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ZIMSEC A Level · 9164/4 · J2010

Statistics Paper 4 June 2010

Questions
41
Total marks
96
Syllabus code
9164/4

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Questions
41
Pass mark
25
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section a

Section a, Question 2

[2 marks]Poisson approximation to the binomial

In a particular survey involving 7076 households, 0.0248% were in favour of amending city council by-laws. The number in favour is to be modelled by a Poisson approximation to the binomial.

Find the mean of that Poisson distribution.

Answer this when you sit the paper.

[2 marks]Poisson approximation to the binomial
In a particular survey involving 7076 households, 0.0248% were in favour of amending city council by-laws. By using a suitable approximation, find the probability that at least 8 households favour the amendment.

Answer this when you sit the paper.

Section a, Question 3

[2 marks]Continuous random variables

X is a continuous random variable with probability density function f(x)f(x). The density is the curve y=x2y=x^{2} for 0≤x≤10\le x\le 1, followed by the straight line running from the point (1; 1)(1;\,1) down to the point (h; 0)(h;\,0) on the x-axis, and f(x)=0f(x)=0 elsewhere.

Find the value of h.

Answer this when you sit the paper.

[1 marks]Continuous random variables

X is a continuous random variable with probability density function f(x)f(x). The density is the curve y=x2y=x^{2} for 0≤x≤10\le x\le 1, followed by the straight line running from the point (1; 1)(1;\,1) down to the point (h; 0)(h;\,0) on the x-axis, and f(x)=0f(x)=0 elsewhere.

Write down the mode.

Answer this when you sit the paper.

[2 marks]Continuous random variables

X is a continuous random variable with probability density function f(x)f(x). The density is the curve y=x2y=x^{2} for 0≤x≤10\le x\le 1, followed by the straight line running from the point (1; 1)(1;\,1) down to the point (h; 0)(h;\,0) on the x-axis, and f(x)=0f(x)=0 elsewhere.

Find the lower quartile.

Answer this when you sit the paper.

[2 marks]Normal approximation to the binomial

A local bookshop reported that 11% of books sold in a year are romance novels. The bookshop sells 316 books on a given day, and the number of those that are romance novels is to be modelled by a normal approximation to the binomial.

Find the standard deviation of that normal distribution.

Answer this when you sit the paper.

[3 marks]Normal approximation to the binomial
A local bookshop reported that 11% of books sold in a year are romance novels. If the bookshop sells 316 books on a given day, find the probability that less than 40 are romance novels.

Answer this when you sit the paper.

[2 marks]Conditional probability

A car is never kept in a garage at night. The probability that a night is wet in summer is 0,80. On the morning following a wet night the probability that the car does not start is 0,25. On the morning following a dry night this probability is 0,04. The starter performance is independent of each morning.

Find the probability that the car does not start on a given morning in summer.

Answer this when you sit the paper.

[3 marks]Conditional probability

A car is never kept in a garage at night. The probability that a night is wet in summer is 0,80. On the morning following a wet night the probability that the car does not start is 0,25. On the morning following a dry night this probability is 0,04. The starter performance is independent of each morning.

Find the probability that the night was wet, given that the car did not start.

Answer this when you sit the paper.

[2 marks]Binomial distribution

A random variable X has a binomial distribution, X∼Bin(n, p)X\sim Bin(n,\,p), with E(X)=32E(X)=\frac{3}{2} and Var(X)=98Var(X)=\frac{9}{8}.

Find the value of p.

Answer this when you sit the paper.

[1 marks]Binomial distribution

A random variable X has a binomial distribution, X∼Bin(n, p)X\sim Bin(n,\,p), with E(X)=32E(X)=\frac{3}{2} and Var(X)=98Var(X)=\frac{9}{8}.

Find the value of n.

Answer this when you sit the paper.

[3 marks]Binomial distribution

A random variable X has a binomial distribution, X∼Bin(n, p)X\sim Bin(n,\,p), with E(X)=32E(X)=\frac{3}{2} and Var(X)=98Var(X)=\frac{9}{8}.

Find P(X≥3)P(X\ge 3).

Answer this when you sit the paper.

