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ZIMSEC A Level · 6032/2 · N2023

Physics Paper 2 November 2023

Questions
32
Total marks
60
Syllabus code
6032/2

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Questions
32
Pass mark
20
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]conservation of linear momentum; impulse and force; circular motion
The total linear momentum of a system of particles stays constant provided that
  1. Ano resultant external force acts on the system.
  2. Bno internal forces act between the particles of the system.
  3. Cthe total kinetic energy of the system is conserved as well.
  4. Devery particle in the system moves with the same velocity.

Question 102

[2 marks]conservation of linear momentum; impulse and force; circular motion
A car travelling at 20 m/s hits a large rock and stops instantly. A passenger of mass 65 kg wearing a seat belt is brought to rest in 0.5 s. Calculate the magnitude of the constant force the belt exerts on the passenger.

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Question 103

[2 marks]conservation of linear momentum; impulse and force; circular motion
A car travelling at 20 m/s hits a large rock and stops instantly. A passenger of mass 65 kg wearing a seat belt is brought to rest in 0.5 s. Calculate the energy absorbed by the safety belt system.

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Question 104

[2 marks]conservation of linear momentum; impulse and force; circular motion
In a rear-end collision the seat is driven forwards and pushes the passenger's torso forwards with it. A headrest reduces the chance of neck injury because it
  1. Areduces the total change of momentum of the head, so a smaller impulse has to act on the neck.
  2. Baccelerates the head forwards with the torso, so head and shoulders move together and the neck bends far less.
  3. Ckeeps the head above the shoulders, so the passenger's centre of gravity stays over the seat throughout.
  4. Dholds the head stationary while the torso is pushed forwards, so the neck takes the load gradually.

Question 105

[3 marks]conservation of linear momentum; impulse and force; circular motion
A force of constant magnitude acts on a moving body and stays perpendicular to the body's velocity at every instant. Which statement describes the resulting motion?
  1. AThe speed increases steadily while the direction of the velocity is unchanged, so the body follows a straight line with uniform acceleration.
  2. BThe speed stays constant while the direction of the velocity changes continuously, so the body follows a circle with its acceleration directed to the centre.
  3. CBoth the speed and the direction of the velocity change continuously, so the body follows an outward spiral whose radius grows steadily as it goes.
  4. DThe speed falls steadily while the direction of the velocity changes, so the body follows a circle of steadily decreasing radius.

Question 201

[2 marks]simple harmonic motion; springs in parallel; CT scanning
A body performs simple harmonic motion only if its acceleration is
  1. Aconstant in magnitude and always directed towards the point of maximum displacement.
  2. Bdirectly proportional to its displacement from a fixed point and always directed towards that point.
  3. Cdirectly proportional to its displacement from a fixed point and always directed away from that point.
  4. Dinversely proportional to its displacement from a fixed point and always directed towards that point.

Question 202

[2 marks]simple harmonic motion; springs in parallel; CT scanning
A trolley of mass 0.5 kg rests on a horizontal track between two springs, each of spring constant 15 N/m, so that both springs push it back whenever it is displaced. Calculate the angular frequency of its oscillations.

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Question 203

[2 marks]simple harmonic motion; springs in parallel; CT scanning
A trolley of mass 0.5 kg oscillates between two springs with an angular frequency of 7.75 rad/s, having been displaced 0.3 m from its equilibrium position and released. Calculate its maximum speed.

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Question 204

[1 marks]simple harmonic motion; springs in parallel; CT scanning
A trolley oscillating on a horizontal track between two springs has its angular frequency worked out from ω=k/m\omega = \sqrt{k/m}, with kk the combined spring constant of the two springs. Which assumption does that calculation make?
  1. AThe displacement is large enough to take the springs past their elastic limit before they are released.
  2. BThe two springs have different spring constants, so their restoring forces do not simply add.
  3. CThe trolley is much lighter than the springs, so most of the oscillating mass is in the springs.
  4. DThe track and the wheels are frictionless, so the oscillation is undamped and the amplitude does not fall.

