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Paper 1 · confidence intervals / Central Limit Theorem

120 bags of mealie-meal have mean mass 750g and standard deviation 3.9g. Using a 95% confidence interval with z=1.96z = 1.96, what is the upper bound of the confidence interval for the mean mass, in grams, correct to 2 decimal places?

A749.30 g
B750.70 g
C750.35 g
D751.40 g
Explanation: The margin of error is 1.96×3.9/120=1.96×0.356=0.6981.96 \times 3.9/\sqrt{120} = 1.96 \times 0.356 = 0.698 g, so the upper bound is 750+0.698=750.70750 + 0.698 = 750.70 g.

Derived from ZIMSEC Statistics Paper 1, November 2021, Q1

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