Section a, Question 4

[1 marks]Unbiased estimates and confidence intervals

The following table shows the observed frequency distribution of the number of matches per box in a random sample of 100 boxes.

Number of matches4546474849505152
Number of boxes541020252592

Calculate the unbiased estimate of the mean number of matches per box.

Answer this when you sit the paper.

[2 marks]Unbiased estimates and confidence intervals

The following table shows the observed frequency distribution of the number of matches per box in a random sample of 100 boxes.

Number of matches4546474849505152
Number of boxes541020252592

Calculate the unbiased estimate of the variance of the number of matches per box.

Answer this when you sit the paper.

[3 marks]Unbiased estimates and confidence intervals

The following table shows the observed frequency distribution of the number of matches per box in a random sample of 100 boxes.

Number of matches4546474849505152
Number of boxes541020252592

Determine a 95% confidence interval for the mean number of matches per box.

  1. A(45,66; 51,88)
  2. B(48,46; 49,08)
  3. C(48,51; 49,03)
  4. D(48,74; 48,80)
[2 marks]Frequency tables and stem and leaf plots

A Harare commuter records the duration of the delays of her commuter train, in minutes and seconds, on twenty mornings: 1:15, 12:17, 5:49, 2:09, 8:54, 6:22, 2:43, 2:39, 6:24, 4:21, 3:13, 0:28, 1:47, 10:37, 1:25, 3:10, 4:58, 3:16, 5:28, 1:32.

The delays are grouped into 2-minute intervals, each interval taking the delays from its lower end up to but not including its upper end. State the frequency of the interval from 2 to 4 minutes.

Answer this when you sit the paper.

[1 marks]Frequency tables and stem and leaf plots

A Harare commuter records the duration of the delays of her commuter train, in minutes and seconds, on twenty mornings: 1:15, 12:17, 5:49, 2:09, 8:54, 6:22, 2:43, 2:39, 6:24, 4:21, 3:13, 0:28, 1:47, 10:37, 1:25, 3:10, 4:58, 3:16, 5:28, 1:32.

The delays are grouped into 2-minute intervals, each interval taking the delays from its lower end up to but not including its upper end. State the interval with the highest frequency.

  1. A2 to 4 minutes
  2. B4 to 6 minutes
  3. C6 to 8 minutes
  4. D0 to 2 minutes
[2 marks]Frequency tables and stem and leaf plots

A Harare commuter records the duration of the delays of her commuter train, in minutes and seconds, on twenty mornings: 1:15, 12:17, 5:49, 2:09, 8:54, 6:22, 2:43, 2:39, 6:24, 4:21, 3:13, 0:28, 1:47, 10:37, 1:25, 3:10, 4:58, 3:16, 5:28, 1:32.

A stem and leaf plot is drawn using the number of minutes as the stem and the number of seconds as the leaf. State how many leaves appear on the stem 1.

Answer this when you sit the paper.

[3 marks]Frequency tables and stem and leaf plots

A Harare commuter records the duration of the delays of her commuter train, in minutes and seconds, on twenty mornings: 1:15, 12:17, 5:49, 2:09, 8:54, 6:22, 2:43, 2:39, 6:24, 4:21, 3:13, 0:28, 1:47, 10:37, 1:25, 3:10, 4:58, 3:16, 5:28, 1:32.

A railway spokesman claims that 80% of trains leave within 5 minutes of the scheduled time of departure. Using these twenty mornings, calculate the percentage of trains that left within 5 minutes.

Answer this when you sit the paper.

[2 marks]Binomial distribution and approximations

John bought a packet of 15 tomato seeds for his garden. The probability of any one seed not germinating is 0.01, independently of the others.

Find the probability that every one of the 15 seeds germinates.

Answer this when you sit the paper.

[2 marks]Binomial distribution and approximations

John bought a packet of 15 tomato seeds for his garden. The probability of any one seed not germinating is 0.01, independently of the others.

Find the probability that he gets at most 13 tomato plants from his seeds.

Answer this when you sit the paper.

[2 marks]Binomial distribution and approximations

In a competition, the title holder has a probability of 0.97 of hitting the target on each of 200 shots, independently. The number of shots he misses is to be modelled by a Poisson approximation to the binomial.

