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Paper 2 · November 2016 · Work, Energy and Power

A light bulb is labelled 240 V, 60 W. Calculate the current that flows through the bulb when it is operating normally.

A4 A

B60 A

C0.004 A

D0.25 A

Explanation

P = IV, so I = P/V = 60/240 = 0.25 A.

Derived from ZIMSEC Physics 5055/2 Paper 2 Theory, November 2016, Q5

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