An object is projected vertically upward from the ground. Its velocity-time graph is a straight line from (0 s, 10 m/s) through (3 s, 0 m/s), continuing with the same slope to about (5 s, -6.7 m/s). Deduce from the graph the time at which the object reaches maximum height.

Model answer

3 s

Also accepted: 3s, t = 3 s

Explanation: Maximum height is reached when the vertical velocity is momentarily zero, which on the graph is where the line crosses the time axis, at t = 3 s.

Derived from ZIMSEC Physics Paper 2, November 2003, Q1

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An object is projected vertically upward from the ground. Its velocity-time graph is a straight line from (0 s, 10 m/s) through (3 s, 0 m/s), continuing with the same slope to about (5 s, -6.7 m/s). Deduce from the graph the time at which the object reaches maximum height.

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