Find the mean of that Poisson distribution.

Answer this when you sit the paper.

[3 marks]Binomial distribution and approximations

In a competition, the title holder has a probability of 0.97 of hitting the target on each of 200 shots, independently. The number of shots he misses is to be modelled by a Poisson approximation to the binomial.

Use that Poisson approximation to find the probability that he hits the target at least 190 times in the 200 shots.

Answer this when you sit the paper.

[3 marks]Geometric distribution and linear transformations

During a practice session a gunman fires at a target from the same place until he succeeds. Independently for each attempt, the probability of hitting the target is 0,8. X is the number of attempts up to and including his first success.

Find the probability that he will need at least 3 attempts to his first success.

Answer this when you sit the paper.

[2 marks]Geometric distribution and linear transformations

During a practice session a gunman fires at a target from the same place until he succeeds. Independently for each attempt, the probability of hitting the target is 0,8. X is the number of attempts up to and including his first success.

Find the variance of X.

Answer this when you sit the paper.

[2 marks]Geometric distribution and linear transformations

During a practice session a gunman fires at a target from the same place until he succeeds. Independently for each attempt, the probability of hitting the target is 0,8. X is the number of attempts up to and including his first success.

Y is the time in minutes he will take over his practice session, where Y = 3X + 2. Find the mean of Y.

Answer this when you sit the paper.

[2 marks]Geometric distribution and linear transformations

During a practice session a gunman fires at a target from the same place until he succeeds. Independently for each attempt, the probability of hitting the target is 0,8. X is the number of attempts up to and including his first success.

Y is the time in minutes he will take over his practice session, where Y = 3X + 2. Find the variance of Y.

Answer this when you sit the paper.

Section a, Question 5

[3 marks]Binomial and Poisson distributions
In a certain country it is known that 34% of the adult population has some knowledge of a foreign language. If 6 adults from this country are chosen at random, find the probability that at least one of those chosen will have some knowledge of a foreign language.

Answer this when you sit the paper.

[3 marks]Binomial and Poisson distributions

A very small proportion of a country's adult population has some knowledge of a particular foreign language. A random sample of adults is taken, and the number in the sample with some knowledge of the language is modelled by a Poisson distribution with mean λ\lambda. The sample size is chosen so that the probability of obtaining at least one adult having some knowledge of the language is 0.98.

Find the value of λ\lambda.

Answer this when you sit the paper.

[2 marks]Binomial and Poisson distributions

For a particular foreign language, only a very small proportion r % of a country's adult population have some knowledge of it. Using a Poisson approximation, the number n of adults that must be selected at random so that the probability of obtaining at least one adult having some knowledge of the language is 0.98 is given by n=391.2rn=\dfrac{391.2}{r}.

Find n for the case where r = 1.2.

Answer this when you sit the paper.

[3 marks]Binomial and Poisson distributions

In a country, a proportion r=13r=\frac{1}{3} per cent of the adult population have some knowledge of a particular foreign language. A random sample of n=917n=917 adults is taken, and the number in the sample with some knowledge of the language is modelled by a Poisson distribution.

Find the probability that precisely 5 adults in the sample will have some knowledge of the language.

Answer this when you sit the paper.

[3 marks]Chi-squared test of independence

Two schools entered their pupils for the Mathematics Olympiad examination and the numbers of pupils falling within each grade are shown in the table below.

Grade AGrade BGrade C
School X231918
School Y151332

A chi-squared test is carried out at the 5% level of significance to determine whether the grades obtained are independent of the school entered.

Calculate the expected frequency of School X pupils obtaining Grade C.

Answer this when you sit the paper.

[1 marks]Chi-squared test of independence

Two schools entered their pupils for the Mathematics Olympiad examination and the numbers of pupils falling within each grade are shown in the table below.

Grade AGrade BGrade C
School X231918
School Y151332

A chi-squared test is carried out at the 5% level of significance to determine whether the grades obtained are independent of the school entered.

State the number of degrees of freedom for the test.

Answer this when you sit the paper.

[3 marks]Chi-squared test of independence

Two schools entered their pupils for the Mathematics Olympiad examination and the numbers of pupils falling within each grade are shown in the table below.

