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Paper 1 · November 2010 · Groups

Under the operation a∗b=ab10a * b = \frac{ab}{10} on the positive rational numbers, write the inverse of an element aa in terms of aa.

Model answer

100/a

Also accepted: 100 / a, a^-1=100/a

Explanation

The identity for this operation is 10, so the inverse a−1a^{-1} satisfies a∗a−1=a a−110=10a*a^{-1}=\dfrac{a\,a^{-1}}{10}=10. Hence a a−1=100a\,a^{-1}=100 and a−1=100aa^{-1}=\dfrac{100}{a}, which is a positive rational whenever aa is.

Derived from ZIMSEC Further Mathematics 9187/1, November 2010, Q4

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