Danho
ZIMSEC A Level · 9164/4 · N2012

Statistics Paper 4 November 2012

Questions
42
Total marks
96
Syllabus code
9164/4

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Questions
42
Pass mark
26
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 1

[1 marks]Grouped data, mean and standard deviation

A group of 50 children raised money for charity. The amount raised by each child, to the nearest dollar ($), is recorded in the table.

amount ($)1 - 56 - 1011 - 1516 - 2021 - 2526 - 30
number of children20105681

State the smallest possible amount which may have been raised by one child.

Answer this when you sit the paper.

[2 marks]Grouped data, mean and standard deviation

A group of 50 children raised money for charity. The amount raised by each child, to the nearest dollar ($), is recorded in the table.

amount ($)1 - 56 - 1011 - 1516 - 2021 - 2526 - 30
number of children20105681

Calculate the mean amount raised.

Answer this when you sit the paper.

[2 marks]Grouped data, mean and standard deviation

A group of 50 children raised money for charity. The amount raised by each child, to the nearest dollar ($), is recorded in the table.

amount ($)1 - 56 - 1011 - 1516 - 2021 - 2526 - 30
number of children20105681

Calculate the standard deviation of the amounts raised.

Answer this when you sit the paper.

Section a, Question 2

[2 marks]Discrete random variables

A discrete random variable X takes the values 0, 1 and 2 with probabilities P0P_0, P1P_1 and P2P_2 respectively. It is given that E(X)=1,2E(X)=1,2 and Var⁡(X)=0,36\operatorname{Var}(X)=0,36.

Find E(X2)E(X^{2}).

Answer this when you sit the paper.

[2 marks]Discrete random variables

A discrete random variable X takes the values 0, 1 and 2 with probabilities P0P_0, P1P_1 and P2P_2 respectively. It is given that E(X)=1,2E(X)=1,2 and Var⁡(X)=0,36\operatorname{Var}(X)=0,36.

Find the value of P2P_2.

Answer this when you sit the paper.

[2 marks]Discrete random variables

A discrete random variable X takes the values 0, 1 and 2 with probabilities P0P_0, P1P_1 and P2P_2 respectively. It is given that E(X)=1,2E(X)=1,2 and Var⁡(X)=0,36\operatorname{Var}(X)=0,36.

Find the value of P0P_0.

Answer this when you sit the paper.

Section a, Question 3

[1 marks]Conditional probability

A student wishes to be enrolled at one of the three Zimbabwean universities BUSE, NUST and MSU. It is equally likely that the student will apply to any one of these three universities. The probability that the student will be admitted at BUSE is 60 %, while the probabilities that the student will be admitted at NUST and at MSU are 45 % and 35 % respectively.

Find the probability that the student applies to BUSE and is admitted there.

Answer this when you sit the paper.

[2 marks]Conditional probability

A student wishes to be enrolled at one of the three Zimbabwean universities BUSE, NUST and MSU. It is equally likely that the student will apply to any one of these three universities. The probability that the student will be admitted at BUSE is 60 %, while the probabilities that the student will be admitted at NUST and at MSU are 45 % and 35 % respectively.

Find the probability that the student will not be admitted at any one of the universities.

Answer this when you sit the paper.

[3 marks]Conditional probability

A student wishes to be enrolled at one of the three Zimbabwean universities BUSE, NUST and MSU. It is equally likely that the student will apply to any one of these three universities. The probability that the student will be admitted at BUSE is 60 %, while the probabilities that the student will be admitted at NUST and at MSU are 45 % and 35 % respectively.

Find the probability that the student applied to NUST, given that the student was not admitted into any one of the universities.

Answer this when you sit the paper.

Section a, Question 4

[3 marks]Normal distribution

The masses of passengers on a flight are normally distributed with mean μ\mu and standard deviation σ\sigma. 1,7 % of the passengers had masses greater than 75 kg and 98 % had masses more than 45 kg.

Find the value of σ\sigma.

Answer this when you sit the paper.

[3 marks]Normal distribution

The masses of passengers on a flight are normally distributed with mean μ\mu and standard deviation σ\sigma. 1,7 % of the passengers had masses greater than 75 kg and 98 % had masses more than 45 kg.

Find the value of μ\mu.

Answer this when you sit the paper.

