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Paper 4 · November 2004 · Enzymes

In this practical, starch solutions A, B and C were each hydrolysed by solution P then tested with Benedict's solution. The expected results were: tube A, dark orange (concentration greater than 0.005 mol/dm3); tube B, green (0.001 mol/dm3); tube C, yellow (0.0025 mol/dm3). Ranking the three tubes from LOWEST to HIGHEST reducing sugar concentration, what is the correct order?

Model answer

B, C, A

Also accepted: B C A, B then C then A

Explanation

Ordering the given concentrations (B 0.001 < C 0.0025 < A >0.005) from lowest to highest reducing sugar gives B, then C, then A.

Derived from ZIMSEC Biology 9190/4 Paper 4, November 2004, Q1

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