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ZIMSEC A Level · 9164/2 · J2016

Pure Mathematics Paper 2 June 2016

Questions
50
Total marks
120
Syllabus code
9164/2

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Questions
50
Pass mark
30
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 1

[2 marks]Integration by substitution
Evaluate ∫π3π2cos⁡x3+cos⁡2x dx\displaystyle\int_{\pi}^{\frac{3\pi}{2}}\frac{\cos x}{3+\cos^{2}x}\,dx, using the substitution u=sin⁡xu=\sin x. Give the exact answer as a single natural logarithm.

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[2 marks]Integration by substitution
The substitution u=sin⁡xu=\sin x is used on ∫π3π2cos⁡x3+cos⁡2x dx\displaystyle\int_{\pi}^{\frac{3\pi}{2}}\frac{\cos x}{3+\cos^{2}x}\,dx. Which integral in uu does it become, limits included?
  1. A∫01du4−u2\displaystyle\int_{0}^{1}\frac{du}{4-u^{2}}
  2. B∫−10u du4−u2\displaystyle\int_{-1}^{0}\frac{u\,du}{4-u^{2}}
  3. C∫0−1du4−u2\displaystyle\int_{0}^{-1}\frac{du}{4-u^{2}}
  4. D∫0−1du2+u2\displaystyle\int_{0}^{-1}\frac{du}{2+u^{2}}
[2 marks]Partial fractions
Express 14−u2\dfrac{1}{4-u^{2}} in partial fractions.
  1. A14(12+u+12−u)\dfrac{1}{4}\left(\dfrac{1}{2+u}+\dfrac{1}{2-u}\right)
  2. B12+u−12−u\dfrac{1}{2+u}-\dfrac{1}{2-u}
  3. C14(12−u−12+u)\dfrac{1}{4}\left(\dfrac{1}{2-u}-\dfrac{1}{2+u}\right)
  4. D12(12+u−12−u)\dfrac{1}{2}\left(\dfrac{1}{2+u}-\dfrac{1}{2-u}\right)
[2 marks]Integration by substitution
In the integral ∫π3π2cos⁡x3+cos⁡2x dx\displaystyle\int_{\pi}^{\frac{3\pi}{2}}\frac{\cos x}{3+\cos^{2}x}\,dx the substitution u=sin⁡xu=\sin x is made. State the new lower and upper limits in uu, in that order.

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Section a, Question 2

[2 marks]Differential equations
The gradient of a curve at a point (x;y)(x;y) is proportional to the product of x\sqrt{x} and y2y^{2}. Which differential equation says this, with kk constant?
  1. Adydx=kx2y\dfrac{dy}{dx}=kx^{2}\sqrt{y}
  2. Bdydx=k(x+y2)\dfrac{dy}{dx}=k\left(\sqrt{x}+y^{2}\right)
  3. Cdydx=kxy2\dfrac{dy}{dx}=\dfrac{k\sqrt{x}}{y^{2}}
  4. Ddydx=ky2x\dfrac{dy}{dx}=ky^{2}\sqrt{x}
[3 marks]Differential equations
A curve satisfies dydx=ky2x\dfrac{dy}{dx}=ky^{2}\sqrt{x} and passes through the points (0;−2)(0;-2) and (9;1)(9;1). Find the exact value of the constant kk.

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[3 marks]Differential equations
A curve has dydx=ky2x\dfrac{dy}{dx}=ky^{2}\sqrt{x} and passes through (0;−2)(0;-2) and (9;1)(9;1). What is its equation?
  1. Ay=9x32−18y=\dfrac{9}{x^{\frac{3}{2}}-18}
  2. By=189−x32y=\dfrac{18}{9-x^{\frac{3}{2}}}
  3. Cy=18x32−9y=\dfrac{18}{x^{\frac{3}{2}}-9}
  4. Dy=x32−918y=\dfrac{x^{\frac{3}{2}}-9}{18}
[2 marks]Asymptotes
Write down an equation of an asymptote of the curve y=18x32−9y=\dfrac{18}{x^{\frac{3}{2}}-9}.
  1. Ay=x32y=x^{\frac{3}{2}}
  2. By=0y=0
  3. Cx=18x=18
  4. Dy=18y=18

Section a, Question 3

[2 marks]Complex numbers, de Moivre's theorem
The roots of z7−8−8i=0z^{7}-8-8i=0 are written as r(cos⁡θ+isin⁡θ)r(\cos\theta+i\sin\theta). Find the exact value of rr.

