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Paper 1 · inequalities / indices

Solve the inequality 33x54<27|3^{-3x} - 54| < 27.

A43<x<1-\tfrac{4}{3} < x < -1
B1<x<431 < x < \tfrac{4}{3}
C43<x<43-\tfrac{4}{3} < x < \tfrac{4}{3}
Dx<43x < -\tfrac{4}{3} or x>1x > -1
Explanation: 33x54<27|3^{-3x}-54|<27 gives 27<33x<8127<3^{-3x}<81, i.e. 33<33x<343^3<3^{-3x}<3^4, so 3<3x<43<-3x<4 and hence 43<x<1-\tfrac{4}{3}<x<-1.

Derived from ZIMSEC Mathematics Paper 1, June 2011, Q1

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