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ZIMSEC A Level · N2019

Chemistry Paper 3 November 2019

Questions
96
Total marks
150

Sit this paper online

Questions
96
Pass mark
58
Sit this paper

Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]bonding / empirical formula / titration
The shape of the dichlorodifluoromethane molecule, CCl2F2CCl_2F_2, is
  1. Abent
  2. Btetrahedral
  3. Ctrigonal pyramidal
  4. Dsquare planar

Question 102

[1 marks]bonding / empirical formula / titration
0.120 g of an organic compound was completely oxidised to 0.176 g of CO2CO_2 and 0.072 g of H2OH_2O. Its relative molecular mass is 60. The molecular formula of the compound is
  1. AC2H6OC_2H_6O
  2. BC3H6O3C_3H_6O_3
  3. CCH2OCH_2O
  4. DC2H4O2C_2H_4O_2

Question 103

[1 marks]bonding / empirical formula / titration
An indigestion tablet of mass 0.50 g whose active ingredient is Mg(OH)2Mg(OH)_2 required 28.30 cm³ of 0.15 moldm⁻³ hydrochloric acid for complete neutralisation. The percentage by mass of Mg(OH)2Mg(OH)_2 in the tablet is [MrM_r Mg(OH)2Mg(OH)_2 = 58]
  1. A10.2 %
  2. B12.3 %
  3. C24.6 %
  4. D49.2 %

Question 104

[3 marks]bonding / empirical formula / titration
An organic compound of mass 0.120 g was completely oxidised to give 0.176 g of carbon dioxide and 0.072 g of water. Determine the empirical formula of the compound.

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Question 105

[3 marks]bonding / empirical formula / titration
0.148 g of the compound was vaporised at 60 degrees C to occupy 67.700 cm3 at a pressure of 101 kPa. Use PV = nRT to calculate the relative molecular mass, Mr, of the compound.

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Question 106

[2 marks]bonding / empirical formula / titration
In the titration of the indigestion tablet, 28.30 cm3 of 0.15 mol dm-3 hydrochloric acid was needed for complete neutralisation. Calculate the number of moles of HCl used.

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Question 107

[2 marks]bonding / empirical formula / titration
The equation for the neutralisation of magnesium hydroxide by hydrochloric acid is
  1. AMgOH + HCl -> MgCl + H2O
  2. BMg(OH)2 + HCl -> MgCl2 + H2O
  3. CMg(OH)2 + 4HCl -> MgCl4 + 2H2O
  4. DMg(OH)2 + 2HCl -> MgCl2 + 2H2O

Question 108

[1 marks]bonding / empirical formula / titration
State, in one word, the role of the active ingredient (magnesium hydroxide) in an indigestion tablet.

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Question 109

[1 marks]bonding / empirical formula / titration
State the bond angle, in degrees, around the central carbon atom in the CCl2F2 molecule.

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Question 201

[1 marks]buffers / equilibria
Blood contains a mixture of H2CO3H_2CO_3 and HCO3−HCO_3^-. Which equation shows the buffering action of this mixture when acid enters the blood?
  1. AH2CO3+OH−→HCO3−+H2OH_2CO_3 + OH^- \rightarrow HCO_3^- + H_2O
  2. BHCO3−+H+→H2CO3HCO_3^- + H^+ \rightarrow H_2CO_3
  3. CH2CO3→CO2+H2OH_2CO_3 \rightarrow CO_2 + H_2O
  4. DHCO3−+OH−→CO32−+H2OHCO_3^- + OH^- \rightarrow CO_3^{2-} + H_2O

Question 202

[1 marks]buffers / equilibria
A 250 cm³ buffer of H2CO3H_2CO_3 and NaHCO3NaHCO_3 has pH 5.94 and [H2CO3][H_2CO_3] = 0.5 moldm⁻³. The mass of NaHCO3NaHCO_3 present is [Ka(H2CO3)K_a(H_2CO_3) = 4.6×10−74.6 \times 10^{-7} moldm⁻³, MrM_r NaHCO3NaHCO_3 = 84]
  1. A1.05 g
  2. B2.10 g
  3. C4.21 g
  4. D16.84 g