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[2 marks]Complex numbers, argument
Find the argument of the complex number 8+8i8+8i, in radians.

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[2 marks]Complex numbers, roots of unity
The equation z7−8−8i=0z^{7}-8-8i=0 has seven roots. Give the smallest positive argument among them, in radians as a multiple of π\pi.

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[3 marks]Complex numbers, de Moivre's theorem
Which of these is a root of the equation z7−8−8i=0z^{7}-8-8i=0?
  1. A82(cos⁡π28+isin⁡π28)8\sqrt{2}\left(\cos\dfrac{\pi}{28}+i\sin\dfrac{\pi}{28}\right)
  2. B2(cos⁡π4+isin⁡π4)\sqrt{2}\left(\cos\dfrac{\pi}{4}+i\sin\dfrac{\pi}{4}\right)
  3. C2(cos⁡π28+isin⁡π28)\sqrt{2}\left(\cos\dfrac{\pi}{28}+i\sin\dfrac{\pi}{28}\right)
  4. D2(cos⁡π7+isin⁡π7)2\left(\cos\dfrac{\pi}{7}+i\sin\dfrac{\pi}{7}\right)
[2 marks]Argand diagrams, loci
On an Argand diagram, what is the locus of the points zz for which Arg(z+1)=π3Arg(z+1)=\dfrac{\pi}{3}?
  1. AA half line starting at (1;0)(1;0), that point excluded, at 60∘60^{\circ} to the positive real axis.
  2. BA circle of radius 1 centred at the origin.
  3. CThe whole straight line through (−1;0)(-1;0) at 60∘60^{\circ} to the positive real axis.
  4. DA half line starting at (−1;0)(-1;0), that point excluded, at 60∘60^{\circ} to the positive real axis.

Section a, Question 4

[2 marks]Repeated differentiation
Given y=x2exy=x^{2}e^{x}, find d2ydx2\dfrac{d^{2}y}{dx^{2}}.
  1. A2ex+2xex+x2ex2e^{x}+2xe^{x}+x^{2}e^{x}
  2. B2xex+x2ex2xe^{x}+x^{2}e^{x}
  3. C4ex+4xex+x2ex4e^{x}+4xe^{x}+x^{2}e^{x}
  4. D2ex+4xex+x2ex2e^{x}+4xe^{x}+x^{2}e^{x}
[3 marks]Repeated differentiation
Given y=x2exy=x^{2}e^{x}, find d3ydx3\dfrac{d^{3}y}{dx^{3}} in its simplest form.
  1. A2ex+6xex+x2ex2e^{x}+6xe^{x}+x^{2}e^{x}
  2. B6ex+6xex+x2ex6e^{x}+6xe^{x}+x^{2}e^{x}
  3. C4ex+6xex+x2ex4e^{x}+6xe^{x}+x^{2}e^{x}
  4. D6ex+4xex+x2ex6e^{x}+4xe^{x}+x^{2}e^{x}
[3 marks]Mathematical induction
For y=x2exy=x^{2}e^{x} the statement dnydxn=(n−1)(2ex)+2xex+dn−1ydxn−1\dfrac{d^{n}y}{dx^{n}}=(n-1)\left(2e^{x}\right)+2xe^{x}+\dfrac{d^{n-1}y}{dx^{n-1}} is to be proved by induction for n≥2n\geq 2. What does the base case n=2n=2 require you to check?
  1. AThat dydx=2xex+x2ex\dfrac{dy}{dx}=2xe^{x}+x^{2}e^{x}.
  2. BThat d2ydx2=4ex+2xex+dydx\dfrac{d^{2}y}{dx^{2}}=4e^{x}+2xe^{x}+\dfrac{dy}{dx}.
  3. CThat d3ydx3=4ex+2xex+d2ydx2\dfrac{d^{3}y}{dx^{3}}=4e^{x}+2xe^{x}+\dfrac{d^{2}y}{dx^{2}}.
  4. DThat d2ydx2=2ex+2xex+dydx\dfrac{d^{2}y}{dx^{2}}=2e^{x}+2xe^{x}+\dfrac{dy}{dx}.
[3 marks]Mathematical induction
In an induction proof it is assumed that dkydxk=(k−1)(2ex)+2xex+dk−1ydxk−1\dfrac{d^{k}y}{dx^{k}}=(k-1)\left(2e^{x}\right)+2xe^{x}+\dfrac{d^{k-1}y}{dx^{k-1}}. Differentiating both sides with respect to xx gives which result?
  1. Adk+1ydxk+1=(k−1)(2ex)+2xex+dkydxk\dfrac{d^{k+1}y}{dx^{k+1}}=(k-1)\left(2e^{x}\right)+2xe^{x}+\dfrac{d^{k}y}{dx^{k}}
  2. Bdk+1ydxk+1=k(2ex)+2xex+dkydxk\dfrac{d^{k+1}y}{dx^{k+1}}=k\left(2e^{x}\right)+2xe^{x}+\dfrac{d^{k}y}{dx^{k}}
  3. Cdk+1ydxk+1=(k+1)(2ex)+2xex+dkydxk\dfrac{d^{k+1}y}{dx^{k+1}}=(k+1)\left(2e^{x}\right)+2xe^{x}+\dfrac{d^{k}y}{dx^{k}}
  4. Ddk+1ydxk+1=(k−1)(2ex)+2ex+dkydxk\dfrac{d^{k+1}y}{dx^{k+1}}=(k-1)\left(2e^{x}\right)+2e^{x}+\dfrac{d^{k}y}{dx^{k}}

