The diagram shows the graph of $y = f(x)$ , passing through $A(-1, 0)$ , $B(0, 1)$ and $C(1, 0)$ . On the graph of $y = 2f(x + 1)$ , the image of $C$ is

(2, 0)

(1, 0)

(0, 2)

(0, 0)

Explanation:

y=2f(x+1)

translates the curve 1 unit to the left and stretches it vertically by factor 2.

C(1,0)

moves to

(0,0)

; the vertical stretch leaves a zero unchanged.

Derived from ZIMSEC Mathematics Paper 1, June 2011, Q7

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