Question 203

[1 marks]buffers / equilibria
For the equilibrium CH3CHO+2CH3OH⇌CH3CH(OCH3)2+H2OCH_3CHO + 2CH_3OH \rightleftharpoons CH_3CH(OCH_3)_2 + H_2O, the yield of CH3CH(OCH3)2CH_3CH(OCH_3)_2 is increased by
  1. Aadding a catalyst
  2. Badding water to the mixture
  3. Cincreasing the total pressure
  4. Dremoving water with a drying agent

Question 204

[1 marks]buffers / equilibria
The H2CO3/HCO3- buffer mixture is important in blood because it
  1. Araises the blood pH well above neutral, which would kill many blood-borne bacteria
  2. Bincreases the oxygen-carrying capacity of red blood cells during heavy exercise
  3. Ckeeps blood pH almost constant, preventing enzyme denaturation
  4. Dprevents blood from clotting inside blood vessels during circulation

Question 205

[2 marks]buffers / equilibria
The H2CO3/HCO3- buffer in blood resists a small rise in pH (addition of OH-) according to the equation
  1. AHCO3- + OH- -> CO3^2- + H2O
  2. BHCO3- + H+ -> H2CO3
  3. CH2CO3 + OH- -> HCO3- + H2O
  4. DH2CO3 -> CO2 + H2O

Question 206

[2 marks]buffers / equilibria
The pH of the H2CO3/NaHCO3 buffer described in Q2(a)(iii) is 5.94. Calculate the hydrogen ion concentration, [H+], of the buffer, in mol dm-3.

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Question 207

[2 marks]buffers / equilibria
Using Ka(H2CO3) = 4.6 x 10^-7 mol dm-3, [H2CO3] = 0.5 mol dm-3 and [H+] = 1.15 x 10^-6 mol dm-3, calculate [HCO3-] in the buffer, in mol dm-3.

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Question 208

[2 marks]buffers / equilibria
In the acetal equilibrium, the initial amount of CH3OH was 0.129 mol and the equilibrium amount was 0.0638 mol. Calculate the amount, in mol, of CH3OH that had reacted.

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Question 209

[3 marks]buffers / equilibria
Using the equilibrium amounts in the 25.00 cm3 mixture (CH3CHO = 0.0984 mol, CH3OH = 0.0638 mol, CH3CH(OCH3)2 = 0.0785 mol, H2O = 0.0418 mol), calculate the Kc for CH3CHO + 2CH3OH <=> CH3CH(OCH3)2 + H2O.

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Question 301

[1 marks]ionisation energy / mass spectrometry
Which equation represents the second ionisation energy of magnesium?
  1. AMg(g)→Mg2+(g)+2e−Mg(g) \rightarrow Mg^{2+}(g) + 2e^-
  2. BMg+(g)→Mg2+(g)+e−Mg^+(g) \rightarrow Mg^{2+}(g) + e^-
  3. CMg2+(g)→Mg3+(g)+e−Mg^{2+}(g) \rightarrow Mg^{3+}(g) + e^-
  4. DMg(g)→Mg+(g)+e−Mg(g) \rightarrow Mg^+(g) + e^-

Question 302

[1 marks]ionisation energy / mass spectrometry
Aluminium exists as three isotopes. Two of them have relative isotopic masses 27.40 (abundance 70.0 %) and 28.00 (abundance 20.2 %). If ArA_r(Al) = 27.0, the relative isotopic mass of the third isotope is
  1. A22.1
  2. B24.3
  3. C26.0
  4. D27.6

Question 303

[1 marks]ionisation energy / mass spectrometry
The first ionisation energy of potassium is lower than that of argon because the outer electron of potassium is
  1. Ain a further shell and is more shielded
  2. Bpaired in the same orbital
  3. Cin a d orbital of lower energy
  4. Dheld by a greater nuclear charge

Question 304

[1 marks]ionisation energy / mass spectrometry
First ionisation energy is defined as
  1. Athe energy released when one mole of gaseous atoms gains one mole of electrons
  2. Bthe energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions
  3. Cthe energy required to remove one mole of electrons from one mole of gaseous 1+ ions to form one mole of gaseous 2+ ions
  4. Dthe energy required to remove one electron from a single gaseous atom

Question 305

[2 marks]ionisation energy / mass spectrometry
Fig. 3.1 shows the successive ionisation energies of magnesium, with large jumps after removing the 2nd electron and after the 10th electron. This pattern shows that magnesium's electrons are arranged in shells of
  1. A2, 8, 8 electrons
  2. B2, 8, 2 electrons
  3. C8, 2, 2 electrons
  4. D2, 10 electrons