Section a, Question 5

[3 marks]Vectors, lines in three dimensions
The perpendicular bisector of the line joining A(0;2;2)A(0;2;2) and B(4;1;0)B(4;1;0) has Cartesian equation x−2=2y−34=z−1x-2=\dfrac{2y-3}{4}=z-1, and it passes through the point D(1;q;0)D(1;q;0). Find the value of qq.

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[3 marks]Vectors, lines in three dimensions
A line has Cartesian equation x−2=2y−34=z−1x-2=\dfrac{2y-3}{4}=z-1. What is a direction vector of the line?
  1. A(121)\begin{pmatrix}1\\2\\1\end{pmatrix}
  2. B(4−1−2)\begin{pmatrix}4\\-1\\-2\end{pmatrix}
  3. C(141)\begin{pmatrix}1\\4\\1\end{pmatrix}
  4. D(231)\begin{pmatrix}2\\3\\1\end{pmatrix}
[3 marks]Vectors, shortest distance
Find the exact shortest distance from the origin to the line x−2=2y−34=z−1x-2=\dfrac{2y-3}{4}=z-1.

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[3 marks]Planes in three dimensions
Find the Cartesian equation of the plane containing the points A(0;2;2)A(0;2;2), B(4;1;0)B(4;1;0) and C(−2;0;3)C(-2;0;3).

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Section a, Question 6

[3 marks]Determinants and singular matrices
The matrix A=(2k4312818k)A=\begin{pmatrix}2&k&4\\3&12&8\\1&8&k\end{pmatrix} is singular. Find the exact values of kk.

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[2 marks]Determinants
Find the determinant of the matrix (2543128185)\begin{pmatrix}2&5&4\\3&12&8\\1&8&5\end{pmatrix}.

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[3 marks]Inverse of a 3 by 3 matrix
Find the inverse of A=(2543128185)A=\begin{pmatrix}2&5&4\\3&12&8\\1&8&5\end{pmatrix}.
  1. A15(−47−8−76−412−119)\dfrac{1}{5}\begin{pmatrix}-4&7&-8\\-7&6&-4\\12&-11&9\end{pmatrix}
  2. B15(−4−71276−11−8−49)\dfrac{1}{5}\begin{pmatrix}-4&-7&12\\7&6&-11\\-8&-4&9\end{pmatrix}
  3. C(−47−8−76−412−119)\begin{pmatrix}-4&7&-8\\-7&6&-4\\12&-11&9\end{pmatrix}
  4. D15(4−787−64−1211−9)\dfrac{1}{5}\begin{pmatrix}4&-7&8\\7&-6&4\\-12&11&-9\end{pmatrix}
[3 marks]Simultaneous equations by matrices
Solve the simultaneous equations 2x+5y+4z=12x+5y+4z=1, 3x+12y+8z=13x+12y+8z=1 and x+8y+5z=1x+8y+5z=1. Give xx, yy and zz.

