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Paper 1 · November 2010 · Integration and Reduction Formulae

Write sin⁡2θ\sin^2 \theta in terms of cos⁡2θ\cos 2\theta.

Model answer

(1-cos2theta)/2

Also accepted: (1-cos(2theta))/2, 1/2 - (1/2)cos2theta

Explanation

The double angle result cos⁡2θ=1−2sin⁡2θ\cos2\theta=1-2\sin^2\theta rearranges to sin⁡2θ=1−cos⁡2θ2\sin^2\theta=\dfrac{1-\cos2\theta}{2}.

Derived from ZIMSEC Further Mathematics 9187/1, November 2010, Q7

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