Question 306

[2 marks]ionisation energy / mass spectrometry
Aluminium oxide is used as an insulator in spark plugs because it
  1. Ais a simple covalent molecule with a low melting point that vaporises easily under engine heat
  2. Bdissolves readily in the fuel-air mixture, preventing any conduction pathway from ever forming
  3. Cis a giant ionic lattice with no mobile ions or electrons to carry charge, and has a very high melting point
  4. Dcontains free-moving delocalised electrons throughout its structure that would readily conduct heat and electric current

Question 307

[3 marks]ionisation energy / mass spectrometry
SiCl4 is a liquid at room temperature whereas PCl5 is a solid because
  1. ASiCl4 is simple covalent with weak van der Waals forces, while solid PCl5 exists as ionic [PCl4]+[PCl6]-
  2. BSiCl4 forms extensive hydrogen bonds between its molecules but PCl5 is completely unable to do so
  3. CPCl5 is simple covalent while SiCl4 is instead a giant ionic lattice held by strong electrostatic forces
  4. DPCl5 has a considerably higher relative molecular mass than SiCl4, giving it far stronger intermolecular forces

Question 308

[2 marks]ionisation energy / mass spectrometry
Aluminium's mass spectrum shows peaks at m/e 27.40 (abundance 70.0%) and m/e 28.00 (abundance 20.2%). Calculate the percentage abundance of the third isotope.

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Question 309

[2 marks]ionisation energy / mass spectrometry
The equation for the first ionisation energy of magnesium is
  1. AMg(g) -> Mg^+(g) + e-
  2. BMg^2+(g) + e- -> Mg^+(g)
  3. CMg^+(g) -> Mg^2+(g) + e-
  4. DMg(g) -> Mg^2+(g) + 2e-

Question 401

[1 marks]halogens / disproportionation / stoichiometry
The oxidation numbers of chlorine in ClO3−ClO_3^- and ClO−ClO^- respectively are
  1. A+3 and +1
  2. B+5 and +1
  3. C+5 and +3
  4. D+1 and +5

Question 402

[1 marks]halogens / disproportionation / stoichiometry
When potassium chlorate(V) is heated just above its melting point it disproportionates. The equation for the reaction is
  1. A2KClO3→KClO4+KCl+O22KClO_3 \rightarrow KClO_4 + KCl + O_2
  2. B4KClO3→3KClO4+KCl4KClO_3 \rightarrow 3KClO_4 + KCl
  3. C2KClO3→2KCl+3O22KClO_3 \rightarrow 2KCl + 3O_2
  4. D2KClO3→KClO4+KClO22KClO_3 \rightarrow KClO_4 + KClO_2

Question 403

[1 marks]halogens / disproportionation / stoichiometry
0.598 g of a metal carbonate, MCO3MCO_3, decomposed on heating to give the metal oxide and 0.222 g of carbon dioxide. The relative formula mass of MCO3MCO_3 is
  1. A58.5
  2. B118.5
  3. C133.0
  4. D237.0

Question 404

[1 marks]halogens / disproportionation / stoichiometry
When chlorine gas is bubbled into hot concentrated sodium hydroxide solution, the observation is that the mixture
  1. Aforms a blue precipitate
  2. Bforms a white precipitate
  3. Cstays colourless, with no precipitate forming
  4. Dproduces a yellow-green gas above the solution

Question 405

[3 marks]halogens / disproportionation / stoichiometry
The ionic equation for the reaction of chlorine with hot concentrated sodium hydroxide is
  1. A3Cl2 + 6OH- -> 5Cl- + ClO3- + 3H2O
  2. B3Cl2 + 6OH- -> 6Cl- + ClO3- + 3H2O
  3. CCl2 + 6OH- -> 5Cl- + ClO3- + 3H2O
  4. DCl2 + 2OH- -> Cl- + OCl- + H2O

Question 406

[1 marks]halogens / disproportionation / stoichiometry
Disproportionation is a reaction in which
  1. Aa single compound decomposes into exactly two different elements
  2. Bthe same species is simultaneously oxidised and reduced
  3. Ca species transfers one electron to a completely different element
  4. Dtwo different elements are both oxidised at the same time

Question 407

[3 marks]halogens / disproportionation / stoichiometry
0.598 g of a metal carbonate, MCO3, decomposed on heating to give the metal oxide and 0.222 g of carbon dioxide. Given that Mr(CO3^2-) = 60, the carbonate is most likely
  1. Anickel(II) carbonate, NiCO3
  2. Bmagnesium carbonate, MgCO3
  3. Ccalcium carbonate, CaCO3
  4. Dcopper(II) carbonate, CuCO3

Question 408

[2 marks]halogens / disproportionation / stoichiometry
0.598 g of a metal carbonate decomposed on heating to give 0.222 g of carbon dioxide. Calculate the number of moles of CO2 produced.