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[3 marks]Matrix transformations
A transformation PP of the plane maps A(1;2)A(1;2) onto A1(3;2)A_{1}(3;2) and B(2;5)B(2;5) onto B1(7;5)B_{1}(7;5). Find the matrix representing PP.
  1. A(3101)\begin{pmatrix}3&1\\0&1\end{pmatrix}
  2. B(1110)\begin{pmatrix}1&1\\1&0\end{pmatrix}
  3. C(1101)\begin{pmatrix}1&1\\0&1\end{pmatrix}
  4. D(1011)\begin{pmatrix}1&0\\1&1\end{pmatrix}
[3 marks]Matrix transformations
Describe fully the transformation of the plane represented by the matrix (1101)\begin{pmatrix}1&1\\0&1\end{pmatrix}.
  1. AA shear with the yy-axis invariant and shear factor 1.
  2. BA shear with the xx-axis invariant and shear factor 1.
  3. CAn enlargement of scale factor 1 centred at the origin.
  4. DA reflection in the line y=xy=x.
[2 marks]Area under a transformation
A triangle ABC of area 4 cm2^{2} is mapped onto triangle A1B1C1A_{1}B_{1}C_{1} by the transformation with matrix (1101)\begin{pmatrix}1&1\\0&1\end{pmatrix}. Find the area of triangle A1B1C1A_{1}B_{1}C_{1}.

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Section b

Section b, Question 7

[1 marks]Projectile motion
A projectile follows the path y=2x−0,01x2y=2x-0,01x^{2}, where xx is the horizontal displacement and yy the vertical displacement from the point of projection. Find the angle of projection, to the nearest degree.

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[2 marks]Projectile motion
A projectile follows the path y=2x−0,01x2y=2x-0,01x^{2}, where xx and yy are the horizontal and vertical displacements in metres from the point of projection. Taking g=9,81g=9,81 m s−2^{-2}, find the initial speed of projection in m s−1^{-1}.

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Section b, Question 8

[2 marks]Resultant of coplanar forces
Three coplanar forces act at a point Y, as shown. The 7 N force is horizontal, the 6 N force is inclined to it at 50∘50^{\circ} on the upper side, and the 5 N force acts backwards at 30∘30^{\circ} below the horizontal. Find the magnitude of the resultant, in newtons, correct to 2 significant figures.

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[3 marks]Resultant of coplanar forces
Three coplanar forces act at a point Y, as shown. The 7 N force is horizontal, the 6 N force is inclined to it at 50∘50^{\circ} on the upper side, and the 5 N force acts backwards at 30∘30^{\circ} below the horizontal. Find the angle, to the nearest degree, that the resultant makes with the 7 N force.

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Section b, Question 9

[2 marks]Kinematics
A particle starts from rest and accelerates at 2 ms−2^{-2} for 3 seconds. Find the velocity it has reached at the end of those 3 seconds, in m s−1^{-1}.

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[2 marks]Kinematics
A particle starts from rest and accelerates at 2 ms−2^{-2} for 3 seconds, then maintains the attained velocity for 4 seconds, then decelerates at 5 ms−2^{-2} for 2 seconds. Find the time, in seconds from the start, at which the particle is instantaneously at rest during the last stage.

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[2 marks]Kinematics
A particle starts from rest and accelerates at 2 ms−2^{-2} for 3 seconds, then maintains the attained velocity for 4 seconds, then decelerates at 5 ms−2^{-2} for 2 seconds. Find the total distance travelled in the 9 seconds, in metres.

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[2 marks]Kinematics
A particle starts from rest and accelerates at 2 ms−2^{-2} for 3 seconds, then maintains the attained velocity for 4 seconds, then decelerates at 5 ms−2^{-2} for 2 seconds. Find its displacement from the starting point at the end of the 9 seconds, in metres.

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Section b, Question 10

[3 marks]Connected particles
Two identical small trays, each of mass 0.2 kg, hang from a light inextensible string passing over a fixed smooth pulley, and they balance. A mass of 80 grammes is then placed on one tray, which begins to move downwards. Taking g=9,81g=9,81 m s−2^{-2}, find the acceleration of the trays in m s−2^{-2}.

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[3 marks]Connected particles
Two identical small trays, each of mass 0.2 kg, hang from a light inextensible string passing over a fixed smooth pulley, and they balance. A mass of 80 grammes is then placed on one tray, which begins to move downwards with the system accelerating at 1,635 m s−2^{-2}. Taking g=9,81g=9,81 m s−2^{-2}, find the tension in the string, in newtons.