Section a, Question 5

[1 marks]Continuous random variables

A continuous random variable X has probability density function

f(x)={ax20≤x≤114(7−3x)1≤x≤730otherwisef(x)=\begin{cases} ax^{2} & 0\le x\le 1 \\ \frac{1}{4}(7-3x) & 1\le x\le \frac{7}{3} \\ 0 & \text{otherwise}\end{cases}

where aa is a constant. Find the value of aa.

Answer this when you sit the paper.

[3 marks]Continuous random variables

A continuous random variable X has probability density function

f(x)={ax20≤x≤114(7−3x)1≤x≤730otherwisef(x)=\begin{cases} ax^{2} & 0\le x\le 1 \\ \frac{1}{4}(7-3x) & 1\le x\le \frac{7}{3} \\ 0 & \text{otherwise}\end{cases}

where aa is a constant, and it may be assumed that a=1a=1.

Find the mean of X.

Answer this when you sit the paper.

[3 marks]Continuous random variables

A continuous random variable X has probability density function

f(x)={ax20≤x≤114(7−3x)1≤x≤730otherwisef(x)=\begin{cases} ax^{2} & 0\le x\le 1 \\ \frac{1}{4}(7-3x) & 1\le x\le \frac{7}{3} \\ 0 & \text{otherwise}\end{cases}

where aa is a constant, and it may be assumed that a=1a=1.

Find the median of X.

Answer this when you sit the paper.

Section a, Question 6

[2 marks]Binomial distribution

20 % of the employees of an organisation joined a Housing Scheme.

From a random sample of 8 employees of the organisation, find the probability that only 2 employees joined the scheme.

Answer this when you sit the paper.

[2 marks]Binomial distribution

20 % of the employees of an organisation joined a Housing Scheme.

From a random sample of 8 employees of the organisation, find the probability that less than 3 employees joined the scheme.

Answer this when you sit the paper.

[1 marks]Normal approximation to the binomial distribution

20 % of the employees of an organisation joined a Housing Scheme.

A random sample of 100 employees of the organisation is taken. Find the variance of the number of employees in the sample who joined the scheme.

Answer this when you sit the paper.

[3 marks]Normal approximation to the binomial distribution

20 % of the employees of an organisation joined a Housing Scheme.

A larger random sample of 100 employees of the organisation was taken. Calculate the probability that less than 25 employees joined the scheme.

Answer this when you sit the paper.

Section a, Question 7

[1 marks]Poisson distribution

A transport company has 2 vans available for daily hire to ferry vegetables to a market. The daily demand for these vans may be assumed to have a Poisson distribution with mean 2.

Find the probability that no van is demanded on a particular day.

Answer this when you sit the paper.

[2 marks]Poisson distribution

A transport company has 2 vans available for daily hire to ferry vegetables to a market. The daily demand for these vans may be assumed to have a Poisson distribution with mean 2.

Find the probability that exactly 2 vans are demanded on a particular day.

Answer this when you sit the paper.

[3 marks]Poisson distribution

A transport company has 2 vans available for daily hire to ferry vegetables to a market. The daily demand for these vans may be assumed to have a Poisson distribution with mean 2.

Calculate the probability that on a particular day the transporter is not able to meet the demand for these vans.

Answer this when you sit the paper.

[3 marks]Poisson distribution

A transport company has 2 vans available for daily hire to ferry vegetables to a market. The daily demand for these vans may be assumed to have a Poisson distribution with mean 2.

Calculate the probability that exactly 4 hirings will occur in two consecutive days.

Answer this when you sit the paper.

Section a, Question 8

[2 marks]Normal distribution

A truck is carrying boxes of bathing soap and washing powder. The mass of a box of bathing soap is normally distributed with mean 65 kg and variance 8, and the mass of a box of washing powder is normally distributed with mean 50 kg and variance 7. All the boxes are independent of one another.

Find the probability that a box of bathing soap weighs less than 62 kg.

Answer this when you sit the paper.

[2 marks]Linear combinations of random variables

A truck is carrying boxes of bathing soap and washing powder. The mass of a box of bathing soap is normally distributed with mean 65 kg and variance 8, and the mass of a box of washing powder is normally distributed with mean 50 kg and variance 7. All the boxes are independent of one another.

Find the standard deviation of the total mass of 2 randomly chosen boxes of bathing soap.

