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Paper 1 · November 2010 · Series and Proof by Induction

Find the value of 10n+12(4n+1)+510^n + 12\left(4^{n+1}\right) + 5 when n=1n = 1.

Model answer

207

Explanation

101=1010^1=10 and 41+1=164^{1+1}=16, so 12×16=19212\times16=192. The total is 10+192+5=20710+192+5=207. Since 207=9×23207=9\times23, the expression is divisible by 9 when n=1n=1, which settles the basis of the induction.

Derived from ZIMSEC Further Mathematics 9187/1, November 2010, Q6

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