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Paper 2 · Integration

Evaluate the exact value of 01x2exdx\displaystyle\int_0^1x^2e^x\,dx using integration by parts.

Model answer

e-2

Also accepted: 0.72, 0.718

Explanation: With u=x2u=x^2, dv=exdxdv=e^x\,dx: x2exdx=x2ex2xex+2ex+C\int x^2e^x\,dx=x^2e^x-2xe^x+2e^x+C. Evaluating from 0 to 1 gives e20.71828e-2\approx0.71828.

Derived from ZIMSEC Pure Mathematics Paper 2, November 2025, Q10

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