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Question 409

[1 marks]halogens / disproportionation / stoichiometry
In the disproportionation 4KClO3 -> 3KClO4 + KCl, state the oxidation number change of the chlorine atoms that are reduced.

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Question 410

[1 marks]halogens / disproportionation / stoichiometry
State the oxidation number of chlorine in the ClO4- ion.

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Question 501

[1 marks]group IV / nitrogen / halogens
A simple molecular group (IV) tetrachloride, XCl4XCl_4, is hydrolysed by water to give XO2XO_2. The equation for the hydrolysis is
  1. AXCl4+4H2O→X(OH)4+4HClXCl_4 + 4H_2O \rightarrow X(OH)_4 + 4HCl
  2. BXCl4+H2O→XO2+2HCl+Cl2XCl_4 + H_2O \rightarrow XO_2 + 2HCl + Cl_2
  3. CXCl4+2H2O→XO2+2HCl+Cl2XCl_4 + 2H_2O \rightarrow XO_2 + 2HCl + Cl_2
  4. DXCl4+2H2O→XO2+4HClXCl_4 + 2H_2O \rightarrow XO_2 + 4HCl

Question 502

[1 marks]group IV / nitrogen / halogens
CCl4CCl_4 is not hydrolysed by water because carbon
  1. Ahas a complete outer shell of eight electrons in CCl4CCl_4
  2. Bforms ionic bonds with chlorine
  3. Chas no accessible d orbitals for water to bond to
  4. Dis less electronegative than chlorine

Question 503

[1 marks]group IV / nitrogen / halogens
A brown solution is formed when chlorine is added to aqueous potassium iodide because
  1. Aiodide ions are oxidised to iodate(V) ions
  2. Bpotassium chloride is brown in solution
  3. Ciodine is displaced from the iodide
  4. Dchlorine forms a brown solution in water

Question 504

[2 marks]group IV / nitrogen / halogens
The shape and bond angle of a simple molecular group (IV) tetrachloride, XCl4, is
  1. Atrigonal pyramidal, 107°
  2. Btetrahedral, 109.5°
  3. Coctahedral, 90°
  4. Dsquare planar, 90°

Question 505

[2 marks]group IV / nitrogen / halogens
PbCl4 decomposes readily on heating but CCl4 does not, because
  1. Athe +4 oxidation state of Pb is destabilised by the inert pair effect, while the C-Cl bonds in CCl4 are strong and carbon's +4 state is stable
  2. BPbCl4 exists only as a simple covalent liquid at room temperature, while CCl4 behaves instead as a typical ionic solid
  3. CCCl4 has a much higher relative molecular mass than PbCl4, giving it far stronger van der Waals forces overall
  4. Dcarbon consistently forms much weaker covalent C-Cl bonds than lead forms in its Pb-Cl bonds

Question 506

[2 marks]group IV / nitrogen / halogens
Phosphorus burns at mild temperatures but nitrogen does not, because
  1. Anitrogen reacts only with reactive metals and never combines directly with oxygen gas at all
  2. Bthe N triple bond is very strong, needing a high activation energy, unlike the weaker P-P single bonds in phosphorus
  3. Cnitrogen gas molecules are far denser than phosphorus vapour molecules under identical laboratory conditions
  4. Dphosphorus has a much lower melting and boiling point than elemental nitrogen gas at standard pressure

Question 507

[2 marks]group IV / nitrogen / halogens
Nitrogen forms NO2 as its stable oxide but phosphorus forms P4O10, because
  1. Aphosphorus is fundamentally unable to form multiple covalent bonds with any oxygen atoms whatsoever
  2. Bnitrogen only reacts with atmospheric oxygen when the surrounding pressure is unusually high
  3. Cnitrogen (period 2) has no accessible d orbitals to expand its octet, but phosphorus (period 3) can use d orbitals to form five bonds
  4. Dnitrogen is considerably more electronegative than phosphorus, so it is only able to form a smaller number of bonds