Grade AGrade BGrade C
School X231918
School Y151332

A chi-squared test is carried out at the 5% level of significance to determine whether the grades obtained are independent of the school entered.

Calculate the value of the chi-squared test statistic.

Answer this when you sit the paper.

[2 marks]Chi-squared test of independence

Two schools entered their pupils for the Mathematics Olympiad examination and the numbers of pupils falling within each grade are shown in the table below.

Grade AGrade BGrade C
School X231918
School Y151332

A chi-squared test is carried out at the 5% level of significance to determine whether the grades obtained are independent of the school entered.

State the critical value of the test statistic at the 5% level of significance.

Answer this when you sit the paper.

[3 marks]Chi-squared test of independence

Two schools entered their pupils for the Mathematics Olympiad examination and the numbers of pupils falling within each grade are shown in the table below.

Grade AGrade BGrade C
School X231918
School Y151332

A chi-squared test is carried out at the 5% level of significance to determine whether the grades obtained are independent of the school entered.

State the conclusion of the test.

  1. AAccept the null hypothesis, since 6,73 is greater than 5,991: grade is independent of the school.
  2. BReject the null hypothesis, since 6,73 is smaller than 9,488: grade depends on the school entered.
  3. CReject the null hypothesis, since 6,73 is greater than 5,991: grade depends on the school entered.
  4. DAccept the null hypothesis, since 6,73 is smaller than 9,488: grade is independent of the school.

Section a, Question 6

[3 marks]Regression and correlation

The following figures relate to the carriage of goods by road in Zimbabwe from 1988 to 1995.

YearGoods carried (Y) (million tonnes)Number of goods vehicles registered (X) (thousands)
1988851630
1989861632
1990881660
1991901736
1992901778
1993951791
1994961773
1995981712

The regression line of goods vehicles registered on goods carried is X=a+bYX=a+bY.

Find the value of b.

Answer this when you sit the paper.

[2 marks]Regression and correlation

The following figures relate to the carriage of goods by road in Zimbabwe from 1988 to 1995.

YearGoods carried (Y) (million tonnes)Number of goods vehicles registered (X) (thousands)
1988851630
1989861632
1990881660
1991901736
1992901778
1993951791
1994961773
1995981712

The regression line of goods vehicles registered on goods carried is X=a+bYX=a+bY.

Find the value of a.

Answer this when you sit the paper.

[2 marks]Regression and correlation

The following figures relate to the carriage of goods by road in Zimbabwe from 1988 to 1995.

YearGoods carried (Y) (million tonnes)Number of goods vehicles registered (X) (thousands)
1988851630
1989861632
1990881660
1991901736
1992901778
1993951791
1994961773
1995981712

The regression line of goods vehicles registered on goods carried is X=827+9,75YX=827+9,75Y. Use this equation to estimate the number of goods vehicles registered, in thousands, if the amount of goods carried is 120 million tonnes.

Answer this when you sit the paper.

[3 marks]Regression and correlation

The following figures relate to the carriage of goods by road in Zimbabwe from 1988 to 1995.

YearGoods carried (Y) (million tonnes)Number of goods vehicles registered (X) (thousands)
1988851630
1989861632
1990881660
1991901736
1992901778
1993951791
1994961773
1995981712

Calculate the product moment correlation coefficient between goods carried and the number of goods vehicles registered.

Answer this when you sit the paper.

[3 marks]Regression and correlation

The following figures relate to the carriage of goods by road in Zimbabwe from 1988 to 1995.

YearGoods carried (Y) (million tonnes)Number of goods vehicles registered (X) (thousands)
1988851630
1989861632
1990881660
1991901736
1992901778
1993951791
1994961773
1995981712

The product moment correlation coefficient between goods carried and the number of goods vehicles registered is 0,708. Comment on the relationship between the two quantities.

  1. AThere is a very strong linear correlation, so the points sit almost exactly along a straight line.
  2. BThere is a strong negative linear correlation, so the more tonnage carried, the fewer vehicles.
  3. CThere is almost no linear correlation, so the tonnage carried says nothing about the vehicles.
  4. DThere is a moderate positive linear correlation, so more tonnage tends to go with more vehicles.

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