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Paper 1 · November 2019 · Logarithms and Exponentials

Solve the equation 3x−1+3x−2=123^{x-1} + 3^{x-2} = 12.

Ax=3x = 3
Bx=4x = 4
Cx=27x = 27
Dx=2x = 2

Explanation

3x3+3x9=4(3x)9=12\tfrac{3^x}{3}+\tfrac{3^x}{9}=\tfrac{4(3^x)}{9}=12, so 3x=27=333^x=27=3^3 and x=3x=3.

Derived from ZIMSEC Mathematics Paper 1, November 2019, Q1

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