Question 508

[2 marks]group IV / nitrogen / halogens
Halogens are not very soluble in water but are more soluble in hexane, because
  1. Ahexane molecules are considerably more polar than water molecules under normal laboratory conditions
  2. Bhalogens are much denser than both water and hexane, so they always sink below either solvent
  3. Chalogen molecules are non-polar, so they dissolve poorly in polar water but readily in non-polar hexane
  4. Dhalogens actually react chemically with water molecules but do not react at all with non-polar hexane

Question 509

[2 marks]group IV / nitrogen / halogens
Name one group (IV) tetrachloride, other than CCl4, that hydrolyses readily in water.

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Question 601

[1 marks]alcohols / triiodomethane test
Propan-1-ol boils at 98 °C while pentan-3-ol boils at 124 °C. Pentan-3-ol has the higher boiling point because it has
  1. Aa larger electron cloud and so stronger van der Waals forces
  2. Bmore hydrogen bonds per molecule
  3. Ca stronger O–H bond
  4. Da branched chain which packs more closely

Question 602

[1 marks]alcohols / triiodomethane test
Pentan-3-ol is oxidised to pentan-3-one by acidified potassium dichromate(VI). In the overall balanced equation for this oxidation, the number of moles of H+H^+ reacting with one mole of Cr2O72−Cr_2O_7^{2-} is
  1. A2
  2. B6
  3. C8
  4. D14

Question 603

[1 marks]alcohols / triiodomethane test
An alcohol gives a pale yellow precipitate when warmed with iodine and aqueous sodium hydroxide. The alcohol must contain
  1. Aa primary −CH2OH-CH_2OH group
  2. Bthe CH3CH(OH)−CH_3CH(OH)- group
  3. Ca carboxylic acid group
  4. Da carbon to carbon double bond

Question 604

[2 marks]alcohols / triiodomethane test
Propan-1-ol is more acidic than pentan-3-ol because
  1. Athe alkyl groups in pentan-3-ol are more electron-donating, destabilising its conjugate base (alkoxide ion)
  2. Bpropan-1-ol simply has a lower boiling point than pentan-3-ol under the same conditions
  3. Cpentan-3-ol has a larger molecule with more inductive electron donation towards water
  4. Dpropan-1-ol forms noticeably stronger hydrogen bonds to surrounding water molecules than pentan-3-ol

Question 605

[2 marks]alcohols / triiodomethane test
State the reagent used in the first step of a two-step test to distinguish propan-1-ol from pentan-3-ol by oxidation.

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Question 606

[3 marks]alcohols / triiodomethane test
The balanced equation for the oxidation of pentan-3-ol to pentan-3-one by acidified potassium dichromate(VI) is
  1. A3CH3CH2CH(OH)CH2CH3 + 2Cr2O7^2- + 8H+ -> 3CH3CH2COCH2CH3 + 4Cr3+ + 7H2O
  2. B3CH3CH2CH(OH)CH2CH3 + Cr2O7^2- + 14H+ -> 3CH3CH2COCH2CH3 + 2Cr3+ + 7H2O
  3. CCH3CH2CH(OH)CH2CH3 + Cr2O7^2- + 8H+ -> CH3CH2COCH2CH3 + 2Cr3+ + 7H2O
  4. D3CH3CH2CH(OH)CH2CH3 + Cr2O7^2- + 8H+ -> 3CH3CH2COCH2CH3 + 2Cr3+ + 7H2O

Question 607

[1 marks]alcohols / triiodomethane test
State the observation made in a positive triiodomethane (iodoform) test.

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Question 608

[1 marks]alcohols / triiodomethane test
In the triiodomethane reaction sequence, step II converts the alcohol into a carbonyl compound. Name this type of reaction.

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Question 609

[2 marks]alcohols / triiodomethane test
State the reagent and conditions needed to convert propan-2-ol into 2-bromopropane, the first step before forming the nitrile CH3CH(CN)CH3.

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Question 610

[1 marks]alcohols / triiodomethane test
Name the type of reaction when 2-bromopropane reacts with KCN in ethanol (reflux) to form CH3CH(CN)CH3.

