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Paper 2 · June 2015 · Differentiation

Given that y=exsin⁡xy=e^{x}\sin x, find d2ydx2\dfrac{d^{2}y}{dx^{2}}, giving your answer in its simplest form.

Model answer

2excos⁡x2e^{x}\cos x

Also accepted: 2e^x cos x, 2e^{x}\cos x, 2e^xcosx

Explanation

By the product rule dydx=exsin⁡x+excos⁡x\dfrac{dy}{dx}=e^{x}\sin x+e^{x}\cos x. Differentiating again, d2ydx2=exsin⁡x+excos⁡x+excos⁡x−exsin⁡x=2excos⁡x\dfrac{d^{2}y}{dx^{2}}=e^{x}\sin x+e^{x}\cos x+e^{x}\cos x-e^{x}\sin x=2e^{x}\cos x.

Derived from ZIMSEC Mathematics Paper 2, June 2015, Q1

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