Danho
ZIMSEC A Level · 9190/4 · J2004

Biology Paper 4 June 2004

Questions
21
Total marks
60
Time allowed
150 min
Syllabus code
9190/4

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Questions
21
Pass mark
13
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 101

[1 marks]Enzyme practical: catalase in yeast
In a school practical, 2 cm3 of 2.0M hydrogen peroxide is added to 2 cm3 of an active (unboiled) yeast suspension in a test tube, and a glowing splint is immediately inserted into the tube above the mixture. What happens to the glowing splint?

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Question 102

[1 marks]Enzyme practical: catalase in yeast
In the same test (2 cm3 of 2.0M hydrogen peroxide added to 2 cm3 of active, unboiled yeast suspension), what is seen in the reaction mixture itself, separate from the glowing-splint test?

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Question 201

[1 marks]Enzyme practical: catalase denatured by boiling
A yeast suspension is boiled for 5 minutes, then cooled under running tap water. Hydrogen peroxide is added and a glowing splint is inserted, exactly as was done with an unboiled sample. What is observed?
  1. ABubbles form in the mixture but the splint does not relight.
  2. BNo bubbles form in the mixture but the splint still relights.
  3. CThe mixture bubbles vigorously, exactly as it did before boiling, and the splint relights when it is inserted.
  4. DNo bubbles form in the mixture and the splint does not relight.

Question 301

[1 marks]Enzyme practical: explaining catalase and denaturation
Name the enzyme present in yeast that is responsible for breaking down hydrogen peroxide into water and oxygen.

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Question 302

[1 marks]Enzyme practical: explaining catalase and denaturation
When catalase breaks down hydrogen peroxide in yeast, which gas is produced?

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Question 303

[3 marks]Enzyme practical: explaining catalase and denaturation
A yeast suspension that was boiled for 5 minutes and then cooled shows no bubbling and does not relight a glowing splint when hydrogen peroxide is added, unlike an unboiled sample of the same yeast suspension. Why?
  1. ABoiling increased the catalase's activity so much that all of the hydrogen peroxide had already reacted before the glowing splint could even be inserted into the tube.
  2. BThe cooling step under running tap water washed all of the hydrogen peroxide out of the tube before any reaction with the yeast could begin.
  3. CThe catalase in the boiled sample was denatured by the heat because it is a protein, so it could no longer catalyse the breakdown of hydrogen peroxide.
  4. DThe yeast suspension in tube B had already been killed by the cold tap water before it was ever placed into the boiling water bath at all.

Question 501

[1 marks]Enzyme practical: substrate concentration and rate
In a catalase-yeast reaction with hydrogen peroxide, why does increasing the substrate (hydrogen peroxide) concentration, up to a point, increase the rate of gas bubble production?

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Question 502

[2 marks]Enzyme practical: substrate concentration and rate
In an enzyme practical using a fixed amount of yeast (catalase), the rate of bubble production rises as hydrogen peroxide concentration increases, but levels off at the highest concentrations tested. What does this levelling off show?
  1. AThe reaction has reached true chemical equilibrium and has therefore stopped producing any further oxygen gas.
  2. BA factor other than substrate concentration, such as the fixed amount of enzyme present, has become limiting.
  3. CHydrogen peroxide concentration remains the only factor limiting the rate at every concentration that was tested.
  4. DThe catalase enzyme has been permanently and irreversibly denatured by the high substrate concentration itself.

Question 601

[1 marks]Enzyme practical: reason for the 30-second wait
In the substrate-concentration practical, why did the procedure require waiting 30 seconds after sealing the reaction tube before starting to count bubbles for one minute?
  1. ATo allow the glowing splint enough time to cool down completely before it was inserted into the tube.
  2. BTo allow the initial, uneven burst of bubble production to settle into a steady, countable rate.
  3. CTo allow the boiling water bath enough time to fully return to its normal, full boiling temperature again.
  4. DTo let enough of the hydrogen peroxide evaporate out of the tube so the bubbles could be counted safely.