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Question 701

[1 marks]alkenes / halogenoalkanes / mechanisms
An alkene of molecular formula C6H12C_6H_{12} was found to be chiral. The alkene is
  1. A2,3-dimethylbut-2-ene
  2. B3-methylpent-1-ene
  3. Chex-1-ene
  4. D2-methylpent-2-ene

Question 702

[1 marks]alkenes / halogenoalkanes / mechanisms
2-bromo-2-methylpropane reacts with warm aqueous sodium hydroxide to form 2-methylpropan-2-ol. The mechanism of this reaction is
  1. ASN1S_N1 nucleophilic substitution
  2. BSN2S_N2 nucleophilic substitution
  3. Celectrophilic addition
  4. Dfree radical substitution

Question 703

[1 marks]alkenes / halogenoalkanes / mechanisms
When 2-bromo-2-methylpropane is heated with hot ethanolic sodium hydroxide, 2-methylpropene is formed. In this reaction the sodium hydroxide acts as
  1. Aa base
  2. Ba nucleophile
  3. Can oxidising agent
  4. Da catalyst

Question 704

[2 marks]alkenes / halogenoalkanes / mechanisms
State the name and conditions for the reaction of 2-bromo-2-methylpropane with aqueous sodium hydroxide to form 2-methylpropan-2-ol.

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Question 705

[2 marks]alkenes / halogenoalkanes / mechanisms
State the name and conditions for the reaction of 2-bromo-2-methylpropane with sodium hydroxide to form 2-methylpropene.

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Question 706

[1 marks]alkenes / halogenoalkanes / mechanisms
Name the type of reaction when 2-methylpropene reacts with hot concentrated sulfuric acid, followed by water, to form G.

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Question 707

[2 marks]alkenes / halogenoalkanes / mechanisms
Name the organic product G formed when 2-methylpropene reacts with hot concentrated sulfuric acid followed by water.

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Question 708

[1 marks]alkenes / halogenoalkanes / mechanisms
State the other product formed (and regenerated) in the reaction of 2-methylpropene with hot concentrated sulfuric acid followed by water.

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Question 709

[2 marks]alkenes / halogenoalkanes / mechanisms
Name compound D, (CH3)3CBr.

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Question 710

[2 marks]alkenes / halogenoalkanes / mechanisms
Explain what makes the carbon bearing the vinyl, methyl, ethyl and hydrogen groups in the C6H12 alkene a chiral centre.

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Question 801

[1 marks]benzene / acidity / hydrolysis
The reagents and conditions for the conversion of benzene into nitrobenzene are
  1. Aconcentrated HNO3HNO_3 alone at 100 °C
  2. Bdilute HNO3HNO_3 and AlCl3AlCl_3 at room temperature
  3. CNaNO2NaNO_2 and dilute HCl below 10 °C
  4. Dconcentrated HNO3HNO_3 and concentrated H2SO4H_2SO_4 at 55 °C

Question 802

[1 marks]benzene / acidity / hydrolysis
The KaK_a values of CH3CO2HCH_3CO_2H, CH2ClCO2HCH_2ClCO_2H and CHCl2CO2HCHCl_2CO_2H are 1.6×10−51.6 \times 10^{-5}, 1.3×10−31.3 \times 10^{-3} and 5.0×10−25.0 \times 10^{-2} moldm⁻³ respectively. The acid strength increases along the series because the chlorine atoms
  1. Adonate electron density to the carboxylate ion
  2. Bincrease the relative molecular mass
  3. Cform hydrogen bonds with water
  4. Dwithdraw electron density and stabilise the carboxylate ion

Question 803

[1 marks]benzene / acidity / hydrolysis
X is 4-chlorotoluene, Y is benzoyl chloride and Z is (chloromethyl)benzene. The order of decreasing ease of hydrolysis of the three compounds is
  1. AY > Z > X
  2. BZ > Y > X
  3. CX > Y > Z
  4. DX > Z > Y

Question 804

[1 marks]benzene / acidity / hydrolysis
State the type of reaction that converts nitrobenzene into phenylamine.

