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Paper 4 (9164, Section B) · November 2004 · Kinematics

The diagram shows the (t, x)(t,\ x) graph for a particle which moves along a straight line. Its first straight section runs from (0, −4)(0,\ -4) to the corner at (2, 2)(2,\ 2), and A is the point where the graph first crosses the t-axis. Find the coordinates of the point A.

Model answer

(4/3, 0)

Also accepted: (4/3; 0), (4/3 , 0), 4/3, 0, 4/3, (1,33; 0), (1.33, 0), (1 1/3, 0)

Explanation

The first section has gradient 2−(−4)2−0=3\dfrac{2-(-4)}{2-0}=3 and passes through (0, −4)(0,\ -4), so its equation is x=3t−4x=3t-4. It meets the t-axis where 3t−4=03t-4=0, that is t=43t=\dfrac{4}{3}. So A(43, 0)A\left(\dfrac{4}{3},\ 0\right).

Derived from ZIMSEC Mathematics 9164/4 Paper 4, November 2004, Q12

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