Paper 1 · November 2010 · Groups
Under the operation on the positive rational numbers, write the inverse of an element in terms of .
Model answer
100/a
Also accepted: 100 / a, a^-1=100/a
Explanation
The identity for this operation is 10, so the inverse satisfies . Hence and , which is a positive rational whenever is.
Derived from ZIMSEC Further Mathematics 9187/1, November 2010, Q4