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Question 805

[3 marks]benzene / acidity / hydrolysis
Benzene, nitrobenzene and phenylamine are each reacted with bromine water. The order of decreasing reactivity towards Br2(aq) is
  1. Aphenylamine > nitrobenzene > benzene
  2. Bphenylamine > benzene > nitrobenzene
  3. Cnitrobenzene > benzene > phenylamine
  4. Dbenzene > phenylamine > nitrobenzene

Question 806

[2 marks]benzene / acidity / hydrolysis
Ethylbenzene reacts with bromine to give 4-bromoethylbenzene, with bromine substituting onto the ring. Name this type of reaction and state the catalyst needed.

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Question 807

[1 marks]benzene / acidity / hydrolysis
State the condition needed for ethylbenzene to react with bromine on its side chain to give (2-bromoethyl)benzene.

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Question 808

[1 marks]benzene / acidity / hydrolysis
Name compound Y, benzoyl chloride, one of the three benzene derivatives compared for ease of hydrolysis in Q8(d).

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Question 809

[3 marks]benzene / acidity / hydrolysis
Benzoyl chloride (Y) hydrolyses much more readily than 4-chlorotoluene (X) because
  1. AX and Y actually hydrolyse at essentially the same rate, since both are simple aryl chloride compounds
  2. BX's carbon attached to chlorine is unusually strongly electrophilic in this case, making it hydrolyse the very fastest
  3. CY has a distinctly weaker C-Cl bond than X does, purely because of steric hindrance introduced by the ring
  4. DY's carbonyl carbon is strongly electrophilic, while in X delocalisation of the chlorine lone pair into the ring strengthens the C-Cl bond

Question 810

[1 marks]benzene / acidity / hydrolysis
Name compound Z, (chloromethyl)benzene, one of the three benzene derivatives compared for ease of hydrolysis in Q8(d).

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Question 901

[1 marks]transition metals / partition
Mn2+Mn^{2+} is more stable than Fe2+Fe^{2+} because Mn2+Mn^{2+} has
  1. Aa larger ionic radius
  2. Ba higher nuclear charge
  3. Ca completely filled 3d subshell
  4. Da half filled 3d subshell

Question 902

[1 marks]transition metals / partition
The partition coefficient of iodine between ether and water is 4. The mass of iodine extracted when 100 cm³ of ether is shaken with 100 cm³ of an aqueous solution containing 8.0 g of iodine is
  1. A1.6 g
  2. B4.0 g
  3. C6.4 g
  4. D7.1 g

Question 903

[1 marks]transition metals / partition
The partition coefficient of iodine between ether and water is 4. The total mass of iodine extracted from 100 cm³ of an aqueous solution containing 8.0 g of iodine using two successive 50 cm³ portions of ether is
  1. A8.00 g
  2. B5.33 g
  3. C6.40 g
  4. D7.11 g

Question 904

[2 marks]transition metals / partition
Iron(III) chloride forms an acidic solution when dissolved in water because
  1. AFe3+ reacts directly with water molecules to form HCl gas
  2. Biron(III) chloride is itself a strong Bronsted base
  3. Cchloride ions hydrolyse in water to form hypochlorous acid
  4. Dthe small, highly charged Fe3+ ion polarises coordinated water molecules, releasing H+ ions

Question 905

[2 marks]transition metals / partition
Neither [Mn(H2O)6]7+ nor [Cr(H2O)6]6+ exists in aqueous solution because
  1. Amanganese and chromium ions in these states are always far too large to fit six water molecules
  2. Bthese particular transition metal ions are fundamentally unable to form any octahedral complexes at all
  3. Cwater cannot act as a ligand for manganese or chromium in any oxidation state whatsoever
  4. Dsuch high ionic charges would completely polarise and decompose the coordinated water ligands

Question 906

[1 marks]transition metals / partition
Partition coefficient is defined as
  1. Athe ratio of the concentrations of a solute in two immiscible solvents at equilibrium, at constant temperature
  2. Bthe number of times an extraction must be repeated to remove all the solute
  3. Cthe ratio of the volumes of the two immiscible solvents used in an extraction
  4. Dthe amount of solute, in grams, that will dissolve in exactly 100 g of a chosen solvent at one fixed temperature

Question 907

[1 marks]transition metals / partition
State one condition that affects the magnitude of a partition coefficient.

