Danho

Paper 2 · November 2023 · Logarithms and Exponentials

Simplify 32x−3⋅81x+1227x\dfrac{3^{2x-3}\cdot81^{x+\frac12}}{27^x}, giving the answer as a single power of 3.

Model answer

3^(3x-1)

Also accepted: 3^{3x-1}, 3^(3x - 1)

Explanation

Write every base as a power of 3: 81x+12=34x+281^{x+\frac12}=3^{4x+2} and 27x=33x27^x=3^{3x}. The numerator is 32x−3⋅34x+2=36x−13^{2x-3}\cdot3^{4x+2}=3^{6x-1}, so the quotient is 36x−1−3x=33x−13^{6x-1-3x}=3^{3x-1}.

Derived from ZIMSEC Pure Mathematics Paper 2, November 2023, Q1

View this paper's sittings and topics→

More questions from this paper

Get the full paper, not just one question

Danho has every sitting for this paper, with your progress tracked question by question, offline.