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Paper 3 · June 2009 · Mole and Stoichiometry Calculations

A mixture of equal volumes of methane and ethane was burned in excess oxygen. After cooling to room temperature, the residual gas absorbed in KOH(aq)KOH_{(aq)} was found to be 30 cm3cm^3. What was the volume of methane at the beginning?

A10 cm3cm^3
B15 cm3cm^3
C20 cm3cm^3
D25 cm3cm^3

Explanation

The marking scheme gives answer A. Let volume of CH4CH_4 = x and C2H6C_2H_6 = x. CH4+2O2→CO2+2H2OCH_4 + 2O_2 \to CO_2 + 2H_2O; 2C2H6+7O2→4CO2+6H2O2C_2H_6 + 7O_2 \to 4CO_2 + 6H_2O. CO2 from methane = x, CO2 from ethane = 2x. Total CO2 = 3x = 30, so x = 10 cm3cm^3.

ZIMSEC Chemistry Paper 3, June 2009, Q2

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