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Paper 1 · gravitation

The distance between the centre of the Earth and a communications satellite is 42 000km. What is the gravitational force between the satellite and the earth? (Mass of Earth =6.0×1024= 6.0 \times 10^{24}kg, Mass of satellite =50= 50kg).

A2.3×1012.3 \times 10^{-1} N
B1.1×1011.1 \times 10^{1} N
C4.8×1084.8 \times 10^{8} N
D1.7×10111.7 \times 10^{11} N
Explanation: F=GMmr2=6.67×1011×6.0×1024×50(4.2×107)2=2.0×10161.76×101511F = \frac{GMm}{r^2} = \frac{6.67\times10^{-11}\times 6.0\times10^{24}\times 50}{(4.2\times10^7)^2} = \frac{2.0\times10^{16}}{1.76\times10^{15}} \approx 11 N =1.1×101= 1.1\times10^1 N.

ZIMSEC Physics Paper 1, June 2003, Q7

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