Question 205

[3 marks]simple harmonic motion; springs in parallel; CT scanning
In computed tomography (CT) scanning, a cross-sectional image of the body is built up because
  1. Aradio waves flip the spin of hydrogen nuclei held in a strong magnetic field, and the signal the nuclei re-emit as they relax is mapped point by point.
  2. Ba pulse of ultrasound is sent into the body and the depth of each boundary is found from the time its echo takes to come back.
  3. Can X-ray beam and its detectors rotate around the patient, and a computer reconstructs the slice from the attenuation measured along many directions.
  4. Dgamma rays emitted by a tracer taken into the patient are picked up by a ring of counters that record where each decay took place.

Question 301

[1 marks]capacitance; capacitors in parallel and charge sharing; logic gates
One farad is the capacitance of a capacitor that stores
  1. Aone coulomb of charge for each joule of energy stored in it.
  2. Bone volt of potential difference for each coulomb of charge on its plates.
  3. Cone coulomb of charge for each volt of potential difference across it.
  4. Done joule of energy for each coulomb of charge on its plates.

Question 302

[2 marks]capacitance; capacitors in parallel and charge sharing; logic gates
A 6.0 uF capacitor is charged to a p.d. of 10 V, then disconnected from the supply and connected in parallel with an uncharged 15 uF capacitor. Calculate the p.d. across the capacitors after the connection.

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Question 303

[2 marks]capacitance; capacitors in parallel and charge sharing; logic gates
A 6.0 uF capacitor charged to 10 V is disconnected from its supply and connected in parallel with an uncharged 15 uF capacitor, after which both sit at a p.d. of 2.86 V. Calculate the charge on the 15 uF capacitor.

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Question 304

[2 marks]capacitance; capacitors in parallel and charge sharing; logic gates
A 6.0 uF capacitor charged to 10 V is disconnected from the supply and then joined in parallel with an uncharged 15 uF capacitor. Which statement about the pair after the connection is correct?
  1. AThey each end at 10 V, because disconnecting the supply fixes the potential difference on the plates.
  2. BThey share the original 60 uC between them and both end at the same potential difference of 2.9 V.
  3. CThey each keep 60 uC, so the total charge in the circuit rises to 120 uC at a shared p.d. of 2.9 V.
  4. DThey share the original 60 uC, and the smaller capacitor ends at the higher potential difference.

Question 305

[2 marks]capacitance; capacitors in parallel and charge sharing; logic gates
In the lamp circuit of Fig. 3.1 the two changeover switches are cross-wired: the contact marked 0 at S1 is joined to the contact marked 1 at S2, and the contact marked 1 at S1 is joined to the contact marked 0 at S2. For which switch settings does the lamp light?
  1. AOnly when the two switches are set to the same number, that is (0, 0) or (1, 1).
  2. BFor every setting except (0, 0), so that the circuit behaves as an OR gate.
  3. COnly when the two switches are set to different numbers, that is (0, 1) or (1, 0).
  4. DOnly for the setting (1, 1), so that the circuit behaves as an AND gate.

Question 306

[1 marks]capacitance; capacitors in parallel and charge sharing; logic gates
A lamp circuit switches on only when its two inputs differ, so it performs the exclusive-OR function. What is the smallest number of two-input NAND gates needed to build this function?
  1. A3
  2. B4
  3. C5
  4. D6

Question 401

[1 marks]Bernoulli's principle; kinetic model and thermal expansion; latent heat and boiling
Bernoulli's principle states that, along a streamline in a non-viscous incompressible fluid in steady flow,
  1. Athe product of the pressure and the volume of the fluid stays constant at a fixed temperature.
  2. Bthe mass of fluid crossing each cross-section per second falls wherever the pipe narrows.
  3. Cthe sum of the pressure and the kinetic and potential energies per unit volume stays constant.
  4. Dthe pressure rises wherever the speed of the fluid rises, provided the height is unchanged.

