Danho
ZIMSEC A Level · J2016

Biology Paper 2 June 2016

Questions
12
Total marks
35

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Questions
12
Pass mark
8
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Question 301

[1 marks]recombinant DNA technology
During the formation of recombinant DNA, an mRNA molecule for the required gene is isolated and an enzyme is used to synthesise a complementary DNA (cDNA) copy of it. Which enzyme carries out this conversion of mRNA into cDNA?

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Question 302

[1 marks]recombinant DNA technology
In recombinant DNA technology, both the DNA containing the required gene and the vector (e.g. plasmid) DNA must be cut at specific recognition sequences into fragments before the gene can be inserted into the vector. Which type of enzyme cuts DNA in this way?

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Question 303

[1 marks]recombinant DNA technology
After a gene has been cut out with a restriction enzyme and inserted into a cut plasmid, which enzyme seals the DNA backbone by joining the fragments together to complete the recombinant DNA molecule?

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Question 401

[1 marks]recombinant DNA technology
In genetic engineering procedures such as the use of bacterial plasmids as vectors to produce human insulin, what is the role of restriction enzymes?
  1. AThey copy an mRNA template into a single strand of complementary DNA for insertion into a vector.
  2. BThey unwind the DNA double helix ahead of the replication fork so that both strands can be copied.
  3. CThey cut DNA at specific recognition sequences, producing fragments so that a required gene can be removed and inserted into a vector.
  4. DThey join two DNA fragments together permanently by forming new phosphodiester bonds across the gap in each strand of the sugar-phosphate backbone.

Question 1901

[1 marks]lipids
Fig. 2.1 shows the structural formulae of two molecules, A and B. Molecule A has a glycerol backbone joined by ester bonds to three fatty acid chains. What class of lipid is molecule A?

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Question 1902

[1 marks]lipids
Fig. 2.1 shows the structural formulae of two molecules, A and B. Molecule B has a glycerol backbone joined to two fatty acid chains and a phosphate group. What class of lipid is molecule B?

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Question 1903

[1 marks]lipids
Some fatty acids have double bonds in their hydrocarbon tails. What is the biological significance of these double bonds?
  1. AThey introduce kinks in the hydrocarbon tail that prevent the fatty acid chains from packing closely together, which lowers the lipid's melting point.
  2. BThey add extra hydrogen atoms along the tail at the point where the double bond was, which raises the lipid's melting point and makes it solidify more readily at low temperature.
  3. CThey let the fatty acid chains pack more tightly together in a regular lattice, which increases the lipid's density and melting point.
  4. DThey replace the ester bonds linking the fatty acids to glycerol, which makes the lipid far more resistant to enzymic hydrolysis.

Question 1904

[1 marks]lipids
Poikilothermic (cold-blooded) animal cells have a higher proportion of unsaturated fatty acids in their membranes than homeothermic (warm-blooded) animal cells. Why is this important?
  1. AUnsaturated fatty acids have lower melting points, so they keep the cell membrane fluid when the animal's body temperature falls in cold surroundings.
  2. BUnsaturated fatty acids are broken down and respired more easily than saturated fatty acids, releasing extra metabolic heat that helps warm the cell in cold environments.
  3. CUnsaturated fatty acids form stronger bonds with membrane proteins, making the membrane more rigid at low temperature.
  4. DUnsaturated fatty acids increase the membrane's permeability to water, allowing the cell to osmoregulate faster in cold water.

Question 2001

[1 marks]enzymes
What term describes the minimum quantity of energy that must be provided to a reaction to break bonds in the reactants and start the reaction?

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Question 2002

[1 marks]enzymes
How does an enzyme increase the rate of a chemical reaction?
  1. AIt supplies extra chemical energy directly to the reactant molecules, increasing the total energy that the reaction releases overall.
  2. BIt permanently binds to the product formed at the active site, physically preventing the reverse reaction from taking place.
  3. CIt raises the local temperature of the substrate molecules bound to it, giving them extra kinetic energy to react faster.
  4. DSubstrate binds to the enzyme's active site, slightly changing the site's shape so that bonds in the substrate break more easily, which lowers the activation energy needed.

Question 2003

[1 marks]enzymes
Heavy metal ions such as mercury, silver and arsenic bind to sites away from an enzyme's active site and change the shape of the active site, reducing the enzyme's activity. What type of enzyme inhibition is this?

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Question 2004

[1 marks]enzymes
Heavy metal ions such as mercury, silver and arsenic act as non-competitive inhibitors of enzymes. How do they cause this inhibition?
  1. AThey bind reversibly to the active site for a short time, briefly blocking substrate binding before dissociating.
  2. BThey bind permanently to sulphydryl/disulphide bonds away from the active site, changing the enzyme's structure so that it precipitates and loses activity.
  3. CThey compete directly with the substrate for the active site, blocking it there until the metal ion happens to be displaced again by an excess of substrate molecules.
  4. DThey lower the kinetic energy of the enzyme molecule, slowing the reaction until the temperature is raised again.

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