Answer this when you sit the paper.

[3 marks]Linear combinations of random variables

A truck is carrying boxes of bathing soap and washing powder. The mass of a box of bathing soap is normally distributed with mean 65 kg and variance 8, and the mass of a box of washing powder is normally distributed with mean 50 kg and variance 7. All the boxes are independent of one another.

Find the probability that 2 randomly chosen boxes of bathing soap weigh a total of more than 140 kg.

Answer this when you sit the paper.

[3 marks]Linear combinations of random variables

A truck is carrying boxes of bathing soap and washing powder. The mass of a box of bathing soap is normally distributed with mean 65 kg and variance 8, and the mass of a box of washing powder is normally distributed with mean 50 kg and variance 7. All the boxes are independent of one another.

Find the probability that the mass of a box of bathing soap is greater than 43\frac{4}{3} of the mass of a box of washing powder.

Answer this when you sit the paper.

Section a, Question 9

[2 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

Calculate the expected frequency for employees with 'A' level qualifications and low earnings.

Answer this when you sit the paper.

[2 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

Calculate the expected frequency for employees with a degree and low earnings.

Answer this when you sit the paper.

[1 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

State the number of degrees of freedom for this test.

Answer this when you sit the paper.

[1 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

State the critical value of the test statistic at the 5 % level of significance.

Answer this when you sit the paper.

[3 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

Calculate the value of the chi-squared test statistic.

Answer this when you sit the paper.

[2 marks]Chi-squared test of association

The table shows a random sample of 4 140 employees classified by educational qualifications and by earnings.

qualificationsearnings: lowearnings: mediumearnings: high
'A' level115293242
diploma171415364
degree684992864

A chi-squared test is carried out, at the 5 % level of significance, of whether there is any association between qualification and earnings.

The calculated value of the test statistic is 45,2 and the critical value at the 5 % level is 9,488. What is the correct conclusion?

  1. ASince 45,2 exceeds 9,488, the test is inconclusive and a much larger sample would be needed.
  2. BSince 45,2 exceeds 9,488, reject the null hypothesis: qualification and earnings are associated.
  3. CSince 45,2 exceeds 9,488, the null hypothesis is disproved, so qualifications cause high earnings.
  4. DSince 45,2 exceeds 9,488, accept the null hypothesis: qualification and earnings are independent.

Section a, Question 10

[2 marks]Hypothesis testing and confidence intervals for a mean

The percentage score, x, was recorded for 250 'O' level Mathematics students and the data is summarised by ∑(x−80)=700\sum(x-80)=700 and ∑(x−80)2=25 142\sum(x-80)^{2}=25\,142. The population mean and variance of X are denoted by μ\mu and σ2\sigma^{2} respectively.

Calculate the sample mean score.

Answer this when you sit the paper.

[3 marks]Hypothesis testing and confidence intervals for a mean

The percentage score, x, was recorded for 250 'O' level Mathematics students and the data is summarised by ∑(x−80)=700\sum(x-80)=700 and ∑(x−80)2=25 142\sum(x-80)^{2}=25\,142. The population mean and variance of X are denoted by μ\mu and σ2\sigma^{2} respectively.

Show that the unbiased estimate of σ2\sigma^{2} is 93,1, correct to one decimal place, by calculating its value.

Answer this when you sit the paper.

[3 marks]Hypothesis testing and confidence intervals for a mean

The percentage score, x, was recorded for 250 'O' level Mathematics students and the data is summarised by ∑(x−80)=700\sum(x-80)=700 and ∑(x−80)2=25 142\sum(x-80)^{2}=25\,142. The population mean and variance of X are denoted by μ\mu and σ2\sigma^{2} respectively.

The unbiased estimate of σ2\sigma^{2} is 93,1. Calculate the value of the test statistic for testing H0H_0: μ=85\mu = 85 against H1H_1: μ<85\mu < 85.

Answer this when you sit the paper.

[2 marks]Hypothesis testing and confidence intervals for a mean

The percentage score, x, was recorded for 250 'O' level Mathematics students and the data is summarised by ∑(x−80)=700\sum(x-80)=700 and ∑(x−80)2=25 142\sum(x-80)^{2}=25\,142. The population mean and variance of X are denoted by μ\mu and σ2\sigma^{2} respectively.