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Question 908

[2 marks]transition metals / partition
Compared with a single extraction using the same total volume of solvent, using several smaller successive extractions
  1. Aremoves exactly the same amount of solute
  2. Bremoves less solute overall
  3. Chas no effect on the amount of solute removed
  4. Dremoves more solute overall

Question 909

[2 marks]transition metals / partition
Fe2+ readily loses an electron to form Fe3+ because
  1. AFe2+ has a completely filled 3d subshell that repels its outer electron
  2. Blosing an electron gives Fe3+ the extra stability of a half-filled 3d5 subshell
  3. CFe2+ is generally regarded as a considerably stronger reducing agent than Mn2+ in solution
  4. DFe3+ consistently has a noticeably larger ionic radius than Fe2+ in aqueous solution

Question 910

[2 marks]transition metals / partition
In the first of the two successive 50 cm3 ether extractions of iodine (partition coefficient 4) from 8.0 g of iodine in 100 cm3 of water, calculate the mass of iodine, in g, remaining in the aqueous layer after the first extraction.

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Question 1001

[1 marks]environmental chemistry / nanochemistry
In flue gas desulphurisation, sulphur dioxide is removed from industrial waste gases by passing them through
  1. Aheated activated charcoal
  2. Bwater under high pressure
  3. Ca slurry of calcium carbonate
  4. Dconcentrated sulphuric acid

Question 1002

[1 marks]environmental chemistry / nanochemistry
A nanostructure is a structure having at least one dimension in the range
  1. A1 to 100 nm
  2. B100 to 1 000 nm
  3. C1 000 to 10 000 nm
  4. D0.1 to 1 nm

Question 1003

[1 marks]environmental chemistry / nanochemistry
Catalysts based on nanostructures are more efficient than those based on bulk material because nanostructures have
  1. Astronger metallic bonding
  2. Ba greater surface area to volume ratio
  3. Ca higher melting point
  4. Da lower density

Question 1004

[2 marks]environmental chemistry / nanochemistry
One environmental effect of sulphur dioxide emissions is that it
  1. Areduces the overall greenhouse effect by reflecting incoming sunlight back to space
  2. Braises the pH of rainwater over time, making it noticeably more alkaline than normal rain
  3. Cdissolves in atmospheric water to form acid rain, lowering the pH of soil and water
  4. Dincreases the overall thickness of the stratospheric ozone layer significantly

Question 1005

[2 marks]environmental chemistry / nanochemistry
In flue gas desulphurisation, sulphur dioxide is removed from waste gas by an alkaline calcium carbonate slurry according to the equation
  1. ACa(OH)2 + SO2 -> CaSO4 + H2
  2. BCaCO3 + 2SO2 -> Ca(SO3)2 + CO2
  3. CCaO + SO2 -> CaSO3
  4. DCaCO3 + SO2 -> CaSO3 + CO2

Question 1006

[1 marks]environmental chemistry / nanochemistry
A disadvantage of landfill as a waste disposal method is that it
  1. Adestroys all disease-causing pathogens present within the buried waste completely
  2. Brequires no future management or monitoring of the land used at all
  3. Cproduces methane, a flammable greenhouse gas, as waste decomposes
  4. Dautomatically recovers all valuable materials from the waste stream for recycling

Question 1007

[2 marks]environmental chemistry / nanochemistry
A further disadvantage of landfill as a waste disposal method is that
  1. Ait produces no unpleasant odours or pests
  2. Bit converts all buried waste into reusable compost
  3. Cleachate produced can contaminate groundwater
  4. Dit eliminates the need for any future waste collection

Question 1008

[1 marks]environmental chemistry / nanochemistry
Waste sorting is recommended before disposal because it
  1. Aseparates recyclable, biodegradable and hazardous waste for appropriate treatment
  2. Bactively prevents any of the collected waste from ever being recycled at all
  3. Cis only ever legally required for genuinely hazardous waste streams specifically
  4. Dsignificantly increases the total volume of waste that ultimately needs final disposal

Question 1009

[2 marks]environmental chemistry / nanochemistry
Soil near a highway typically has higher lead levels than soil in other areas because
  1. Avehicles historically burned leaded petrol, depositing lead compounds from exhaust near roads
  2. Blead compounds are deliberately added to vehicle tyres to improve their road grip
  3. Clarge deposits of lead-rich ore are commonly found naturally beneath most road surfaces
  4. Droad surface paint historically contained unusually high concentrations of lead compounds

Question 1010

[2 marks]environmental chemistry / nanochemistry
In flue gas desulphurisation, the calcium sulphite formed is further oxidised in air. Name the useful solid product formed.

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