Question 701

[1 marks]Enzyme practical: improving experimental design
This enzyme practical is carried out at room temperature, which is not precisely controlled. Suggest one change to the experimental design that would control temperature more precisely and improve the accuracy of the results.

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Question 702

[1 marks]Enzyme practical: improving experimental design
This enzyme practical uses hydrogen peroxide solutions of different concentrations with no pH control. Suggest one change to the experimental design, besides temperature control, that would improve the accuracy of the results, given that catalase's activity is sensitive to pH.

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Question 801

[1 marks]Enzyme practical: classifying catalase
Catalase catalyses the breakdown of hydrogen peroxide into water and oxygen. Based on the type of reaction it catalyses, to which broad class of enzymes does catalase belong?

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Question 1301

[1 marks]Plasmolysis practical: explaining the graph's shape
In a plasmolysis practical, plant epidermal cells are placed in sucrose solutions of increasing concentration and water moves out of the cells into the surrounding solution. By what process does this water movement occur?
  1. AFacilitated diffusion
  2. BActive transport
  3. COsmosis
  4. DSimple diffusion

Question 1302

[1 marks]Plasmolysis practical: explaining the graph's shape
For water to move out of a plant cell into a surrounding sucrose solution by osmosis, the water potential of the cell must be ___ than the water potential of the solution.

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Question 1303

[3 marks]Plasmolysis practical: explaining the graph's shape
In a plasmolysis practical, as the concentration of the surrounding sucrose solution increases, the percentage of visibly plasmolysed epidermal cells also increases. What explains this trend?
  1. AHigher sucrose concentrations dissolve the cell wall directly, which causes plasmolysis in a larger proportion of the cells.
  2. BSucrose molecules actively diffuse into the cells and replace the water content that was originally present there.
  3. CThe water potential gradient between the cell and the solution becomes steeper, so more water leaves the cells by osmosis.
  4. DHigher sucrose concentrations increase the rate of active transport of water molecules into the cells themselves.

Question 1401

[2 marks]Plasmolysis practical: why cells differ in solute potential
In a piece of plant epidermal tissue placed into a single sucrose solution, not every cell shows the same solute potential. Why do cells within the same piece of tissue not all have the same solute potential?
  1. ADifferent cells contain different amounts and types of solutes, since their metabolic activity varies from cell to cell.
  2. BAll cells within a single piece of tissue always have identical solute potential, unless the tissue has been physically damaged.
  3. CSolute potential depends mainly on a cell's physical size rather than on the solutes that the cell contains.
  4. DOnly the outermost cells of a piece of tissue are able to differ in solute potential from the cells beneath them.

Question 1501

[1 marks]Plasmolysis practical: sources of inaccuracy
In the plasmolysis practical, pieces of epidermis were removed from each petri dish in turn (one dish at a time) after the dishes had all been left aside together. Suggest one source of inaccuracy this introduces.

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Question 1502

[1 marks]Plasmolysis practical: sources of inaccuracy
Besides unequal immersion time, suggest one other source of inaccuracy in the plasmolysis practical that comes from natural variation between the individual cells examined.

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Question 1701

[1 marks]Ovary specimen: event after full follicle development
Specimen Z1 is a stained section of a mammalian ovary showing oogenesis, from an early primary follicle through to a fully developed mature Graafian follicle. What event follows once a mature Graafian follicle has fully developed?

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Question 1801

[1 marks]Ovary specimen: fate of the corpus luteum
After ovulation, the ruptured Graafian follicle remains in the ovary. Name the structure it becomes.

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Question 1802

[2 marks]Ovary specimen: fate of the corpus luteum
If fertilisation and pregnancy do not occur, what is the fate of the corpus luteum that forms in the ovary after ovulation?
  1. AIt functions as an endocrine gland for a short time and then undergoes regression and degeneration.
  2. BIt is expelled from the body together with the unfertilised secondary oocyte during menstruation.
  3. CIt remains permanently active in the ovary, continuing to secrete hormones for the rest of a woman's life.
  4. DIt immediately develops back into a new primary follicle, ready for the next ovarian cycle.

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