The ball's initial vertical velocity is $u \approx 20.6$ m s $^{-1}$ upward and $g = 9.81$ m s $^{-2}$ . Calculate the time taken to reach the greatest height, where the vertical velocity is momentarily zero.

Model answer

2.1 s

Also accepted: 2,1 s, 2.10 s

Explanation: At the greatest height

v=0

. Using

v=u-gt

t = u/g = 20.6/9.81 \approx 2.1

Derived from ZIMSEC Physics Paper 3, November 2003, Q1

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