The test statistic for H0H_0: μ=85\mu = 85 against H1H_1: μ<85\mu < 85 is z=−3,61z = -3,61, and the test is carried out at the 5 % level of significance. What is the correct conclusion?

  1. ASince −3,61<−1,645-3,61 < -1,645, reject H0H_0: the mean score is less than 85 % at the 5 % level.
  2. BSince −3,61<−1,96-3,61 < -1,96, reject H0H_0: the mean score is less than 85 % at the 5 % level.
  3. CSince −3,61<−1,645-3,61 < -1,645, do not reject H0H_0: the mean score can be taken as 85 %.
  4. DSince ∣−3,61∣>1,645|-3,61| > 1,645, reject H0H_0: the mean score differs from 85 % at the 5 % level.
[3 marks]Hypothesis testing and confidence intervals for a mean

The percentage score, x, was recorded for 250 'O' level Mathematics students and the data is summarised by ∑(x−80)=700\sum(x-80)=700 and ∑(x−80)2=25 142\sum(x-80)^{2}=25\,142. The population mean and variance of X are denoted by μ\mu and σ2\sigma^{2} respectively.

The sample mean is 82,8 and the unbiased estimate of σ2\sigma^{2} is 93,1. Calculate a symmetric 95 % confidence interval for the mean score.

Answer this when you sit the paper.

Section a, Question 11

[3 marks]Regression and correlation

A farmer supplies potatoes daily to a hypermarket. The masses of potatoes supplied and the fuel consumed by the delivery truck per trip were recorded for eight such trips.

mass in tonnes (x)0,71,82,53,24,15,46,36,9
volume of fuel in litres (y)10,011,212,213,013,014,215,615,8

The equation of the regression line of Y on X is of the form Y=a+bXY=a+bX. Find the value of the constant bb.

Answer this when you sit the paper.

[3 marks]Regression and correlation

A farmer supplies potatoes daily to a hypermarket. The masses of potatoes supplied and the fuel consumed by the delivery truck per trip were recorded for eight such trips.

mass in tonnes (x)0,71,82,53,24,15,46,36,9
volume of fuel in litres (y)10,011,212,213,013,014,215,615,8

The equation of the regression line of Y on X is of the form Y=a+bXY=a+bX, where b=0,907b=0,907. Find the value of the constant aa.

Answer this when you sit the paper.

[3 marks]Regression and correlation

A farmer supplies potatoes daily to a hypermarket. The masses of potatoes supplied and the fuel consumed by the delivery truck per trip were recorded for eight such trips.

mass in tonnes (x)0,71,82,53,24,15,46,36,9
volume of fuel in litres (y)10,011,212,213,013,014,215,615,8

The regression line of Y on X is Y=9,62+0,907XY=9,62+0,907X, where X is the mass in tonnes and Y is the volume of fuel in litres. Use it to estimate the maximum mass of potatoes that may be transported by 14 litres of fuel.

Answer this when you sit the paper.

[3 marks]Regression and correlation

A farmer supplies potatoes daily to a hypermarket. The masses of potatoes supplied and the fuel consumed by the delivery truck per trip were recorded for eight such trips.

mass in tonnes (x)0,71,82,53,24,15,46,36,9
volume of fuel in litres (y)10,011,212,213,013,014,215,615,8

Find the product moment correlation coefficient between the mass of potatoes and the volume of fuel consumed.

Answer this when you sit the paper.

[2 marks]Regression and correlation

A farmer supplies potatoes daily to a hypermarket. The masses of potatoes supplied and the fuel consumed by the delivery truck per trip were recorded for eight such trips.

mass in tonnes (x)0,71,82,53,24,15,46,36,9
volume of fuel in litres (y)10,011,212,213,013,014,215,615,8

The product moment correlation coefficient for these data is 0,988. What does this say about the relationship between fuel consumption and the mass of potatoes?

  1. AThere is almost no linear correlation, so the mass carried and the fuel consumed are unrelated quantities.
  2. BThere is only a moderate positive correlation, so mass explains about half of the change in fuel consumed.
  3. CThere is a very strong positive linear correlation, so the fuel consumed rises as the mass carried rises.
  4. DThere is a very strong negative linear correlation, so the fuel consumed falls as the mass carried rises.

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