Danho

Paper 4 · conditional probability / Bayes theorem

A manufacturing plant uses three machines, A, B and C, contributing 40%, 45% and 15% of daily output respectively, with defect rates of 4%, 3% and 1% for A, B and C respectively. Given that a randomly chosen tin is defective, what is the probability, to 3 decimal places, that it came from machine B?

Model answer

0.435

Also accepted: 0.436, 27/62

Explanation: By Bayes' theorem, P(Bdefective)=P(B)P(defectiveB)P(defective)=0.45×0.030.031=0.01350.031=27620.435P(B\mid\text{defective}) = \dfrac{P(B)P(\text{defective}\mid B)}{P(\text{defective})} = \dfrac{0.45\times0.03}{0.031} = \dfrac{0.0135}{0.031} = \dfrac{27}{62} \approx 0.435.

Derived from ZIMSEC Maths Paper 1, June 2007, Q1 (Statistics)

View this paper's sittings and topics

More questions from this paper

Get the full paper, not just one question

Danho has every sitting for this paper, with your progress tracked question by question, offline.

Get it on Google Play
Download on the App Store