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Paper 1 · Modulus / inequalities

Solve the inequality x1<x|x-1| < x.

Ax>12x > \tfrac{1}{2}
Bx<12x < \tfrac{1}{2}
C0<x<10 < x < 1
Dx>1x > 1
Explanation: Squaring both sides gives (x1)2<x2(x-1)^2<x^2, i.e. 2x+1<0-2x+1<0, so x>12x>\tfrac12.

Derived from ZIMSEC Mathematics Paper 1, June 2017, Q1

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