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[2 marks]Connected particles
A mass of 80 grammes rests on a tray that is accelerating vertically downwards at 1,635 m s−2^{-2}. Taking g=9,81g=9,81 m s−2^{-2}, find the force in newtons that the tray exerts on the 80 gramme mass.

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Section c

Section c, Question 11

[2 marks]Probability density functions
A continuous random variable XX has probability density function ff with f(x)=0f(x)=0 outside 1≤x≤51\leq x\leq 5. On 1≤x≤31\leq x\leq 3, f(x)=kf(x)=k; on 3≤x≤43\leq x\leq 4 the graph is a straight line rising from kk to 2k2k; on 4≤x≤54\leq x\leq 5 it is a straight line falling from 2k2k to 0. Find the exact value of kk.

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[2 marks]Probability density functions
A probability density function has f(4)=49f(4)=\dfrac{4}{9} and f(5)=0f(5)=0, and its graph is a straight line between x=4x=4 and x=5x=5. What is f(x)f(x) on that interval?
  1. A209−49x\dfrac{20}{9}-\dfrac{4}{9}x
  2. B169−49x\dfrac{16}{9}-\dfrac{4}{9}x
  3. C49x−169\dfrac{4}{9}x-\dfrac{16}{9}
  4. D49−49x\dfrac{4}{9}-\dfrac{4}{9}x

Section c, Question 12

[2 marks]Normal distribution
For a standard Normal variable ZZ, find the value of zz for which P(Z>z)=0,03P(Z>z)=0,03. Give your answer to 3 decimal places.

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[2 marks]Normal distribution
The diameters of washers from a machine are Normally distributed with standard deviation 0.1 mm. There is to be a probability of only 3% that a diameter exceeds 2.0 mm. Find the mean diameter, in millimetres, correct to 3 significant figures.

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Section c, Question 13

[2 marks]Probability
Bag A contains 3 red balls and 2 white balls. Bag B contains 2 red balls and 3 white balls. A bag is selected at random and two balls are drawn from it, one after the other without replacement. Find the probability that both balls drawn are red.

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[3 marks]Conditional probability
Bag A contains 3 red balls and 2 white balls. Bag B contains 2 red balls and 3 white balls. A bag is selected at random and two balls are drawn from it, one after the other without replacement. Given that both balls drawn are red, find the probability that they came from bag A.

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Section c, Question 14

[2 marks]Discrete random variables
Two unbiased tetrahedral dice, each with faces marked 1, 2, 3 and 4, are tossed and XX is the sum of the two scores. Find P(X=5)P(X=5).

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[3 marks]Expectation
A player pays $1 to toss two unbiased tetrahedral dice with faces marked 1, 2, 3 and 4. If the sum of the scores is 2, 3 or 4 the player wins nothing; if it is 5, 6 or 7 the player wins $2; if it is greater than 7 the player wins $4. Find the expected gain, in dollars, from each game.

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Section c, Question 15

[2 marks]Measures of location
A stem and leaf diagram records the hectares owned by farmers around a small town, with key 1/3 meaning 13 hectares. Stem 0 has leaves 1, 4, 7; stem 1 has 1, 3, 8, 9; stem 2 has 0, 1, 2, 4, 7, 8; stem 3 has 0, 0, 2, 3, 4, 5, 7, 7; stem 4 has 2, 3, 5, 7. Find the median number of hectares.

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[2 marks]Measures of spread
A stem and leaf diagram records the hectares owned by farmers around a small town, with key 1/3 meaning 13 hectares. Stem 0 has leaves 1, 4, 7; stem 1 has 1, 3, 8, 9; stem 2 has 0, 1, 2, 4, 7, 8; stem 3 has 0, 0, 2, 3, 4, 5, 7, 7; stem 4 has 2, 3, 5, 7. Find the upper quartile.

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[2 marks]Measures of spread
A stem and leaf diagram records the hectares owned by farmers around a small town, with key 1/3 meaning 13 hectares. Stem 0 has leaves 1, 4, 7; stem 1 has 1, 3, 8, 9; stem 2 has 0, 1, 2, 4, 7, 8; stem 3 has 0, 0, 2, 3, 4, 5, 7, 7; stem 4 has 2, 3, 5, 7. Find the interquartile range.

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