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Paper 1 · indices / exponential equations

Solve the equation 5x1+5x2=305^{x-1} + 5^{x-2} = 30.

Ax=2x = 2
Bx=3x = 3
Cx=5x = 5
Dx=125x = 125
Explanation: 5x1+5x2=5x(15+125)=6255x=305^{x-1}+5^{x-2}=5^x\left(\tfrac15+\tfrac1{25}\right)=\tfrac{6}{25}5^x=30, so 5x=125=535^x=125=5^3 and x=3x=3.

Derived from ZIMSEC Mathematics Paper 1, November 2013, Q1

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