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Paper 3 · atomic structure

What is the composition of the free radical of chlorine, 35Cl^{35}Cl?

atomic structure - ZIMSEC Chemistry past paper diagram
A17 protons, 18 neutrons, 16 electrons
B17 protons, 18 neutrons, 17 electrons
C18 protons, 17 neutrons, 17 electrons
D18 protons, 17 neutrons, 18 electrons
Explanation: The marking scheme gives answer B. 35Cl^{35}Cl has 17 protons and 18 neutrons. As a free radical it has one unpaired electron but the same number of electrons as protons (17), so it is neutral with 17 electrons.

ZIMSEC Chemistry Paper 3, June 2009, Q1

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