Practise online Get the app

Paper 1 · June 2012 · Functions and Graphs

Given that $-4 < x < 2$ is the solution of the inequality $|x + a| < b$ , find the values of $a$ and $b$ .

A

a = 1

,

b = 3

B

a = 1

,

b = 6

C

a = -1

,

b = 3

D

a = 3

,

b = 1

Explanation

|x+a|<b

means

-b-a<x<b-a

. Matching with

-4<x<2

:

-b-a=-4

and

b-a=2

. Adding gives

-2a=-2

, so

a=1

and

b=3

.

Derived from ZIMSEC Mathematics Paper 1, June 2012, Q1

View this paper's sittings and topics→

More questions from this paper

In triangle $ABC$ , $AB = m$ cm, $AC = 12$ cm and angle $B\hat{A}C = 60°$ . Given that the area of the triangle is $\sqrt{675}$ cm $^2$ , find the exact value of $m$ .
Solve the simultaneous equations $2^x + 3^y = 5$ and $2^{x+2} - 3^{y+1} = 13$ .
Solve the equation $5^{x-1} + 5^{x-2} = 30$ .
Express $\dfrac{6}{3 + \sqrt{5} + \sqrt{14}}$ in the form $a + b\sqrt{c} + d\sqrt{e}$ .
A polynomial $f(x)$ leaves remainder $-9$ when divided by $(x-3)$ and remainder $-6$ when divided by $(2x-1)$ . Find the remainder when $f(x)$ is divided by $(x-3)(2x-1)$ .

Get the full paper, not just one question

Danho has every sitting for this paper, with your progress tracked question by question, offline.

Get it on Google Play Download on the App Store