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Paper 4 (9164, Section B) · November 2004 · Kinematics

The (t, x)(t,\ x) graph for a particle moving along a straight line starts at x=−4x=-4 m when t=0t=0 and finishes at x=−2x=-2 m when t=7t=7 s, where x metres is the displacement from a fixed origin. Find the average velocity of the particle, in ms−1^{-1}.

Model answer

2/7

Also accepted: 0,286, 0.286, 0,29, 0.29, 0,2857, 0.2857, 2/7 ms^-1

Explanation

Average velocity is the change in displacement divided by the time taken, not the distance travelled divided by the time. The particle moves from −4-4 m to −2-2 m, a change of −2−(−4)=2-2-(-4)=2 m, over 7 s, so the average velocity is 27=0.286\dfrac{2}{7}=0.286 ms−1^{-1}.

Derived from ZIMSEC Mathematics 9164/4 Paper 4, November 2004, Q12

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