Question 402

[2 marks]Bernoulli's principle; kinetic model and thermal expansion; latent heat and boiling
Bernoulli's equation, p+12ρv2+ρgh=p + \tfrac12\rho v^2 + \rho gh = constant, is an expression of the conservation of energy because
  1. Athe pressure term measures the heat given out by the fluid, which balances the kinetic energy it gains.
  2. Bit shows that the mass of fluid entering a pipe each second is equal to the mass of fluid that leaves that pipe each second.
  3. Cthe density of the fluid is unchanged, so the fluid can neither gain nor lose gravitational potential energy.
  4. Deach of its three terms is an energy per unit volume of fluid, and no energy leaves a non-viscous fluid in steady flow.

Question 403

[2 marks]Bernoulli's principle; kinetic model and thermal expansion; latent heat and boiling
Explained by the kinetic model of matter, a liquid expands more than a solid does for the same rise in temperature because
  1. Aits molecules are not held at fixed sites and its intermolecular forces are weaker, so the same energy pushes them further apart.
  2. Bits molecules are already touching the container, so the container's own expansion is added to that of the liquid.
  3. Cits molecules vibrate about fixed sites while a solid's molecules move freely, so its vibrations have the larger amplitude.
  4. Dits molecules are heavier, so each one carries more kinetic energy at a given temperature and needs more room.

Question 404

[2 marks]Bernoulli's principle; kinetic model and thermal expansion; latent heat and boiling
While a liquid is boiling its temperature does not rise. The heat supplied during boiling is used
  1. Ato raise the mean kinetic energy of all of the molecules, which is what lets the fastest of them break through the surface of the liquid.
  2. Bto raise the pressure of the liquid until it becomes equal to the pressure of the atmosphere above the surface.
  3. Cto do work against the intermolecular forces holding the molecules in the liquid, and to push back the atmosphere as vapour forms.
  4. Dto increase the specific heat capacity of the liquid, so that its temperature can no longer rise while it boils.

Question 405

[3 marks]Bernoulli's principle; kinetic model and thermal expansion; latent heat and boiling
Other than for reasons of hygiene, food cooks faster in a closed container because
  1. Athe lid keeps air away from the food, so oxidation of the food no longer takes energy away from the heating.
  2. Bthe trapped vapour lowers the pressure inside, and a lower pressure lets water boil at a temperature well above 100 degrees C.
  3. Cthe trapped vapour raises the pressure inside, and the boiling point rises with pressure, so the food cooks at a higher temperature.
  4. Dthe lid reflects the infrared radiation from the flame back into the food, adding to the heat conducted through the base.

Question 501

[2 marks]line spectra; alpha scattering and the nuclear atom; half-life and decay constant
Which pair correctly distinguishes an emission line spectrum from an absorption line spectrum?
  1. AEmission: bright lines on a dark background from excited atoms falling to lower levels. Absorption: dark lines on a continuous bright background where photons have been removed.
  2. BEmission: dark lines on a continuous bright background where photons have been removed. Absorption: bright lines on a dark background from excited atoms falling to lower levels.
  3. CEmission: a continuous band of all colours given out by a hot solid. Absorption: bright lines on a dark background given out by a cool low-pressure gas.
  4. DEmission: bright lines whose wavelengths depend on the temperature of the gas. Absorption: dark lines whose wavelengths depend on the pressure of the gas.

Question 502

[3 marks]line spectra; alpha scattering and the nuclear atom; half-life and decay constant
In the alpha-particle scattering experiment a very small number of the alpha particles were deflected through more than 90 degrees. This observation shows that
  1. Athe electrons in the atom carry enough momentum to turn a fast alpha particle back along its path.
  2. Bthe gold foil used was many atoms thick, so each alpha particle met a great many nuclei in turn.
  3. Cthe atom is a sphere of positive charge in which the electrons sit embedded at regular intervals.
  4. Dthe positive charge and nearly all the mass of an atom are concentrated in a very small, dense nucleus.

