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Paper 1 · Exponential equations

Solve the equation 3x1+3x2=123^{x-1} + 3^{x-2} = 12.

Ax=2x = 2
Bx=3x = 3
Cx=4x = 4
Dx=27x = 27
Explanation: 3x3+3x9=4(3x)9=12\tfrac{3^x}{3}+\tfrac{3^x}{9}=\tfrac{4(3^x)}{9}=12, so 3x=27=333^x=27=3^3 and x=3x=3.

Derived from ZIMSEC Mathematics Paper 1, November 2019, Q1

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