between the lines has sin⁡θ=521\sin\theta=\sqrt{\dfrac{5}{21}}. Find the exact area of triangle ABC.

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Section b

Section b, Question 9

[3 marks]Equilibrium of coplanar forces
Two forces P and Q, each of magnitude 80 N, act on an object and are inclined at 60∘60^\circ to each other. Find the magnitude of the single force required to keep the object in equilibrium.

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Section b, Question 10

[2 marks]Kinematics: uniform acceleration in a straight line
A cheetah starts from rest at A and accelerates at 3 ms−2^{-2} in a straight line, catching an antelope at C where AC = 54 m. Find the time taken by the cheetah to catch the antelope.

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[2 marks]Kinematics: uniform acceleration in a straight line
A cheetah at A and an antelope at B, where AB = 24 m, both start from rest at the same instant. The antelope accelerates uniformly away in the direction AB and is caught 6 seconds later at C on AB produced, where AC = 54 m. Find the acceleration of the antelope.

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Section b, Question 11

[2 marks]Connected particles on an inclined plane with friction
A 1 kg mass lies on a rough plane inclined at θ\theta, where sin⁡θ=35\sin\theta=\dfrac35, and the coefficient of friction is 14\dfrac14. Find the total force, in terms of gg, resisting motion of the mass up the plane.

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[2 marks]Connected particles on an inclined plane with friction
A 1 kg mass on a rough plane inclined at θ\theta (where sin⁡θ=35\sin\theta=\dfrac35, coefficient of friction 14\dfrac14) is joined by a string over a smooth pulley to a 4 kg mass hanging freely. Why does the 1 kg mass slide up the plane?
  1. ABecause the 4 kg weight 4g4g exceeds the total resistance of 0,8g0{,}8g.
  2. BBecause sin⁡θ>cos⁡θ\sin\theta>\cos\theta for this angle.
  3. CBecause friction always acts up a plane when a string is attached.
  4. DBecause the 1 kg mass is lighter than the 4 kg mass, whatever the angle.
[2 marks]Connected particles on an inclined plane with friction
A 1 kg mass on a rough incline (total resistance 0,8g0{,}8g N) is connected over a smooth pulley to a 4 kg mass hanging freely. Taking g=9,81g=9{,}81 ms−2^{-2}, find the acceleration of the system.

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[2 marks]Connected particles on an inclined plane with friction
A 4 kg mass hanging 2,5 m above the floor accelerates downwards from rest at 6,286{,}28 ms−2^{-2}. Find the velocity with which it hits the floor.

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Section b, Question 12

[2 marks]Projectile motion from a raised point
A particle is projected at 35∘35^\circ above the horizontal with speed 25 ms−1^{-1}. Find the vertical component of its initial velocity.

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[2 marks]Projectile motion from a raised point
A particle is projected at 35∘35^\circ above the horizontal with speed 25 ms−1^{-1} from a point O which is 5 m above level ground. Taking g=9,81g=9{,}81 ms−2^{-2}, find the height above the ground of H, the highest point of its path.

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[2 marks]Projectile motion from a raised point
A projectile reaches its highest point H at 15,4815{,}48 m above level ground, then falls freely to the ground at B. Taking g=9,81g=9{,}81 ms−2^{-2}, find the time taken to travel from H to B.

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[3 marks]Projectile motion from a raised point
A particle projected at 35∘35^\circ with speed 25 ms−1^{-1} from a point O 5 m above level ground takes 1,461{,}46 s to reach its highest point and a further 1,781{,}78 s to fall to the ground at B. Find the horizontal distance between O and B.

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Section c

Section c, Question 13

[2 marks]Probability: exhaustive outcomes and independent selections
An experiment has only two possible outcomes. The first occurs with probability pp and the second with probability p2p^{2}. Find the value of pp correct to 3 decimal places.

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[3 marks]Probability: exhaustive outcomes and independent selections
In a city the probability that a person favours capital punishment is 0,55 and that a person is against it is 0,45. Two persons are selected at random. Find the probability that at least one of them favours capital punishment.

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Section c, Question 14

[2 marks]Continuous random variables: probability density function and expectation
Show that f(x)=128(6x−4)f(x)=\dfrac{1}{28}(6x-4) for 2≤x≤42\le x\le4 is a probability density function by evaluating ∫24128(6x−4) dx\displaystyle\int_{2}^{4}\frac{1}{28}(6x-4)\,dx.

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[3 marks]Continuous random variables: probability density function and expectation
The continuous random variable X has probability density function f(x)=128(6x−4)f(x)=\dfrac{1}{28}(6x-4) for 2≤x≤42\le x\le4 and zero elsewhere. Find E(X)E(X).

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Section c, Question 15

[2 marks]Cumulative frequency curves, quartiles and interquartile range
The masses of 200 students, measured to the nearest kg, are grouped as 46-50 (20 students), 51-55 (60), 56-60 (56), 61-65 (35), 66-70 (19) and 71-75 (10). Find the cumulative frequency up to the upper class boundary 60,5 kg.

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[3 marks]Cumulative frequency curves, quartiles and interquartile range
The masses of 200 students, to the nearest kg, are grouped as 46-50 (20), 51-55 (60), 56-60 (56), 61-65 (35), 66-70 (19) and 71-75 (10). Estimate the lower quartile of the distribution.

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[3 marks]Cumulative frequency curves, quartiles and interquartile range
The masses of 200 students, to the nearest kg, are grouped as 46-50 (20), 51-55 (60), 56-60 (56), 61-65 (35), 66-70 (19) and 71-75 (10), giving Q1=53,0Q_1=53{,}0 kg. Estimate the interquartile range.

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[1 marks]Cumulative frequency curves, quartiles and interquartile range
The masses of 200 students, to the nearest kg, are grouped as 46-50 (20), 51-55 (60), 56-60 (56), 61-65 (35), 66-70 (19) and 71-75 (10). Estimate the percentage of students with a mass of 54 kg or less.

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Section c, Question 16

[3 marks]Normal distribution and the binomial distribution
The heights of flowers in a bed are normally distributed with mean 21,1 cm and standard deviation 4,0 cm. Find the probability that a flower has a height greater than 25 cm.

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[2 marks]Normal distribution and the binomial distribution
The heights of flowers in a bed are normally distributed with P(height>25 cm)=0,1648P(\text{height}>25\text{ cm})=0{,}1648. Eight flowers are picked at random. State the distribution of the number of these flowers whose heights are less than 25 cm.

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[3 marks]Normal distribution and the binomial distribution
The number of flowers under 25 cm among 8 picked at random follows B(8; 0,8352)B(8;\,0{,}8352). Find the probability that fewer than three of them have heights less than 25 cm, giving your answer to 3 significant figures.

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