Question 503

[1 marks]line spectra; alpha scattering and the nuclear atom; half-life and decay constant
The decay constant λ\lambda of a radioactive isotope and its half-life t1/2t_{1/2} are related so that
  1. Athe product λt1/2\lambda t_{1/2} is equal to ln⁡2\ln 2, about 0.693.
  2. Bthe ratio λ/t1/2\lambda / t_{1/2} is equal to ln⁡2\ln 2, about 0.693.
  3. Cthe product λt1/2\lambda t_{1/2} is equal to 1 exactly.
  4. Dthe product λt1/2\lambda t_{1/2} is equal to 2 exactly.

Question 504

[2 marks]line spectra; alpha scattering and the nuclear atom; half-life and decay constant
The half-life of a radioactive isotope is 62 years. Calculate the fraction of a sample that remains after 31 years.

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Question 505

[2 marks]line spectra; alpha scattering and the nuclear atom; half-life and decay constant
Radioactive isotopes occur naturally in food and drink, yet they do little harm to body tissue. One reason is that
  1. Athe isotopes present have half-lives of a few seconds, so almost all of them decay before the food is swallowed.
  2. Bonly a trace of the isotope is present, so the activity and the dose rate to any tissue are both very small.
  3. Cthe isotopes present decay by emitting gamma rays, which pass straight through the body without interacting.
  4. Dthe digestive system converts the isotopes into stable nuclides before they can reach any of the body tissues.

Question 601

[2 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
Amplitude modulation and frequency modulation alter a carrier wave so that
  1. AAM varies the carrier's frequency with the signal and leaves its amplitude fixed, while FM varies its amplitude and leaves its frequency fixed.
  2. BAM varies the carrier's amplitude with the signal while FM varies its wavelength, and both leave the speed of the carrier unchanged.
  3. CAM and FM both vary the carrier's amplitude, but FM also shifts the carrier onto a higher frequency band before transmission.
  4. DAM varies the carrier's amplitude with the signal and leaves its frequency fixed, while FM varies its frequency and leaves its amplitude fixed.

Question 602

[1 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
One disadvantage of transmitting information as an analogue signal is that
  1. Anoise picked up along the route is amplified with the signal at every repeater and cannot be separated from it.
  2. Bit varies in steps rather than continuously, so the fine detail of the original information is lost on the way.
  3. Cit can only be sent along a wire, since an analogue waveform cannot be used to modulate a carrier wave.
  4. Dit has to be sampled many times each second, which sets a limit on the highest frequency the system can carry.

Question 603

[2 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
An analogue signal is fed to an analogue to digital converter working at a sampling frequency of 0.5 kHz. Calculate the time interval between successive samples, in milliseconds.

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Question 604

[2 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
Fig. 6.1 shows an analogue signal in volts against time in milliseconds. It is fed to an analogue to digital converter working at a sampling frequency of 0.5 kHz, the first sample being taken at t=0t = 0. Read to the nearest volt, what are the sampled voltages?
  1. A2 V, 4 V, 6 V, 3 V, 4 V, 2 V and 1 V
  2. B2 V, 7 V, 3 V, 4 V and 1 V
  3. C2 V, 6 V, 4 V, 3 V and 1 V
  4. D2 V, 6 V, 3 V, 4 V and 1 V

Question 605

[2 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
A four-bit analogue to digital converter records one level per volt. Which set of four-bit words represents the sampled voltages 2 V, 6 V, 3 V, 4 V and 1 V, taken in that order?
  1. A0100, 0110, 1100, 0010, 1000
  2. B0001, 0101, 0010, 0011, 0000
  3. C0010, 0011, 0110, 0100, 0001
  4. D0010, 0110, 0011, 0100, 0001

Question 606

[1 marks]amplitude and frequency modulation; analogue to digital conversion; sampling
The signal recovered from a four-bit analogue to digital converter comes out as a coarse staircase rather than a smooth curve. Its quality is improved by
  1. Aincreasing the sampling frequency, so that the steps are narrower and follow the original curve more closely.
  2. Bdecreasing the sampling frequency, so that fewer steps are needed and each one of them lasts a good deal longer.
  3. Creducing the number of bits per sample, so that each level is recorded with a shorter binary word.
  4. Dincreasing the amplitude of the carrier wave, so that the steps in the recovered signal are taller.

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